Title: Polyprotic AcidBase Equilibria
1Chapter 11
- Polyprotic Acid-Base Equilibria
2Focus of Chapter
- Determination of pH of polyprotic systems
- Buffers made from polyprotic systems
- Determination of the principle species in
solution at any given pH
3Common Polyprotic Systems
- Diprotic
- Sulfuric Acid
- Oxalic Acid
- Triprotic
- Phosphoric Acid
- Amino Acids
- Minimum - Diprotic Systems
4Polyprotic Systems
- Polyprotic Acids and Bases - compounds that can
donate or accept more than one proton - Diprotic Acids and Bases - a compound that can
donate or accept two protons
5Diprotic Acids and Bases
- Amino Acid Structure
- Neutral molecule is a zwitterion, a molecule that
have both a positive and negative charge - This form is due to the acidity of the carboxylic
acid functional group compared to that of the
ammonium group forcing the amino acid to
rearrange to give the zwitterion. - Low pH - both the ammonium and carboxyl groups
are protonated - High pH - neither group is protonated
6Diprotic Acid and Base - pH Determination Example
- Calculate the pH and composition of individual
solutions of 0.0500 M H2L, 0.0500 M HL, and
0.0500 M L-.
7Diprotic Acid and Base - pH Determination Example
- 0.0500 M H2L
- Diprotic system - can dissociate twice
- From pKas - K14.69 x 10-3 and K21.79 x 10-10
- H2L from K1 is a weak acid - partial
dissociation - HL from K2 hardly dissociates at all
- Approximation - H from H2L gtgt H from HL -
behaves as a monoprotic acid
8Diprotic Acid and Base - pH Determination Example
- 0.0500 M L-
- Diprotic System - hydrolyze twice
- From KaKbKw - Kb1 Kw/K25.59 x 10-5
- Kb2 Kw/K12.13 x 10-12
- L- from Kb1 is a weak base
- HL from Kb2 hardly hydrolyzes at all
- Approximation - L- behaves as a monoprotic base
9Diprotic Acid and Base - pH Determination Example
- Diprotic System
- more complicated
- can react to give H2L or L- (amphiprotic)
- HL ? H L- Ka21.79 x 10-10
- HL H2O ? H2L OH- Kb22.13 x 10-12
- Use the systematic treatment of equilibria
10Diprotic Acid Calculation Summary
- Solution H2A
- K1 x2 / F - x where x H HA
- H2A F - x and A2- calculated using
K2 - Solution HA-
- H ?(K1K2F K1Kw) / (K1 F)
- should be close to 1/2(pK1 pK2)
- HA- F
- use K1, K2, H, and HA to solve for H2A
and A2-
11Diprotic Acid Calculation Summary
- Solution of A2-
- Kb1 x2 / F - x where x OH- HA-H2A F
- x and A2- calculated using K2
12Diprotic Acid and Base - pH Determination Example
- Potassium hydrogen phthalate, KHP, is a salt of
the intermediate for of phthalic acid. Calculate
the pH of both 0.10 M and 0.010 M KHP. (pK1
2.950 pK2 5.408)
13Diprotic Buffers
- Calculated the same was as for monoprotic buffers
- pH pK1 log HA- / H2A
- pH pK2 log A2- / HA-
14Diprotic Buffer Example
- Find the pH of a solution prepared by dissolving
1.00 g of potassium hydrogen phthalate and 1.20 g
of disodium phthalate in 50.0 mL of water. - How many milliliters of 0.800 M KOH should be
added to 3.38 g of oxalic acid to give a pH of
4.40 when diluted to 500.0 mL.
15Polyprotic Acids and Bases
- Extension of the treatments completed for the
diprotic systems - Example - Triprotic System
16Polyprotic Acids and Bases
- Triprotic System
- Equations
- H3A ? H H2A-
- H2A- ? H HA2-
- HA2- ? H A3-
- A3- H2O ? HA2- OH-
- HA2- H2O ? H2A- OH-
- H2A- H2O ? H3A OH-
17Polyprotic Acids and Bases
- A solution of H3A
- Treat like a monoprotic weak acid
- H3A ? H H2A-
- H3A ? F(H3A)
- H H2A- x K1 x2 / (H3A - x)
- HA2- value from K2
- A3- value from K3
18Polyprotic Acids and Bases
- A solution of H2A-
- H2A- ? H HA2-
- H2A- H2O ? H3A OH-
- H2A- ? F(H2A-)
- H ?(K1K2F K1Kw) / (K1 F)
- H3A value from K1
- HA2- value from K2
- A3- value from K3
19Polyprotic Acids and Bases
- A solution of HA2-
- HA2- ? H A3-
- HA2- H2O ? H2A- OH-
- HA2- ? F(HA2-)
- H ?(K2K3F K2Kw) / (K2 F)
- H2A- value from K2
- A3- value from K3
- H3A value from K1
20Polyprotic Acids and Bases
- A solution of A3-
- Treat like a monoprotic weak acid
- A3- H2O ? HA- OH-
- A3- ? F(A3-)
- OH- HA2- x Kb1 x2 / (A3- -
x) - H2A- value from Kb2
- H3A value from Kb3
- H Kw / OH-
21Polyprotic Acids and Bases
- Find the pH of 0.10 M H3His2, 0.10 M H2His,
0.10 M HHis, and 0.10 M His-, where His stands
for the amino acid histidine.
22Principle Species in Solution?
- How do you identify the primary species in
solution? - Evaluate the pKs of the system.
- If the pH lt pK1, then the most acidic species is
the predominant species - If the pH gt pKb1, then the species with the least
number of protons is predominant - If the pH resides between two pK values then the
intermediate that lies within that region will be
predominant
23Principle Species in Solution?
- What is the principle species of benzoic acid at
pH 8? - What is the predominant form of ammonia in a
solution of pH 7.0? Approximate what fraction is
in this form
24Principle Species in Solution?
- What is the principle species of oxalic acid in
solution at a pH 4.00? - What is the principle form of arginine at pH
10.0? Approximately what fraction is in this
form? What is the second most abundant form at
this pH?
25Principle Species in Solution?
- In the pH range 1.82 - 8.99, H2Arg is the
principal form of arginine. Which is the second
most prominent species at pH 6.O? at pH 5.0?