Title: Answer the following questions:
1Answer the following questions
- Define the term spontaneous reaction.
- Which of the following reactions do you think are
spontaneous? - 1) A nail rusting.
- 2) The decomposition of carbon in diamond to
graphite. - 3) The combination of hydrogen and oxygen to
form water. - 4) The decomposition of hydrogen peroxide.
- 5) The combustion of butane.
- What does the spontaneity of a reaction indicate
about the speed at which the reaction occurs?
2Chemical Kinetics
3Kinetics
- The study of reaction rates.
- Spontaneous reactions are reactions that will
happen - but we cant tell how fast. (Spontaneity
implies nothing about speed) - For example Diamond will spontaneously turn to
graphite so slow it is not detectable. - Reaction mechanism- the steps by which a reaction
takes place.
4Factors that Affect Reaction Rates
- Nature of the reactants
- Concentration of the reactants
- Temperature
- Presence of a catalyst
5Collision Theory of Reaction Rates
- For a reaction to occur, particles must collide.
- Increasing the concentration or reactants results
in a greater number of collisions and therefore,
a faster rate. - Not all collisions are effective collisions.
6Effective Collisions
- For a collision to be effective
- 1) particles must possess a necessary minimum
energy to break bonds and form new ones
(activation energy) - 2) particles must have proper orientation at
the time of the collision. (see page 554)
7Reaction Rate
- Defined as the change in the concentration of a
reactant or product per unit time. - RateConc.of A at t2-Conc. of A at t1
- t2 t1
- Rate DA Dt
8For this reaction N2 3 H2 ? 2 NH3
As the reaction progresses the concentration H2
goes down
CONCENTRATION
H2
TIME
9- As the reaction progresses the concentration N2
goes down 1/3 as fast
CONCENTRATION
N2
H2
H2
TIME
10- As the reaction progresses the concentration NH3
goes up.
N2
H2
NH3
11Calculating Rates
- Average rates are taken over long intervals
- Instantaneous rates are determined by finding the
slope of a line tangent to the curve at any given
point because the rate can change over time
12Defining Rate
- We can define rate in terms of the disappearance
of the reactant or in terms of the rate of
appearance of the product. - In our example N2 3H2 ? 2NH3 -DN2
-3DH2 2DNH3
Dt Dt Dt
13Rate Laws
- Reactions are reversible.
- As products accumulate they can begin to turn
back into reactants. - Initially, the rate will depend on only the
amount of reactants present. - Therefore, reactions must be studied at a point
soon after the reactants are mixed. - This is called the Initial rate method.
14Rate Laws
- The concentration of the products do not appear
in the rate law because this is an initial rate. - The order must be determined experimentally,
and cant be obtained from the equation - The order indicates to what degree the
concentration affects the rate.
15Types of Rate Laws
- Differential Rate law - describes how rate
depends on concentration (often simply called
rate law) - Integrated Rate Law - describes how concentration
depends on time. - For each type of differential rate law there is
an integrated rate law and vice versa. - Rate laws can help us better understand reaction
mechanisms.
16Reaction Mechanism
- The step by step pathway by which a reaction
occurs is called its mechanism. - The individual steps are called elementary steps.
- The rate law for an elementary step can be
written from its molecularity. - Molecularity is defined as the number of species
that must collide to produce the reaction
indicated by that step.
17Examples of Elementary Steps
Elementary Step Molecularity Rate Law
A ? products Unimolecular Rate kA
A A ? products Bimolecular Rate kA2
A B? products Bimolecular Rate kAB
A A B? products Termolecular RatekA2B
A B C?products Termolecular RatekABC
182 NO2 ? 2 NO O2
- The rate will only depend on the concentration of
the reactants. - Rate kNO2n
- This is called a rate law expression or
differential rate law. - k is called the rate constant.
- n is the order of the reactant -usually a
positive integer and must be determined
experimentally - Overall reaction order is the sum of the orders
for each individual reactant.
19Integrated Rate Laws
- Integrated Rate Laws express the reactant
concentration as a function of time (instead of
rate as a function of the reactant
concentration). - We will only be considering reactions involving a
single reactant when determining integrated rate
laws.
