12.3 Surface Area of Pyramids and Cones - PowerPoint PPT Presentation

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12.3 Surface Area of Pyramids and Cones

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12.3 Surface Area of Pyramids and Cones Objectives/Assignment Find the surface area of a pyramid. Find the surface area of a cone. Assignment: 2-36 even Finding the ... – PowerPoint PPT presentation

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Title: 12.3 Surface Area of Pyramids and Cones


1
12.3 Surface Area of Pyramids and Cones
2
Objectives/Assignment
  • Find the surface area of a pyramid.
  • Find the surface area of a cone.
  • Assignment 2-36 even

3
Finding the surface area of a pyramid
  • A pyramid is a polyhedron in which the base is a
    polygon and the lateral faces are triangles with
    a common vertex. The intersection of two lateral
    faces is a lateral edge. The intersection of the
    base and a lateral face is a base edge. The
    altitude or height of a pyramid is the
    perpendicular distance between the base and the
    vertex.

4
More on pyramids
  • A regular pyramid has a regular polygon for a
    base and its height meets the base at its center.
    The slant height of a regular pyramid is the
    altitude of any lateral face. A nonregular
    pyramid does not have a slant height.

5
Pyramid Arena
6
Ex. 1 Finding the Area of a Lateral Face
  • Architecture. The lateral faces of the Pyramid
    Arena in Memphis, Tennessee, are covered with
    steal panels. Use the diagram of the arena to
    find the area of each lateral face of this
    regular pyramid.

7
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8
Hexagonal Pyramids
  • A regular hexagonal pyramid and its net are shown
    at the right. Let b represent the length of a
    base edge, and let l represent the slant height
    of the pyramid. The area of each lateral face is
    1/2bl and the perimeter of the base if P 6b.
    So the surface area is as follows

9
Hexagonal pyramid
S (Area of base) 6(Area of lateral face)
S B 6( ½ bl)
Substitute
Rewrite 6( ½ bl) as ½ (6b)l.
S B (6b)l
Substitute P for 6b
S B Pl
Surface Area of a Regular Pyramid
The surface area S of a regular pyramid is S B
½ Pl, where B is the area of the base, P is the
perimeter of the base, and l is the slant height.
10
Ex. 2 Finding the surface area of a pyramid
  • To find the surface area of the regular pyramid
    shown, start by finding the area of the base.
  • Use the formula for the area of a regular
    polygon,
  • ½ (apothem)(perimeter). A diagram of the base is
    shown to the right.

11
Ex. 2 Finding the surface area of a pyramid
  • After substituting, the area of the base is ½ (3
    )(6 6), or
  • square meters.

12
Surface area
  • Now you can find the surface area by using 54
    for the area of the base, B.

13
Finding the Surface Area of a Cone
  • A circular cone, or cone, has a circular base and
    a vertex that is NOT in the same plane as the
    base. The altitude, or height, is the
    perpendicular distance between the vertex and the
    base. In a right cone, the height meets the base
    at its center and the slant height is the
    distance between the vertex and a point on the
    base edge.

14
Finding the Surface Area of a Cone
  • The lateral surface of a cone consists of all
    segments that connect the vertex with points on
    the base edge. When you cut along the slant
    height and like the cone flat, you get the net
    shown at the right. In the net, the circular
    base has an area of ?r2 and the lateral surface
    area is the sector of a circle.

15
More on cones . . .
  • You can find the area of this sector by using a
    proportion, as shown below.

Area of sector
Arc length

Set up proportion
Area of circle
Circumference
2?r
Area of sector
Substitute

?l2
2?l
2?r
Multiply each side by ?l2
Area of sector ?l2
2?l
Area of sector ?rl
Simplify
?The surface area of a cone is the sum of the
base area and the lateral area, ?rl.
16
Theorem
  • Surface Area of a Right Cone
  • The surface area S of a right cone is S ?r2
    ?rl, where r is the radius of the base and l is
    the slant height

17
Ex. 3 Finding the surface area of a cone
  • To find the surface area of the right cone shown,
    use the formula for the surface area.

S ?r2 ?rl
Write formula
S ?42 ?(4)(6)
Substitute
S 16? 24?
Simplify
S 40?
Simplify
?The surface area is 40? square inches or about
125.7 square inches.
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