Title: Impulse and Momentum Review Mr. Horton
1Impulse and Momentum ReviewMr. Hortons AP
Physics
- This is whats on the test
2Basic Relations , momentum
- Momentum a vector that is mv
- Find the momentum of a 40kg bike that is going
10m/s South - If the momentum of a go cart is 2500kgm/s east
when it is going 10m/s east, what is its mass? - If the momentum of a 100kg go cart is 2500kgm/s
east, find its velocity
3Basic Relations , momentum
- Find the momentum of a 40kg bike that is going
10m/s South 400kgm/s South - If the momentum of a go cart is 2500kgm/s east
when it is going 10m/s east, what is its mass?
250kg - If the momentum of a 100kg go cart is 2500kgm/s
east, find its velocity 25m/s East
4Basic Relations , momentum
- If the momentum of a go cart is 2500kgm/s east,
what would its momentum be if it doubled its
speed? - If the momentum of a go cart is 2500kgm/s east,
what would the momentum of another go cart be if
its mass is 25 greater but it has the same
velocity?
5Basic Relations, momentum
- If the momentum of a go cart is 2500kgm/s east,
what would its momentum be if it doubled its
speed? Double, 5000kgm/s east - If the momentum of a go cart is 2500kgm/s east,
what would the momentum of another go cart be if
its mass is 25 greater but it has the same
velocity? 25 greater, 3250kgm/s
6Basic Relations, impulse
- Impulse Ft
- Find the impulse of a 4000N average force to the
west that acts for 50s. - Find the impulse of a 4000N average force to the
west that acts for half the time as above. - Will the change in momentum be the same, greater,
or less for the 50s impulse?
7Basic Relations, impulse
- Impulse Ft
- Find the impulse of a 4000N average force to the
west that acts for 50s. 200,000Ns west - Find the impulse of a 4000N average force to the
west that acts for half the time as above.
100,000Ns west - Will the change in momentum be the same, greater,
or less for the 50s impulse? Greater (2x greater)
8Basic Relations, impulse is the change in
momentum
- Impulse Ft change in momentum
- If (and only if) the momentum change is the same,
force will decrease if time increases. - An object has 400kgm/s of momentum to the north
when a 10N force to the north is applied for 2s.
Find the change in momentum and the final
momentum. - An object has 400kgm/s of momentum to the north
when a 10N force to the south is applied for 2s.
Find the change in momentum and the final
momentum.
9Basic Relations, impulse is the change in
momentum
- An object has 400kgm/s of momentum to the north
when a 10N force to the north is applied for 2s.
Find the change in momentum and the final
momentum. 20Ns north 420kgm/s north - An object has 400kgm/s of momentum to the north
when a 10N force to the south is applied for 2s.
Find the change in momentum and the final
momentum. 20Ns south 380kgm/s north
10Basic Relations, impulse is the change in
momentum
- An object has 400kgm/s of momentum to the north
when a 10N force to the east is applied for 20s.
Find the change in momentum and the final
momentum. - An object has 400kgm/s of momentum to the north
. Find the impulse required to stop it.
11Basic Relations, impulse is the change in
momentum
- An object has 400kgm/s of momentum to the north
when a 10N force to the east is applied for 20s.
Find the change in momentum and the final
momentum. Pythag 44.7m/stan-1 (40/20) 63
deg North of E
12Basic Relations, impulse is the change in
momentum
- An object has 400kgm/s of momentum to the north.
Find the impulse required to stop it. Dmv -
400kgm/s -400Ns 400Ns south
13Impulse and Momentum at an angle
- An object has 400kgm/s of momentum 30deg east of
south. Find the components in the north and
east. - An object has 400kgm/s of momentum 30deg east of
south when a 20N force is applied to it for 20s
at 30deg east of south. Find its final momentum
and velocity.
14Impulse and Momentum at an angle
- An object has 400kgm/s of momentum 30deg east of
south. Find the components in the north and
east. - 400 sin(30deg) 200kgm/seast
- 400 cos(30deg) 346.4kgm/seast
- Vel (400kgm/s)/mass 30deg east of south.
