Provable Protocols for Unlinkability - PowerPoint PPT Presentation

About This Presentation
Title:

Provable Protocols for Unlinkability

Description:

Title: PowerPoint Presentation Last modified by: Amos Fiat Created Date: 1/1/1601 12:00:00 AM Document presentation format: On-screen Show Other titles – PowerPoint PPT presentation

Number of Views:63
Avg rating:3.0/5.0
Slides: 30
Provided by: csTauAc5
Category:

less

Transcript and Presenter's Notes

Title: Provable Protocols for Unlinkability


1
Provable Protocols for Unlinkability
  • Ron Berman, Amos Fiat, Amnon Ta-Shma
  • Tel Aviv University

2
Unlinkability
  • S Set of message initiators
  • T Set of message recipients
  • Every s ? S sends a message to some t ? T and
    may request a response
  • Goal Prevent adversary from knowing who is
    talking to whom
  • Adversary may control all nodes in T and many
    other nodes and links in the network

3
The model
  • A complete graph of N nodes
  • The adversary is capable of eavesdropping to
    almost all links an e fraction of the links are
    honest
  • The adversary may also control almost all nodes,
    subject to the above
  • A public key infrastructure is in place
  • A set S of M nodes wish to send unlinkable two
    way communications to a set T of M nodes
  • The Adversary is adaptive but not malicious.
    I.e., Adversary cannot corrupt or discard
    messages.

4
Prior Work
  • Seminal Papers of David Chaum, 1979, 1981
  • Reduction to Traffic Analysis (Onion Routing)
  • Chaumian Mixes
  • Literally dozens (hundreds?) of papers since,
    dedicated conferences, etc., etc.
  • Many implementations
  • Typical paper
  • Attack on prior protocol(s)
  • Suggest new protocol
  • Repeat
  • Very few attempts to give rigorous definitions,
    let alone proofs
  • Notable exception Rackoff and Simon, 1993

5
General Structure Chaumian Mixes
  • Choose a random path and send message along path
  • Hope for sufficiently many collisions along path
  • If N nodes, and polylog(N) length path, then
    essentially need all nodes to send messages
  • Does not matter how many nodes actually want to
    send messages, many dummy messages required.

Many attacks, counter measures, counter attacks,
counter counter measures, etc.
6
Chaums reduction to traffic analysis Onion
Routing
Note messages are same length
7
Prior work Chaumian Mixes
Honest nodes are used to prevent adversary from
knowing how messages were routed A to C, A to
C, or A to C, A to C.
8
Our Results
  • New definitions of unlinkability based on
    information theory
  • Prove equivalence to Rackoff-Simon definitions
  • Prove that a suitable modification of Chaums
    original protocol is secure
  • Argue that many previous informal arguments
    must be wrong
  • Improve (?) on Rackoff-Simon in many ways
  • Adaptive adversary, allow arbitrary prior
    knowledge
  • No secure computation
  • Much, much, simpler
  • Much more efficient. No need to flood network
    with dummy messages
  • Weaker attack model (not all links are under
    adversary control) (New definition of improve)

9
Only Traffic Analysis
  • We will simply assume during this talk that the
    adversary cannot do anything except eavesdrop
    onto traffic
  • An Adversary controlled link reports on all
    traffic through the link
  • An Adversary controlled node reports on all
    trafic through the node and how routing was done

10
How to define Unlinkability
  • ? - Random variable, permutation from S to T,
    may be drawn from arbitrary prior distribution
  • C Random variable, gives all the adversary
    learns during communications

11
How to define Unlinkability
  • Rackoff and Simon
  • Let n be a security parameter, C and ? as
    before

(Were ignoring the issue of computational
indistinguishability in this talk) (RS only
allow the uniform prior distribution)
12
Other Definitions (Equivalent)
We need the following observation to prove these
equivalences, 0 a 1
Is this new? Seems unlikely.
13
Why use I(AB) rather than 1?
  • I(AB) is monotonic

