Title: Why do we study Kinetics
1Introduction
- Why do we study Kinetics?
- To obtain important information about how fast
reactants are converted to products. - How fast a reaction reaches equilibrium
- To obtain a detailed picture of what molecules do
to each other when they react. - Reaction mechanism - the sequence of physical
and chemical processes by which the conversion
from reactants to products occurs. - To learn ways to control or optimize reaction
rates and/or yields by manipulating reaction
conditions (economic implications are important
in reactor design). - Concentration
- Temperature
- Pressure
- Presence of a catalyst
A
B
2Kinetics vs. Equilibrium Thermodynamics
- The final equilibrium state does not depend on
the path used in going from the initial state to
the final state. - The rate at which the system reaches equilibrium
does depend on the path taken. - In general, the time required to reach
equilibrium in chemical reactions can vary over
many orders of magnitude. - Often, the product of a reaction is not the one
which is the most stable energetically (i.e., the
thermodynamic product), but is the one produced
the fastest (i.e., the kinetic product). - Equilibrium
- Reactions spontaneously go to equilibrium
- A?B is spontaneous when ?Agt ?B
- A?B is spontaneous when ?Alt ?B
- When ?A ?B , neither A?B or A?B is spontaneous
and the system has reached a state of chemical
equilibrium. - Limits the extent of a spontaneous reaction.
- Given an infinite amount of time, a closed system
will reach its equilibrium state - Significant quantities of reactants and products
- Negligible quantities of reactants complete
3Le Chateliers Principle
- If an external stress is applied to a system at
chemical equilibrium, the equilibrium point will
change to relieve that stress. - Energy is required to move a reaction away from
equilibrium - Heating an exothermic reaction shifts the
equilibrium to the left. - The minimum free energy state for the system at a
particular temperature. - Independent of reaction path.
- (a) rxn goes to completion
- (b) A B at equilibrium
- (c) rxn does not go
- Dynamic equilibrium is maintained because the
forward rxn is proceeding at exactly the same
rate as the reverse rxn. - Law of Mass Action
- kA k-1B
- The free energy of the system, G, changes
- with the extent of reaction, ?, until the
- equilibrium state is achieved.
4The Equilibrium Constant
- For the general reaction
- The equilibrium constant, Keq, is defined as
- From the Law of Mass Action
- For a reaction that goes to equilibrium, Keq is
related to the Gibbs Free Energy as - Where,
5Dependence of Keq on Temperature
- From Le Chateliers Principle, heat can shift the
equilibrium. - The temperature dependence of the equilibrium
constant is governed by the heat of reaction,
?Ho. - The vant Hoff equation (two forms below) is
obtained from the Gibbs-Helmholtz equation - Integration yields
An increase in T causes a decrease in Keq for an
exothermic reaction.
6Properties of the Equilibrium Constant
- For the reaction
- Or
- And thus, K1 (K2)2
- For a series of reactions
7The Reaction Rate
- The rate of a reaction dictates how fast products
are formed or how fast reactants are consumed. - The reaction rate may be defined in the
differential form - Rates are most commonly written in terms of
"moles per liter per time" (e.g., Msec-1). - For the general reaction
- The rate may be defined in any one of the
following ways - When the reaction is balanced in terms of moles,
the derivatives are normalized by the
stoichiometric coefficients. - Note Always define the specific rate that you
are using!
8Factors Affecting Reaction Rates
- Fundamental Effects
- Temperature - usually, ?T ?rate (always, if
elementary process) - Concentration (Pressure) - ?C usually ?rate
however, it may ?rate. - Catalysts - not consumed in the overall reaction
- ?rate - Process Effects
- Heat Transfer - temperature gradients, thermal
conductivity - Mass Transfer - mixing efficiency, viscosity
- In general, many reactions may be possible, but
the observed reactions are the ones which proceed
the fastest Consider the dehydration of ethanol
for the desired production of diethyl ether - CH3CH2OH ? CH2CH2 H2O (conc.
H2SO4, 170oC) - or
- 2CH3CH2OH ? CH3CH2OCH2CH3 H2O (dil. H2SO4,
140oC) - The different products are not due to differences
in equilibria. - Rather, ethylene is formed faster than diethyl
ether at the high temperature. - At the low temperature, diethyl ether is formed
faster.
