Balancing Redox Equations - PowerPoint PPT Presentation

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Balancing Redox Equations

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Balancing Redox Equations analyze: Mg + S MgS 1. assign oxidation numbers to all elements 2. figure out change in oxidation numbers what is oxidized? – PowerPoint PPT presentation

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Title: Balancing Redox Equations


1
Balancing Redox Equations
2
analyze Mg S ? MgS
  • 1. assign oxidation numbers to all elements
  • 2. figure out change in oxidation numbers
  • what is oxidized?
  • what is reduced?

Mg 0 to 2 oxidation
S 0 to -2 reduction
3
Mg S ? MgS
2 -2
0
0
  • half-reactions

Mg is oxidized 0 to 2
Mg ? Mg2 2e-
S is reduced 0 to -2
S 2e- ? S-2
4
electrons lost electrons gained
add half-reactions
  • Mg ? Mg2 2e-
  • S 2e- ? S-2

5
Zn 2HCl ? H2 ZnCl2
  • Zn goes from 0 to 2 oxidation
  • H goes from 1 to 0 reduction
  • Cl goes from -1 to -1 no change

6
Zn 2HCl ? H2 ZnCl2
0 1 -1 0
2 -1
  • Zn ? Zn2 2e-
  • 2H1 2e- ? H2

______________________________________
Zn 2H1 2e- ? Zn2 2e- H2
7
Balancing Redox Equations
  1. assign oxidation to all elements
  2. determine elements that changed oxidation number
  3. identify element oxidized element reduced
  4. write half-reactions (diatomics must stay as is)
  5. electrons lost/gained must be equal
    (multiply half-reactions if
    necessary)
  6. add half-reactions
    transfer co-efficients to skeleton
    equation
  7. balance rest of equation by counting atoms

8
Cu AgNO3 ? Cu(NO3)2 Ag
  • Cu goes from 0 to 2 oxidation
  • Ag goes from 1 to 0 reduction
  • N goes from 5 to 5 no change
  • O goes from -2 to -2 no change

9
Half-Reactions
  • Cu ? Cu2 2e-
  • Ag1 1e- ? Ag

multiply by 2
  • Cu ? Cu2 2e-
  • 2Ag1 2e- ? 2Ag

______________________
10
Transfer Co-efficients
  • compare skeleton equation sum of ½ rxns
  • Cu AgNO3 ? Ag Cu(NO3)2
  • vs.
  • Cu 2Ag1 2e- ? 2Ag Cu2 2e-
  • transfer co-efficients!
  • Cu 2AgNO3 ? 2Ag Cu(NO3)2

11
Cu HNO3 ? Cu(NO3)2 NO2 H2O
1
4
  • Cu 0 to 2 oxidized
  • H 1 to 1 no change
  • O -2 to -2 no change
  • N starts as 5
  • ends as 5 no change Cu(NO3)2
  • ends as 4 reduction NO2

cant just say N! sayN in HNO3 or N5
  • half-reactions
  • Cu ? Cu2 2e-
  • N5 1e- ? N4

12
  • half-reactions
  • Cu ? Cu2 2e-
  • N5 1e- ? N4

multiply half-reactions as necessary of
electrons lost gained
Cu ? Cu2 2e- 2 (N5 e- ? N4)
balance remaining atoms by inspection
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