Triangles and Parallelograms Lesson 11.2 - PowerPoint PPT Presentation

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Triangles and Parallelograms Lesson 11.2

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Triangles and Parallelograms Lesson 11.2 Theorem 100: The area of a parallelogram is equal to the product of the base and the height. A = bh b h Find the area of ... – PowerPoint PPT presentation

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Title: Triangles and Parallelograms Lesson 11.2


1
Triangles and ParallelogramsLesson 11.2
2
Theorem 100 The area of a parallelogram is equal
to the product of the base and the height. A
bh
h
b
A
Find the area of MATH
3
A
You will receive one point for each line, plus
the correct unit. Minimum 3 lines.
A bh 13(6) 78cm2
4
Theorem 101 The area of a triangle is equal to
one-half the product of a base and the height (or
altitude) for that base.
A bh Where b is the length of the base and
h is the altitude. Altitude may be inside,
outside or the leg of the triangle. The base may
not always be at the bottom.
h
b
5
Find the area of this triangle.
12mm
8mm
A 48 mm2
Find the base of a triangle with an altitude of
15 and area 60.
x 8
6
Find the area of a parallelogram whose sides are
14 and 6 and whose acute angle is 60. Draw and
label.
D
U
C
K
How will you find the height?
7
D
U
C
K
S
Drop line DS to form a 30-60-90 triangle. Line DS
is
A bh 14( ) 42
8
Team Activity Draw a parallelogram that has a
perimeter of 40 units . What is its area? Which
team created the parallelogram with the GREATEST
area? What shape is it?
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