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6.1 Solving One-Step Linear Inequalities x 8 > 1

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6.1 Solving One-Step Linear Inequalities x + 8 1 6.2 Solving Multi-step Linear Inequalities 5x 3 12 6.3 Solving Compound Inequalities -5 – PowerPoint PPT presentation

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Title: 6.1 Solving One-Step Linear Inequalities x 8 > 1


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6.1 Solving One-Step Linear Inequalities x 8 gt
1 6.2 Solving Multi-step Linear Inequalities 5x
3 gt 12 6.3 Solving Compound Inequalities -5lt2x
3 lt 7 6.4 Solving Absolute-value Equations and
Inequalities x-48 5x13 14 6.5 Graphing
Linear Inequalities in Two Variables
Graph x y gt 3
2
6.6 Stem and leaf plots mean, median, mode
6.7 Box and whisker plots
3
  • Ch 7 Systems of Linear Equations and Inequalities

November 28 A 7.1 29 A 7.2 30 H 7.3 December 1 D 7.3 2 A Quiz 7.1-7.3 new7.4
5 A 7.4 6 Penance Service 7.5 7 Penance Service 7.6 8 Mass 7.6 review 9 A
12 A Chapter Review 13 A Chapter 7 Test 14 H Review for final 15 D Review for final 16 A Review for final
21 Final Exam Ch 1-7        
Due Tuesday 11/29 7.1 p401 12,16,18,
22,26,36,44 Due Wednesday 11/30 7.2 p408-411
14,16,18,20, 26, 30,35,44,48-51 Due
Thursday 12/1 7.3 p414 8, 14, 18, 24, 26, 30,
36, 40, 44 Due Friday 12/2 7.3 p414 45-52, 56
p417 1-9
4
7.1 Solving systems of linear equations by
graphing Graph-Estimate-Check












y3x-12 and y-2x3
(3,-3)
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7.1 p401 12,16,18, 22,26,36,44
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7.1 Solving a System of Linear Equations by
Graphing 7.2 Solving a System of Linear Equations
by Substitution
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Solve by Substitution 3xy5 and 2x-y10
(3,-4)
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Solve by Substitution 2x6y15 and x2y
(3,3/2)
18
Solve by Substitution x2y4 and xy-7
(6,-1)
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Homework p408-411 14,16,18,20, 26,
30,35,44,48-51
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7.1 Solving a System of Linear Equations by
Graphing 7.2 Solving a System of Linear Equations
by Substitution 7.3 Solving Linear Systems by
Linear Combination Solving by graphing can be
challenging Substitution is easier than graphing,
but sometimes it is not easy to isolate the
variable. lets try Linear Combination -x2y-8
x6y-16 x6y-16 8y-24 y-3 To
find x, plug in -3 into one of the
equations x6(-3) -16 x-18-16 x2
solution (2, -3) Check -22(-3)-8
27
Solve by linear combination3x-6y -12 -x3y6
3x -6y -12 -3x9y 18 (multiply each term by
3) 3y6 y2 To find x
3x-6(2) -12 3x0
x0 Check -(0) 3(2) 6
3(0)-6(2)-12 Solution (0,2)
Solve by linear combination 5x-4y3 2x8y-2
2(5x)-2(4y) 2(3) (multiply first equation
by 2 to get
ys to cancel) 10x -8y 6 2x 8y
-2 12x 4 x 1/3 To find y 2(1/3)8y -2 2/3
8y -2 8y-2 2/3 8y -8/3 y-1/3 Check 5(1/3)
-4(-1/3) 3 2(1/3) 8(-1/3)
-2 Solution (1/3, -1/3)
28
Solve by linear combination 2u4v8 3v5u-13
2u-4v8 -5u3v -13 (reorganize so variables
on same side) 10u 20v 40 (to get u to
cancel, multiple top equation by 5) -10u 6v
-26 (to get u to cancel, multiple bottom
equation by 2) -14v14
v-1 2u4(-1)8 (to find u, plug in
v-1 into one of the equations) 2u4 u2 Check
2(2)4(-1)8 3(-1)5(2)-13 Solution
(u,v)(2, -1)
29
2. When the 2nd equation was multiplied by -2,
4y(-2) is not8y
3. When adding 9x7x, it is not2x
30
3x 6 (add equations, ys cancel) x 2 2-y2
(insert 2 for x in 2nd equation) -y0 so
y0 Check 3(2) 6 and 2-02 Solution (2, 0)
-1/2g 4 (add equations, hs cancel) g-8
(solve for g) (1/2)(-8)h2 (insert -8 for g
in 1st equation) -4h2 h6 Check
(1/2)(-8)62 -(-8)-62 Solution (-8, 6)
7.3 p414 8, 14, 18, 24, 26, 30, 36, 40, 44
31
-x-3y-3 (multiply 1st equation by -1) x6y3
3y0 y0 x3(0)3 (insert 0 for y in 1st
equation) x3 Check 33(0)3 36(0)3 Solution
(3,0)
9x -3z 20 -9x-18z-6 (multiply 2nd equation by
-3) -21z14 z-2/3 9x-3(-2/3)20 (insert
-2/3 for z in 1st equation) 9x220 9x18
x2 Check 9(2)-3(-2/3)20
3(2)6(-2/3)2 Solution (2, -2/3)
7.3 p414 8, 14, 18, 24, 26, 30, 36, 40, 44
32
3b 2c46 -3b-15c-33 (multiply 2nd equations by
-3) -13c13 c-1 3b2(-1)46 3b48
b16 Check 3(16)2(-1)46
5(-1)1611 Solution (16, -1)
0.1g-h-4.3 (subtract -4.3 from both
sides) -0.2gh3.6 (reorganize multiply by
-1) -0.1g-0.7 g7 0.1(7)-h4.30 (insert 7 for
g in 1st equation) .7-h4.30 5h Check
0.1(7)-54.30 3.6-0.2(7)5 Solution
(7,5)
7.3 p414 8, 14, 18, 24, 26, 30, 36, 40, 44
33
Solve by linear combination
4ab0 (reorganize 1st equation) 1a-b5
(reorganize 2nd equation) 5a5 a1 3(1)9b8b-1
(insert 1 for a in 1st equation) 4-b
b-4 Check 3(1)9(-4)8(-4)-1
5(1)-10(-4)4(1)-9(-4)5 Solution (1,-4)
1.5v-6.5w3.5 -1.5v-6w9 (multiply 2nd equation
by -3) -12.5w12.5 w-1 0.5v2(-1)-3 0.5v-
2-3 0.5v-1 v-2 Check 1.5(-2)-6.5(-1)3.5
0.5(-2)2(-1)-3 Solution (-2,-1)
34
y(9/7) x y-3x12 7y9x (multiplied 1st
equation by 7) -7y21x-84 (multiplied 2nd
equation by -7) 030x-84 30x84
x14/5 y-3(14/5)12 -8 2/5 12 3 3/5
solution (14/5, 18/5) Check 18/5 (9/7)
(14/5) 18/5 -3(14/5) 12
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  • sspeed in still air
  • wwind speed
  • s-w 300
  • sw450
  • 2s750
  • s375
  • If s375, then 375-w300
  • w75
  • Check 375-75300
  • 37575450
  • 375mph speed of plane
  • 75mph speed of wind

