Title: Making Solutions
1PREPARING SOLUTIONS AND REAGENTS
2Chemical Solutions (aqueous water is the
solvent)
- Types of vessels (least to most precise)
- Beaker
- Erlennmeyer flask
- Graduated cylinder
- Volumetric flask
3- DEFINITIONS
- SOLUTES -- substances that are dissolved
- SOLVENTS -- substance in which solutes are
dissolved (usually water) - AMOUNT -- how much
4Goals
- Make solutions
- Dilute solutions
- Convert between different concentrations of
solutions
5Facts of Life
- Mass is measured in Grams, mg, µg
- 1g 1000mg 1,000,000µg
- Volume is measured in liters, mL, µL
- 1L 1000mL 1,000,000 µL
- Density of water is 1 g / mL
6Facts of life (contd)
- Concentration means amount of solute in a volume
of solution - Expressed in many ways
- 1. percent
- 2. mg/ mL
- 3. molar
- 4. X solution
7Each star represents 1 mg of NaCl. What is the
total amount of NaCl in the tube? _____ What is
the concentration of NaCl in the tube (in mg/mL)?
_____
5 mg ? 8 mL 1 mL ? 0.63 mg, so the
concentration is 0.63 mg/mL
8 mL
8Percent Solutions
- Per means for every one
- Cent means 100
- Example a 5 sugar solution has
- 5 grams of sugar for 100g of solution, or
- 5g 100 g of water 100 mL, and the
- 100mL solution is mostly water.
9Make 250 mL of a 3 starch solution
- 3 g / 100 g 3 g / 100 mL because density of
water is 1 g / mL - Set up a ratio
- 3 g / 100 mL ?g / 250 mL
- Use 7.5 g of starch and bring to a volume of
(BTV) 250 mL with distilled water
10mg / mL Solutions
- 5 mg/mL has 5 milligrams of solute in 1
milliliter of solution
11Make a 250 mL of a 3 mg /mL starch solution
- Set up a ratio
- 3 mg / 1 mL ?mg / 250 mL
- Use 750 mg of starch and bring to a volume of
(BTV) 250 mL with distilled water
12Molar Solutions
- 1 mole is 6.02 x 1023 items
- Molecular weight or Formula weight is really the
mass of 1 mole of molecules (see periodic table) - Example 1 mol of sodium chloride (NaCl) has a
mass of 58.44 g. -
13MOLARITY
- Molarity is number of moles of a solute that
are dissolved per liter of total solution. - A 1 M solution contains 1 mole of solute per
liter total volume.
14MOLE
15EXAMPLE SULFURIC ACID
- For a particular compound, add the atomic weights
of the atoms that compose the compound. - H2SO4
- 2 hydrogen atoms 2 X 1.00 g 2.00 g
- 1 sulfur atom 1 X 32.06 g 32.06 g
- 4 oxygen atoms 4 X 16.00 g 64.00 g
-
98.06 g
16EXAMPLE CONTINUED
- A 1M solution of sulfuric acid contains 98.06 g
of sulfuric acid in 1 liter of total solution. - "mole" is an expression of amount
- "molarity" is an expression of concentration.
17DEFINITIONS
- "Millimolar", mM, millimole/L.
- A millimole is 1/1000 of a mole.
-
- "Micromolar", µM, µmole/L.
- A µmole is 1/1,000,000 of a mole.
18 FORMULA
- HOW MUCH SOLUTE IS NEEDED FOR A SOLUTION OF A
PARTICULAR MOLARITY AND VOLUME? - (g solute ) X (mole) X (L) g solute
needed - 1 mole L
- or
- FW X molarity x volume g solute
needed
19EXAMPLE
- How much solute is required to make 300 mL of 0.8
M CaCl2?
20ANSWER
- (111.0 g) x (0.8 mole) x (0.3 L) 26.64 g
- mole L
21- Make 250 mL of a 3 molar NaCl solution
- 58.44g x 3 moles x 0.25 L ? g
- 1 mole 1 L
- ? 43.8g of NaCl
- BTV of 250 mL
22X solutions
- X means times
- A 40X buffer solution is 40 times more
concentrated than the standard working solution - Stock solutions / concentrates
- How much stock solution you need total volume
you need divided by the X number
23Diluting Solutions
- Conc 1 x Vol. 1 Conc 2 x Vol 2
- Usually want 1 X solutions
24Example Frozen Orange Juice
- Solution 1 is the frozen concentrate
- Solution 2 is the 1X juice you drink
- How concentrated is it?
- C1 V1 C2 V2
- (? X) (250mL) (1X) (1000 mL)
25Answer Frozen OJ is 4X because ¼ of the final
volume is the concentrated oj
26Example bleach sterilant
- Solution 1 is 100 bleach stock solution
- Solution 2 is 6 bleach what you want
- How do you make 350 mL of 6 bleach?
- C1 V1 C2 V2
- (100) (?) (6) (350 mL)
27Answer You need 21 mL of 100 bleachBTV 350
mL.