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FIRST LAW OF THERMODYNAMICS

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INTRODUCTION TO NAVAL ENGINEERING THERMODYNAMICS II FIRST LAW OF THERMODYNAMICS THE GENERAL ENERGY EQUATION Energy In = Energy Out or U2 - U1 = Q - W where U1 ... – PowerPoint PPT presentation

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Title: FIRST LAW OF THERMODYNAMICS


1
INTRODUCTION TO NAVAL ENGINEERING
THERMODYNAMICS II
2
INTRODUCTION TO NAVAL ENGINEERING
FIRST AND SECOND LAWS OF THERMODYNAMICS
3
FIRST LAW OF THERMODYNAMICS
Energy can be neither created nor destroyed but
only transformed
4
THE GENERAL ENERGY EQUATION
  • Energy In Energy Out
  • or
  • U2 - U1 Q - W
  • where
  • U1 internal energy of the system at the
    beginning
  • U2 internal energy of the system at the end
  • Q net heat flow into the system
  • W net work done by the system

5
ELEMENTS OF A THERMODYNAMIC CYCLE
6
ELEMENTS OF A THERMODYNAMIC CYCLE
7
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8
THERMODYNAMIC CYCLES
  • CLOSED
  • Working fluid never leaves the cycle, except
    through accidental leakage (ex steam cycle)
  • OPEN
  • Working fluid is taken in, used, then discarded
    (ex internal combustion engine)

9
ENGINES
  • HEATED
  • heat is added to the working substance in the
    engine itself (ex internal combustion engine)
  • UNHEATED
  • the working substance receives heat in some
    device that is separate from the engine (ex
    steam turbines)

10
CLOSED UNHEATED
11
OPEN HEATED
12
FLOW PROCESSES
  • NON-FLOW
  • One in which the working fluid does not flow
    into or out of its container in the course of the
    process (ex air compressors, internal combustion
    engines)
  • STEADY FLOW
  • One in which a working substance flows steadily
    and uniformly (ex boilers, turbines, condensers)

13
USING THE G.E.E. (Non-Flow)
  • Q12 (U2 - U1) wk12/J
  • where
  • Q12 total heat transferred (Btu)
  • U2, U1 total internal energy at points 1 and
    2 (Btu)
  • wk12 work done between states 1 and 2
    (ft-lbs)
  • J constant of 778 ft-lbs/Btu

14
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15
G.E.E. (Non-Flow) EXAMPLE
  • 5 LBM of a fluid is compressed in the cylinder
    using 350 Btus of work. If internal energy
    initially was 100 Btu/lbm and 150 Btu/lbm at the
    end of the compression, how much heat was
    added/lost?
  • Q12 (U2 - U1) wk12/J

16
STEADY FLOW SYSTEMS AND THE GENERAL ENERGY
EQUATION
17
ENTHALPY (H or h)
  • COMBINATION OF
  • INTERNAL ENERGY (U)
  • FLOW WORK
  • Mechanical energy necessary to maintain the
    steady flow of the fluid
  • Flow work pV/J (Btu)
  • H pV/J U

18
STATE CHANGES
  • Isobaric
  • the pressure of and on the working fluid is
    constant
  • Isenthalpic
  • the enthalpy of the working fluid does not change
    (h1 h2)
  • Isothermal
  • temperature is constant
  • Adiabatic
  • occurs in such a way that there is no transfer of
    heat to or from the system during the process

19
THE SECOND LAW OF THERMODYNAMICS
  • (1) All energy received as heat by a heat engine
    cycle cannot be converted into work (This means
    that no cycle can have a thermal efficiency of
    100)

20
THE SECOND LAW OF THERMODYNAMICS
(2) The transformation of heat to work is
dependent on a temperature difference and on the
flow of heat from a high temperature reservoir to
a low temperature reservoir. (In other word heat
must flow from hot to cold)
21
THE SECOND LAW OF THERMODYNAMICS
(3) It is impossible to construct an engine that,
operating in a cycle, will produce no effect
other than the transfer of heat from a low
temperature reservoir to a high temperature
reservoir
22
THE SECOND LAW OF THERMODYNAMICS
FRICTION HAPPENS
23
ENTROPY
  • A THEORETICAL MEASURE OF ENERGY THAT CANNOT BE
    TRANSFORMED INTO MECHANICAL WORK IN A
    THERMODYNAMIC SYSTEM.
  • The total amount of entropy in a system always
    goes up.
  • No thermodynamic process can occur without some
    losses.
  • First Law You cant win
  • Second Law You cant even break even

24
ENTROPY (cont)
  • A MEASURE OF DISORDER
  • always growing in our universe
  • THE END OF THE UNIVERSE IS UPON US
  • CRUCIAL PART OF REAL THERMODYNAMIC EQUATIONS

25
CARNOT CYCLE
TEMP
ENTROPY
26
CARNOT EFFICIENCY
27
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