15Impulse and Momentum at an angle
- An object has 400kgm/s of momentum 30deg east of
south. Find the components in the north and
east. - 400 sin(30deg) 200kgm/seast
- 400 cos(30deg) 346.4kgm/seast
16Impulse and Momentum at an angle
- An object has 400kgm/s of momentum 30deg east of
south. If it strikes another object that is at
rest, what must the total momentum be after the
collision in the north and east directions? What
condition are we assuming for this to be true?
17Impulse and Momentum at an angle
- Since momentum must be conserved (if there are no
outside forces), its the same as before - 400 sin(30deg) 200kgm/seast
- 400 cos(30deg) 346.4kgm/seast
18Conservation of Momentum
- The total linear momentum of an isolated system
remains constant. An isolated system is one for
which the vector sum of the external forces
acting on the system is zero. All of the momentum
before an event must be the same after the event.
m1v1f m2v2f m1v1i m2v2i
19Conservation of Momentum
- If a 80kg guy is rolling on his skates very fast
towards his girlfriend at 8m/s while she is
rolling towards him at 2m/s. Find their final
velocity if they hold on to one another after the
collision assuming that she is only half his
mass. - m1v1f m2v2f m1v1i m2v2i
- 8okgv1f 40kgv2f 80kg8m/s 40kg(-2m/s)
- Since they move together, v1f v2f vf
20Conservation of Momentum
- 8okgv1f 40kgv2f 80kg8m/s 40kg(-2m/s)
- Since they move together, v1f v2f vf
- 8okgvf 40kgvf 80kg8m/s 40kg(-2m/s)
- 8okgv1f 40kgv2f 560kgm/s
- 120kg(v1f) 560kgm/s
- 4.67m/s in the boyfriends initial direction
(which was made the pos direction above)
21Conservation of Momentum
- If he pushed her fast enough so that he stops,
how fast would the girlfriend have to be going? - m1v1f m2v2f m1v1i m2v2i
- 8okg0m/s 40kgv2f 80kg8m/s 40kg(-2m/s)
- 0 40kgv2f 560kgm/s
- v2f (560kgm/s)/40kgv2f 14 m/s in the orig
direction of the boyfriend
22Conservation of Momentum
- If a superball is 0.4kg and going 25m/s east
before striking a wall and returning at 25m/s,
find the force that the wall exerted if the time
of contact was 0.20 sec. - Dmv Ft 0.4kg(-25m/s 25m/s) Ft
0.4kg(-50m/s) -20kgm/s Ft -20kgm/s
F(0.20s) - F -100N
23Conservation of Momentum
- The drawing shows a collision between two pucks
on an air hockey table. Puck A has a mass of
0.25 kg and is moving along the x-axis with a
velocity of 5.5 m/s. It makes a collision with
puck B, which has a mass of 0.5 kg and is
initially at rest. After the collision, the two
pucks fly apart with the angles shown in the
drawing. Find the final speed of (a) puck A and
(b) puck B.
24- p initial, total 5.5(.25) 1.375kgm/s to the
right. - After collision in the y directionmvAsin(65) -
mvBsin(37) 0 - After collision in the x direction mvAcos(65)
mvBcos(37) 1.375kgm/s right. - After collision in the y direction.25vA(.9063)
.5vB(-.60) 0 - vB 0.753vA.
- After collision in the x direction.25vA(.4226)
.5vB(.7986) 1.375kgm/s r
- .25vA(.4226) .5(0.753vA)(.7986) 1.375kgm/s r
- 0.4063vA 1.375kgm/s rt
- vA 3.4m/s Now plug back into vB 0.753vA.
0.753(3.4m/s) - vB 0.753vA. 0.753(3.4m/s) 2.55m/s
25Impulse again
- If two objects collide, Newtons 3rd law tells us
that the forces must be equal but opposite
directions. Common sense tells us that if A is
in contact with B for some time, t, then B is
also in contact with A for time, t. - Therefore, the impulse between two interacting
bodies will also be equal but opposite (if there
are no outside forces)
26Test Taking Skills
- Tip 1 Take everything one step at a time and
include units for each step. - Tip 2 Watch the signs/directions
- Tip 3 When adding vectors, dont forget to add
head-to-tail - Tip 4 If you put the correct answer, dont
change it!! ? - Tip 5 Ask yourself if the answer makes sense.