Title: ChE 551 Lecture 11
1ChE 551 Lecture 11
- Review Of Statistical Mechanics
2Last Time We Started Stat Mech To Estimate
Thermodynamic Properties
- All thermodynamic properties are averages.
- There are alternative ways to compute the
averages state averages, time averages, ensemble
averages. - Special state variables called partition
functions.
3Properties Of Partition Functions
- The partition functions are like any other state
variable. - The partition functions are completely defined if
you know the state of the system. - You can also work backwards, so if you know the
partition functions, you can calculate any other
state variable of the system.
4Properties Of Partition Functions
- Assume m independent normal modes of a molecule
- qmolecular partition function
- qnpartition function for an individual mode
- gndegeneracy of the mode
5How Many Modes Does A Molecule Have?
- Consider molecules with N atoms
- Each atom can move in x, y, z direction
- ? 3N total modes
- The whole molecule can translate in x, y, z
- ? 3 Translational modes
- Non linear molecules can rotate in 3 directions
- ?3 rotational modes
- 3N-6 Vibrational modes
- Linear molecules only have 2 rotational modes
- 3N-5 vibrational modes
6Equations For Molecular Partition Function
7Equations For The Partition Function For
Translational, Rotational, Vibrational Modes And
Electronic Levels
qt?1-10?/ax
q
1
qt3?106-107
qr2?102-104
Where Sn is symmetry number
8Key Equations Continued
Rotation of a nonlinear
qr3?104-105
molecule with a
?
?
3
4
5
q
10
10
r
moment of inertia of I
a
,
I
, I
, about three
b
c
orthogona
l axes
qv?1-3
Vibration of a harmonic
?
?
q
1
3
v
oscillator when energy
levels are measured
where ?
is the
relative to the harmonic
vibrational frequency
oscillators zero point
energy
?
?
?
E
Electronic Level
?
?
?
?
q
exp
e
?
?
?
?
??
T
q
E)
exp(
?
(Assuming That the
B
e
Levels Are Widely
Spaced)
9Table 6.7 Simplified Expressions For Partition
Functions
Type of Mode Partition Function Partition Function after substituting values of kB and hp
Average velocity of a molecule
Translation of a molecule in thre dimensions (partition function per unit volue
Rotation of a linear molecule
Rotation of a nonlinear molecule
Vibration of a harmonic oscillator
6
10Example 6.C Calculate The Partition Function For
HBr At 300K
11How Many Modes In HBr
- Total Modes 6
- Translations 3
- Rotations 2
- Leaves 1 vibration
12The Translational Partition Function
From Pchem Where qt is the translational
partition function per unit volume, mg is the
mass of the gas atom in amu, kB is Boltzmanns
constant, T is temperature and hp is Planks
constant
6.C.1
13Simplification Of Equation 6.3.1
(6.C.2)
(6.C.3)
Combining 6.C.2 and 6.C.3
3
14Solution Continued
- Equation 6.C.4 gives qt recall mg81 AMU, T300K
3
3
(6.C.5)
15The Rotational Partition Function
- From P-chem for a linear molecule
kB
(6.C.6)
kB
Derivation
Algebra yields
16Derivation Of Simplified Function
(6.C.7)
(6.C.8)
(6.C.9)
17Calculation of Rotation Function Step Calculate
I
(6.C.10)
?
(6.C.13)
18Step 2 Calculate qr2
- Substituting in I from equation (6.C.13) and Sn
1 into equation 6.C.9 yields
(6.C.14)
19The Vibrational Partition Function
(6.C.15) where qv is the vibrational partition
function, hp is Planks constant ? is the
vibrational frequency, kB is Boltzmanns constant
and T is temperature. Note
Derivation
20Simplified Expression For The Term In The Exponent
(6.C.16)
(6.C.17)
Therefore
(6.C.18)
21Evaluation Of h? For Our Case
(6.C.19)
Substituting
(6.C.19)
(6.C.15)
(6.C.20)
22Summary
- qT843/ , qr24.4 qv1
- Rotation and translation much bigger than
vibration -
23Example Calculate The Molecular Velocity Of HBr
Derivation
24Derivation Of Expression For Molecular Velocities
- Use the classical partition function (replace
sums by integrals). The expectation value of the
molecular velocity, ?v?, is given by
(6.B.1)
25Solution Cont
- Consider a single molecule whose energy is
independent of position. Substituting momentum p
mass times the velocity, and canceling out all
of the excess integrals yields
(6.B.2)
26Next Substitute For U
(6.B.3)
(6. B.5)
27Performing The Algebra Noting ? 1/kBT Yields
P-Chem expression for molecular velocity
(6. B.8)
28Simplified Expression
29Next Derive Adsorption Isotherm
- Consider adsorption on a surface with a number of
sites - Ignore interactions
- Calculate adsorption concentration as a function
of gas partial pressure
30Solution Method
- Derive an expression for the chemical potential
of the adsorbed gas as a function of the gas
concentration - Calculate canonical partition function
- Use AkBT ln(Qcanon) to estimate chemical
potential - Derive an expression for the chemical potential
of a gas - Equate the two terms to derive adsorption
isotherm
31Solution Step 1 Calculate The Canonical
Partition Function
- According to equation (6.72),
- qPartition for a single adsorbed molecule on a
given site - gathe number of equivalent surface
arrangements.
