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Lecture Problem 11'22

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Gain ductility (less brittle) How? Form martensite (from c) Reheat to tempering temp and expose ... (like Steel hardness and ductility) is critical to your ... – PowerPoint PPT presentation

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Title: Lecture Problem 11'22


1
Lecture Problem 11.22
  • Ross Sclafani
  • 4.13.2007

2
The Problem
3
The Figure
4
The Background
  • Phase Diagram of C iron-carbon alloy

Eutectoid
5
Before We Begin
  • How to read an Isothermal Transformation Diagram
  • You are only transforming
  • the remaining austenite
  • You can only move in
  • two directions
  • Down OR
  • Right

6
Example 1
  • We start with pure
  • austenite
  • T 400C
  • Microstructures
  • _at_t1s 100 austenite
  • _at_t20s 50 austenite
  • 50 bainite
  • _at_t103s 100 bainite

7
Example 2 Time Travel?
  • Diagram only shows transformations over time at a
    fixed temp.
  • We always start from the far left (t0s)
  • However, we can also cool to a 2nd temperature
  • T1400C, T225C

50 Bainite
50 Bainite 50 Martensite
8
The Solution
  • What exactly is proeutectoid cementite?
  • Cementite (Fe3C)
  • Lever Rule
  • If we pass through this
  • temp range Cem. will form

9
The Solution
  • Back to the isothermal transformation
  • Cool (instantaneously) from 900C to 680C
  • (forming 6.2 p.c.)
  • Expose at 650C for 10s
  • remaining 93.8 austenite ? pearlite)

10
The Solution
  • Pearlite transformations
  • Coarse High T, High carbon diffusion rate,
    thick stripes
  • Fine Low T (600C), Low diffusion, thin stripes
  • Only expose to dashed line (50 line)
  • Cool to bainite temp and cure
  • Technically, impossible for 50/50 due to
    cementite formation (6.2C, 46.9P, 46.9B)

11
The Solution
  • Martensite ? very hard
  • However, very brittle
  • Formed simply by quenching (or cont. cool to room
    temp) austenite

Optional
12
The Solution Last One!
We want our tempering time to be reasonable (not
105s 1 day) Pick 425C for this application to
achieve significant gains
  • Benefits of tempering
  • Sacrifice hardness
  • Gain ductility (less brittle)
  • How?
  • Form martensite (from c)
  • Reheat to tempering temp and expose
  • Gains dependent on temper temp AND time

13
Why Should You Care?
  • When controlling materials properties (like Steel
    hardness and ductility) is critical to your
    application
  • One example everyone is familiar with
  • E8 Both your hammer head and screwdriver blade
    were heated, quenched (to form martensite), then
    tempered to a specified hardness
  • Now your hammer wont shatter when you hit a nail

14
Any Questions?
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