4. The Postulates of Quantum Mechanics - PowerPoint PPT Presentation

About This Presentation
Title:

4. The Postulates of Quantum Mechanics

Description:

4. The Postulates of Quantum Mechanics 4A. Revisiting Representations Recall our position and momentum operators P and R They have corresponding eigenstate r and k – PowerPoint PPT presentation

Number of Views:835
Avg rating:3.0/5.0
Slides: 31
Provided by: WakeFo60
Learn more at: http://users.wfu.edu
Category:

less

Transcript and Presenter's Notes

Title: 4. The Postulates of Quantum Mechanics


1
4. The Postulates of Quantum Mechanics
4A. Revisiting Representations
  • Recall our position and momentum operators R and
    P
  • They have corresponding eigenstate r and k
  • If we measure the position of a particle
  • The probability of finding it at r is
    proportional to
  • If it is found at r, then afterwards it is in
    state
  • If we measure the momentum of a particle
  • The probability of momentum ?k is proportional to
  • After the measurement, it is in state
  • This will generalize to any observable we might
    want to measure
  • When we arent doing measurements, we expect
    Schrödingers Equation to work

2
4B. The Postulates
Vector Space and Schrödingers Equation
Postulate 1 The state vector of a quantum
mechanical system at time t can be described as a
normalized ket ?(t)? in a complex vector space
with positive definite inner product
  • Positive definite just means
  • At the moment, we dont know what this space is

Postulate 2 When you do not perform a
measurement, the state vector evolves according
to where H(t) is an observable.
  • Recall that observable implies Hermitian
  • H(t) is called the Hamiltonian

3
The Results of Measurement
Postulate 3 For any quantity that one might
measure, there is a corresponding observable A,
and the results of the measurement can only be
one of the eigenvalues a of A
  • All measurements correspond to Hermitian
    operators
  • The eigenstates of those operators can be used as
    a basis

Postulate 4 Let a,n? be a complete
orthonormal basis of the observable A, with
Aa,n? aa,n?, and let ?(t)? be the state
vector at time t. Then the probability of
getting the result a at time t will be
  • This is like saying the probability it is at r is
    proportional to ?(r)2

4
The State Vector After You Measure
Postulate 5 If the results of a measurement of
the observable A at time t yields the result a,
the state vector immediately afterwards will be
given by
  • The measurement is assumed to take zero time
  • THESE ARE THE FIVE POSTULATES
  • We havent specified the Hamiltonian yet
  • The goal is not to show how to derive the
    Hamiltonian from classical physics, but to find a
    Hamiltonian that matches our world

5
Comments on the Postulates
  • I have presented the Schrödinger picture with
    state vector postulates with the Copenhagen
    interpretation
  • Other authors might list or number them
    differently
  • There are other, equally valid ways of stating
    equivalent postulates
  • Heisenberg picture
  • Interaction picture
  • State operator vs. state vector
  • Even so, we almost always agree on how to
    calculate things
  • There are also deep philosophical differences in
    some of the postulates
  • More on this in chapter 11

6
Continuous Eigenvalues
  • The postulates as stated assume discrete
    eigenstates
  • It is possible for one or more of theselabels to
    be continuous
  • If the residual labels are continuous, just
    replace sums by integrals
  • If the eigenvalue label is continuous, the
    probability of getting exactly ? will be zero
  • We need to give probabilities that ? lies in some
    range, ?1 lt ? lt ?2.
  • We can formally ignore this problem
  • After all, all actual measurements are to finite
    precision
  • As such, actual measurements are effectively
    discrete (binning)

7
Modified Postulates for Continuous States
Postulate 4b Let ?,?? be a complete
orthonmormal basis of the observable A, with
A?,?? ??,??, and let ?(t)? be the state
vector at time t. Then the probability of
getting the result ? between ?1 and ?2 at time t
will be
Postulate 5b If the results of a measurement of
the observ-able A at time t yields the result ?
in the range ?1 lt ? lt ?2, the state vector
immediately afterwards will be given by
8
4C. Consistency of the Postulates
Consistency of Postulates 1 and 2
  • Postulate 1 said the state vector is always
    normalized postulate 2 describes how it changes
  • Is the normalization preserved?
  • Take Hermitian conjugate
  • Mulitply on left and right to make these
  • Subtract

9
Consistency of Postulates 1 and 5
  • Postulate 1 said the state vector is always
    normalized postulate 5 des-cribes how it changes
    when measured
  • Is the normalization preserved?

10
Probabilities Sum to 1?
  • Probabilities must be positive and sum to 1

Postulate 4 Independent of Basis Choice?
  • Yes

Postulate 5 Independent of Basis Choice?
  • Yes

11
Sample Problem
A system is initially in the state When S2 is
measured, (a) What are the possible outcomes and
corresponding probabilities, (b) For each outcome
in part (a), what would be the final state vector?
  • We need eigenvalues and eigenvectors

12
Sample Problem (2)
(b) For each outcome in part (a), what would be
the final state vector?
  • If 0
  • If 2?2

13
Comments on State Afterwards
  • The final state is automatically normalized
  • The final state is always in an eigenstate of the
    observable, with the measured eigenvalue
  • If you measure it again, you will get the same
    value and the state will not change
  • When there is only one eigenstate with a given
    eigenvalue, it must be that eigenvector exactly
  • Up to an irrelevant phase factor

