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Integration Using Substitution

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The method of integration by substitution for indefinite ... Example1: sin(3x 5)dx. Step 2: Find du. u= 3x 5. du= 3 dx. Step 1: Let u=(3x 5) sin(3x 5)dx ... – PowerPoint PPT presentation

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Title: Integration Using Substitution


1
IntegrationUsing Substitution
  • Pauline Aguayo
  • Brent Rivas
  • Adam Ortiz
  • Matthew Gazmen
  • Araceli Resendiz
  • Katie Jensen

2
INTEGRAL anti-derivative
INTEGRATING
Integrating is finding the integral of something
  • The method of integration by substitution for
    indefinite integrals involves changing a
    variable( say x ) of an integrand to another
    variable( u ).

3
Five Steps of Integrating by Substitution 1) Let
u the inner part of a function. 2) Find du 3)
Re-write the integral in terms of u (and change
the limits if necessary.) 4) Evaluate the
integral in terms of u 5) Replace u with the
original g(x)
4
Formulas
  • Properties of Indefinite Integrals
  • ?kf (x)dx k?f (x)dx for any constant k
  • ?(f(x)g(x))dx ?f(x)dx ? g(x)dx
  • Power Formulas
  • ?undu (u(n1))/(n1) C when C? -1
  • ?u-1du ?1/u du ln(u) C

5
Formulas(continued)
Trigonometric Functions
  • ?(csc(u))2du -cot(u) C
  • ?sec(u)tan(u)du sec(u) C
  • ?csc(u)cot(u)du -csc(u) C
  • ?cos(u)du sin(u) C
  • ?sin(u)du-cos(u) C
  • ?(sec(u))2du tan(u) C

6
Formulas(continued)
  • Exponential and Logarithmic
  • ?eudu eu C
  • ?ln(u)du uln(u)- u C
  • ?loga u du ?(ln(u)/In(a))du (uln(u)- u)/
    (ln(a)) C
  • ?au du (au)/ (ln(a)) C

7
Example1
?sin(3x5)dx
  • Step 1 Let u(3x5)

8
?sin(3x5)dx
Step 1 Let u(3x5)
u 3x5 du 3 dx
  • Step 2 Find du

9
?sin(3x5)dx
Step 1 Let u(3x5)
Step 2 Find du du3
  • Step 3 Find dx
  • du 3 dx
  • du 3 dx
  • 3
  • 1 du dx
  • 3 m

10
?sin(3x5)dx
Step 1 Let u(3x5)
Step 2 Find du du3
Step 3 Find dx dx du
3
  • Step 4 Substitute

?sin(u) dx ?sin(u) du
3 ??sin(u)du ??sin(3x5)du
11
?sin(3x5)dx
Step 1 Let u(3x5)
Step 2 Find du du3
Step 3 Find dx dx du
3
  • Step 4 Substitute ??sin(3x5)du

Step 5 Integrate
??sin(3x5)du ??(-cos(3x5)) C
12
?sin x ecos x dx
Example2
  • -?(-sin x)ecos x dx
  • -?ecos x (-sin x)dx
  • -?eu du
  • -eu C
  • -ecos x C

13
?x²v(5 2x³)dx
Example3
  • ? (5 2x³)½ x² dx
  • 1/6 ? (5 2x³)½ 6x² dx
  • 1/6 ? u½ du
  • 1/6(?)u3/2 C
  • 1/9(5 2x³)3/2 C

14
Example4
  • ? x cos (2x2) dx
  • ? x x cosu x dx
  • ? x x cosu x 1/4x du
  • ¼ ? cosu x du
  • ¼ sinu C
  • ¼ sin (2x2) C
  • First Step let u 2x2
  • du 4x
  • 1/4x du dx
  • Second Step Replace 2x2 with u
  • Third Step Multiply x x cosu x 1/4x du and then
    you cancel the x.
  • Fourth Step Change cos to sin

15
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16
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