Title: FLOW THROUGH POROUS MEDIA
1FLOW THROUGH POROUS MEDIA
2DERIVATION OF RICHARDS EQUATION IN RECTANGULAR
COORDINATES
The general continuity equation is q a
v where q is the flow rate, volume/time
(L3/T) a is the cross-section area
perpendicular to the flow, (L2) v is the flow
velocity, length/time (L/T)
3Flow in the x-direction
4Flow in the y-direction
5Flow in the z-direction
6From Continuity of mass
Where Q is the volumetric water content and t is
time.
7From Continuity of mass
8By canceling out terms
9 Applying the Darcy Law to each velocity term
10FLOW THROUGH POROUS MEDIA
11FLOW THROUGH POROUS MEDIA
In unsaturated soil the total potential can be
estimated as the sum of the matric potential and
the gravity potential
Since the gravity potential only acts in the
vertical, or z-direction, the total potential,
h, can be replaced by the matric potential, Y,
in all terms except the one involving z
12FLOW THROUGH POROUS MEDIA
13FLOW THROUGH POROUS MEDIA
This equation is known as the Richard's Equation.
When only the terms involving z on the left are
used, this equation can be used to simulate the
vertical infiltration of water into the soil
profile.
14FLOW THROUGH POROUS MEDIA
For saturated flow h will be the total head, F
and there can be no change in moisture content
with time.
15FLOW THROUGH POROUS MEDIA
For a homogeneous, isotropic soil Kx Ky Kz K
16FLOW THROUGH POROUS MEDIA
Since K is not 0, the term inside the bracket
must be 0
17FLOW THROUGH POROUS MEDIA
This is called the LaPlace Equation for Saturated
Flow in a homogeneous soil.
18Porous Media Transport of Chemicals
- DIFFUSION transport from points or higher
concentration to points of lower concentration. - Molecular Diffusion is due to the random movement
of molecules - Turbulent Diffusion is due to the random movement
of the fluid carrier. Also called dispersion.
19Molecular Diffusion
High Concentration
Low Concentration
- Many molecules move from High to Low
- Few molecules move from Low to High
- Result is decrease in high concentration and
increase in low concentration
20HYDRODYNAMIC DISPERSION
DUE TO UNEVEN FLOW VELOCITY WITHIN A PORE
21HYDRODYNAMIC DISPERSION
DUE TO UNEVEN VELOCITIES BETWEEN PORES
22HYDRODYNAMIC DISPERSION
DUE TO VARYING FLOW PATHS
23FICKS LAW OF DIFFUSION
- D Diffusion Coefficient, L2 / T
- C Chemical Concentration , M / L3
- qx Rate of mass transport in the x-direction.
M/ L2T
24FICKS LAW OF DIFFUSIONCOMBINED WITH THE
CONTINUITY
Dx
A
Volume ADx
25FICKS LAW OF DIFFUSION
- Considering one-dimensional flow in the
x-direction, for continuity
26FICKS LAW OF DIFFUSIONThe Combined Diffusion
Equation
27ADVECTION
- Chemical Transport due to bulk movement of the
fluid. - The fastest form of chemical transport in porous
media. - Concentration decreases in the direction of fluid
movement.
28The Combined Advection/ Dispersion Equation
where s represents all the source and sink terms
that occur in the real environment.
29The Combined Advection/ Dispersion
EquationAssumptions
- one dimensional flow
- uniform flow velocity in the column
- constant moisture content
- linear, instantaneous, reversible adsorption
30Chemical Breakthrough
Co
A
Qs
L
C/Co relative concentration
C
31Plug Flow
Q
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33Flow with Advection
Q
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36Sorption Retardation Coefficient
R number of pore volumes _at_ C/C00.5
37The Combined Advection/ Dispersion Equation
considering adsorption
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41Combining Adsorption Advection-Dispersion
Degradation and Source-Sinks
42Travel Time of a Chemical Through Porous Media
- Continuity Equation Q AV
- Q is the flow rate (Volume / Time)
- A is the total media flow cross-section area.
- V is the average flow velocity through the media.
- Q is the water fraction by volume in the media.
43Travel Time of a Chemical Through Porous Media
QAV VQ/A
V
A
44Travel Time of a Chemical Through Porous Media
QAaVa VaQ/Aa AaAQ Va V/Q
Va
Aa
45Velocity Through Porous Media
Flow Rate 1 CMS
Total Area 2 M2
VQ/A1/2 0.5MPS
Q 1/2 0.5
Open Area 1 M2
VaV/Q 0.5/0.5 1 MPS
46Travel Time of a Chemical Through Porous Media
- Va is the actual flow velocity in the pores of
the media. - Va V / Q
- Mw CwQ Mass of chemical in the flowing water
- MT Cw(QKdBd) The total mass of chemical in
the media.
47Travel Time of a Chemical Through Porous Media
- Z the distance over which travel occurs
- T Travel time of the chemical over distance Z.
- V Z / T
- Therefore T Z / V
- Actual Ta Z / Va ZQ / V
48Travel Time of a Chemical Through Porous Media
- When adsorption of the chemical occurs within the
media, the travel time must account for this by - Tr Z ( Q Kd Bd ) / V
- V may be the infiltration rate
49Factors Influencing Chemical Leaching (Rate of
Water Movement)
- Soil Properties
- Infiltration Rate
- Porosity
- Soil Moisture
- Physical Properties
- Surface Roughness
- Slope
50Factors Influencing Chemical Leaching (Rate of
Water Movement)
- Physical Properties
- Rainfall amount and intensity
- crop species and stage of growth
- weather
- temperature
- solar radiation
- wind velocity
51Factors Influencing Chemical Leaching
(Soil-Chemical Interactions)
- Solute Properties
- adsorption coefficient
- solubility
- vapor pressure
- disassociation and ionization properties
- chemical reactions
52Factors Influencing Chemical Leaching
(Soil-Chemical Interactions)
- Soil Properties
- organic matter content
- soil texture
- pH
- degradation rate
53Factors Influencing Chemical Leaching (Management
Factors)
- Application Rate
- Chemical placement
- incorporation
- banding
- formulation
- Timing of application
- split application
- time of application
54Chemical Leaching Screening Model Example
- Silty Clay Soil
- Topsoil 1 meter thick
- Moisture Content 0.4 L/L
- Topsoil Bulk Density 1.3 kg/L
- Atrazine Applied at a rate of 1.1 kg/ha
- Kd 2 L/kg
- Half-Life 60 days
55Chemical Leaching Screening Model Example
- Assume average Iowa conditions with annual
infiltration 1 meter - 1 m/yr 1/365 0.0027 m/day V
- T Z(Q KdBd ) / V
- 1 ( 0.4 2 1.3 ) / 0.0027
- 3 / 0.0027 1095 days
- 1095 / 60 18.25 half-lives
56Chemical Leaching Screening Model Example
- 1.1 kg/ha-yr atrazine / 1m/yr water 0.11 mg/L
initial chemical concentration. - 0.11 mg / L divided by 218
- 0.00000041962 mg/L at the bottom of the root
zone.