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Interpretation of Phase Diagrams

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Title: Interpretation of Phase Diagrams


1
Chapter 6
  • Interpretation of Phase Diagrams

Phase diagrams summarize in graphical form the
ranges of temperature (or pressure) and
composition over which phases or mixtures of
phases are stable under conditions of
thermodynamic equilibrium. Phase diagram
contains information of compounds composition,
solid solution, phase transition and melting
temperature.
2
Phase rule P F C 2
  • P number of phases
  • C number of components
  • F degree of freedom

PV nRT 3 variables, 1 equation
Total number of degree of freedom (C-1)P
2 Number of relations C(P-1) Net degree of
freedom F (C-1)P 2 C(P-1) C P 2
C1 C2 .. Cc 100
P-1 relations m1 m2 m3 m4 m5 . mP
mi free energy
One needs P-1 equations to describe the
equilibrium between phases
3
P number of phases
  • How to distinguish phases?
  • l   crystalline phases MgSiO3, Mg2SiO4
  • l   polymorphism a- b- g-
  • l   solid solution ( one phase )
  • l   defects
  • ordered defects distinguished
    phases
  • disordered defects one phase
  • (considered as solid solution)
  • WO3-x (WnO3n-1 W20O59, W19O56)
  • l   liquid (miscibility or immiscibility)
  • l   gas one phase
  •  
  •  

4
C number of components
  • CaO-SiO2 two components
  • MgO (heating below mp) one component
  • FeO appears to be one component, but two
    components

? 3Fe2 ? 2Fe3 Feo ? FeO is in fact Fe1-xO
(wüstite) x Fe
5
Phase diagram of CaO-SiO2
6
F degree of freedom
  • Independent variable to describe a system

For example boiling water P 2, C 1 F C
P 2 1 - 2 2 1 So only temperature or
pressure is enough to describe the system, that
is, T and P are dependent variables.
7
Thermodynamically stable or kinetically stable
8
How do you know a compound is thermodynamically
stable or kinetically stable?
  • eg. 1. Ca3SiO5 is prepared above 1300oC.
  • At 1100oC, Ca3SiO5 ? CaO Ca2SiO4
  • Ca3SiO5 is thermodynamically stable above
    1300oC but is kinetically stable at 1100oC.
  • eg. 2. At ambient temperature and pressure,
    graphite is thermodynamically stable and diamond
    is kinetically stable.

Usually metastable products can be obtained by
quenching the reaction before it reaches
equilibrium.
9
One component system
  • F C P 2 3 P
  • One phase, P 1, F 2
  • It takes two independent variables to
    describe the system. Ex. Ideal gas law PV nRT
  • Two phases, F 1,
  • e.g. Boiling water. Need to know P or T.
  • Three phases no variables.

10
One component system
BE gives the change of transition temperature
with pressure. (F 1) FC change of melting
point of polymorph Y with pressure. (F 1) AB,
BC sublimation curves for X and Y. (F 1)
CD vapour pressure curve for the liquid. (F
1) Points B, C are triple points. (F 0) In area
X, Y etc, F 2
11
Phase diagram of water
12
Phase diagram of SiO2
At 1600 bar
  • a-quartz ? b-quartz
  • liquid SiO2
  • ? b-tridymite and
  • b-cristobalite have lower density than quartz

However, many metastable phases can be obtained
by quenching.
At 500 bar
a-quartz ? b-quartz? b-tridymite ? b-cristobalite
? liquid SiO2
573oC
870oC
1470oC
1710oC
13
Condensed System
  • For most systems and applications of interest
    in solid state chemistry, the condensed phase
    rule is applicable, pressure is not a variable
    and the vapour phase is not important.

Condensed Phase Rule P F C 1
e.g. SiO2 (Fig 6.5) 1 F 1 1 gt F
1 So that temperature is the only factor for
the change of polymorphs
14
Eutectic Binary System
y invariant point xyz liquidus curve cyd
solidus curve
eutectic point
What happens if the system is heated from
points e and f ?
In order to determine the relative amounts of two
phases in a mixture, the level rule is used
15
Level Rule
(amount of liquid) x (distance of hf) (amount
of B) x (distance of Bf)
(amount of B) hf/Bh (amount of liquid) Bf/Bh
16
B
Liquid
(amount of B) hf/Bh (amount of liquid)
Bf/Bh Composition of liquid h
17
Amount of liquid in varies T
  • T1 0.43 (43 liq.)
  • T2 liq in f Bf/Bj 0.53
  • T3 0.71
  • T4 melt complete

18
Eutectic Reaction
  • Reactions at f point
  • T gt T1 57 B (43 liq.)
  • T lt T1 70 B (30 A)
  • mixture of A B crystallized
  • The reaction described above are those that
    should occur under equilibrium conditions.

19
A method to lower melting point
  • From the eutectic binary system, it can be
    considered that B is added to lower the melting
    point of A.
  • For example, NaCl is added to lower the
    melting point of ice (to 21 oC)

20
Binary systems with the formation of compounds
Point x peritectic point. Compound AB melts
congruently or incongruently.
Describe what happens when system is cooled at
composition n ?
21
Non-equilibrium products
  • Describe what happens when system is cooled
    at composition n ?

When the system is cooled at composition n, one
should get AB B (equilibrium product) But if A
L ? AB L is very slow, one will get A AB
B ( non-equilibrium products)
22
Phase diagram of CaO-SiO2 system
23
Immiscible Liquids
24
Formation of metastable 2-liquid system
It happens when 2-liquid ? B liquid is very
slow upon cooling
25
Binary system with complete range of solid
solution
26
Cored (phenomenon of non-equilibrium)
  • When the system is cooled at composition b,
    the central part that forms first may have
    composition a and on moving out radially from the
    centre the crystal becomes increasingly rich in B.

Still forms a single crystal (the same structure
type of A and B) but with concentration gradient.
27
What forms solid solution?
  • A and B have the same structure type and ions
    in them have similar size.

e. g. CaAl2Si2O8 and NaAlSi3O8 in plagioclase
feldspar system
28
The plagioclase feldspar system
29
Glass formation
  • Recently, there has been much scientific and
    technological interest in glassy semiconductors
    and metals, materials with unusual electrical and
    mechanical properties.

If the liquid is cool rapidly (quenched) to room
temperature, there may not be time for any
crystallization to occur and a glass forms.
30
Partial Solid Solution
  • If ions are quite different in size
  • ? complete solid solution may not be possible.
  • e.g. forsterite (Mg2SiO4) vs willemite (Zn2SiO4)

31
Partial Solid Solution
32
A slightly complicated partial solid solution
33
A complicated Partial Solid Solution
34
Binary system with polymorph transitions
35
example
36
Another example
37
The Fe-C diagram
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