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Atomic Masses

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Title: Atomic Masses


1
Atomic Masses
How do you measure something too small to be seen?
A scale is needed what would be a good standard?
12
C
6
1 atomic mass unit (AMU) 1/12 mass of Carbon-12
2
What would be the atomic mass of an element that
was twice as heavy as Carbon-12?
24
What about one that is half as heavy?
6
The average atomic mass is NOT the mass number
3
- Gas state atoms are ionized at low pressure
- The ions are accelerated toward a magnet
- Magnet deflects them from straight line
- Deflection is inverse of atomic mass
- Atoms can be compared by weight
The Mass Spectrometer
4
For example
It takes a magnet 1.583 times as strong to
deflect a stream of Fluorine atoms as it does a
stream of Carbon-12 atoms
What is the mass of Fluorine?
1.583 X 12.00amu 19.00amu
5
Fluorine is unique
All Fluorine atoms have 9 protons and 10 neutrons
All other atoms have several isotopes
In order to determine the atomic mass The
relative amounts of each isotope must be
accounted for
6
When a pure sample of Chlorine is passed through
the device the following graph is obtained
7
What does this tell us?
Atomic mass
Abundance
Cl-35 34.97amu 75.53 Cl-37 36.97amu 24.47
8
Atomic mass
- includes the fact that not all samples of
elements are like Fluorine
- not all abundances are like Chlorine
- the periodic table value is the average mass of
all of those elements in the universe
- the units are amus
Q How is the periodic table value calculated?
9
What the?...
Y1 and Y2 are the masses of each isotope
Y1 and Y2 are the abundances of each isotope
10
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11
Bromine is a red-orange liquid that has an
average atomic mass of 79.90amu. Its name is
derived from the Greek bromos which means
stench. It has two naturally occurring
isotopes Br-79 (78.92 amu) and Br-81 (80.92
amu). What is the abundance of the heavier
isotope?
Strategy the two isotopes have to add up to
100. If Br-81 X, then Br-79 must equal?...
100 - X
12
The heavier isotope has an abundance of 49
13
Q If 75 of the Chlorine in the universe is
Cl-35 and the rest is Cl-37 should the table
entry for Chlorine be closer to 35 or 37?
35
Q What is Chlorines atomic mass?
35.453 amu
14
Masses of atoms and Avagadros number
Consider H and He Helium is about 4 times as
heavy as Hydrogen
A sample of 100 Helium atoms should weigh about 4
times as much as 100 Hydrogen atoms
A sample of a million Helium atoms should weight
about 4 time as much as a million Hydrogen atoms
15
By that thinking 4 grams of Helium should
contain the same number of atoms as 1 gram of
Hydrogen
Specifically 4.003 grams of Helium contains the
same number of atoms as 1.008 grams of Hydrogen
A sample of any element with a mass in grams
equal to its atomic mass contains the same number
of atoms (NA), regardless of the identity of the
element
16
The numerical value of NA is 6.022x1023 and is
known a Avagadros Number
It was obtained by experiments comparing the
weights of various gases whose relative weights
were already known
Q How many atoms are in a ten gram sample of
Titanium?
17
Q How many atoms are in a ten gram sample of
Titanium?
10.0 g Ti
1 mole Ti
6.022 x 1023 atoms
x
x

48 g Ti
1 mole Ti
1.26 x 1023 atoms
18
Avagadros Number worth of anything is called a
mole
The mass of one mole of a compound is numerically
equal to the sum of all of the atoms in the
formula
Sugar is C12H22O11
Baking Soda is NaHCO3
Copper nails are just Cu
19
Mole Mass Conversions
m MM x n
One of the most important equations used in
chemistry!!!
(m) is the mass in grams
(MM) is the molar mass
(n) is the number of moles
20
m MM x n
Aspirin is a compound called acetylsalicylic acid
(ASA). Its formula is C9H8O4 What is the mass of
0.509 moles of ASA?
m MM x n (180 g/mole) x (0.509 moles)
91.6 g
C 12 x 9 108 H 1 x 8 8 O 16 x 4 64
MM 180 g/mol
21
Same problem done MY way
180 g C9H8O4
O.509 moles C9H8O4
x

91.6 g
1 mole C9H8O4
22
Some problems are harder than others
A 1.00 g sample of aspirin contains 75.2 by mass
of C9H8O4 How many moles of ASA are in the sample?
Mass of ASA? 0.752 x 1.00g 0.752 g
1 mole C9H8O4
0.752 g C9H8O4
0.00418 moles
x

180 g C9H8O4
23
How many Carbon atoms are present in a 12.0 g
sample of C9H8O4?
12.0 g C9H8O4
1 mole C9H8O4
6.02 x 1023 molecules
9 C atoms
x
x
x
180 g C9H8O4
1 mole C9H8O4
1 molecule
3.61 x 1023 Carbon atoms
There is only ONE problem in chemistry!!!
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