32Step 1A Calculate ga
- Consider Na different (e.g., distinguishable)
molecules adsorbing on So sites. The first
molecule can adsorb on So sites, the second
molecule can adsorb on (So-1) sites, etc.
Therefore, the total number of arrangements is
given by
(6.83)
33Next Now Account For Equivalent
- If the Na molecules are indistinguishable,
several of these arrangements are equivalent. - Considering the Na sites which hold molecules.
If the first molecule is on any Na of these
sites, and the second molecule is on any Na-1 of
those sites, etc., the arrangement will be
equivalent. The number of equivalent
arrangements is giving by Na(Na-1)(Na-2)1Na! - (6.84)
- Therefore, the total number of inequivalent
arrangements will be given by - (6.85)
34Step 1b Combine To Calculate
- Combining equations (6.72) and (6.85)
- (6.86)
- where qa is the molecular partition function for
an adsorbed molecule.
35Step 2 Calculate The Helmholtz Free Energy
- The Helmholtz free energy at the layer, As is
given by -
- (6.87)
- Combining equations (6.86) and (6.87) yields
-
-
- (6.88)
kB
kB
36Use Stirlings Approximation To Simplify Equation
(6.88).
For any X. If one uses equation (6.89) to
evaluate the log terms in equation (6.88), one
obtains
kB
(6.90)
37Step 3 Calculate The Chemical Potential Of The
Adsorbed Layer
- The chemical potential of the layer, µs is
defined by - (6.91)
- substituting equation (6.90) into equation (6.91)
yields - (6.92)
kB
38Step 4 Calculate The Chemical Potential For The
Gas
- Next, lets calculate µs, the chemical potential
for an ideal gas at some pressure, P. Lets
consider putting Ng molecules of A in a cubic box
that has longer L on a side. If the molecules
are indistinguishable, we freeze all of the
molecules in space. Then we can switch any two
molecules, and nothing changes.
39Step 4 Continued
- There are Ng! ways of arranging the Ng molecules.
Therefore, -
- (6.93)
- substituting equation (6.93) into equation
(6.91) yields -
-
- (6.94)
- where Ag is the Helmholtz free energy in the gas
phase, and qg is the partition function for the
gas phase molecules.
40Lots Of Algebra Yields
kB
(6.95)
41Step 5 Set ?g ?a To Calculate How Much Adsorbs
- Now consider an equilibrium between the gas phase
and the adsorbed phase. At equilibrium - (6.96)
- substituting equation (6.92) and (6.95) into
equation (6.96) and rearranging yields - Taking the exponential of both sides of Equation
(6.97)
(6.97)
(6.98)
42Note That Na Is The Number Of Molecules In The
Gas Phase
- Na is the number of adsorbed molecules and
(So-Na) is the number of bare sites.
Consequently, the left hand side of equation
(6.98) is equal to KA, the equilibrium constant
for the reaction - Consequently
(6.99)
(6.100)
43If we want concentrations, we have to divide all
of the terms by volume
Partition function per unit volume
Memorize this equation
44Table 6.7 Simplified Expressions For Partition
Functions
Type of Mode Partition Function Partition Function after substituting values of kB and hp
Average velocity of a molecule
Translation of a molecule in thre dimensions (partition function per unit volue
Rotation of a linear molecule
Rotation of a nonlinear molecule
Vibration of a harmonic oscillator
6
45Summary
- Can use partition functions to calculate
molecular properties - Be prepared to solve an example on the exam
46Question
- What did you learn new today