Title: CHEM 120: Introduction to Inorganic Chemistry
1CHEM 120 Introduction to Inorganic Chemistry
- Instructor Upali Siriwardane (Ph.D., Ohio State
University) - CTH 311, Tele 257-4941, e-mail
upali_at_chem.latech.edu - Office hours 1000 to 1200 Tu Th 800-900
and 1100-1200 M,W, F
2Chapters Covered and Test dates
- Tests will be given in regular class periodsÂ
from 930-1045 a.m. on the following days - September 22,    2004 (Test 1) Chapters 1 2
- October 8,        2004(Test 2) Chapters 3,
4 - October 20,        2004 (Test 3) Chapter 5 6
- November 3,       2004 (Test 4) Chapter 7 8
- November 15,     2004 (Test 5) Chapter 9 10
- November 17,     2004 MAKE-UP Comprehensive
test (Covers all chapters - Grading
- ( Test 1 Test 2 Test3 Test4 Test5)
x.70 Homework quiz average x 0.30 Final
Average - Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5
3Chapter 5. Calculations and the Chemical Equation
5.1 The Mole Concept and Atoms The Mole and
Avogadro's Number Calculating Atoms, Moles, and
Mass 5.2 Compounds The Chemical Formula 5.3
The Mole Concept Applied to Compounds 5.4 The
Chemical Equation and The Information It Conveys
A Recipe for Chemical Change Features of a
Chemical Equation The Experimental Basis of a
Chemical Equation 5.5 Balancing Chemical
Equations 5.6 Calculations Using the Chemical
Equation General Principles Use of Conversion
Factors Theoretical and Percent Yield
Pharmaceutical Chemistry The Practical
Significance of Percent Yield
4The mole concept and atoms
- In ch 1 we learned that 1 amu 1.661 x
10-24 g - So if the average mass of a gold atom is196.97
amu x 1.661 x 10-24 g 3.27 x 10-22 g
1 amu - a very
small no.
5- Where did I get the 196.97 anu for the mass of
one Au atom? - From the ____________________!!!
- If I write amu after these nos. it implies that I
have the mass of ______ atom of that element (in
amu). - But 3.27 x 10-22 g is too small an amt to work
with in the lab. - What to do?
- Scale up to quantities that we can handle by
6Avogadros number
- Defining one mole (mol) as amt of substance that
contains as many elementary entities (atoms,
molecules, ions , etc) as there are in atoms in
exactly 12 g of the carbon-12 isotope. This is
determined experimentally and is...
7(No Transcript)
8Useful relationship
9Some problems
- How many atoms are there in 5.10 moles of sulfur?
Whats the mass of 5.10 moles of S? - How many moles of calcium atoms are in 1.16 x
1024 atoms of Ca? How many grams?
10- Which of the following has more atoms 1.10g of
hydrogen atoms or 14.7 g of chromium atoms? - How many moles are in 0.040 kg Na?
11- Whats the mass, in grams, of one atom of
potassium? - One atom of some element has a mass of 1,45 x
10-22 g. Identify the element.
12Compounds
- The chemical formula
- MgO (ion pair)
- H2O
- C12H22O11
- Ca3(PO4)2
- CuSO4.5H2O vs CuSO4
13The mole concept applied to compounds
- The formula weight of a species is the sum of
atomic masses (amu) of the atoms in a species. - Formula weight of NH3
-
- For an ionic compound
- MgF2
14Covalent Cpds ? Molecular weight ?moles ?
(Molar Mass) Ionic Cpds ? Formula weight ?
Formula units ? (Molar Mass)
- In general we talk about
- moles for covalent compounds
- formula units rather than moles of ionic
compounds.
15Molar mass
- Mass of one mole of NH3
- Mass of 6.022 x 1023 molecules of NH3 is
- Mass of one molecule of NH3 is.
16- Mass of one mole of MgF2 is
- Mass of one formula unit of MgF2 is
- Mass of 6.022 x 1023 formula units of MgF2 is
17- Calc the molar mass of Ca(NO3)2.
- Calc the molar mass of a compound if 0.372 mol of
it has a mass of 152g.
18- 5.38. How many grams of each are required to have
0.100 mol of - A. NaOH
- B. H2SO4
- C. C2H5OH
- D. Ca3(PO4)2
19- 5.40. How many moles are in 50.0 g of
- A. CS2
- B. Al2(CO3)3
- C. Sr(OH)2
- D. LiNO3
20- Calc the no. of C, H, and O atoms in 1.50 g of
glucose (C6H12O6). - What is the average mass of one C3H8 molecule?
- What is the mass of 5.00 x 1024 molecules of NH3?
21Law of conservation of mass
- Mass is neither created nor destroyed in an
ordinary chemical rxn. - Or the sum of the masses of the reactants is
equal to the sum of the masses of the products
22- mercury oxygen ---gt mercury(II)oxide
- 10.03g ? 10.83g
-
-
- Easier to use symbols for chem eqns.
23- reactants ? products
- lhs rhs
- may indicate physical state by (s), (g), (l),
(aq)-aqueous solution - Remember that H2,N2,O2,F2,Cl2,Br2,I2 occur as
diatomics in nature and are used as diatomics in
chemical eqns
24- To balance Have to have same no of each kind of
atom on both sides of the eqn. The bonding
arrangement changes, but the no of each kind of
atom doesnt change.
25(D)
26Chemical equations
- Indicate phases of reactants and products
Fe(s) 2 HBr(aq)
Conditions etc.
