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Post Test Equilibrium

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mole products - # mole reactants. Substitution for Kp. Kp = Kc(RT ... 2) The removal of reactants: this is 'bad' and will shift equilibrium toward the ... – PowerPoint PPT presentation

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Title: Post Test Equilibrium


1
Post Test - Equilibrium
  • 1. Define equilibrium
  • 2. Write Keq for
  • a) H2 (g) I2 (g) ? HI (g)
  • b) Cu2 (aq) (SO4)2- (aq) ? CuSO4(s)
  • c) O3 (g) ? O2 (g)

2
Chapter 14 Equilibrium
  • Equilibrium is the condition in which the rate of
    formation of products equals the rate of
    formation of reactants

3
Equilibrium
  • We have seen reactions proceed from reactants to
    products
  • A reversible reaction occurs when enough of the
    product has been formed that the product begins
    to break down and form reactants

4
Equilibrium
  • A reversible reaction is symbolized by double
    arrows

2 SO2
O2
2 SO3
Equilibrium occurs when the rate of the forward
reaction equals the rate of the reverse reaction
5
Equilibrium
  • Equilibrium is defined in terms of concentration
  • Once at equilibrium, the concentration of
    reactants and products does not change

6
Equilibrium Continued
  • If one of the double arrows is drawn larger than
    the other one, the longer arrow indicate the
    favored side of the reaction
  • Equilibrium is a balance between the rate of the
    forward reaction and the reverse reaction

7
Equilibrium Expressions
  • Equilibrium expressions (Keq) equal products over
    reactants
  • Kc can be used in place of Keq
  • Kc specifies concentration
  • Kp specifies pressure (used for gases)

8
Equilibrium Expressions
  • Ka weak acid (weak electrolytes)
  • Kb weak base (weak electrolytes)
  • Ksp solubility of substances (slightly soluble)

9
Equilibrium Expressions
  • Keq expressions are written only for reactants
    and products in aqueous or gas form
  • Solids and liquids are left out

10
Setting Up Equilibrium Expressions
  • mA nB ? sC rD
  • The equilibrium expression is
  • Keq products / reactants

Cs Dr
Keq
Am Bn
11
Interpreting Equilibrium Expressions
  • The symbol means molar concentration
  • The exponents in the expressions are the
    coefficients for the balanced equation
  • The units for Keq are not generally used

12
Write Equilibrium Expressions
  • 1. N2O4 ? 2NO2
  • 2. H2 I2 ? 2HI
  • 3. N2 H2 ? NH3
  • 4. BrCl ? Br2 Cl2

13
Solving Equilibrium Problems
  • 5) What is the value for the Keq when 0.1 M H2
    reacts with 0.5 M O2 to produce 0.5 M H2O?
  • First, write balanced equation
  • Second, write Keq expression
  • Third, substitute values in the expression and
    solve
  • Ans) Keq 50

14
Solve
  • 6) 4 M N2 reacts with 6 M H2 to produce 10 M
    NH3
  • 7) 5 M CO2 breaks down to produce 6 M CO and 3 M
    O2 in an equilibrium reaction
  • Ans 2) 0.116
  • Ans 3) 4.32

15
More About Kp
  • Kp expressions are written for gases
  • 2 NO (g) O2 (g) ? 2 NO2 (g)
  • Kp (PNO2)2 / ( ( PNO ) 2 PO2)

16
Ideal Gas Law Kp Values
  • Ideal Gas Law PV nRT
  • P nRT/V, n/V concentration, c
  • P cRT, R 0.0821, T in Kelvin
  • Substitute cRT in place of P in Kp

17
Substitution for Kp
  • Kp (cRTNO22 ) / ((cRTNO)2 cRTO2)
  • Through complex substitutions,
  • Kp KcRT?ngas
  • ?ngas mole products - mole reactants

18
Substitution for Kp
  • Kp Kc(RT?ngas)
  • Example Consider the following equilibrium
    N2O4 (g) ? 2 NO2 (g)
  • The reaction occurs at 319 K and Kp is found to
    be 0.660. Determine Kc.

19
More About Kp
  • Kp KcRT?ngas
  • Given Kc 1.8 x 10-6 for
  • 2 NO (g) O2 (g) ? 2 NO2 (g) _at_257K
  • Derive Kp

20
Reverse Kc and Kp
  • If the Kc or Kp is known, the inverse (Kc or
    Kp) can be determined by taking the inverse
    value
  • If Kc 1.8 x 10-3, what is Kc?

