Title: The
1The
Pythagorean
Theorem
c
a
b
2Pythagorean Theorem Essential Questions
- How is the Pythagorean Theorem used to identify
side lengths? - When can the Pythagorean Theorem be used to
solve real life patterns?
3This is a right triangle
4We call it a right triangle because it contains a
right angle.
5The measure of a right angle is 90o
90o
6 in the
The little square
angle tells you it is a
right angle.
90o
7About 2,500 years ago, a Greek mathematician
named Pythagorus discovered a special
relationship between the sides of right triangles.
8Pythagorus realized that if you have a right
triangle,
9and you square the lengths of the two sides that
make up the right angle,
10and add them together,
11you get the same number you would get by squaring
the other side.
12Is that correct?
?
?
13It is. And it is true for any right triangle.
14The two sides which come together in a right
angle are called
15The two sides which come together in a right
angle are called
16The two sides which come together in a right
angle are called
legs.
17The lengths of the legs are usually called a and
b.
a
b
18The side across from the right angle
is called the
hypotenuse.
a
b
19And the length of the hypotenuse
is usually labeled c.
c
a
b
20The relationship Pythagorus discovered is now
called The Pythagorean Theorem
c
a
b
21The Pythagorean Theorem says, given the right
triangle with legs a and b and hypotenuse c,
c
a
b
22then
c
a
b
23You can use The Pythagorean Theorem to solve many
kinds of problems.
Suppose you drive directly west for 48 miles,
48
24Then turn south and drive for 36 miles.
48
36
25How far are you from where you started?
48
36
?
26Using The Pythagorean Theorem,
48
482
362
c2
36
c
27Why?
Can you see that we have a right triangle?
28Which side is the hypotenuse?
Which sides are the legs?
29Then all we need to do is calculate
30And you end up 60 miles from where you started.
So, since c2 is 3600, c is
48
36
60
31Find the length of a diagonal of the rectangle
?
32Find the length of a diagonal of the rectangle
?
c
b 8
a 15
33(No Transcript)
34Find the length of a diagonal of the rectangle
17
35Practice using The
Pythagorean Theorem to solve these right
triangles
36 13
37(No Transcript)
38 24
(a)
(c)
39Check It Out! Example 2
A rectangular field has a length of 100 yards and
a width of 33 yards. About how far is it from one
corner of the field to the opposite corner of the
field? Round your answer to the nearest tenth.
40Check It Out! Example 2 Continued
Rewrite the question as a statement.
Find the distance from one corner of the field
to the opposite corner of the field.
List the important information
Drawing a segment from one corner of the field
to the opposite corner of the field divides the
field into two right triangles.
The segment between the two corners is the
hypotenuse.
The sides of the fields are legs, and they are
33 yards long and 100 yards long.
41Check It Out! Example 2 Continued
You can use the Pythagorean Theorem to write an
equation.
42Check It Out! Example 2 Continued
a2 b2 c2
Use the Pythagorean Theorem.
332 1002 c2
Substitute for the known variables.
1089 10,000 c2
Evaluate the powers.
11,089 c2
Add.
105.304 ? c
Take the square roots of both sides.
105.3 ? c
Round.
The distance from one corner of the field to the
opposite corner is about 105.3 yards.
43The Pythagorean Theorem
- For any right triangle, the sum of the areas of
the two small squares is equal to the area of the
larger. - a2 b2 c2
44Proof
45Lets look at it this way
a
c
a
c
b
b
c2
a2
b2
46Baseball Problem
- A baseball diamond is really a square.
- You can use the Pythagorean theorem to find
distances around a baseball diamond.
47Baseball Problem
- The distance between
- consecutive bases is 90
- feet. How far does a
- catcher have to throw
- the ball from home
- plate to second base?
48Baseball Problem
- To use the Pythagorean theorem to solve for x,
find the right angle. - Which side is the hypotenuse?
- Which sides are the legs?
- Now use a2 b2 c2
49Baseball ProblemSolution
- The hypotenuse is the distance from home to
second, or side x in the picture. - The legs are from home to first and from first to
second. - Solution
- x2 902 902 16,200
- x 127.28 ft
50Ladder Problem
- A ladder leans against a second-story window of a
house. If the ladder is 25 meters long, and the
base of the ladder is 7 meters from the house,
how high is the window?
51Ladder ProblemSolution
- First draw a diagram that shows the sides of the
right triangle. - Label the sides
- Ladder is 25 m
- Distance from house is 7 m
- Use a2 b2 c2 to solve for the missing side.
Distance from house 7 meters
52Ladder ProblemSolution
- 72 b2 252
- 49 b2 625
- b2 576
- b 24 m
- How did you do?