9The Differential Rate Law
- The net rate for an equilibrium reaction which
proceeds from left to right is - net reaction rate forward rate - reverse
rate - At equilibrium, the net reaction rate is zero,
and the forward rate equals the reverse rate. - When a reaction mixture is far from its
equilibrium composition, either the forward or
reverse rate is dominant, depending on the
reactant or product concentrations. - For the forward reaction
- A ? B
- the first order differential rate law is
- where k is the first order rate constant with
units (time) -1. In general, rate constants have
units (time)-1(concentration)1-n, where n is the
overall order of the reaction. - Since the rate kA, a plot of rate vs. A
yields a straight line with a slope equal to the
rate constant, k.
10The Differential Rate Law(continued)
- A second order differential rate law may be given
by - such that a plot of rate vs. A2 yields a
straight line with a slope equal to k. - In general,
- rate kA?B?C? ...
- Where, ? ? ? ... "overall order of the
reaction" - (The reaction is order ? with respect to A,
etc.)
11Order of the Reaction
- The order of the reaction with respect to each
reagent must be found experimentally and cannot
be deduced or predicted from the net equation for
the reaction. - For example,
- H2 Br2 ? 2HBr
- has the following rate law
-
- This reaction is first order with respect to
hydrogen, one-half order with respect to bromine,
and three-halves order overall. - This kinetic behavior is in contrast to that of
- H2 I2 ? 2HI
- which has the following rate law
-
12The Integrated Rate Law
- The differential rate laws show how the rate of
reactions depend on concentration. - Now, the integrated rate laws will show how the
concentrations depend on time. - For a first order reaction, we know that
- This ordinary differential equation can be
solved, -
- and rearranged to yield the integrated rate law
- From the integrated rate law for this first order
reaction, it is clear that the change in A with
time is an exponential decay function.
Thus, a plot of lnA vs. time will yield a
straight line with a slope equal to -k and an
intercept of lnAo.
13The Integrated Rate Law(continued)
- For a single reactant, second order reaction
-
- the ordinary differential equation may be solved,
-
- to yield the integrated rate law for the second
order reaction -
- Thus, a plot of 1/A vs. time will yield a
straight line with a slope of k and an intercept
of 1/Ao.
14The Half-Life (t1/2) of Simple Kinetic Processes
- Any kinetic process has a characteristic time
called the half-life, t1/2. - The half-life is the time it takes for the
process to be half-completed. - For chemical reactions, the half-life is the time
it takes to reduce the concentration of a
particular reactant to one-half of its original
concentration. - Thus, at t t1/2
-
- For a first order reaction
-
- For a second order reaction
15Reactions and Mechanisms
- All complex chemical transformations can be
broken down into a series of elementary reactions
which are either unimolecular, bimolecular, or
rarely, trimolecular. - The detailed description of these events is
termed the mechanism of the reaction. - Elementary reactions Simple reactions that yield
rate equations which correspond to the reaction
stoichiometry. - Elemenatry reactions describe molecular events
order and molecularity are the same, such that - Unimolecular - follows 1st order kinetics.
- Bimolecular - follows 2nd order kinetics.
- A mechanism (or kinetic scheme) is a collection
of the elementary reactions for a net process. - Note that, depending on the manner in which the
stoichiometry of the overall reaction is
described, algebraic manipulations of the
elementary reactions may be required for the
individual steps to add up to the overall
reaction. - Consider the net reaction
-
- The mechanism for this reaction could follow the
elementary trimolecular reaction, or more likely,
the sequence of elementary reactions given below.
16Elementary Steps
- Since the rate law for an elementary step
corresponds to the stoichiometry,
17The Rate Limiting Step
- The overall products E and F cannot be formed
faster than the rate of the slowest step in the
three step sequence above. - Thus, the slowest step in the sequence is the
rate limiting step. - While we may define the overall rate in any of
four ways, -
- If step 1 is the rate limiting step, then the
observed rate law will be -
- In this case, the complex overall mechanism
follows simple bimolecular kinetics.
