Plastic Deformation - PowerPoint PPT Presentation

1 / 13
About This Presentation
Title:

Plastic Deformation

Description:

Plastic Deformation Permanent, unrecovered mechanical deformation s = F/A stress Deformation by dislocation motion, glide or slip Dislocations – PowerPoint PPT presentation

Number of Views:186
Avg rating:3.0/5.0
Slides: 14
Provided by: Sossina6
Category:

less

Transcript and Presenter's Notes

Title: Plastic Deformation


1
Plastic Deformation
  • Permanent, unrecovered mechanical deformation

s F/A stress
  • Deformation by dislocation motion, glide or
    slip
  • Dislocations
  • Edge, screw, mixed
  • Defined by Burgers vector
  • Form loops, cant terminate except at crystal
    surface
  • Slip system
  • Glide plane Burgers vector

maximum shear stress
2
Crystallography of Slip
  • Slip system glide plane burgers vector
  • Correspond to close-packed planes directions
  • Why?
  • Fewest number of broken bonds
  • Cubic close-packed
  • Closest packed planes
  • 1 1 1
  • 4 independent planes
  • Closest packed directions
  • Face diagonals
  • lt1 1 0gt
  • 3 per plane (only positive)
  • 12 independent slip systems

3
  • HCP
  • BCC
  • Planes 1 1 0
  • 6 independent planes
  • Directions lt1 1 1gt
  • 2 per plane (only positive)
  • 12 independent slip systems
  • Planes 0 0 1
  • 1 independent plane
  • Directions lt1 0 0gt
  • 3 per plane (only positive)
  • 3 independent slip systems

Occasionally also 1 1 2 planes in BCC are
slip planes
Diamond structure type 1 1 1 and lt1 1 0gt ---
same as CCP, but slip less uncommon
4
Why does the number of independent slip systems
matter?
Are any or all or some of the grains in the
proper orientation for slip to occur?
s F/A
?
?
HCP
?
?
CCP
maximum shear stress
  • Large of independent slip systems in CCP ??
    at least one will be active for any particular
    grain
  • True also for BCC
  • Polycrystalline HCP materials require more
    stress to induce deformation by dislocation
    motion

5
Dislocations in Ionic Crystals
like charges touch
2
1
like charges do not touch
long burgers vector compared to metals
compare possible slip planes
(1) slip causes like charges to touch
(2) does not cause like charges to touch
6
Energy Penalty of Dislocations
bonds are compressed
E
R0
R
compression
tension
Energy / length ? b2
Thermodynamically unfavorable Strong interactions
bonds are under tension
attraction ? annihilation
repulsion ? pinning
Too many dislocations ? become immobile
7
Summary
  • Materials often deform by dislocation glide
  • Deforming may be better than breaking
  • Metals
  • CCP and BCC have 12 indep slip systems
  • HCP has only 3, less ductile
  • bBCC gt bCCP ? higher energy, lower mobility
  • CCP metals are the most ductile
  • Ionic materials/Ceramics
  • Dislocations have very high electrostatic energy
  • Deformation by dislocation glide atypical
  • Covalent materials/Semiconductors
  • Dislocations extremely rare

Now on to elastic deformation
8
Elastic Deformation
  • Connected to chemical bonding
  • Stretch bonds and then relax back
  • Recall bond-energy curve
  • Difficulty of moving from R0
  • Curvature at R0
  • Elastic constants
  • (stress) (elastic constant) (strain)
  • stress and strain are tensors ? directional
  • the elastic constant being measured depends on
    which component of stress and of strain

9
Elastic Constants
Y Youngs modulus (sometimes E)
F
stress
uniaxial, normal stress
material elongates l0 ? l
strain
elongation along force direction
l0
observation
Y
s (stress)
e (strain)
material thins/necks A0 ? Ai true stress use
Ai engineering stress use A0
10
Elastic Constants
Connecting Youngs Modulus to Chemical Bonding
R0
F k DR
? k(length) Y
stressarea
strainlength
Coulombic attraction
want k in terms of E, R0
observed within some classes of compounds
11
Elastic Constants
Bulk Modulus, K
  • apply hydrostatic pressure

P F/A
s -P
  • measure change in volume
  • linear response

Can show
analogous to Youngs modulus
Coulombic
Useful relationship
12
Elastic Constants
Poissons ratio, n
  • apply uniaxial stress

s F/A
F
  • measure e

- elongation parallel to force
  • measure e?

- thinning normal to force
e
e?
Rigidity (Shear) Modulus, G
  • apply shear stress

t F/A
A
Dl
  • measure shear strain

F
?f
tanf
?? f
l0
y
F
x
13
Elastic Constants
General Considerations
? 6 parameters
Stress, s 3 ? 3 symmetric tensor
Strain, e 3 ? 3 symmetric tensor
? 6 parameters
In principle, each and every strain parameter
depends on each and every stress parameter
? 36 elastic constants
? 21 independent elastic constants in the most
general case
Some are redundant
Material symmetry
? some are zero, some are inter-related
Isotropic material
? only 2 independent elastic constants
normal stress
? only normal deformation
shear stress
? only shear deformation
Cubic material
? G, Y and n are independent
Write a Comment
User Comments (0)
About PowerShow.com