p414 45-52, 56 p417 1-9
36
48) boat traveled upstream 8 miles in 1 hour
boat traveled downstream 8 miles in ½ hour
b-w8 boat speed-speed of water 8 mph
bw16 boat speed speed of water16
mph 2b24 b12
w4 Boat was traveling at 12 mph, water was
going 4mph.
p414 45-52, 56 p417 1-9
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Quiz Prep












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  • Ch 7 Systems of Linear Equations and Inequalities

November 28 A 7.1 29 A 7.2 30 H 7.3 December 1 D 7.3 2 A Quiz 7.1-7.3 new7.4
5 A 7.4 6 Penance Service 7.5 7 Penance Service 7.6 8 Mass 7.6 review 9 A
12 A Chapter Review 13 A Chapter 7 Test 14 H Review for final 15 D Review for final 16 A Review for final
21 Final Exam Ch 1-7        
Due Monday 12/5 7.4 p421 12, 20, 28, 42, 48
chapter 1 summary p54-56 Due Tuesday 12/6 7.5
p429 12-17,18,24,30,43-46 chapter 2 review Due
Wednesday 12/7 7.6 p435 9-14, 26 chapter 3
review Due Thursday 12/8 7.6 p435 37,43
chapter 4 review Due Friday 12/9 chapter
7 review p440 2-32 (pick one in each section)
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7.4 Applications of Linear Systems
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What would you use to solve this system of
equations? Why?
48
Crcp32.75 Cpcr.2
Total cost regular total cost premium
32.75 Cost premium cost regular .2 Regular
gas amount (cost) premium gas amount
(cost)32.75 10c 15(c.20) 32.75 25c 3
32.75 25c 29.75 c1.19 cost for regular,
1.39 cost for premium To check 10(1.19)
15(1.19.20)32.75
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2x y 3 2x - 3 y 4x 3(2x-3) 21 4x 6x
9 21 10x 30 x 3 4(3) 3y 21 12 3y
21 3y 9 y 3 (3,3) Check 2(3) -3 3 4(3)
3(3) 21
50
-x -2y -2 (multiply 1st equation by -1) x
4y -2 2y -4 y -2 x 2(-2) 2
x6 (6, -2) Check 6 2(-2) 2 6 4 (-2)
-2
51
-41.5x-2.5y8.5 multiply 1st equation by
-4 -6x10y-34 6x30y24 (add both equations to
cancel xs) 40y-10 y
-.25 6x30 (-.25)24 6x-7.5 24 6x 31.5 x 5.25
?(5.25, -.25) Check 1.5 (5.25)-2.5(-.25)8.5
6(5.25)30(-.25)24 Solution (5.25,
-.25)
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Year Hemlock(4) Spruce (6)
0 14 8
1 18 14
2 22 20
3 26 26
4 30 32





14


8



(3,26)
y4x14
y4x 14 y6x 8 6x84x14 (substitution) 2x6
x3 (at 3 years they are equal) y4(3)1426
inches
y6x8
1 2 3
4 5
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Chapter 1 Summary http//www.classzone.com/books/a
lgebra_1/
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2 equations, same slope, different yintercepts,
no solution
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2 equations, same slope, same yintercepts,
infinite of solutions
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7.5 p429 12-17,18,24,30,43-46 chapter 2 review
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Weight of necklace weight of 30 small beads
weight of 6 large beads Weight of bracelet
weight of 10 small beads weight of 2 large
beads 3.6 30x 6y 1.2 10x 2y -3.6-30x-6y
(multiply 2nd equation by -3) 00 They are
equivalent equations, so we cannot use them to
solve the problem.
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Chapter 2 Summary http//www.classzone.com/books/a
lgebra_1/
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7.6 p435 9-14, 26 chapter 3 review
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