14
4D.Measurement and Reduction of State Vector
How Measurement Changes Things
  • Whenever you are in an eigenstate of A,
    and you measure A, the results are
    certain, and the measurement doesnt change the
    state vector
  • Eigenstates with different eigenvalues are
    orthogonal
  • The probability of getting result a is then
  • The state vector afterwards will be
  • Corollary If you measure something twice, you
    get the same result twice, and the state vector
    doesnt change the second time

15
Sample Problem
  • We need eigenvalues and eigenvectors for both
    operators
  • Eigenvalues for both are ? ½?

A single spin ½ particle is described by a
two-dimensional vector space. Define the
operators The system starts in the state If
we successively measure Sz, Sz, Sx, Sz, what are
the possible outcomes and probabilities, and the
final state?
  • It starts in an eigenstate of Sz
  • So you get ½ ?, and eigenvector doesnt change

100
100
16
Sample Problem (2)
If we successively measure Sz, Sz, Sx, Sz, what
are the possible outcomes and probabilities, and
the final state?
  • When you measure Sx next, we find that the
    probabilities are
  • Now when you measure Sz, the probabilities are

50
50
50
50
50
50
17
Commuting vs. Non-Commuting Observables
  • The first two measurements of Sz changed nothing
  • It was still in an eigenstate of Sz
  • But when we measured Sx, it changed the state
  • Subsequent measurement of Sz then gave a
    different result
  • The order in which you perform measurements
    matters
  • This happens when operators dont commute, AB ?
    BA
  • If AB BA then the order you measure doesnt
    matter
  • Order matters when order matters
  • Complete Sets of Commuting Observables (CSCOs)
  • You can measure all of them in any order
  • The measurements identify ?? uniquely up to an
    irrelevant phase

18
4E. Expectation Values and Uncertainties
Expectation values
  • If you measure A and get possible eigenvalues
    a, the expectation value is
  • There is a simpler formula
  • Recall
  • The old way of calculating expectation value of
    p
  • The new way of calculating expectation value of p

19
Uncertainties
  • In general, the uncertainty in a measurement is
    the root-mean-squared difference between the
    measured value and the average value
  • There is a slightly easier way to calculate this,
    usually

20
Generalized Uncertainty Principle
  • We previously claimed
    and we will now prove it
  • Let A and B be any two observables
  • Consider the following mess
  • The norm of any vector is positive
  • The expectation values are numbers, they commute
    with everything
  • Now substitute
  • This is two true statements, the stronger one
    says

21
Example of Uncertainty Principle
  • Lets apply this to a position and momentum
    operator
  • This provides no useful information unless i j.

Sample Problem
Get three uncertainty relations involving the
angular momentum operators L
22
4F. Evolution of Expectation Values
General Expression
  • How does ?A? change with time due to
    Schrödingers Equation?
  • Take Hermitian conj. of Schrödinger.
  • The expectation value will change
  • In particular, if the Hamiltonian doesnt depend
    explicitly on time

23
Ehrenfests Theorem Position
  • Suppose the Hamiltonian is given by
  • How do ?P? and ?R? change with time?
  • Lets do X first
  • Now generalize

24
Ehrenfests Theorem Momentum
  • Lets do Px now
  • Generalize
  • Interpretation
  • ?R? evolution v p/m
  • ?P? evolution F dp/dt

25
Sample Problem
The 1D Harmonic Oscillator has Hamiltonian Calc
ulate ?X? and ?P? as functions of time
  • We need 1D versions of these
  • Combine these
  • Solve it
  • A and B determined by initial conditions

26
4G. Time Independent Schrödinger Equation
Finding Solutions
  • Before we found solution when H was independent
    of time
  • We did it by guessing solutions with separation
    of variables
  • Left side is proportional to ??, right side is
    independent of time
  • Both sides must be a constant times ??
  • Time Equation is not hard to solve
  • It remains only to solve the time-independent
    Schrödinger Equation

27
Solving Schrödinger in General
  • Given ?(0)?, solve Schrödingers equation to get
    ?(t)?
  • Find a complete set of orthonormal eigenstates of
    H
  • Easier said than done
  • This will be much of our work this year
  • These states are orthonormal
  • Most general solution to time-independent
    Schrödinger equation is
  • The coefficients cn can then be found using
    orthonormality

28
Sample Problem
An infinite 1D square well with allowed region 0
lt x lt a has initial wave function in the
allowed region. What is ?(x,t)?
  • First find eigenstates and eigenvalues
  • Next, find the overlap constants cn
  • sin(½n?) 1, 0, -1, 0, 1, 0, -1, 0,

29
Sample Problem (2)
An infinite 1D square well with allowed region 0
lt x lt a has initial wave function in the
allowed region. What is ?(x,t)?
  • Now, put it all together

30
Irrelevance of Absolute Energy
  • In 1D, adding a constant to the energy makes no
    difference
  • Are these two Hamiltonians equivalent in quantum
    mechanics?
  • These two Hamiltonians have the same eigenstates
  • The solutions of Schrödingers equation are
    closely related
  • The solutions are identical except for an
    irrelevant phase
Write a Comment
User Comments (0)
About PowerShow.com