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Title: Object-Oriented Design Inheritance and Class Examples


1
Object-Oriented DesignInheritance and Class
Examples
2
Inheritance Example -- Class.zip
  • One reason to use inheritance is that it permits
    you to reuse code from a previous project, but
    gives you the flexibility to slightly modify it
    if the old code doesn't do exactly what you need
    for the new project.
  • It doesn't make sense to start every new project
    from scratch since some code will certainly be
    repeated in several programs and you should
    strive to build on what you did previously.

3
INHERITANCE
  • A SIMPLE CLASS TO START WITH
  • Example program ------gt VEHICLE.H

4
VEHICLE.H
  • It consists of four simple methods which can be
    used to manipulate data pertaining to our
    vehicle.
  • We will eventually refer to this as a base class
    or parent class.

5
THE IMPLEMENTATION FOR VEHICLE Example program
------gt VEHICLE.CPP
  • The initialize() method assigns the values input
    as parameters to the wheels and weight variables.
  • We have methods to return the number of wheels
    and the weight, and finally, we have one that
    does a trivial calculation to return the loading
    on each wheel.

6
USING THE VEHICLE CLASS Example program ------gt
TRANSPRT.CPP
  • Inheritance uses an existing class and adds
    functionality to it to accomplish another,
    possibly more complex job.
  • It declares four objects of the vehicle class,
    initializes them, and prints out a few of the
    data values to illustrate that the vehicle class
    can be used as a simple class because it is a
    simple class. We are referring to it as a simple
    class as opposed to calling it a base class or
    derived class as we will do next.

7
OUR FIRST DERIVED CLASS Example program ------gt
CAR.H
  • The vehicle class is inherited due to the "
    public vehicle" added to line 7.
  • This derived class named car is composed of all
    of the information included in the base class
    vehicle, and all of its own additional
    information.
  • Even though we did nothing to the class named
    vehicle, we made it into a base class because of
    the way we are using it here.

8
OUR FIRST DERIVED CLASS Example program ------gt
CAR.H
  • To go a step further, even though it will be used
    as a base class in an example program later,
    there is no reason it cannot continue to be used
    as a simple class in the previous example
    program.
  • In fact, it can be used as a simple class and a
    base class in the same program. The question of
    whether it is a simple class or a base class is
    answered by the way it is used.

9
OUR FIRST DERIVED CLASS Example program ------gt
CAR.H
  • In this case, the vehicle base class can be used
    to declare objects that represent trucks, cars,
    bicycles, or any number of other vehicles you can
    think up.
  • The class named car however can only be used to
    declare an object that is of type car because we
    have limited the kinds of data that can be
    intelligently used with it.
  • The car class is therefore more restrictive and
    specific than the vehicle class. The vehicle
    class is more general than the car class.

10
OUR FIRST DERIVED CLASS Example program ------gt
CAR.H
  • If we wished to get even more specific, we could
    define a derived class using car as the base
    class, name it sports_car, and include such
    information as red_line_limit for the tachometer
    which would be silly for the family station
    wagon.
  • The car class would therefore be used as a
    derived class and a base class at the same time,
    so it should be clear that these names refer to
    how a class is used.

11
HOW DO WE DECLARE A DERIVED CLASS?
  • A derived class is defined by including the
    header file for the base class as is done in line
    5, then the name of the base class is given
    following the name of the derived class separated
    by a colon as is illustrated in line 7.
  • All objects declared as being of class car
    therefore are composed of the two variables from
    the class vehicle because they inherit those
    variables, and the single variable declared in
    the class car named passenger_load.

12
HOW DO WE DECLARE A DERIVED CLASS?
  • An object of this class will have three of the
    four methods of vehicle and the two new ones
    declared here.
  • The method named initialize() which is part of
    the vehicle class will not be available here
    because it is hidden by the local version of
    initialize() which is a part of the car class.
  • The local method will be used if the name is
    repeated allowing you to customize your new class.

13
A Graphical Representation of an object of this
class.
14
Information Hiding
  • Note that the implementation for the base class
    only needs to be supplied in its compiled form.
  • The source code for the implementation can be
    hidden for economic reasons to aid software
    developers.
  • Hiding the source code also allows the practice
    of information hiding. The header for the base
    class must be available as a text file since the
    class definitions are required in order to use
    the class.

