EFFECT OF CENTRIFUGAL AND CORIOLIS FORCES DUE TO EARTH

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EFFECT OF CENTRIFUGAL AND CORIOLIS FORCES DUE TO EARTH

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EFFECT OF CENTRIFUGAL AND CORIOLIS FORCES DUE TO EARTH S ROTATION ON g Effect of centrifugal force The acceleration of a particle in frame of reference S ... –

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Title: EFFECT OF CENTRIFUGAL AND CORIOLIS FORCES DUE TO EARTH


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EFFECT OF CENTRIFUGAL AND CORIOLIS FORCES DUE TO
EARTHS ROTATION ON g
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Effect of centrifugal force
  • The acceleration of a particle in frame of
    reference S rotating with a constant angular
    velocity ? is given by

  • .(1)
  • Here r is position vector of the particle and the
    other terms have their usual meaning.

When a particle is at rest on the surface of
earth which rotates
with constant angular velocity ? about its polar
axis, then
3
  • Then, Coriolis acceleration0
  • i.e.
  • and

4
  • Therefore, from equation (1),
  • the acceleration is given by

  • (2)

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  • Acceleration due to gravity at P acts along
    PO. The components of g are

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This acceleration is given by eqn. (2) as
  • where ? is latitude of particle P.

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This equation shows that centrifugal acceleration
decreases the effective acceleration due to
gravity.
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  • Hence
  • there is no effect of rotation of earth on the
    value of acceleration due to gravity at its poles
  • there is maximum effect of rotation of earth on
    the value of acceleration due to gravity at its
    equator.

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2. Effect of Coriolis Force
  • Consider a point P at latitude ? on the surface
    of earth. Let the earth rotate with constant
    angular velocity ? about its polar axis.
  • ? makes an angle ? with y- axis at point P

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  • Imagine a point P vertically above P and drop a
    body of mass m, then velocity v acquired by it
    at time t is given by
  • Vx and vy are taken as zero because body has
    velocity only along negative z-axis. The coriolis
    force acting on the particle is given by

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  • This shows that coriolis force acts on the
    particle along positive x-axis.
  • From Newtons second law of motion

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  • Using the relation, v uat along negative
    z-direction.
  • Integration w. r. t. time t gives

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  • Again integrating w.r.t. t, we get
  • Hence, due to coriolis force, the particle
    dropped vertically downwards suffers a deviation
    along positive x-axis i.e. towards east.
  • The displacement of the particle will be maximum
    for ?0 i.e.
  • at the equator.

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THANX!
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