18The Mass Balance
- A complete Mass Balance analysis considers the
rates of consumption and formation of all species
in the total reaction mechanism such that
19The Steady-State Approximation
- We may now impose the Steady-State (Bodenstein)
Approximation by assuming that, after a very
short period of time, the concentration of
intermediates (i.e., C and D) reaches a low,
steady-state, "equilibrium" value. - Since the concentrations of these intermediates,
which are being formed and consumed, are low,
then the change in the concentrations of these
intermediates is assumed to be zero. - Thus
- After substituting for C and D into the mass
balances, we recover the rate
20The Reaction Mechanism
- Consider the overall reaction
- 2NO2 F2 ? 2NO2F
- which follows the experimentally observed rate
law -
- Obviously, this overall reaction is not an
elementary process because the rate determining
step is only first-order with respect to NO2. - Thus, the most logical mechanism follows a series
of steps -
- such that kexp k1
21The Reaction Mechanism(continued)
- For the reaction
- 2Br- 2H H2O2 ? Br2 2H2O
- which follows the rate law
-
- the rate determining step is a trimolecular
reaction among a hydrogen peroxide molecule, a
bromide ion, and a proton. - This may be shown as
- and the faster second step must be
- HOBr Br- H ? Br2 H2O
22The Reaction Mechanism(continued)
- As suggested earlier, the mechanism of a reaction
may change if the conditions under which it is
run are altered. For example, consider the
reaction - NO2 CO ? CO2 NO
- At high temperatures (gt 500 K) the rate is found
to be -
- however, at low temperatures, the rate law is
found to be -
- Of the two possible reactions,
- a) NO2 CO ? CO2 NO (favored at high
T) - b) NO2 NO2 ? NO3 NO (favored at low
T) - the latter is favored at low temperatures.
23The Reaction Mechanism(continued)
- Recall the reaction shown earlier
- H2 Br2 ? 2HBr
- which has the following experimental rate law
-
- Considerable experimentation has shown the
mechanism to be -
- where M may be any molecule of any gas.
24The Reaction Mechanism(continued)
- The previous reaction scheme is a chain mechanism
because - steps 2) and 3) convert H2 and Br to HBr without
a net consumption of the active free radicals. - Since step 2) is the rate determining step, the
rate law for the overall reaction is given by - Since it would be more convenient to have the
rate law expressed in terms of the bromine
molecule concentration, the equilibrium condition
may be used, such that -
- Note it must be assumed that the equilibrium step
is fast relative to the slow step. - Thus, by substituting this equilibrium
relationship into the rate law from step 2), we
find -
- which has the same form as the experimental rate
law. Furthermore, -
- This example shows the importance of
understanding the origin of the experimental rate
law in determining the reaction mechanism. - Note that the factor of 2 arises from the manner
in which we defined the experimental rate law.
25The Reaction Mechanism(continued)
- The rate law sometimes cannot positively be used
to determine the mechanism. - For example, consider the reaction
- 2NO O2 ? 2NO2
- which follows the rate law
-
- Both mechanisms below are consistent with the
rate law. -
- or
26The Reaction Mechanism(continued)
- As a further example of the link between the
reaction mechanism and the rate law, consider the
following reaction - 2NO H2 ? N2O H2O
- One proposed mechanism is
-
- With the rapid equilibrium,
-
- and the rate of the slow step
- Combining, we obtain the experimental rate law
-
27The Reaction Mechanism(continued)
- Another possible mechanism for the above reaction
involving a fast equilibrium is -
- which also leads to
- If the equilibrium step is not very fast relative
to the rate determining step (RDS), then another
possible mechanistic treatment may be as follows -
- A mass balance on N2O2 yields,
-
28Example Problem
- The following overall gas phase reaction
- H2(g) I2(g) ? 2HI
- Has been found to proceed by the following
mechanism - Show that this mechanism is consistent with the
experimental rate law - What is the origin of the experimental rate
constant? - What does the experimental rate law suggest about
the relative rates of the above elementary steps? - Under what conditions would the rate shift to
follow the rate law?
I2(g)
2I(g)
k2
H2(g) 2I(g)
2HI(g)
29Searching for a Mechanism
- Uncovering a reaction mechanism requires
extensive chemical investigation. - Define the stoichiometry.
- Monitor reactant or product concentrations with
time for deriving empirical rate expressions. - Propose the mechanism of the reaction.
- Test the mechanism
- Since there are numerous interrelationships
between these three areas of investigation, this
is usually not a trivial process. - the proposed stoichiometry may change based on
the kinetic data, which in turn may have been
formulated based on the mechanistic studies. - Rules and Clues and Suggestions for Developing a
Mechanism - The mechanism must add up to the overall
reaction. - The mechanism must result in the proper kinetics.
