Title: Physics 1A, Section 6
1Physics 1A, Section 6
2Section Business
- Section 6 office hour
- Caltech/Downs 101
- Tuesdays 400 - 530 PM
- See other choices on course web site
- http//www.its.caltech.edu/tmu/ph1a
- Section web site
- http//www.submm.caltech.edu/cdd/PHYS1A_2008
3Week 1 Reading/Lecture Review
- T.M.U. chapters 1-2 lectures
- units dimensions
- dimensional analysis (estimation)
- law(s) of falling bodies
- constant acceleration (compare eq. 2.14-2.16)
- s s0 v0t ½ at2
- v v0 at
- distance, velocity, acceleration (general case)
- v ds/dt
- a dv/dt
4A modern look athistorical laws of falling bodies
- Oresme (14th century)
- v ? t
- s ? t2
- (both correct)
5A modern look athistorical laws of falling bodies
6A modern look athistorical laws of falling bodies
7A modern look athistorical laws of falling bodies
- Galileo (17th century)
- s ? t2 (correct)
8A modern look athistorical laws of falling bodies
9A modern look athistorical laws of falling bodies
10A modern look athistorical laws of falling bodies
- da Vinci (15th century)
- s ? (t)(t 1)/2 t2/2 t/2
11A modern look athistorical laws of falling bodies
- da Vinci (15th century)
- s ? (t)(t 1)/2 t2/2 t/2
- v ds/dt ? t 1/2 (moving at the start)
12A modern look athistorical laws of falling bodies
- Albert of Saxony (14th century)
- v ? s
13A modern look athistorical laws of falling bodies
- Albert of Saxony (14th century)
- v ? s
- ds/dt ks
14A modern look athistorical laws of falling bodies
- Albert of Saxony (14th century)
- v ? s
- ds/dt ks
- s Cekt
15A modern look athistorical laws of falling bodies
- Albert of Saxony (14th century)
- v ? s
- ds/dt ks
- s Cekt
- v Ckekt
16A modern look athistorical laws of falling bodies
- Albert of Saxony (14th century)
- v ? s
- ds/dt ks
- s Cekt
- v Ckekt
- Takes an infinite time to start from
infinitesimal velocity!
17Quiz Problem 35
18Quiz Problem 35
- Answer
- a) a(t) jt a0
- v(t) jt2/2 a0t v0
- x(t) jt3/6 a0t2/2 v0t x0
- b) (see graph)
- c) A was ahead at t 0.5 s.
- d) J will win.
19Quiz Problem 46
20Quiz Problem 46
- Answer
- a) D VsT
- sqrtW2 (X-VrT)2
- b) tan q (X-VrT)/W
- c) Vs gt Vr
- d) (Vs2-Vr2)T2 2XVrT (W2X2) 0
- Use quadratic formula.
- e) T W/sqrtVs2-Vr2
- f) T W/Vs
- X WVr/Vs
21Thursday, October 9
- T.M.U., Problem 3-7
- Quiz Problem 19
- Optional, but helpful, to look at these in
advance.