Title: Polyfunctional Natural Products: Carbohydrates
1Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1235)
2Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1235)
Problem 24.1 Generalize from the definition of a
triose to generate the structures of an
aldotetrose and an aldopentose.
Glyceraldehyde is an aldotriose because it has a
three-carbon backbone and an aldehyde group. Fig.
24.2
3Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1236)
Aldo sugars are written with the aldehyde group
at the top and the primary alcohol at the bottom.
In this scheme, called a Fischer projection,
horizontal bonds are taken as coming toward the
viewer and vertical bonds as retreating. If the
OH adjacent to the primary alcohol at the bottom
is on the right, the sugar is a member of the D
series. If it is on the left, it is in the L
series. Fig. 24.3
4Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1237)
There is no relation between D and L and the sign
of optical rotation, () and (-). Fig. 24.4
5Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1237)
6Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1237)
Problem 24.3 Write Fischer projections for the
molecules in Figure 24.6
7Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1237)
22 stereoisomers both D and L isomers shown
23 stereoisomers only D-diastereoisomers shown!
8Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1238)
24 stereoisomers only D-diastereoisomers shown!
The eight D-aldohexoses Fig. 24.10
9Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1238)
D-Fructose, a common ketohexose. Fig. 24.10
10Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1238)
Problems 24.4 24.5 Problem 24.6 Treatment of
D-glucose with sodium borohydride (NaBH4) gives
D-glucitol (sorbitol), C6H14O6. Show the
structure of D-glucitol and write a brief
mechanism for this simple reaction
11Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1239)
Why?
Although reduction with sodium borohydride,
followed by hydrolysis, proceeds normally to give
an alcohol, neither NMR or IR reveals large
amounts of an aldehyde in the starting
material. Fig. 24.12
12Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1239)
Intramolecular hemiacetal formation is analogous
to hydration and intermolecular hemiacetal
formation. Five- and six-membered ring
hemiacetals are easily made, and are often more
stable than their open forms. Fig. 24.13
13Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1240)
Example
Intramolecular hemiacetal formation is analogous
to hydration and intermolecular hemiacetal
formation. Five- and six-membered ring
hemiacetals are easily made, and are often more
stable than their open forms. Fig. 24.13
14Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1241)
In an aldohexose, intramolecular hemiacetal
formation results in a furanose (five-membered
ring) or pyranose (six-membered ring) Fig. 24.14
15Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1241)
Fischer projections for D-glucofuranose and
D-glucopyranose Fig. 24.5
16Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1242)
If two compounds are in equilibrium, irreversible
reaction of the minor partner can result in
complete conversion into a product. As long as
the equilibrium exists, the small amount of the
reactive molecule will be replenished as it is
used up. Fig. 24.16
17Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1242)
Intramolecular hemiacetal formation results in
two C(1) stereoisomers called anomers. Fig.
24.17
18Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1245)
The first step in creating a three-dimensional
drawing is rotation around the indicated
carbon-carbon bond. This motions generates a new
Fischer projection. Fig. 24.19
19Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1245)
Problem 24.9 Draw the flat, Haworth form of the
?-anomer.
Next, tip the molecule over in clockwise fashion
to produce a flat Haworth form Fig. 24.20
20Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1245)
Problem 24.10 Follow this same procedure for the
?-anomer.
Now let the flat, Haworth form relax to a chair.
Dont forget that there are always two possible
chair forms. Fig. 24.21
21Polyfunctional Natural ProductsCarbohydrates
- 24.1 Nomenclatuur and Structure (page 1246)
Problem 24.11 Transform the Fischer projection
into a three-dimensional picture of
D-mannopyranose
22Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1246)
- 24.2a Mutarotation of Sugars
23Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1246)
- 24.2a Mutarotation of Sugars
The ?- and ?-anomers can equilibrate through the
small amount of the open form present at
equilibrium Fig. 24.22
24Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1247)
- 24.2a Mutarotation of Sugars
Problem 24.12 Write a mechanism for the
acid-catalyzed mutarotation of D-glucopyranose
(in 3-dimensional structures!)
25Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1246)
- 24.2b Isomerization of Sugars in Base
Explain!
In base, D-glucose equilibrates with D-mannose
and D-fructose, a keto sugar. Fig. 24.23
26Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1248)
- 24.2b Isomerization of Sugars in Base
Lobry de Bruijn-Alberda van Ekenstein reaction!