- The mechanism must match all other experimental
information. - The stoichiometry can distinguish between a
single or multiple reactions. - A complicated stoichiometry or one which changes
with the conditions or extent of the reaction is
clear evidence of multiple reactions. - The stoichiometry can suggest whether the
reaction is elementary or not. - No elementary reactions with molecularity greater
than 3 have been observed to date. - For example, the following reaction is not
elementary.
30Developing a Mechanism (continued)
- The principle of microscopic reversibility must
be preserved. - The forward and reverse reactions must proceed
via the same pathway and through the same
activated complex. - Thus, the reversible reaction
- 2NH3 ? N2 3H2
- cannot be elementary since the reverse reaction
(tetramolecular) is highly improbable. - NOTE All steps may be considered as reversible
the "irreversible" reactions are those which have
extremely large equilibrium constants (reactant
concentration is negligibly low at equilibrium). - Microscopic reversibility also indicates that
structural changes such as bond rupture or
formation, transfer of atoms or molecular
fragments, or molecular syntheses are likely to
occur one step at a time. - Trimolecular (3rd order) elementary steps are
usually slow. - Inverse orders often arise from rapid equilibria
prior to the RDS. - If a stoichiometric coefficient for a reactant
exceeds the species order in the rate law, then
there are often one or more intermediates after
the RDS. - When a rate law contains noninteger orders, there
are usually intermediates present in the reaction
sequence.
31Developing a Mechanism (continued)
- A change in Ea with temperature indicates a
shift in the controlling mechanism of the
reaction. - A rise in Ea with temperature indicates that the
controlling mechanism has shifted to an alternate
or parallel path. - A drop in Ea indicates a shift of the RDS to
another reaction in the succession of elementary
steps. - These concepts may be visualized graphically as
- Parallel Reactions A high Ea pathway governs at
high T. The reaction proceeds along path of
least resistance. - Series Reactions The slow step in the mechanism
changes. The reaction is always limited by the
slowest step. - Finally, the most likely mechanism is usually
the simplest.
Mech. 1
A ? R
High Ea
Mech. 2
Low Ea
ln k
ln k
High Ea
Low Ea
1/T
1/T
32Testing Kinetic Models
- Propose a feasible mechanism for the reaction
- which follows the rate law
-
- Note that the reaction is evidently not
elementary, or it would follow -
- Kinetic Model I
- With this mechanism,
2A B
A2B
33Testing Kinetic Models(continued)
- If we impose the steady-state approximation for
A2 - such that
- the rate expression in terms of measurable
quantities becomes - It is common practice to restrict the more
general model, such as above, by arbitrarily
selecting the magnitudes of the various rate
constants. - In this way, one of the restricted (simpler)
forms may match the observed kinetics. Thus, for
k-1 very small - Or for k-2 very small
34Testing Kinetic Models(continued)
- Since neither of the above rate expressions
matches the experimentally observed rate law, the
hypothesized Model I must be incorrect. - However, the similarity between the above
expression (for k-2 very small) and the
experimental rate law does hint that the correct
mechanism will involve a similar form with the
intermediate reacting with A instead of B in the
rate determining step. - Thus, the mechanism for the Kinetic Model II is
- Now, the rate expression is
- If we impose the steady-state approximation for
AB
35Testing Kinetic Models(continued)
- the rate expression in terms of measurable
quantities becomes (again) - Thus, restriction of this model with the
condition that k-2 is negligible yields - This is the same form as the experimental rate
law, and thus, the kinetic Model II is consistent
with the experimental observations. - Note that the condition requiring k-2 to be
negligibly small indicates that the second step
may be considered as an irreversible reaction.
36Temperature Dependence of the Reaction Rate
- The rate expression may be thought of as
consisting of a temperature dependent term (i.e.,
the rate constant, k) and a composition dependent
term or terms. - In practically all cases, the temperature
dependence of the reaction rate constant has been
found to be well represented by Arrhenius' Law - where A is the pre-exponential term known as the
frequency factor, Ea is the activation energy for
the reaction, R is the gas constant, and T is the
absolute temperature. - The Arrhenius Law is often encountered in the
logarithmic form - which when plotted, yields an approximately
straight line
37Temperature Dependence of the Reaction Rate
(continued)
- The following equation is useful for calculating
rate constants at various temperatures given
knowledge of the activation energy, Ea, and the
magnitude of the rate constant at one
temperature. - A plot of lnk vs. 1/T gives a straight line with
a large slope for a high Ea and a low slope for a
small Ea. - Ea is almost always positive.
