Title: EE 362 Electric and Magnetic Properties of Materials
1EE 362 Electric and Magnetic Properties of
Materials
- Dr. Brian T. Hemmelman
- Chapter 8 Slides
2Assumptions (2)
- Abrupt Junction There is a clear dividing line
between the p-type material and the n-type
material. - Abrupt Space Charge Region The edge of the
space charge region are well defined and abrupt. - Boltzmann Approximation Applies The doping
concentrations used in both materials are low
enough that EF gt 3kT away from the conduction and
valence band edges. - Low-Level Injection The quantity of minority
holes and electrons injected across the pn
junction are small enough to be low-level - Total current through the pn structure is
constant We do not violate Kirchoffs Current
Law the amount of current that flows into one
terminal is that same amount of current that
flows out the other terminal and all parts in
between. - Each electron and hole current component is
continuous No black holes or antimatter
allowed! - The electron and hole currents are constant in
the depletion region No recombination in the
depletion region
3Boundary Conditions (3)
The built-in potential for the junction was found
to be
Lets rearrange this a bit.
4Boundary Conditions (4)
Under complete ionization though we have
where nn0 is the electron majority carrier
concentration on the n-side and np0 is the
electron minority carrier concentration on the
p-side. Thus, for thermal equilibrium we have
5Boundary Conditions in Forward Bias (5)
When we apply a positive voltage (from p to n) we
generate an electric field that opposes the
internal electric field. Therefore the energy
bands are less curved.
6Boundary Conditions in Forward Bias (6)
Intuitively we know that should lead to more
charge and current due to spillover (think of
our stack of cannonballs now able to get over the
band-bending). Quantitatively, now becomes
np is the forward biased electron concentration
on the p-side.
So
Similarly,
These are the concentrations of minority carriers
at the edge of the space charge region.
7Boundary Conditions in Forward Bias (7)
In forward bias we have increased the quantity of
minority charge carriers on both sides of the
depletion region because we are injecting
electrons from the n-side to the p-side (where
they are now the minority carrier) and we are
injecting holes from the p-side to the n-side
(where they are now the minority carrier).
8Minority Carrier Distribution (8)
We have found what the concentrations were at the
edge of the space charge region. What are they
elsewhere? Note, we have created additional
minority charges above the thermal equilibrium
value. This is just like the generation of
minority charge carriers we studied in Chapter 6.
The difference is that instead of
photogeneration, they are being generated by
injection across the space charge region. Thus,
we can use everyones favorite Ambipolar
Transport Equation!
More specifically, we have in the n-region
where
(excess minority holes on n-side)
9Boundary Conditions for Excess Minority Carrier
Distribution (9)
Now, the applied electric field exists primarily
across the space charge region only (and not very
much outside of it). Thus E ? 0, and we also
have g 0. If we are looking at steady-state
(after the voltage was applied) then
So
10Boundary Conditions for Excess Minority Carrier
Distribution (10)
In a 1-dimensional case this is just an ordinary
derivative, and so we can rewrite this as
The general solutions to these equations are
We can conclude that both A and D must be zero in
order to keep the excess minority carrier
concentration from going to infinity.
11Boundary Conditions for Excess Minority Carrier
Distribution (11)
We can also determine additional boundary
conditions for the problem.
12Minority Carrier Distribution (12)
Applying these additional boundary conditions
lets us completely solve the Ambipolar Transport
Equations to find the minority carrier
distributions on the n-side and the p-side.
Note ?pn(x) ? 0 as x ? ? and ?np(x) ? 0 as x ? -?
13p-n Junction Current (13)
- Now, go back to our assumptions
- Total current through the junction is constant.
- Electron and hole current components are constant
through the depletion region. - Thus,
14p-n Junction Current (14)
What are these two values, Jp(xn) and
Jn(-xp)? They are the value of the diffusion
currents at the edge of the depletion
region! Recall that the electric field outside of
the depletion region is 0 (or almost 0).
Therefore we will not have any significant drift
of excess minority electrons on the p-side or of
excess minority holes on the n-side. The values
of these two diffusion currents at the edge of
the depletion region are found as
15p-n Junction Current (15)
However, for uniformly doped regions both pn0 and
np0 are constants so
Using the formulae for ?pn(x) and ?np(x) derived
on Slide 12 we find the above equations will
evaluate to
16p-n Junction Current (16)
Since the current components through the
depletion region are constant (no recombination)
we can extend these two values across the
depletion region and add the two together to get
the total current density.
