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Wednesday, September 5

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17.1 1. Draw the nontemplate strand of DNA for the template shown below. Compare and contrast its base sequence with the mRNA molecule. DNA A C C A A A C C G A G T – PowerPoint PPT presentation

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Title: Wednesday, September 5


1
17.1 1. Draw the nontemplate strand of DNA for
the template shown below. Compare and contrast
its base sequence with the mRNA molecule. DNA
A C C A A A C C G A G T   mRNA U G G U U U G G
C U C A
2
17.1 1. Draw the nontemplate strand of DNA for
the template shown below. Compare and contrast
its base sequence with the mRNA molecule. DNA
A C C A A A C C G A G T T G G T T T G G C T C
A mRNA U G G U U U G G C U C A
3
17.1 1. Draw the nontemplate strand of DNA for
the template shown below. Compare and contrast
its base sequence with the mRNA molecule. DNA
A C C A A A C C G A G T T G G T T T G G C T C
A mRNA U G G U U U G G C U C A
4
17.1 2. What protein product would you expect
from a poly-G mRNA that is 30 nucleotides
long? 5-GGGGGGGGGGGGGGGGGGGGGGGGGGGGGG-3
5
17.1 2. What protein product would you expect
from a poly-G mRNA that is 30 nucleotides
long? 5-GGGGGGGGGGGGGGGGGGGGGGGGGGGGGG-3 Gly-G
ly-Gly-Gly-Gly-Gly-Gly-Gly-Gly-Gly
6
17.2 1. Compare and contrast the functioning of
DNA polymerase and RNA polymerase.
7
DNA polymerase
RNA polymerase
8
  • DNA polymerase
  • Assembles chains from monomers
  • RNA polymerase
  • Assembles chains from monomers

9
  • DNA polymerase
  • Assembles chains from monomers
  • Complementary base pairing
  • RNA polymerase
  • Assembles chains from monomers
  • Complementary base pairing

10
  • DNA polymerase
  • Assembles chains from monomers
  • Complementary base pairing
  • Reads 3?5
  • Assembles 5 ?3
  • RNA polymerase
  • Assembles chains from monomers
  • Complementary base pairing
  • Reads 3?5
  • Assembles 5 ?3

11
  • DNA polymerase
  • Needs a primer
  • RNA polymerase
  • Can start from scratch

12
  • DNA polymerase
  • Needs a primer to start
  • Uses A, T, G C
  • Uses nucleotides containing deoxyribose
  • RNA polymerase
  • Can start from scratch
  • Uses A, U, G C
  • Uses nucleotides containing ribose

13
17.2 2. Is the promoter at the upstream or
downstream end of a transcription unit?
14
17.2 2. Is the promoter at the upstream or
downstream end of a transcription unit? Upstream
15
17.2 3. In a prokaryote, how does RNA polymerase
know where to start transcribing a gene? In a
eukaryote?
16
17.2 3. In a prokaryote, how does RNA polymerase
know where to start transcribing a gene? In a
eukaryote? Prokaryote RNA polymerase
recognizes promoter Eukaryote Transcription
factors mediate binding
17
17.2 4. How is the primary transcript produced
by a prokaryotic cell different from that
produced by a eukaryotic cell?
18
17.2 4. How is the primary transcript produced
by a prokaryotic cell different from that
produced by a eukaryotic cell? Prokaryote
used immediately as mRNA Eukaryote Must be
modified before being used as mRNA
19
17.3 1. How does the alteration of the 5 and 3
ends of pre-mRNA affect the mRNA that exists in
the nucleus?
20
  • 17.3
  • 1.
  • How does the alteration of the 5 and 3 ends of
    pre-mRNA affect the mRNA that exists in the
    nucleus?
  • Facilitates transportation
  • Prevents degradation
  • Facilitates ribosomal attachment

21
17.3 2. Describe the role of snRNPs in RNA
splicing.
22
  • 17.3
  • 2.
  • Describe the role of snRNPs in RNA splicing.
  • Joins with other proteins to form spliceosomes.
  • Removes introns, splices exons together.

