Title: SN1 and SN2 Reactions
1SN1 and SN2 Reactions
SN1 SN2
Rate kRX kRXNuc-
Carbocation intermediate? Y N
Stereochemistry mix Inversion of configuration
Rearrangement H, CH3 possible No rearrangements
2SN1 and SN2 Reactions
SN1 SN2
Substrate 3gt2gt1 CH3Xgt1gt2
Nucleophile Unimportant, but usually weak Strong and unhindered
Leaving group Excellent Better than nucleophile
Solvent Polar and ionizing Polar aprotic
3SN1 and SN2 Reactions
- Do not occur with vinyl halides or aryl halides.
- Consider the carbocation formed for SN1.
- Consider the backside attack for SN2.
4Elimination Reactions
- The substitution reaction mechanisms you have
learned are just part of the picture. - In the SN1 and SN2 reactions, the species that
acts as a nucleophile may also act as a base and
abstract a proton. This causes the elimination
of HX and the formation of an alkene. - An elimination reaction can occur along with the
substitution reaction.
5Elimination
B- is a species acting as a base. Since HX is
lost, this particular reaction is called a
dehydrohalogenation.
6E1 Reactions
- E1 elimination, unimolecular
- Rate ksubstrate (a first order process)
- The rate-limiting step is the formation of the
carbocation, the same as for SN1 (thats why E1
competes).
7E1 Reaction Mechanism
- Step 1 The substrate forms a carbocation
intermediate (rate-limiting step). - Step 2 Methanol acts as a base and removes
H(fast step).
8E1 Reaction Profile
rate k(CH3)3Br
-EA(step 1)/RT
k Ae
9E1 Occurs with and Competes with SN1
- When bromocyclohexane is heated with methanol,
two products are possible.
- Can you draw the mechanism that leads to each
product?
10SN1 E1 competing mechanisms
11E1 Reactions
- E1 reactions are exothermic.
- E1 reactions occur in at least two steps and
compete with SN1 reactions. - The first step is slow. It is the formation of
the carbocation intermediate. - The second step is fast. It is the abstraction
of H from the carbocation by the base.
12Factors Affecting E1 Reactions
- Structure of the substrate
- Can a stable carbocation be formed?
- Strength of the base
- Nature of the leaving group
- The solvent in which the reaction is run.
- Must be able to stabilize the carbocation and the
LG (which is usually an ion).
13Factors Affecting E1 Reactions - Structure of the
Substrate
- The most important factor influencing the rate of
E1 reactions is the stability of the carbocation
formed. - Stability of carbocation 3 gt 2 gt1
- Relative rates for E1 3gt21(resonance)
14Factors Affecting E1 Reactions - Strength of the
Base
- The rate is not much affected by the strength of
the base. Weak bases will work.
15Factors Affecting E1 Reactions - the Leaving Group
16Factors Affecting E1 Reactions - Solvent Effects
- The solvent must be capable of dissolving both
the carbocation and the leaving group. - E1 reactions require highly polar solvents that
strongly solvate ions. - Typical solvents water, an alcohol, acetone (to
help the alkyl halide to dissolve), or a mix.
17Rearrangements in E1 Reactions
- The carbocation can undergo a structural
rearrangement to produce a more stable species. - hydride shift (H)
- methyl shift (CH3)
- If ionization would lead to a 1 carbocation,
look for a rearrangement to occur. - Ionizations can be forced by the addition of
reagents such as AgNO3. (How?)
18A Hydride Shift Can Occur in Either SN1 or E1
Reactions
CH3OH
H
-H
SN1
- What would the E1 products be?
19A Methyl Shift Can Occur in Either SN1 or E1
Reactions
CH3OH
CH3
-H
SN1
- What would the E1 product be?
20Zaitsevs Rule
- When two or more elimination products are
possible, the product with the more substituted
double bond will predominate.
21Zaitsevs Rule
- When two or more elimination products are
possible, the product with the more substituted
double bond will predominate. - Alkyl groups are electron-donating and contribute
electron density to the p bond. - Bulky groups can be more widely separated.
22E1 Reactions - Summary
- The structure of the carbocation is the most
important factor - Relative rates for E1 3gt2.
- The base is typically weak or moderate in
strength. - The LG should be good.
- The solvent should be polar and protic to
stabilize the carbocation and LG. - Products can exhibit rearrangements and will
follow Zaitsevs Rule.