Title: Application of Steady-State Heat Transfer
1Application of Steady-State Heat Transfer
2Steady-state heat transfer
- Temperature in a system remains constant with
time. - Temperature varies with location.
3Conductive heat transfer in a rectangular slab
4Example
- For the stainless steel plate 1 cm thick is
maintained at 110?C, while the other face is at
90 ?C. Calculate temperature at 0.5 cm from the
110?C-temperature face. - Given
- heat flux 34,000 W/m2
- thermal conductivity of stainless steel 17 W/m
?C
5Conductive Heat Transfer through a Tubular
Pipe
- Consider a long hollow cylinder
6Conductive Heat Transfer through a Tubular
Pipe
- Consider a long hollow cylinder
7Example
- A 2 cm thick steel pipe (k 43 W/m?C) with 6 cm
inside diameter is being used to convey steam
from a boiler to process equipment for a distance
of 40 m. The inside pipe surface temperature is
115?C, and the outside pipe surface temperature
is 90?C. Under steady state conditions, calculate
total heat loss to the surrounding.
8Heat conduction in multilayered systems
9Composite rectangular wall (in series)
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11 composite thermal resistance
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13Composite rectangular wall (in parallel)
q A ?T k / x A ?T / (x/k) ? T1
?T2 ?T3 ?T R Resistance x/k
1/C 1/RT 1/R11/ R21/ R3
(1/(x1 / k 1)) (1/(x2 / k 2)) (1/(x3
/ k 3))
14and it is resistance which is additive when
several conducting layers lie between the hot and
cool regions, because A and Q are the same for
all layers. In a multilayer partition, the total
conductance is related to the conductance of its
layers by
So, when dealing with a multilayer partition, the
following formula is usually used
15Example
- A cold storage wall (3m X 6m) is constructed of a
15 cm thick concrete (k 1.37 W/m?C). Insulation
must be provided to maintain a heat transfer rate
through the wall at or below 500 W. If k of
insulation is 0.04 W/m?C. The outside surface
temperature of the wall is 38?C and the inside
wall temperature is 5?C.
16Example
How many joules of thermal energy flow through
the wall per second? ----------------------------
--------------- Heat is like a fluid  whatever
flows through the insulation must also flow
through the wood.Â
17Across insulationHins (0.20)(40)(25 -
T)/0.076 Â Â Â Â 2631.6 -105.3 T Â Â Â Â Â
Across woodHwood (0.80)(40)(T - 4)/0.019Â Â
  1684.2 T - 6736.8Heat is like a fluid
 whatever flows through the insulation must also
flow through the woodHwood   Hins  1684.2
T - 6736.8 2631.6 -105.3 T Â Â 1789.5 T
9368.4 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
   T 5.235 C    HHwoodHins      Â
             H 1684.2 (5.235) -
6736.8 2080 J/s   H 2631.6 - 105.3 (5.235)
 2080 J/s  Â
                   k
(insulation) 0.20 J/(s-m-C)k (wood) Â Â Â
0.80 J/(s-m-C)
18Series and parallel one-dimensional heat transfer
through a composite wall and electrical analog
19Composite cylindrical tube(in series)
r1
r3
r2
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21Example
- A stainless steel pipe (k 17 W/m?C) is being
used to convey heated oil. The inside surface
temperature is 130?C. The pipe is 2 cm thick with
an inside diameter of 8 cm. The pipe is insulated
with 0.04 m thick insulation (k 0.035 W/m?C).
The outer insulation temperature is 25?C.
Calculate the temperature of interface between
steel and isulation. Assume steady-state
conditions.
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23THERMAL CONDUCTIVITY CHANGE WITH TEMPERATURE
Heat transfer through a slab
?
24THERMAL CONDUCTIVITY CHANGE WITH TEMPERATURE
Heat transfer through a cylindrical tube
25Problem
- 1. Find the heat transfer per unit area through
the composite wall. Assume one-dimensional heat
flow.
Given kA 150 W/m?C kB 30 W/m?C kC 50
W/m?C kD 70 W/m?C AB AD
26Problem
- 2. One side of a copper block 5 cm thick is
maintained at 260?C. The other side is covered
with a layer of fiber glass 2.5 cm thick. The
outside of the fiber glass is maintained at 38?C,
and the total heat flow through the
copper-fiber-glass combination is 44 kW. What is
the area of the slab? - 3. A wall is constructed of 2.0 cm of copper, 3.0
mm of asbestos, and 6.0 cm of fiber glass.
Calculate the heat flow per unit area for an
overall temperature difference of 500?C.
27Problem
- 4. A certain material has a thickness of 30 cm
and a thermal conductivity of 0.04 W/m?C. At a
particular instant in time the temperature
distribution with x, the distance from the left
face, is T 150x2 - 30x, where x is in meters.
Calculate the heat flow rates at x 0 and x 30
cm. Is the solid heating up or cooling down? - 5. A certain material 2.5 cm thick, with a
cross-sectional area of 0.1 m2, has one side
maintained at 35?C and the other at 95?C. The
temperature at the center plane of the material
is 62?C, and the heat flow through the material
is 1 kW. Obtain an expression for the thermal
conductivity of the material as a function of
temperature.