20First-Order Rate Laws
- Consider the following reaction
- 2N2O5 ? 4NO2 O2
- The rate law (differential) is determined to be
- Rate kN2O5
- This means that if the concentration of N2O5 is
doubled, the rate of production of the products
is also doubled.
21Integrated First-Order Rate Law
- The previous differential rate law can be
integrated and as a result, written in the
following form - lnN2O5 -kt lnN2O50
- Where
- ln indicates the natural log
- t is the time
- N2O5 is the concentration at time t
- N2O5o is the initial concentration
22Integrated First-Order Rate Laws
- All integrated first order rate laws take the
following general form - lnA -kt lnAo
- Items to note
- 1) The equation shows how the concentration of
A depends on time -
23Integrated First-Order Rate LawslnA -kt
lnAo
- 2) The above equation is of the form ymx b,
where a plot of y vs. x is a straight line with
slope m and intercept b. - In the above rate law
- ylnA xt m-k blnAo
- As a result, plotting lnA vs. time always
gives a straight line. (This fact is often used
to test whether a reaction is 1st order or not) - 3) The integrated rate law for a 1st order
reaction can also be written as - ln(Ao/A) kt
-
24Half-Life
- The time required for a reactant to reach half of
its original concentration is called the
half-life of a reactant and is designated with
the symbol t1/2. - The general equation for the half-life of a first
order reaction is - t1/2 0.693/k
- (Half-life does not depend on concentration)
252nd Order Rate Laws
- Consider the following reaction
- 2C2H6 (g) ? C8H12(g)
- The rate law (differential) is determined to be
- Rate kC2H62
- This means that if the concentration of C2H6 is
doubled, the rate of production of the products
is quadrupled.
26Integrated Second-Order Rate Laws
- The previous differential rate law can be
integrated and as a result, written in the
following form - 1/C4H6 kt 1/C4H6o
- All integrated second order rate laws have the
form - 1/A kt 1/Ao
- Note
- 1) A plot of 1/A vs. time produces a straight
line with a slopek. - 2) The half-life equation for a 2nd order
reaction is t1/2 1/kAo
27Zero-Order Rate Laws
- The rate law for a zero order reaction is rate
k - This means that changing the concentration has no
effect on the rate of the reaction. - Example N2O5 ? 2NO2 1/2O2
- The integrated rate law for a zero order reaction
is - A -kt Ao
- Note
- 1) A plot of A vs. time results is a straight
line - 2) the half life equation is
- t1/2 A0/2k
28Interpreting Differential Rate Laws
29A B C ? products
- The rate law is determined to be
- rate kAB2
- What happens to the reaction rate
- when we make the following changes
- to the concentrations?
30The concentration of A is doubled, while B and C
remain unchanged.
- The rate remains the same.
- The rate doubles.
- The rate is cut in half.
- The rate is quadrupled.
- The rate is increased by a factor of 8.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
31The concentration of B is doubled while A and C
remain unchanged.
- The rate remains the same.
- The rate doubles.
- The rate is cut in half.
- The rate quadruples.
- The rate increases by a factor of 8.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
32The concentration of C is doubled while A and B
remain unchanged.
- The rate remains the same.
- The rate is doubled.
- The rate is cut in half.
- The rate is quadrupled.
- The rate is increased by a factor of 8.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
33The concentration of all three reactants are
doubled simultaneously.
- The rate remains the same.
- The rate is doubled.
- The rate is cut in half.
- The rate is quadrupled.
- The rate increases by a factor of 8.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
34The concentration of A is cut in half while B and
C are doubled.
- The rate remains the same.
- The rate is doubled.
- The rate is cut in half.
- The rate is quadrupled.
- The rate increases by a factor of 8.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
35Which of the following is the rate law for a
first order reaction?
- Rate kA
- Rate kA2
- Rate kAB
- Rate kA2B
- Rate kA2B2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
36Which is a rate law that is second order with
respect to B?
- Rate kA
- Rate kA2
- Rate kAB
- Rate kA2B
- Rate kA2B2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
37Which is the rate law for a third order reaction?
- Rate kA
- Rate kA2
- Rate kAB
- Rate kA2B
- Rate kA2B2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
38Which rate law represents a reaction in which the
initial rate will increase by a factor of eight
when A and B are doubled?
