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FURTHER APPLICATIONS OF INTEGRATION

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9 FURTHER APPLICATIONS OF INTEGRATION SURFACE OF REVOLUTION A surface of revolution is formed when a curve is rotated about a line. Such a surface is the lateral ... – PowerPoint PPT presentation

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Title: FURTHER APPLICATIONS OF INTEGRATION


1
9
FURTHER APPLICATIONS OF INTEGRATION
2
FURTHER APPLICATIONS OF INTEGRATION
8.2Area of a Surface of Revolution
In this section, we will learn about The area of
a surface curved out by a revolving arc.
3
SURFACE OF REVOLUTION
  • A surface of revolution is formed when a curve
    is rotated about a line.
  • Such a surface is the lateral boundary of a solid
    of revolution of the type discussed in Sections
    6.2 and 6.3

4
AREA OF A SURFACE OF REVOLUTION
  • We want to define the area of a surface of
    revolution in such a way that it corresponds to
    our intuition.
  • If the surface area is A, we can imagine that
    painting the surface would require the same
    amount of paint as does a flat region with area
    A .

5
AREA OF A SURFACE OF REVOLUTION
  • Lets start with some simple surfaces.

6
CIRCULAR CYLINDERS
  • The lateral surface area of a circular cylinder
    with radius r and height h is taken to be
    A 2prh
  • We can imagine cutting the cylinder and
    unrolling it to obtain a rectangle with
    dimensions of 2prh and h.

7
CIRCULAR CONES
  • We can take a circular cone with base radius r
    and slant height l, cut it along the dashed line
    as shown, and flatten it to form a sector of a
    circle with radius and central angle ? 2pr/l.

8
CIRCULAR CONES
  • We know that, in general, the area of a sector
    of a circle with radius l and angle ? is ½ l2 ?.

9
CIRCULAR CONES
  • So, the area is
  • Thus, we define the lateral surface area of a
    cone to be A prl.

10
AREA OF A SURFACE OF REVOLUTION
  • What about more complicated surfaces of
    revolution?

11
AREA OF A SURFACE OF REVOLUTION
  • If we follow the strategy we used with arc
    length, we can approximate the original curve by
    a polygon.
  • When this is rotated about an axis, it creates a
    simpler surface whose surface area approximates
    the actual surface area.
  • By taking a limit, we can determine the exact
    surface area.

12
BANDS
  • Then, the approximating surface consists of a
    number of bandseach formed by rotating a line
    segment about an axis.

13
BANDS
  • To find the surface area, each of these bands can
    be considered a portion of a circular cone.

14
BANDS
Equation 1
  • The area of the band (or frustum of a cone) with
    slant height l and upper and lower radii r1 and
    r2 is found by subtracting the areas of two
    cones

15
BANDS
  • From similar triangles, we have
  • This gives

16
BANDS
Formula 2
  • Putting this in Equation 1, we get
  • or
  • where r ½(r1 r2) is the average radius of the
    band.

17
AREA OF A SURFACE OF REVOLUTION
  • Now, we apply this formula to our strategy.

18
SURFACE AREA
  • Consider the surface shown here.
  • It is obtained by rotating the curve y f(x), a
    x b, about the x-axis, where f is positive
    and has a continuous derivative.

19
SURFACE AREA
  • To define its surface area, we divide the
    interval a, b into n subintervals with
    endpoints x0, x1, . . . , xn and equal width ?x,
    as we did in determining arc length.

20
SURFACE AREA
  • If yi f(xi), then the point Pi(xi, yi) lies on
    the curve.
  • The part of the surface between xi1 and xi is
    approximated by taking the line segment Pi1 Pi
    and rotating it about the x-axis.

21
SURFACE AREA
  • The result is a band with slant height l
    Pi1Pi and average radius r ½(yi1 yi).
  • So, by Formula 2, its surface area is

22
SURFACE AREA
  • As in the proof of Theorem 2 in Section 8.1, we
    have
  • where xi is some number in xi1, xi.

23
SURFACE AREA
  • When ?x is small, we have yi f(xi) f(xi)
    and yi1 f(xi1) f(xi), since f is
    continuous.
  • Therefore,

24
SURFACE AREA
Formula 3
  • Thus, an approximation to what we think of as
    the area of the complete surface of revolution is

25
SURFACE AREA
  • The approximation appears to become better as n ?
    8.

26
SURFACE AREA
  • Then, recognizing Formula 3 as a Riemann sum for
    the function we have

27
SURFACE AREADEFINITION
Formula 4
  • Thus, in the case where f is positive and has a
    continuous derivative, we define the surface area
    of the surface obtained by rotating the curve y
    f(x), a x b, about the x-axis as

28
SURFACE AREA
Formula 5
  • With the Leibniz notation for derivatives, this
    formula becomes

29
SURFACE AREA
Formula 6
  • If the curve is described as x g(y), c y
    d, then the formula for surface area becomes

30
SURFACE AREA
Formula 7
  • Then, both Formulas 5 and 6 can be summarized
    symbolicallyusing the notation for arc length
    given in Section 8.1as

31
SURFACE AREA
Formula 8
  • For rotation about the y-axis, the formula
    becomes
  • Here, as before, we can use either
  • or

32
SURFACE AREAFORMULAS
  • You can remember these formulas in the following
    ways.

33
SURFACE AREAFORMULAS
  • Think of 2py as the circumference of a circle
    traced out by the point (x, y) on the curve as
    it is rotated about the x-axis.

34
SURFACE AREAFORMULAS
  • Think of 2px s the circumference of a circle
    traced out by the point (x, y) on the curve as
    it is rotated about the y-axis.

35
SURFACE AREA
Example 1
  • The curve , 1 x 1, is an arc of
    the circle x2 y2 4 .
  • Find the area of the surface obtained by
    rotating this arc about the x-axis.
  • The surface is a portion of a sphere of radius 2.

36
SURFACE AREA
Example 1
  • We have

37
SURFACE AREA
Example 1
  • So, by Formula 5, the surface area is

38
SURFACE AREA
Example 2
  • The arc of the parabola y x2 from (1, 1) to
    (2, 4) is rotated about the y-axis.
  • Find the area of the resulting surface.

39
SURFACE AREA
E. g. 2Solution 1
  • Using y x2 and dy/dx 2x, from Formula 8, we
    have

40
SURFACE AREA
E. g. 2Solution 1
  • Substituting u 1 4x2, we have du 8x dx.
  • Remembering to change the limits of integration,
    we have

41
SURFACE AREA
E. g. 2Solution 2
  • Using x and dx/dy ,
  • we have the following solution.

42
SURFACE AREA
E. g. 2Solution 2
43
SURFACE AREA
Example 3
  • Find the area of the surface generated by
    rotating the curve y ex, 0 x 1, about the
    x-axis.

44
SURFACE AREA
Example 3
  • Using Formula 5 with y ex and dy/dx ex, we
    have

45
SURFACE AREA
Example 3
46
SURFACE AREA
Example 3
  • Since tan a e , we have
  • sec2a 1 tan a 1 e2
  • Thus,
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