1 is not monotonic (the little birdy principle
does not work)
The intuition the closer to the prior, B, the
less information the adversary has
Let A be a random variable giving the number of
heads in 10 coin tosses Let B be the binomial
distribution for the number of heads in 10 coin
tosses Let C be a random variable giving the
number of heads in the first coin toss Let D be a
random variable giving the number of heads in the
2nd coin toss
14
The little Birdy Principle
  • Richard M. Karp (1988)
  • Revealing more information to the adversary only
    makes his/her life easier
  • Certainly true in the context of computational
    complexity
  • Is this true in the context of unlinkability?
  • Depends on the definition of unlinkability
  • Many previous papers implicitly make use of the
    little birdy principle in informal arguments
  • Does not hold for the Rackoff-Simon definitions

15
How could this possibly be?
  • The little birdy principle must hold, its
    obvious, isnt it?
  • Actually, in some form it does hold, it holds on
    average
  • The reason that it does not always hold is that
    in some circumstances, revealing more information
    (selected information), only confuses the
    adversary
  • There must be a good political joke here
    somewhere, but I could not figure it out

16
How to prove unlinkability
  • Define Protocol
  • Define Obscurant Network
  • Construct Obscurant Networks
  • Search for Obscurant Network embedding within
    execution of protocol (Uses Little Birdy
    Principle)
  • Extend result to allow prior information Use
    protocol folding (Uses Little Birdy Principle)

17
The protocol
  • Nodes wishing to send messages (and only nodes
    wishing to send messages)
  • Choose a random path of length polylog(N)
  • Use Chaums onion routing to send and receive
    messages along this path

18
Silly, isnt it?
  • If only 100 messages are initiated, and there are
    106 nodes in the network, there will be no
    collusions
  • If the adversary controls all links then the
    adversary knows exactly who is talking to whom
  • Change attack model adversary controls all by an
    arbitrarily small constant fraction of the links

19
The protocol
20
Introducing ambiguity via links
A crossover structure of honest links introduces
ambiguity
21
Obscurant Networks
  • A network with crossover switches such that a
    pebble placed on the inputs, and setting all
    crossovers uniformly at random, will result in a
    uniform distribution over the outputs
  • Example Butterfly network
  • Important an obscurant network does not obscure
    permutations
  • What about non-powers of 2?

22
Obscurant Networks of all sizes
Uniformly at random for these nodes
Uniformly at random for these nodes
Average the probability mass
23
Do permutation obscurant networks exist??
  • Dont know, open problem.
  • Dont you need a permutation obscurant network??
  • Yes, and no, what we actually find are repeated
    embeddings of single pebble obscurant networks

24
A combinatorial lemma (N. Alon, FOCS 2001)
  • Given a graph with a constant fraction, f, of the
    total edges
  • Choose 4 nodes at random
  • A crossover network will connect them with
    probability f4
  • f is the fraction of honest edges

25
Strategy
  • Reveal all links used in every 2nd layer, this is
    to make pairs of layers independent choices of
    four nodes
  • For a sufficiently long set of paths, find an
    obscurant network in the execution of the
    protocol
  • Reveal all other edges
  • This revelation should not harm the protocol
    (requires some effort)

26
Strategy (continued)
  • How do we move from single pebble obscurant to
    unlinkable?
  • Reveal the jth path (as a proof technique!!) to
    argue about the others

27
Dealing with Prior Information
Reveal to the adversary the relationship between
layer i and layer 6-i
28
Dealing with Prior Information Folding the
Network upon itself
29
Completing the Argument Prior Information
Because the distributions
(Choose the last T-1 levels at random, and fill
in the 1st level to get the permutation)
Given the middle permutation, and c2 ? C2, we can
compute p, thus the data processing inequality
holds
Write a Comment
User Comments (0)
About PowerShow.com