- Rate kA
- Rate kB2
- Rate kAB
- Rate kA2B
- Rate kA2B2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
39Which rate law represents a reaction in which the
rate will increase by a factor of two when A
and B are doubled?
- Rate kA
- Rate kB2
- Rate kAB
- Rate kA2B
- Rate kA2B2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
40Which rate law represents a reaction in which the
rate will not change when A is doubled and B
is held constant?
- Rate kA
- Rate kB2
- Rate kAB
- Rate kA2B
- Rate kA2B2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
41A reaction occurs according to the following rate
law rate kA. If the temperature of the
reaction chamber were increased, which of the
following would be true?
- The rate of reaction and the rate constant will
increase. - The rate of reaction and the rate constant will
not change. - The rate of reaction will increase and the rate
constant will decrease. - The rate of reaction will increase and the rate
constant will not change. - The rate of reaction will not change and the rate
constant will increase.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
42Determining the form of a rate law(Method of
Initial Rates)
- The initial rate is the instantaneous rate right
after the reaction begins (t0) - Eliminates the effect of the reverse reaction.
- The initial concentrations of the reactants are
varied. - The reaction rate is determined for each trial.
- See the example problem on p. 536
43A 2B ? C
Trial Initial A Initial B Initial Rate of formation of C
1 0.010 M 0.010 M 1.5 x 10-6 M/s
2 0.010 M 0.020 M 3.0 x 10-6 M/s
3 0.020 M 0.010 M 6.0 x 10-6 M/s
44The rate law for the reaction is
- Rate k AB
- Rate k A2B
- Rate k AB2
- Rate k A2B2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
45Reaction Mechanism (continued)
- In most mechanisms, one step is slower than the
others. - A reaction can never occur faster than its
slowest step. - The slow step is the rate-determining step.
46Determining Possible Reaction Mechanisms
- The balanced equation for the overall reaction is
equal to the sum of all of the individual steps. - The rate law expression matches the coefficients
of the rate determining step.
47Example
- NO2 CO ? NO CO2
- rate kNO22
- One proposed mechanism
- NO2 NO2 ? N2O4 (slow)
- N2O4 CO ? NO CO2 NO2 (fast)
- NO2 CO ? NO CO2
- N2O4 is an intermediate (forms in one step and is
consumed in a later step) - This proposed mechanism is consistent with the
experimentally determined rate law.
48Another possible mechanism
- NO2 NO2 ? NO3 NO (slow)
- NO3 CO ? NO2 CO2 (fast)
- NO2 CO ? NO CO2
- In order to be a possible mechanism the following
two criteria must be met - 1) The individual steps must add up to the
overall reaction - 2) The mechanism is consistent with the
experimentally determined rate law expression
49Equilibrium Step
- An equilibrium step is a step in which a product
can rapidly re-form the reactants to reach
equilibrium. - The concentration of products is equal to the
concentration of the reactants at equilibrium. - An equilibrium step is indicated by a double
arrow. (lt -- gt ) - Substitutions can be made in the rate law
expression between the reactants and the products.
50Example
- 2NO Br2 ? 2NOBr
- rate kNO2Br2
- Proposed mechanism
- NO Br2 lt --gt NOBr2 (fast)
- NOBr2 NO ? 2NOBr (slow)
- 2NO Br2 ? 2NOBr
- Rate kNOBr2NO can be substituted with
- Rate kNOBr2NO or RatekNO2Br2
51A multi step reaction takes place by the
following mechanismA B ? C DA C ? D
EWhich of the species shown is an intermediate
in the reaction?
- A
- B
- C
- D
- E
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
52Which of the following is the rate law for the
predicted mechanism for the production of NO2?NO
O2 lt-gt NO3 (fast)NO3 NO ? 2NO2 (slow)
- Rate kNOO2
- Rate kNO3NO
- Rate kNO2O2
- Rate kNO22
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32
53Homework problems to be completed by tomorrow
- Chapter 12 problems 51-53, 55, 65, 75, and 82
54Example Problem p. 569-571
- Complete homework problems 32,34,39-42, 44, 46,
48, and 89.