15
THE CAR CLASS IMPLEMENTATION Example program
------gt CAR.CPP
  • The first thing you should notice is that this
    file has no indication of the fact that it is a
    derived class of any other file, that can only be
    determined by inspecting the header file for the
    class.
  • Since we can't tell if it is a derived class or
    not, it is written in exactly the same way as any
    other class implementation file.

16
ANOTHER DERIVED CLASS Example program ------gt
TRUCK.H
  • This class adds two more variables and three more
    methods.
  • A very important point that must be made is that
    the car class and the truck class have absolutely
    nothing to do with each other, they only happen
    to be derived classes of the same base class or
    parent class as it is sometimes called.

17
A Graphical Representation of the truck class
18
Example program ------gt TRUCK.H
  • Note that both the car and the truck classes have
    methods named passengers() but this causes no
    problems and is perfectly acceptable.
  • If classes are related in some way, and they
    certainly are if they are both derived classes of
    a common base class, you would expect them to be
    doing somewhat similar things.
  • In this situation there is a good possibility
    that a method name would be repeated in both
    child classes.

19
THE TRUCK IMPLEMENTATION Example program ------gt
TRUCK.CPP
  • Examine the file named TRUCK.CPP for the
    implementation of the truck class.
  • It has nothing unusual included in it.

20
USING ALL THREE CLASSES Example program ------gt
ALLVEHIC.CPP
  • It uses the parent class vehicle to declare
    objects and also uses the two child classes to
    declare objects.
  • This was done to illustrate that all three
    classes can be used in a single program.

21
Example program ------gt ALLVEHIC.CPP
  • All three of the header files for the classes are
    included in lines 3 through 5 so the program can
    use the components of the classes.
  • Notice that the implementations of the three
    classes are not in view here and do not need to
    be in view.
  • This allows the code to be used without access to
    the source code for the actual implementation of
    the class. However, it should be clear that the
    header file definition must be available.

22
Example program ------gt ALLVEHIC.CPP
  • In this example program, only one object of each
    class is declared and used but as many as desired
    could be declared and used in order to accomplish
    the programming task at hand.
  • The classes were developed, debugged, and stored
    away previously, and the interfaces were kept
    very simple.

23
Compile and Link
  • The three classes and the main() program can be
    compiled in any order desired.
  • All four must be compiled prior to linking the
    four resulting object (or binary) files together.
  • Be sure you do the required steps to compile and
    execute this program because the effective use of
    C will require you to compile many separate
    files and link them together.

24
WHY THE ifndef VEHICLE_H ?
  • When we define the derived class car, we are
    required to supply it with the full definition of
    the interface to the vehicle class since car is a
    derived class of vehicle and must know all about
    its parent.
  • We do that by including the vehicle class into
    the car class, and the car class can be compiled.
    The vehicle class must also be included in the
    header file of the truck class for the same
    reason.

25
WHY THE ifndef VEHICLE_H ?
  • When the preprocessor gets to the car class, it
    includes the vehicle class because it is listed
    in the car class header file, but since the
    vehicle class was already included in line 3 of
    ALLVEHIC.CPP, it is included twice and we attempt
    to re-declare the class vehicle.
  • Of course it is the same declaration, but the
    system doesn't care, it simply doesn't allow
    re-declaration of a class.

26
Linked ListsExamples
27
The Main Concept
  • Static Array
  • Pre-allocation Required
  • Waste-full if you allocate too much
  • Fatal if you allocate too little
  • Data has to be shifted when an item is inserted
    or deleted at specified position
  • Dynamic Array
  • Determine the size before allocating memory
  • Costly reallocation, insertion, deletion
  • Data has to be shifted
  • Linked List
  • Truly dynamic, memory is allocated as needed

28
Linked Lists
  • To maintain a given order you don't have to
    store data in this order.
  • Each item of the list points to the next one.
  • You can always determine the successor, no
    matter where it is physically.
  • You can insert and delete items without shifting
    the whole list.
  • The size of the list can be increased easily by
    adding successors.