A mechanism of the equilibration of D-Glucose and
D-mannose involves formation of an enolate
followed by reprotonation Fig. 24.24
27Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1248)
- 24.2b Isomerization of Sugars in Base
Protonation on oxygen generates a double enol,
which can lead to D-fructose (or the
D-aldohexoses, D-glucose, and D-mannose). Fig.
24.25
28Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1249)
- 24.2c Reduction
29Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1249)
- 24.2c Reduction
Problem 24.15 Reduction of D-altrose with sodium
borohydride in water gives an optically active
molecule, D-altritol. However, the same procedure
aplied to D-allose gives an optically inactive,
meso hexa-alcohol. Explain.
30Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1250)
- 24.2d Oxidation
31Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1250)
- 24.2d Oxidation
Problem 24.16 Write a mechanism for this
oxidation. Hint for the first step What reaction
is likely between an aldehyde and water?
32Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1250)
- 24.2d Oxidation
Problem 24.17 Examination of the NMR and IR
spectra of typical aldonic acids often shows
little evidence for the carboxylic acid group.
Explain this odd behavior.
33Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1251)
- 24.2d Oxidation
Oxidation with nitric acid generates an aldaric
acid in which the end groups are both carboxylic
acids. Figure 24.28
34Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1251)
- 24.2e Ether and Ester formation
35Polyfunctional Natural ProductsCarbohydrates
- 17.10 Synthesis of Ethers from Alkoxides (pag
845)
Formation of ethers via Sn2 process!
Williamson ether synthesis!!
Alkoxides can displace halides in an SN2 reaction
to make ethers. This reaction is the Williamson
ether synthesis. Figure 17.56
36Polyfunctional Natural ProductsCarbohydrates
- 17.10 Synthesis of Ethers from Alkoxides
Formation of ethers via Sn2 process!
Williamson ether synthesis!!
Alkoxides can displace halides in an SN2 reaction
to make ethers. This reaction is the Williamson
ether synthesis. Figure 17.56
37Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1251)
- 24.2e Ether and Ester formation
Formation of ethers via Sn2 process!
Williamson ether synthesis!!
A similar process can be carried out in base with
a Williamson ether synthesis. Notice in this
example that neither the existing ether at C(1)
nor the pyranose ring connection is disturbed in
the benzylation. Figure 24.30
38Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1251)
- 24.2e Ether and Ester formation
?
39Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1251)
- 24.2e Ether and Ester formation
All the free hydroxyl groups can be esterified
with acetic anhydride. Figure 24.30
40Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1253)
- 24.2e Ether and Ester formation
?
41Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1253)
- 24.2e Ether and Ester formation
Treatment with dilute HCl and alcohol converts
only the OH at the anomeric position C(1) into
an acetal called a glycoside. Figure
24.32
42Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1253)
- 24.2e Ether and Ester formation
Glycoside!
Why only methoxylation at the C-1 position?
Treatment with dilute HCl and alcohol converts
only the OH at the anomeric position C(1) into
an acetal called a glycoside. Figure
24.32
43Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1253)
- 24.2e Ether and Ester formation
Although all OH groups can be reversibly
protonated, loss of only the anomeric OH leads to
a resonance-stabilized cation. Addition of
alcohol at this position gives the glycoside.
Figure 24.33
44Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1253)
- 24.2e Ether and Ester formation
Although all OH groups can be reversibly
protonated, loss of only the anomeric OH leads to
a resonance-stabilized cation. Addition of
alcohol at this position gives the glycoside.
Figure 24.33
45Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1254)
- 24.2e Ether and Ester formation
Methyl ?- and methyl ?-D-glucopyranosides. Figure
24.34
46Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1254)
- 24.2e Ether and Ester formation
?
47Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1254)
- 24.2e Ether and Ester formation
Hydrolysis of the fully methylated compounds
leads to a hemiacetal in which only the methoxyl
group at the anomeric position C(1) has been
converted into an OH. Figure 24.35
48Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1254)
- 24.2e Ether and Ester formation
Problem 24.18 Explain carefully why it is only
the acetal methoxyl group that is converted into
a hydroxyl group.
49Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1255)
- 24.2f Osazone Formation
What product would you expect from the above
reaction?
50Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1255)
- 24.2f Osazone Formation
What product would you expect from the above
reaction?
51Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1255)
- 24.2f Osazone Formation
The small amount of free aldehyde present at
equilibrium accounts for phenylhydrazone
formation at C(1). Figure 24.36
52Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1256)
- 24.2f Osazone Formation
Problem 24.14 Write a mechanism for the above
reaction.
53Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1256)
- 24.2f Osazone Formation
The actual reaction is far more complicated!
54Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1256)
- 24.2f Osazone Formation
Osazone formation involves conversion of C(2) as
well as C(1) into phenylhydrazones. Figure
24.37
55Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1256)
- 24.2f Osazone Formation
How come?
56Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1256)
- 24.2f Osazone Formation
The C(1) phenylhydrazone is an imine and
therefore in equilibrium with an enamine. This
enamine is also an enol. Figure 24.38
57Polyfunctional Natural ProductsCarbohydrates
Reaction of the ketone with phenylhydrazine leads
to a new phenylhydrazone that can eliminate
aniline to give a new imine. Reaction with a
third equivalent of phenylhydrazine leads to the
osazone. Figure 24.39
58Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1257)
- 24.2f Osazone Formation
Attention!!!!
59Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1257)
- 24.2g Methods of Lengthening and Shortening
Chains in Carbohydrates
60Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1257)
- 24.2g Methods of Lengthening and Shortening
Chains in Carbohydrates
61Polyfunctional Natural ProductsCarbohydrates
Kiliani-Fischer Synthesis
62Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1259)
- 24.2f Methods of Lengthening and Shortening
Chains in Carbohydrates
Problem 24.20 Apply the Kiliani-Fischer synthesis
to D-glyceraldehyde. What new sugars are formed?
It is not necessary to write mechanisms for the
reactions.
63Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1259)
- 24.2f Methods of Lengthening and Shortening
Chains in Carbohydrates
Problem 24.21 The following two sugars are
produced by Kiliani-Fischer synthesis from an
unknown sugar (Fig. 24.42). What is the
structure of that unknown sugar?
64Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1259)
- 24.2f Methods of Lengthening and Shortening
Chains in Carbohydrates
The Ruff degradation
65Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1259)
- 24.2f Methods of Lengthening and Shortening
Chains in Carbohydrates
Mechanism complicated!
The Ruff degradation shortens the starting sugar
by one carbon. It is the original aldehyde carbon
that is lost! Figure 24.43
66Polyfunctional Natural ProductsCarbohydrates
- 24.2 Reactions of Sugars (page 1260)
- 24.2f Methods of Lengthening and Shortening
Chains in Carbohydrates
The Wohl degradation
67Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1262)
Accomplished by Emil Fischer in 1891
68Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1263)
Second step Determining the configuration of
C(2) in arabinose by oxidation
Oxidation of D-arabinose leads to an optically
active diacid, which shows that the OH at C(2) in
D-arabinose is on the left. Figure 24.49
69Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1263)
Current knowledge about the structures of
D-arabinose, D-glucose and D-mannose
What we now know about the structures of
D-arabinose, D-glucose, and D-mannose. Only the
configuration at C(3) of D-arabinose, which
becomes C(4) in D-glucose and D-mannose, is left
to be determined. Figure 24.50
70Polyfunctional Natural ProductsCarbohydrates
If true than both diacids should be optically
active upon oxidation with nitric acid!
Third step Determining the configuration of
C(4) in glucose en mannose by oxidation
Figure 24.51
71Polyfunctional Natural ProductsCarbohydrates
If true than both diacids should be optically
active upon oxidation with nitric acid!
Third step Determining the configuration of
C(4) in glucose en mannose by oxidation
Figure 24.51
72Polyfunctional Natural ProductsCarbohydrates
Third step Determining the configuration of
C(4) in glucose en mannose by oxidation
If true than only one acid should be optically
active!
Assumption OH on the left!
However, if the unknown OH is on the left, one
possible diacid is meso, not optically
active. Figure 24.52
73Polyfunctional Natural ProductsCarbohydrates
Third step Determining the configuration of
C(4) in glucose en mannose by oxidation
If true than only one acid should be optically
active!
However, if the unknown OH is on the left, one
possible diacid is meso, not optically
active. Figure 24.52
74Polyfunctional Natural ProductsCarbohydrates
Experimental Result Both sugars gave an
optically active diacid!
75Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1265)
Now we know the structure of D-arabinose,
L-arabinose, and the two structures (A and B)
shared by D-glucose and D-mannose. We do not know
which structure belongs to D-glucose and which to
D-mannose Figure 24.53
76Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1266)
Two different sugars may give the same aldaric
acid when oxidized!
