Differentiation Lesson 1 - PowerPoint PPT Presentation

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Differentiation Lesson 1

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Differentiation Lesson 1 Chapter 7 We need to be able to find the gradient of a straight line joining two points: Gradient = Find the gradient of the line joining (4 ... – PowerPoint PPT presentation

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Title: Differentiation Lesson 1


1
DifferentiationLesson 1
  • Chapter 7

2
We need to be able to find the gradient of a
straight line joining two points
Find the gradient of the line joining (4, -11)
and (-2, 7)
3
Describe the way the gradient is changing on
these graphs
4
Finding the gradient of a curve
  • (differentiation)

5
How can you find the gradient of a curve if it
keeps changing??
6
E.g. the function y x2
Go to GSP file
7
The ideal way to find a gradient of a curve is to
find the gradient of the tangent at the point we
are interested in
8
Finding the gradient
  • The process of finding the gradient of a curve is
    called differentiation
  • You can differentiate any function to find its
    gradient

9
In general it can be shown that
  • If f(x) xn where n is a real number
  • Then
  • f (x) nxn-1

f(x) xn
10
In general it can be shown that
f(x) xn
f (x) nxn-1
11
In other words
f(x) xn f (x) nxn-1
E.g. 1
-1
1) Multiply function by power of x 2) Subtract 1
from the power
12
In other words
f(x) xn f (x) nxn-1
E.g. 1
1) Multiply function by power of x 2) Subtract 1
from the power
13
Notation
14
Now do Ex 7B on page 109
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