26'6Lenses - PowerPoint PPT Presentation

About This Presentation
Title:

26'6Lenses

Description:

Focal length of a diverging lens is virtual and considered negative. ... Image Formation by a Converging Lens. Magnifying Glass. Image Formation by a Diverging Lens ... – PowerPoint PPT presentation

Number of Views:46
Avg rating:3.0/5.0
Slides: 12
Provided by: mah57
Learn more at: http://bohr.winthrop.edu
Category:

less

Transcript and Presenter's Notes

Title: 26'6Lenses


1
26.6 Lenses
2
Converging Lens
Focal length of a converging lens is real and
considered positive.
3
Diverging Lens
Focal length of a diverging lens is virtual and
considered negative.
4
26.7 The Formation of Images by LensesRay
Diagrams
5
Image Formation by a Converging Lens
6
Magnifying Glass
7
Image Formation by a Diverging Lens
8
26.8 The Thin-lens Equation and the Magnification
Equation
9
Sign Conventions
Focal length   f is () for a converging lens.
  f is () for a diverging lens. Object Image
distances  Real (), virtual (
). Magnification   m is () for an image that
is upright with respect to the object.   m is
() for an image that is inverted with respect to
the object.
10
P44, P814
A diverging lens has a focal length of 32 cm. An
object is placed 19 cm in front of this lens.
Calculate (a) the image distance and (b) the
magnification(c) Is the image real or
virtual?(d) Is the image upright or
inverted?(e) Is the image enlarged or reduced in
size?(f) Draw a ray diagram.
11
P45, P814
An object is located 9.0 cm in front of a
converging lens (f 6.0 cm). Using an
accurately drawn ray diagram, determine where the
image is located. Calculate the image properties
using the lens-equation and magnification
equation.
Write a Comment
User Comments (0)
About PowerShow.com