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Survival Models and Life Contingencies

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Life table. Fractional age at death. Actuarial mathematics: ... to the life span of a person, e.g., whole-life insurance, pension valuation ... – PowerPoint PPT presentation

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Title: Survival Models and Life Contingencies


1
Chapter 9
  • Survival Models and Life Contingencies
  • (sample extract)

2
Learning Objectives
  • Distribution of age of death using cumulative
    distribution function, survival function and
    density function
  • Future lifetime distribution
  • Actuarial notations
  • Parametric survival models
  • Life table
  • Fractional age at death

3
  • Actuarial mathematics
  • For analyzing and managing financial risks
  • Risks depend on probabilities of survival or
    termination.
  • Survival models are often related to the life
    span of a person, e.g., whole-life insurance,
    pension valuation

4
9.1 Survival Distribution Function
  • Let X be the random variable (RV) representing
    the age of an individual when death occurs (i.e.,
    refer to X as the age at death).
  • The cumulative distribution function (CDF) of X
    is defined as
  • (9.1)
  • The complementary function of the CDF, called the
    survival distribution function (SDF) is defined
    as
  • (9.2)

5
  • FX(x) is non-decreasing with FX(0) 0 and FX(?)
    1.
  • SX(x) is non-increasing with SX(0) 1 and SX(?)
    0.
  • If X is continuous, the probability density
    function (PDF) is given by
  • (9.3)
  • The force of mortality (FM), denoted by ?x, is
    defined as
  • (9.4)
  • FM represents the instantaneous risk of imminent
    death for an individual given that she has
    already reached age x.

6
  • CDF, SDF, PDF and FM are equivalent forms of
    specifying
  • the distribution of X.
  • If one of them is properly defined, the other
    functions can be
  • uniquely determined.
  • Example 9.1
  • Let (a) Show that SX(x) is a proper
    survival function
  • (b) Determine the corresponding CDF, PDF and
    FM.

7
  • Since SX(x) is a nonincreasing function with
    SX(0) 1 and
  • SX(?) 0, it is a proper SDF.
  • By (9.2) the CDF of X is
  • By (9.3) the PDF of X is

8
  • By (9.4) the FM is

9
  • Future lifetime
  • Let T(x) represent the future lifetime of an
    individual aged x, i.e., T(x) X x with X gt
    x.
  • When no confusion about the present age of the
    individual is likely, we simply denote the future
    lifetime variable by T.
  • The SDF of T is
  • (9.5)

10
  • and its PDF is
  • (9.6)
  • Example 9.2
  • If SX(x) 1 0.01x for 0 x 100, find (a)
    the median age at death m, (b) the SDF and PDF of
    T T(m), and (c) the expected future life time
    at m.

11
  • We need to solve SX(m) 1 0.01m 0.5.
  • Hence, m 50.
  • The SDF of T T(50) is
  • The PDF of X is

12
  • The PDF of T is
  • Thus the expected future lifetime at 50 is
  • The PDF of T can also be obtained by
    differentiating ST(t)
  • directly to obtain fX(t) dST(t)/dt 0.02

13
9.2 Actuarial Notations
  • Denote tqx as the conditional probability of
    death in the age interval (x, x t), given alive
    at age x (i.e., the probability that a person
    aged x will die within t years. Then
  • (9.7)
  • The conditional probability of surviving to age x
    t, given the person is alive at age x, is
    denoted by tpx 1 tqx. Hence,
  • (9.8)

14
  • In the particular case of t 1, we simplify the
    above notations to qx and px.
  • For the more general event that an individual
    aged x survives t years and dies within the next
    s years we denote its probability by tsqx,
    where
  • (9.9)
  • The suffix s may be suppressed if it is equal to
    1. Thus, tqx is the probability of an
    individual aged x surviving t years and dying
    within the next year. Hence, tqx t1qx t qx.

15
  • Alternatively, using the result Pr(AnBC)
    Pr(AC) ? Pr(BAnC), we have
  • (9.10)
  • Over a period of t s, the following chain rule
    holds
  • (9.11)
  • If n is an integer, it is easy to generalize
    (9.11) to
  • (9.12)

16
  • For the conditional probability of death, we have
  • (9.13)
  • Using the SDF of the future lifetime random
    variable T, we have
  • (9.14)

17
  • Example 9.5
  • If iqx 0.05 for i 0, 1, , 7, calculate
    3px4.
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