21
Values for Kc and Kp
  • When actual numerical values for Kp and Kc are
    determined, the magnitude of the value infers
  • a. The reaction goes to completion if K is large
    (mainly products)
  • b. The reaction proceeds slowly if K is small
    (mainly reactants)

22
Examples
  • Is the reaction CaO (s) CO2 (g) ? CaCO3 (s)
    likely to occur to any appreciable extent at 298
    K? The kP is found to 1.9 x 10-23 for CaCO3 (s) ?
    CaO (s) CO2 (g)
  • Ans) Yes, because Kp is large (5.3 x 1022)

23
Using Equilibrium Expressions
  • 8) A mixture of 5.00 x 10-3 moles of H2 (g) and
    1.00 x 10-2 moles I2 (g) are placed in a 5.00 L
    container at 448 K and allowed to react
    equilibrium. At equilibrium, the HI 1.87 x
    10-3 M. Calculate Kc.

ICE
24
Solution
  • Use an ICE Chart (Initial, Change, Equilibrium)
  • To determine change, consider the stoichiometry
    in the balanced equation
  • Ans) 50.5

25
Pop Quiz
  • 1. Define equilibrium
  • 2. Write equilibrium expressions
  • a) Ag (aq) Cl- (aq) ? AgCl (s)
  • b) CaCO3 (s) ? CaO (s) CO2 (g)

26
Example 9
  • The initial concentrations of N2 and O2 _at_2300 K
    are both 1.4 M. What are the equilibrium
    concentrations of all three components if Kc
    1.7 x 10-3?
  • N2 (g) O2 (g) ? 2 NO (g)
  • Use the ICE Chart

27
Example 10
  • A 0.100 M Acetic Acid (HC2H3O2) reacts with water
    to form hydronium (H3O) and Acetate Ion
    (C2H3O2-). Determine the equilibrium
    concentrations of all reactants and products (as
    applicable) if Kc 1.77 x 10-5

28
Example 11
  • The reaction below has a Kc of 4.06 at 500C. If
    0.100 mol of CO and 0.100 mol H2O are placed in
    a 1.00 liter container, calculate the equilibrium
    concentrations.
  • CO (g) H2O (g) ? CO2 (g) H2 (g)

29
Example Problem 12
  • At 35C, K 1.6 x 10-5 for the reaction
  • 2 NOCl (g) ? 2 NO (g) Cl2 (g)
  • Calculate the concentrations of all species at
    equilibrium

30
Quiz - ICE Chart Problems
  • The Keq for the following reaction is 1.0 x 102
    at a certain temperature. If 2.0 moles each of
    H2 F2 are introduced into a 0.50 L container,
    determine the equilibrium concentrations.
  • H2 (g) F2 (g) ? HF (g)

31
LeChâteliers Principle
  • LeChâteliers Principle states that when a change
    is imposed on a system at equilibrium, the system
    will shift in a manner that will reduce the
    impact of the stress

32
LeChâteliers Principle
  • In order to determine shift in equilibrium, the
    stress must be considered good or bad
  • If the stress is good, the system shifts in the
    opposite direction of the stress
  • If the stress is bad, the system shifts in the
    same direction of the stress

33
Possible Stresses LeChâteliers Principle
  • 1) The addition of more reactants this is
    good and will shift equilibrium toward the
    products
  • 2) The removal of reactants this is bad and
    will shift equilibrium toward the reactants

34
Possible Stresses LeChâteliers Principle
  • Example H2 (g) O2 (g) ? H2O (g)
  • Adding more H2 or O2 will shift toward products
  • Removing H2 or O2 will shift toward reactants

35
Possible Stresses LeChâteliers Principle
  • 3) Additional Products will shift toward
    reactants side removal of product will shift
    toward products side
  • 4) Heat To determine the shift in equilibrium
    in heat, heat must be a reactant or product in
    the equilibrium
  • Example N2 (g) O2 (g) ? 2 NO (g) ?H 180.5
    kJ

36
Possible Stresses LeChâteliers Principle
  • 5) Catalysts have no overall effect on
    equilibrium
  • 6) Inhibitors have no overall effect on
    equilibrium

37
Possible Stresses LeChâteliers Principle
  • 7) Pressure Changes
  • If pressure increases, volume decreases
  • If pressure decreases, volume increases
  • To determine volume, consider coefficients for
    the substances that are gases

38
13) Predict the following shifts
  • 2 SO3 (g) ? 2 SO2 (g) O2 (g) ?H 510 kJ
  • A) Additional SO3 is added
  • B) SO2 is removed
  • C) The catalyst MnO4 is added
  • D) O2 is added
  • E) The temperature is decreased
  • F) Pressure is increased

39
14) Review - Predict Changes
  • PCl3 (g) 3 NH3 (g) ? P(NH2)3 (g) 3 HCl (g),
    ?H - 198 kJ
  • a. Addition of PCl3
  • b. Addition of NaOH
  • c. Reducing Pressure
  • d. Reducing Temperature
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