- Reactions with a high Ea are very temperature
sensitive reactions with a low Ea are not so
sensitive. - Reactions are much more temperature-sensitive at
low temperatures than at high temperatures. - It is important to note that the Arrhenius Law is
an empirical relationship that fits experimental
data very well over wide temperature ranges, and
is suggested to be a very good approximation to
the "true" temperature dependency by the
following theoretical approaches. - Collision Theory
- Transition State Theory
38Collision Theory
- In order for two molecules to react, they must
"collide." - From this collision theory, the minimum condition
for the following reaction to occur, - A B ? R
- is that the centers of mass of molecules A and B
must come to within a certain critical distance
of one another. - The exact value of this critical distance, ?,
depends on the nature of the reacting molecules,
but is expected to be within ca. 2 or 3 Å (i.e.,
about the length of a chemical bond). - For bimolecular collisions of unlike molecules A
and B, kinetic theory gives - where
- nA and nB (NCA or B)/103, number of molecules
of A or B per cm3 - k Boltzmann's constant 1.3 x 10-16 erg/oK
- T absolute temperature
- M mass of molecule A or B in gms (MW/NA)
- While the above expression yields the collision
rate for bimolecular reactions, experimental
evidence has shown that only a small fraction of
collisions result in the conversion of reactants
to product. - Thus, the true reaction rate is much lower than
the collision rate. - This suggests that only the more energetic
collisions (i.e., those having an energy in
excess of a minimum energy, E) will lead to
reaction.
39Collision Theory (continued)
- Experimental evidence has shown that reaction
rates are generally very sensitive to
temperature. - However, this temperature dependency is more
complex than that indicated in the above
equation, which shows that - Thus, to combine the requirement of energetic
collisions and a complex temperature dependency
with the collision theory, we must consider the
energy distribution function of molecules from
the Maxwell-Boltzmann Distribution Law of gases. - This energy distribution takes the form of
- and is visualized graphically as
40Collision Theory (continued)
- If the molecular kinetic energy required for
reaction is defined as the activation energy, Ea,
the above figure shows that as the temperature
increases, the fraction of molecules having an
energy greater than the critical Ea increases
dramatically. - Thus, the rate expression may be modified as
- Thus, collision theory predicts that the
temperature dependency of the rate of reaction
follows - Note that for a 10 degree increase in
temperature, the T1/2 term increases the rate by
a factor of - while the exponential term increases the rate by
a factor of - Therefore, since the overwhelming factor is the
exponential term, the rate effectively follows
41Collision Theory (continued)
- In addition to the minimum energy requirement,
molecules with three dimensional structure must
collide with the proper orientation for reaction.
When both energy and orientation factors are
considered, the theoretical expression for the
rate of a bimolecular reaction becomes -
- where the quantity P is the steric factor related
to the orientation requirement (i.e., a
probability of proper orientation during the
collision). - In general, P is on the order of 10-1 for simple
atoms and molecules, but may decrease to 10-5 for
complex molecules. - Therefore, the temperature dependency of the rate
constant becomes - which is of course the Arrhenius equation.
- The frequency factor, A, expresses the rate at
which molecules approach close enough in the
proper orientation to react. - From these theoretical treatments, it would seem
possible to predict reaction rates. In practice,
however, this is rarely done satisfactorily
because the exact structure of the transition
state is poorly understood, which makes it very
difficult to predict Ea and A.
42Transition State Theory
- Transition-state theory suggests that reactants
combine to form unstable intermediates called
activated complexes (i.e., the transition states)
which then decompose spontaneously into products.
- Thus, for an elementary, reversible reaction,
- we have the following conceptual scheme
- Transition-state theory views the reaction rate
to be governed by the rate of intermediate
decomposition. - The rate of intermediate formation is assumed to
be so rapid that it is present in equilibrium
concentrations at all times. - From these considerations, the mechanism may be
treated as - where an equilibrium exists between the
concentration of reactants and activated complex,
such that
43Transition State Theory(continued)
- Transition-state theory also submits that the
rate constant for the decomposition of an
activated complex is the same for all reactions,
and is given by -
- where h is Planck's constant (h 6.63 x 10-27
erg?sec) - kT is the thermal energy.
