Title: Module 8
1Module 8
- Non equilibrium Thermodynamics
2Lecture 8.1
3NON-EQUILIRIBIUM THERMODYNAMICS
Steady State processes. (Stationary)
Concept of Local thermodynamic eqlbm
4NON-EQLBM THERMODYNAMICS
Postulate I
Although system as a whole is not in eqlbm.,
arbitrary small elements of it are in local
thermodynamic eqlbm have state fns. which
depend on state parameters through the same
relationships as in the case of eqlbm states in
classical eqlbm thermodynamics.
5NON-EQLBM THERMODYNAMICS
Postulate II
Entropy gen rate
fluxes
affinities
6NON-EQLBM THERMODYNAMICS
Purely resistive systems
Flux is dependent only on affinity
at any instant
at that instant
System has no memory-
7NON-EQLBM THERMODYNAMICS
Coupled Phenomenon
Since Jk is 0 when affinities are zero,
8NON-EQLBM THERMODYNAMICS
where
kinetic Coeff
Relationship between affinity flux from other
sciences
Postulate III
9NON-EQLBM THERMODYNAMICS
Heat Flux
Momentum
Mass
Electricity
10NON-EQLBM THERMODYNAMICS
- Postulate IV
- Onsager theorem in the absence of magnetic
fields
11NON-EQLBM THERMODYNAMICS
- Entropy production in systems involving heat Flow
12NON-EQLBM THERMODYNAMICS
Entropy gen. per unit volume
13NON-EQLBM THERMODYNAMICS
14NON-EQLBM THERMODYNAMICS
Entropy generation due to current flow
Heat transfer in element length
15NON-EQLBM THERMODYNAMICS
Resulting entropy production per unit volume
16NON-EQLBM THERMODYNAMICS
Total entropy prod / unit vol. with both electric
thermal gradients
affinity
affinity
17NON-EQLBM THERMODYNAMICS
18Analysis of thermo-electric circuits
- Addl. Assumption Thermo electric phenomena can
be taken as LINEAR RESISTIVE SYSTEMS
higher order terms negligible
Here K 1,2 corresp to heat flux Q, elec flux
e
19Analysis of thermo-electric circuits
- ? Above equations can be written as
Substituting for affinities, the expressions
derived earlier, we get
20Analysis of thermo-electric circuits
We need to find values of the kinetic coeffs.
from exptly obtainable data.
21End of Lecture
22Lecture 8.2
23Analysis of thermo-electric circuits
- The basic equations can be written as
Substituting for affinities, the expressions
derived earlier, we get
24Analysis of thermo-electric circuits
We need to find values of the kinetic coeffs.
from exptly obtainable data.
25Analysis of thermo-electric circuits
- Consider the situation, under coupled flow
conditions, when there is no current in the
material, i.e. Je0. Using the above expression
for Je we get
Seebeck effect
26Analysis of thermo-electric circuits
or
Seebeck coeff.
Using Onsager theorem
27Analysis of thermo-electric circuits
- Further from the basic eqs for Je JQ, for Je
0 - we get
28Analysis of thermo-electric circuits
- For coupled systems, we define thermal
conductivity as
This gives
29Analysis of thermo-electric circuits
- Substituting values of coeff. Lee, LQe, LeQ
calculated above, we get
30Analysis of thermo-electric circuits
Using these expressions for various kinetic coeff
in the basic eqs for fluxes we can write these as
31Analysis of thermo-electric circuits
- We can also rewrite these with fluxes expressed
as fns of corresponding affinities alone
Using these eqs. we can analyze the effect of
coupling on the primary flows
32PETLIER EFFECT
- Under Isothermal Conditions
Heat flux
33PETLIER EFFECT
Heat interaction with surroundings
Peltier coeff.
Kelvin Relation
34PETLIER REFRIGERATOR
35THOMSON EFFECT
Total energy flux thro' conductor is
Using the basic eq. for coupled flows
36THOMSON EFFECT
The heat interaction with the surroundings due to
gradient in JE is
37THOMSON EFFECT
Since Je is constant thro' the conductor
38THOMSON EFFECT
Using the basic eq. for coupled flows, viz.
Thomson heat
Joulean heat
39THOMSON EFFECT
reversible heating or cooling experienced due to
current flowing thro' a temp gradient
Thomson coeff
Comparing we get
40THOMSON EFFECT
We can also get a relationship between Peltier,
Seebeck Thomson coeff. by differentiating the
exp. for ?ab derived earlier, viz.
41End of Lecture
42Analysis of thermo-electric circuits
- ? Above equations can be written as
Substituting for affinities, the expressions
derived earlier, we get
43Analysis of thermo-electric circuits
We need to find values of the kinetic coeffs.
from exptly obtainable data.