23
17.3 3. How can alternative RNA splicing
generate a greater number of polypeptide products
than there are genes?
24
17.3 3. How can alternative RNA splicing
generate a greater number of polypeptide products
than there are genes? THE CAT ATE THE RBAT
25
17.3 3. How can alternative RNA splicing
generate a greater number of polypeptide products
than there are genes? THE CAT ATE THE RBAT
26
17.3 3. How can alternative RNA splicing
generate a greater number of polypeptide products
than there are genes? THE CAT ATE THE RBAT
27
17.4 1. Which two processes ensure that the
correct amino acid is added to a growing
polypeptide chain?
28
  • 17.4
  • 1.
  • Which two processes ensure that the correct amino
    acid is added to a growing polypeptide chain?
  • Aminoacyl-tRNA synthase
  • tRNA codon

29
17.4 2. Describe how the formation of
polyribosomes can benefit the cell.
30
17.4 2. Describe how the formation of
polyribosomes can benefit the cell. Multiple
copies of a protein in a short time.
31
17.4 3. Describe how a polypeptide to be
secreted is transported to the endomembrane
system.
32
  • 17.4
  • 3.
  • Describe how a polypeptide to be secreted is
    transported to the endomembrane system.
  • Signal peptide is recognized by SRP.
  • SPR brings polypeptide to ER lumen.

33
17.5 1. Describe three properties of RNA that
allow it to perform diverse roles in the cell.
34
  • 17.5
  • 1.
  • Describe three properties of RNA that allow it
    to perform diverse roles in the cell.
  • Hydrogen bonds with DNA or RNA
  • Specific 3-D shape
  • Catalize chemical reactions.

35
17.6 1. In figure 17.22 (orange book and green
book) number the RNA polymerases in order of
their initiation of transcription. Then number
each mRNAs ribosomes in order of their
initiation of translation.
36
17.6 2. Would the arrangement shown in Figure
17.22 be found in a eukaryotic cell? Explain.
37
17.7 1. What happens when one nucleotide pair is
lost from the middle of the coding sequence of a
gene?
38
  • 17.7
  • 1.
  • What happens when one nucleotide pair is lost
    from the middle of the coding sequence of a gene?
  • Frame shift mutation
  • Nonfunctional protein

39
17.7 2. The template strand of a gene contains
the sequence 3-TACTTGTCCGATATC-5. Draw a
double strand of DNA and the resulting strand of
mRNA, labeling all 5 and 3 ends. Determine the
amino acid sequence. Then show the same after a
mutation changes the template DNA sequence to
3-TACTTGTCCAATATC-5. What is the effect on the
amino acid sequence?
40
17.7 2. Template strand 3-TACTTGTCCGATATC-5 Dr
aw a double strand of DNA.
41
17.7 2. Double strand 3-TACTTGTCCGATATC-5 5-AT
GAACAGGCTATAG-3 Draw the resulting strand of
mRNA, labeling all 5 and 3 ends
42
17.7 2. Double strand 3-TACTTGTCCGATATC-5 5-AT
GAACAGGCTATAG-3 mRNA 5-AUGAACAGGCUAUAG-3
43
17.7 2. mRNA 5-AUGAACAGGCUAUAG-3 Determine
the amino acid sequence.
44
17.7 2. mRNA AUG AAC AGG CUA UAG Determine the
amino acid sequence.
45
17.7 2. mRNA AUG AAC AGG CUA UAG Polypeptide
Met-Asn-Arg-Leu
46
17.7 2. Then show the same after a mutation
changes the template DNA sequence to
3-TACTTGTCCAATATC-5.
47
17.7 2. Template strand 3-TACTTGTCCAATATC-5 Dr
aw a double strand of DNA.
48
17.7 2. Double strand 3-TACTTGTCCAATATC-5 5-AT
GAACAGGTTATAG-3 Draw the resulting strand of
mRNA, labeling all 5 and 3 ends
49
17.7 2. Double strand 3-TACTTGTCCAATATC-5 5-AT
GAACAGGTTATAG-3 mRNA 5-AUGAACAGGUUAUAG-3
50
17.7 2. mRNA 5-AUGAACAGGUUAUAG-3 Determine
the amino acid sequence.
51
17.7 2. mRNA AUG AAC AGG UUA UAG Determine the
amino acid sequence.
52
17.7 2. mRNA AUG AAC AGG UUA UAG Polypeptide
Met-Asn-Arg-Leu
53
17.7 2. mRNA AUG AAC AGG UUA UAG Polypeptide
Met-Asn-Arg-Leu The resulting polypeptide is
the same. .
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