- Thus, the observed reaction rate (from the
rate-limiting elementary step) is given by - Notice that while the rate constant for the
intermediate decomposition is relatively large
and the same for all reactions, the rate of the
overall reaction is directly proportional to the
thermodynamic equilibrium constant. - From thermodynamic principles, the equilibrium
constant, Keq may be expressed in terms of the
free energy, ?G - Thus, the rate of the forward mechanism (i.e.,
the pathway which produces AB) becomes
44Transition State Theory(continued)
- Since both ?S and ?H vary very slowly with
temperature, the middle term, e?S/R, is
considered to be a constant. - Thus, for the forward reaction of the elementary,
reversible reaction, - the forward rate constant is of the form
- where,
- If the activation energy, Ea, is defined as the
change in enthalpy for the forward equilibrium
reaction, ?Hfor (which is always positive), then
the transition-state theory for an overall
exothermic reaction (i.e., ?Hnet lt 0) may be
visualized graphically as
45Transition State Theory(continued)
- Transformation of reactants to products
- Where, E1 ?Hfor E2 ?Hrev and ?Hr ?Hnet
- Once the activated complex, AB, is formed from A
and B, it can either revert back into A B or
form the new product AB. Similarly, we can start
with AB to form AB, which then either reverts
back to AB or forms A B. - This transition-state theory suggests that the
rate at which A and B react to form AB is
governed by Ea, and not by ?Hnet.
AB
46Transition State Theory(continued)
- By defining Ea ?H, transition-state theory
predicts that the rate constant will be of the
form -
- Again, it can be shown that the overwhelming
dependence on temperature resides in the
exponential term. - Thus, Arrhenius' Law is a good approximation to
temperature dependency of both collision and
transition-state theories. - It should be noted that the Arrhenius equation is
usually not followed over a very wide temperature
range (e.g., a plot of lnk vs. 1/T may deviate
from linearity). - Thus, more sophisticated treatments may be
required. - The thermodynamic arguments (above) for the
transition-state theory are valid only for
elementary reactions. - Very large deviations from the exponential
Arrhenius expression often mean that the
experimental rate constant being measured is a
combination of rate constants (and/or equilibrium
constants) for several elementary reaction with
different activation energies and frequency
factors.
47Reaction Rates in Solution
- The theoretical treatments of reaction rates
described earlier, (i.e., Collision Theory), were
considered for simple gas phase systems in which
no more than three molecules collide at the same
time. - The situation is quite different for reactions
which take place in the more condensed
environments of solutions. - Reactants in solution are not "free" to move
towards each other and collide due to the
significant forces from neighboring solvent
molecules. - Reactions in solution are often complicated
events in which the behavior of the surrounding
solvent molecules must be considered. - Three general factors influence reaction rates in
solution. - 1. The rate at which initially separated reactant
molecules come together and become neighbors.
This is called the rate of encounters. - 2. The time that two reactants spend as neighbors
before moving away from each other. This is
called the duration of an encounter. During this
time, the reactants may collide with each other
hundreds of times. - 3. The requirement of energy and orientation
which two neighboring reactant molecules must
satisfy in order to react. - Any one of these three factors may dominate in
governing the reaction rate. - Factors 1 and 3 are similar to the factors
considered for gas phase reactions, while factor
2 is unique to dense phases (e.g., liquids).
48Diffusion Controlled Reactions
- Some reactions occur as soon as the reactant
molecules come together. - For these fast reactions, the activation energy
and orientation requirements are negligible. - The reaction rate is limited only by the first
factor (i.e., the rate at which encounters
occur). - In solution, reactant molecules move through the
liquid medium by diffusion, and thus the rate is
diffusion limited or is said to be diffusion
controlled. - A simple mechanism for these reactions may be
given by - where kD is the rate constant for diffusion of A
and B towards each other, k-D is the rate
constant for diffusion of A and B away from each
other, and kc is the rate constant for the
conversion of the complex (AB) to product R
(i.e., the rate constant with out diffusive
effects). - Using the Steady-State Approximation on (AB) see
later
49Diffusion Controlled Reactions(continued)
- If the equilibrium is not fast compared to the
second step, then the rate expression may be
given by - When kc is very large (i.e., a fast reaction once
the reactants encounter each other) relative to
k-D, the rate constant kc cancels out and thus
the rate is controlled by kD. - The rate of diffusion controlled reactions often
depend on the nature of the solvent. - As the viscosity of the medium decreases, the
rate of reaction increases. - In addition, the characteristics of the diffusing
species are also important, as shown in the Table
below.
