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11.2 Reaction Rate and Concentration

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11.2 Reaction Rate and Concentration YOU ARE EXPECTED TO BE ABLE TO: Define the initial rate of a reaction as the instantaneous rate at the start of the reaction. – PowerPoint PPT presentation

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Title: 11.2 Reaction Rate and Concentration


1
11.2 Reaction Rate and Concentration
  • YOU ARE EXPECTED TO BE ABLE TO
  • Define the initial rate of a reaction as the
    instantaneous rate at the start of the reaction.
  • Write a rate law expression for a given reaction
    given experimental results that show the
    variation of initial rate with concentration.
  • Define the concept of order of reaction and
    determine the order of a given reaction from
    initial rate vs concentration data

2
Initial Rate of Reaction
  • The initial rate of reaction is the instantaneous
    rate measured at the start of the reaction
  • The initial rate can be used as a benchmark
  • Measurements of the initial rate for a reaction
    at different starting concentrations can be used
    to determine the effect of concentration on rate

3
The Rate Expression or Rate Law
  • In general
  • Reactions occur as a result of collisions
  • The higher the concentration of molecules, the
    greater the rate
  • In some reactions, the rate is directly
    proportional to the concentration
  • In other cases, the rate may increase much more
    quickly than the concentration
  • The relationship between rate and concentration
    is known at the rate law or rate expression

4
Determining the Rate Law Expression
  • The rate law MUST be determined from experiment
    it is not related to the stoichiometry of the
    equation for the reaction
  • Examine the concentration vs time graph for N2O5
  • Determine instantaneous rates at different times
    and concentrations of N2O5
  • Plot instantaneous rate vs N2O5
  • This is a straight line, (equation y mx b)
  • Rate kN2O5 this is the rate law expression
    k is the rate constant

5
Using Initial Rates to determine the rate Law
  • Measurements of the initial rate of reaction at
    different initial concentrations can be used to
    determine the rate law expression
  • If a graph of initial concentration vs initial
    rate is a straight line, then rate is directly
    proportional to concentration
  • rate k reactant
  • If a graph is a curve, then rate kreactantm

6
Order of Reaction
  • The rate law expression is of the form
  • Rate kAm
  • The power to which the concentration is raised is
    called the order of reaction
  • If m 0, then zero order
  • If m 1, then first order
  • If m 2, then second order

7
Calculating the Order of Reaction when there is
One Reactant
  • If m is not equal to 1, the order of the reaction
    can be determined by comparing two rates at two
    different concentrations
  • Rate1 kA1m
  • Rate2 kA2m
  • Rate1 kA1m A1 m
  • Rate2 kA2m A2

8
Example 11.1
  • CH3CHO(g) ? CH4(g) CO(g)
  • 0.10M 0.20M 0.30M
    0.40M
  • Rate (mol/L.s) 0.085 0.34 0.76
    1.4
  • Choose the first two concentrations
  • Rate2 0.34 4.0
  • Rate1 0.085
  • CH3CHO2 0.20 2.0
  • CH3CHO1 0.10
  • 4.0 (2.0)m m 2
  • Rate kCH3CHO2 The reaction is second order

9
Calculate the Rate Constant
  • Rate kCH3CHO2
  • Choose one set of data
  • 0.085mol/L.s k x (0.10 mol/L)2
  • k 0.085mol/L.s 8.5 L/mol.s
  • (0.10 mol/L)2

10
Order of Reaction with More Than One Reactant
  • Most reactions involve gt1 reactant
  • aA bB ? products
  • General rate law expression is
  • rate kAm x Bn
  • m is order with respect to A
  • n is order with respect to B
  • Overall order is m n

11
Determining the Order
  • Hold concentration of one reactant constant and
    vary other - measure initial rate
  • Repeat, holding concentration of other reactant
    constant
  • See Example 11.2, page 308

12
Determining the Order of Reaction Graphically
  • As an alternative to calculating the order of
    reaction by comparing two pieces of data, a
    graphical process can be used
  • Plot rate vs concentration
  • If the result is a straight line, there is a
    first order reaction, slope k
  • If the result is a curve, it is necessary to
    construct a graph of (natural) log rate vs
    (natural) log concentration to determine m

13
Why Use a Logarithm?
  • If rate kAm
  • Then ln rate ln k m ln a
  • This will be a straight line with slope m

14
Zero Order Reactions
  • In rare cases, the rate of reaction is
    independent of the concentration of reactant(s)
  • In these cases
  • Rate kA0
  • A plot of rate vs A would be a horizontal
    straight line
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