Oxidation with nitric acid renders the ends of a
sugar equivalent. Both the aldehyde end and the
primary alchohol end are converted into the same
group, a carboxylic acid. Figure 24.54
77Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1266)
Two different sugars may give the same aldaric
acid when oxidized!
78Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1266)
If D-glucose has the structure A, oxidation of
another sugar, L-gulose, can give the same
aldaric acid. Note in this case that the L-gulose
is drawn with the CH2OH at the top and the CHO at
the bottom. Figure 24.55
79Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1266)
If glucose would have structure B only glucose
would yield this aldaric acid!
However, there is no sugar other than B that can
give this aldaric acid. As this fact does not
match the experimental results, D-glucose must
have structure A. Figure 24.56
80Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1266)
However, this is not true! Conclusion Glucose
has structure A!
However, there is no sugar other than B that can
give this aldaric acid. As this fact does not
match the experimental results, D-glucose must
have structure A. Figure 24.56
81Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1266)
This outcome also reveals the structure of
L-Gulose!
However, there is no sugar other than B that can
give this aldaric acid. As this fact does not
match the experimental results, D-glucose must
have structure A. Figure 24.56
82Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1267)
Structures unraveled sofar!
Now we know the structures of these aldohexoses
and aldopentoses. Figure 24.57
83Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1268)
D-Arabinose and D-ribose give the same osazone,
and therefore can differ only at C(2). The
structure of D-ribose is therefore known.
L-Ribose is simply the mirror image of the
D-isomer. Figure 24.58
84Polyfunctional Natural ProductsCarbohydrates
- 24.4 The Fischer Determination of the
Structures of D-Glucose (and the 15 other
Aldohexoses (page 1268)
In a similar way the structures of all the other
aldopentoses and aldohexoses were
established. See Figures 24.59, 24.60, 24.61 and
24.62
85Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
(page 1270)
Examples Disaccharides sucrose, lactose,
maltose, Polysaccharide cellulose
How can this structure be unraveled?
86Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
(page 1270)
Hydrolysis shows the individual monosaccharides!
In acid, ()-lactose is hydrolyzed to D-glucose
and D-galactose. Figure 24.63
87Polyfunctional Natural ProductsCarbohydrates
Hydrolysis in dilute acid means that there must
be a glycosidic linkage in ()-lactose Figure
24.64
88Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
(page 1271)
The remaining questions about the structure of
()-lactose. Figure 24.65
89Polyfunctional Natural ProductsCarbohydrates
The acid group in lactobionic acid marks the
position of the aldehyde in ()-lactose. As
hydrolysis of lactobionic acid gives a gluconic
acid (not a galactonic acid), it is glucose that
has the free aldehyde in ()-lactose. Figure 24.66
90Polyfunctional Natural ProductsCarbohydrates
The acid group in lactobionic acid marks the
position of the aldehyde in ()-lactose. As
hydrolysis of lactobionic acid gives a gluconic
acid (not a galactonic acid), it is glucose that
has the free aldehyde in ()-lactose. Figure 24.66
We still dont know which OH is making the
connection!!!
91Polyfunctional Natural ProductsCarbohydrates
The position of the OH used to attach glucose to
C(1) of galactose can be determined through a
series of methylation and hydrolysis
experiments. Figure 24.67
92Polyfunctional Natural ProductsCarbohydrates
The position of the OH used to attach glucose to
C(1) of galactose can be determined through a
series of methylation and hydrolysis
experiments. Figure 24.67
93Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
(page 1274)
Problem 24.23 Make a good three-dimensional
drawing of ()-lactose
A Fischer projection for ()-lactose. Figure
24.67
94Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
(page 1271)
Sucrose
No aldehyde oxidation with Br2/H2O possible!!!
-gt A nonreducing sugar
Suggest a basic structural feature for such a
sugar
95Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
(page 1271)
Sucrose No aldehyde oxidation with Br2/H2O
possible!!!
-gt A nonreducing sugar
In nonreducing sugars, there is no free aldehyde
group. Attachment must be between both C(1)
atoms. Sucrose is an example. Figure 24.69
96Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
(page 1276)
Polysaccharides
Cellulose and amylose Figure 24.70
97Polyfunctional Natural ProductsCarbohydrates
- 24.5 Something more Di- and Polysaccharides
- Problems 24.24 24.25
- 24.8 Additional Problems (page 1279)
- Problems 24.27 24.28 24.29 24.30 24.31
24.32 24.33 24.34 24.37 24.38 24.39 24.40
24.42 24.43 24.44 24.46 24.48