17p-n Junction Current (17)
All the terms out front that are not dependent on
the applied voltage we can rename as the
parameter called the ideal reverse saturation
current density
Thus, we can rewrite the pn junction diode
equation into the familiar form
18p-n Junction Current (18)
Vt is the thermal voltage which is 0.0259 Volts
at T 300K. For Va Vt the exponential term
will dominate and we can rewrite the current
density as
If we multiply by the cross-sectional area of the
diode we then get the I-V relationship for a
diode.
19Diode Current Components Outside the Depletion
Region (19)
We computed the diffusion currents at the edge of
the depletion region to get the diode equation.
We can compute the minority carrier diffusion
current components throughout the rest of the
diode as well. They are
20Diode Current Components Outside the Depletion
Region (20)
21Another Real-World Example (21)
- When you break a bone, there are two parts that
can begin to regrow or heal. - The first is the periosteum cells (the bones
fibrous covering). The innermost periosteum
cells have the power of osteogenesis (bone
formation). - After a fracture, these cells get turned on and
begin to divide. The daughter cells turn into
osteoblasts. - Osteoblasts are the cells that make the collagen
fibers of bone (collagen fibers are based on
proteins). - Apatite crystals then condense out of the blood
serum onto the fibers.
22Another Real-World Example (22)
23Another Real-World Example (23)
- The other tissue that forms new bone is marrow.
- Its cells dedifferentiate and form a blastema,
filling the central part of the fracture. - The blastema cells then turn to cartilage cells
and then into more osteoblasts (same sequence as
regeneration of salamander limbs).
24Another Real-World Example (24)
- There is a third growth process unique to bone,
Wolffs Law Bone responds to stress by growing
into whatever shape meets the demands of its
environment. - When bone is bent, one side is compressed and the
other is stretched. Extra bone grows to shore up
the compressed side and some is absorbed from the
stretched side.
25Another Real-World Example (25)
- This occurs because something stimulates the
periosteum to grow new bone at a surface where
there is compressional stress, and dissolves bone
where there is tensional stress. - What is something that reacts to stress/strain?
- Consider piezoelectricity (like the piezoelectric
buzzer elements you can buy).
26Another Real-World Example (26)
- In a piezoelectric material, a small amount of
electrons are freed up from bonds under stress
and migrate toward the side of compression (the
charge on the inside of the curve is negative). - Once a steady-state stress is achived the charge
buildup disappears. - When you reduce the stress, an equal an opposite
pulse occurs.
27Another Real-World Example (27)
- This is almost what happens in bone, but not
quite. There isnt as much of a rebound signal
when stress is released. - Regeneration studies show the build-up of
negative charge is what is the growth stimulation
signal. The removal of the rebound charge is
what keeps bone growth from happening on the
tensile side.
28A Biological pn Junction (28)
- Collagen and apatite are the keys!
- Collagen exhibits n-type behavior.
- Apatite is p-type.
- Collagen is the piezoelectric material
- Mechanical stress produces a piezoelectric signal
from the collagen. - That signal has two phases for stress and release.
29A Biological pn Junction (29)
- The signal is rectified by the pn junction
between apatite and collagen. - Its strength indicates how much stress is there.
- Its polarity tells the cells which direction the
stress is. - Osteogenic cells in the negative potential area
are stimulated to grow more bone.
30A Biological pn Junction (30)
31Diffusion Resistance (31)
Our ideal diode I-V relationship is
ID ? Diode Current IS ? Reverse Saturation Current
The small-signal incremental conductance is just
the slope of the DC I-V curve.
32Diffusion Resistance (32)
The small-signal incremental resistance then is
As long as Va is somewhat large then the -1
term is negligible and thus
33Diffusion Capacitance (33)
As you increase or decrease the applied voltage,
the excess carriers will increase or decrease
slightly. This is like the buildup of charge on
two capacitor plates.
34Small Signal Models (34)
Small-signal equivalent circuit
Complete small-signal equivalent circuit