50The Solvent Cage Effect
- The second factor which affects the rate of
reactions in solution involves the effects of
solvent molecules on the motions of reactant
molecules. - Once two reactant molecules diffuse together,
their first collision may not satisfy the energy
and orientation requirements for reaction. - The surrounding solvent molecules create a
"solvent cage" which inhibits the separation of
the reactant molecules. - This solvent "cage effect" provides the
opportunity for the molecules to undergo many
more collisions before finally either reacting or
diffusing away from each other. - The duration of such an encounter may be 10-10
sec, during which the reactant molecules may
collide 100's of times. - The cage effect tends to increase the reaction
rate by increasing the opportunity for reactant
molecules to find the required energy and/or
orientation to react during the caged encounter. - In contrast to gas phase reactions, in which
molecules collide only once during an encounter,
solution phase reactions involve encounters which
may consist of many collisions.
51The Melt Cage in Reactive Extrusion(Functionaliza
tion of Polypropylene)
Conventional approach using symmetric peroxides,
ROOR
Maleic anhydride must diffuse through melt to
find the polymeric radical.
Alternative using functionalized peroxides
Functionalized peroxides create polymeric
radical and graft in the same melt cage.
Greater grafting efficiency compared to the
conventional approach!
Bohn, C.C. Manning, S.C. Moore, R.B. A
Comparison of Carboxylated and Maleated
Polypropylene as Reactive Compatibilizers in
Polypropylene/Polyamide-6,6 Blends, J. Appl.
Polym. Sci. 2001, 79, 2398-2407.
52Energy and Orientation Requirement for Reactions
in Solution
- The third factor which affects the rate of
reactions in solution involves the energy and
orientation requirement. - primarily governed by the nature of the reacting
species. - the solvent may play a role as shown in the
following example - (CH3)3CCl OH- ? (CH3)3COH Cl-
- proceeds by the mechanism
- (CH3)3CCl ? (CH3)3C Cl- (slow)
- (CH3)3C OH- ? (CH3)3COH
(fast) - This reaction is first order with respect to
(CH3)3CCl and does not depend on the
concentration of OH-. - The rate does depend on the nature of the
solvent. - If the polarity of the solvent is systematically
varied in mixed solvents of water with acetone,
then the reaction rate is 104 times faster in a
9010 (water-acetone) solvent relative to a 1090
(water-acetone) solvent. - The RDS involves the production of a pair of ions
which is more easily accomplished in a highly
polar solvent in which the ions are more stable.
- In general, reactions in solution will occur
fastest in solvents in which the activated
complex is most stable (i.e., thus yielding a low
Ea). - In the above example, the activated complex is
highly polar, and is fastest in the more polar
solvents.
53Catalysis
- By formal definition, a catalyst is a substance
which increases the rate of a reaction without
itself undergoing change. - Consider the base catalyzed hydrolysis of an
ester - the overall reaction is
- CH3COOC2H5 H2O ? C2H5OH CH3COOH
- The hydroxide ion is not required by the
stoichiometry of the overall reaction, but its
addition does increase the reaction rate. - Notice, however, that one of the products is an
acid. - As the reaction proceeds, the OH- is, in fact,
consumed. - Thus, a practical definition for a catalyst may
be any substance which can increase a rate of
reaction while not being required in the
stoichiometry of the overall reaction. - Catalysts increase reaction rates by providing
new, faster paths by which a reaction can
proceed. - Consider the reaction
- A B ? AB (very slow, high Ea)
- The rate of this reaction may be increased by the
use of substance C, which is a homogeneous
catalyst (i.e., the catalytic process occurs in
one phase) that provides an alternate reaction
pathway
54Catalysis (continued)
- The above catalytic scheme may be represented
graphically by - Note that careful consideration of the reaction
conditions must be realized because the catalyst
also increases the rate of the reverse reaction. - Heterogeneous catalysts pertain to two phases, in
which the rate of reaction is increased by
reaction pathways involving the phase or surface
boundaries. - These systems often involve adsorption of
reactants onto the catalyst surface. - For example, the hydrogenation of ethylene
- H2 C2H4 ? C2H6
- is catalyzed in the presence of small Ni, Pt or
Pd particles (with a high surface area). - These metals can adsorb large quantities of H2
which greatly increases the local concentration
of reactant. - Furthermore, the metal lattice allows the H2
molecules to dissociate into much more reactive
hydrogen atoms.