(s) solid
(g) gas
(l) liquid
27Balancing chemical eqns
- Use correct formulas for the reactants and
products (if word eqn at start) - Balance by putting coefficients (nos) in front of
the formulas. You may not change the formulas!
These coefficients are called the stoichiometric
(measure of mass) coefficients. - By convention use the lowest set of whole no.
coefficients to balance.
28- Start by balancing elements that appear only once
on each side of the equation - Balance remaining elements
- Check your balanced equation!
- To predict products--do an experiment
29To balance
- hydrogen nitrogen ? ammonia
- 1. write the symbols for the species in the rxn
-
30- Now figure out how to get the same no of atoms of
each kind on both sides by using whole no
coefficients in front of the species. - As H2 _N2 ? NH3, then
- H2 _N2 ? _ NH3, then
- _ H2 _N2 ? _ NH3
- Now have _ Hs, _Ns on both sides and the lowest
set of whole no coefficients have been used. The
equation is balanced.
31- 3H2 N2 ? 2NH3
- 3 mol of H2 reacts with 1 mol of N2 to form 2 mol
of NH3 - 3 molecules of H2 reacts with 1 molecule of N2 to
form 2 molecules of NH3 - 6H 2N reacts to give 6H and 2N
- 6g of H2 reacts with 28 g of N2 to form 34g of
NH3 - Note that
32Balance
- C2H6 O2 ? CO2 H2O
- H2O2 g H2O O2
- C2H5OH O2 g CO2 H2O
- KOH H3PO4 g K3PO4 H2O
- N2O5 g N2O4 O2
33Balance
- NH4NO3 g N2O H2O
- NH4NO2 g N2 H2O
- Be2C H2O g Be(OH)2 CH4
- NH3 CuO g Cu N2 H2O
34Balance
- S2Cl2(s) NH3(g) g N4S4(s) NH4Cl(s) S8(s)
35Calculations using the chemical eqn
- Quantitative study of reactants and products in a
chemical reaction - How much product will be formed?
- How much reactant is needed?
- Use coefficients in a balanced equation to
convert between moles of different substances in
a chemical reaction.
36Chemical Reaction
- 3H2(g) N2(g) ------gt 2NH3(g) Â
- 3 mol H2 (reactant) 1 mol N2 (reactant)
consumed - 3 mol H2 (reactant) 2 mol NH3 (products)
produced - 1 mol N2 (reactant) 2 mol NH3 (products)
produced - 3 x 2 (6) g H2 (reactant) 1x 28 (28)mol N2
(reactant) consumed - 3 x 2 H2 (6) (reactant) 2x 17 (34) NH3
(products) produced - 1 x 28 (28) g N2 (reactant) 2 x 17 (34) NH3
(products) produced
37Chemical reactions
- Hydrogen reacts with nitrogen to form NH3.
- theoretically it is should be that when 6 g of
hydrogen reacts completely with 28 g of
nitrogen, 34 g of ammonia is formed. - However in real chemical reactions actual __ g of
hydrogen reacting with __ g of nitrogen, __ g of
ammonia is produced need be experimentally
determined.
382H2 O2 g 2H2O
392H2 O2 g 2H2O
- How many moles of H2 is needed to completely
react with19.8 mol O2? - How many moles of H2O are formed when 25.4 mol of
H2 react?
402H2 O2 g 2H2O
- How many moles of H2 react with 38 g of O2?
- What mass of H2O is formed when 59.0g of H2
reacts completely with O2? How much O2 reacted
in this case?
41Mass relationships in chemical equations
- Mole-to-mole conversions
- use mole ratios as conversion factors
- Mass-to-mole and mole-to-mass conversions
- use molecular weights as conversion factors
- Mass-to-mass conversions
- do in multiple steps
42General prescription
43Problems
- How many grams of Al2O3 can be produced from 15.0
g Al? - 4 Al(s) 3O2(g) g 2Al2O3(s)
44- C3H8 O2 ? CO2 H2O balance
- How many mol of O2 does it take to completely
burn 7.0 mol of C3H8? - How many mol each of CO2 and H2O are produced?
- How many grams of oxygen does it take to
completely burn 25.0 g of C3H8? - How many grams each of CO2 and H2O are produced
when 25.0 g of C3H8 is burned?
45- A 4.00 g sample of Fe3O4 reacts with O2 to
produce Fe2O3. - 4Fe3O4(s) O2(g)g 6Fe2O3(s)
- Determine the no. of grams of Fe2O3 produced.
46Theoretical and percent yield
- How good an experimentalist are you?
- What if 100 of reactants are not converted to
desired products? - Frequently happens because of side reactions
(other products), handling, etc. - 100 amount is theoretical yield
- Amount obtained is actual yield
47- Theoretical yield - amount of product that would
result if all limiting reagent gave only product - Actual yield - the amount of product actually
obtained from a reaction (almost always less than
the theoretical yield) - Percent yield - calculated by
- yield actual yield ? 100
- theoretical yield
48- Theoretical yield is what we calculate assuming
100 conversion of reactants to products. - In the combustion of 33.5g of C3H6, 16.1 g of H2O
is isolated. What is the percent yield?
49- If the yield of Fe2O3 in problem was 90.0 what
was the actual yield of Fe2O3?
50- A 3.5 g sample of water reacts with PCl3
according to 3H2O PCl3 g H3PO3 3HCl. - How many grams of H3PO3 are produced?