29
(a) A linked list of integers (b) insertion (c)
deletion
30
Pointers
  • A pointer variable (or just pointer) contains the
    location of address in memory, of a memory cell.
  • By using a pointer to a particular memory cell,
    you can locate the cell and determine its content.

int p,q q1234 pq
31
Pointers dynamic memory allocation
  • A pointer can point at the memory area allocated
    at execution time.

int p pnew int10 (p2)1234 p12222 d
elete p
int p pnew int p1234 delete p
32
A pointer to an integer
33
(a) Declaring pointer variables (b) pointing to
statically allocated memory (c) assigning a value
34
(d) Allocating memory dynamically (e) assigning
a value (f) copying a pointer
35
(g) Allocating memory dynamically and assigning a
value (h) assigning NULL to a pointer variable
(i) de-allocating memory
36
An incorrect pointer to a de-allocated node
37
Programming with pointer variables and
dynamically allocated memory
38
Programming with pointer variables and
dynamically allocated memory
39
Programming with pointer variables and
dynamically allocated memory
40
Pointer-based Linked Lists
  • A linked list contains components that are linked
    to one another.
  • Each component (a node) contains
  • a data item,
  • a pointer to the next item.

41
A node
42
A Node
struct Node int item Node next
  • Any time you allocate memory using new, you must
    de-allocate it by using delete.
  • head points at the first element on the list.

Node p,head headNULL pnew
Node p-gtitem1 p-gtnextNULL headp ... delete
p
43
A head pointer to a list
44
A misconception
  • Memory is allocated for Node structure, head
    points at the allocated area.
  • head points at 'nothing'
  • The allocated memory is lost (a memory leak)
  • You shouldn't allocate memory for head, it is
    just a pointer.

headnew Node headNULL
45
A lost cell
46
The List Traversal
Let a current pointer point to the first node in
the linked list. while (the current pointer is
not NULL) Display the data portion of the
current node Set the current pointer to the next
pointer of the current node
Node cur ... for (curhead cur!NULL
curcur-gtnext) cout ltlt cur-gtitem ltlt endl
47
The effect of the assignment cur cur-gtnext
48
Deleting a Specified Node
  • Assumption The linked list exists.
  • There are three pointers set
  • head the first element of the list,
  • cur the current element of the list,
  • prev the previous element of the list.
  • Deletion

prev-gtnextcur-gtnext cur-gtnextNULL delete
cur curNULL
49
Deleting a node from a linked list
50
Deleting the First Node
  • The previous method doesn't work for the first
    element, because prev has nothing to point at.
  • This is a special case.
  • When the first node is deleted, the value of head
    has to be changed
  • headhead-gtnext
  • The memory occupied by the first element has to
    be de-allocated.

51
Deleting the first node
52
Summary of the deletion process
  • Locate the node using the List Traversal
    algorithm (keep in mind the special treatment of
    the first node).
  • Disconnect the node from the list by changing the
    pointers.
  • Return the node to the system (de-allocate
    memory).

53
Inserting a new node
  • cur points at the current node,
  • prev points at the previous node,
  • newPtr points at the new node which will be
    inserted before the current node.
  • 1st special case insertion at the beginning.
  • 2nd special case insertion at the end (actually
    not so special).

newPtrnew Node newPtr-gtdata999 newPtr-gtnextcu
r prev-gtnextnewPtr
54
Inserting a new node into a linked list
55
Inserting at the beginning of the List
  • head has to point to the new node.
  • the new node has to point at the beginning of the
    linked list.

newPtr-gtnexthead headnewPtr
56
Inserting at the beginning of a linked list
57
Inserting at the end of the List
  • It is not a special case.
  • It works exactly as for other nodes (except the
    head)
  • Add the new node when cur is NULL.

58
Inserting at the end of a linked list
59
Summary of the Insertion process
  • Determine the point of insertion (using the List
    Traversal algorithm)
  • Create a new node and store the new data in it.
  • Connect the new node to the linked list by
    changing appropriate pointers.

60
Determining cur and prev
  • The list should be traversed until the
    appropriate place for a new node is found.
  • Let's create a linked list of sorted numbers.
  • Insertions at the beginning and at the end are
    covered.

prevNULL curhead while(cur ! NULL and
newValue gt cur-gtitem) prevcur curcur-gtnext

61
When prev points to the last node and cur is
NULL, insertion will be at the end of the linked
list
62
When prev is NULL and cur points to the first
node, insertion or deletion will be at the
beginning of the linked list
63
A pointer-Based ADT List
private struct ListNode // a node
ListItemType item ListNode next
int size //number of items ListNode head
ListNode find(int index) const //
Returns a pointer to // the index-th node
// in the linked list.
typedef desired-type-of-list-item
ListItemType class List public //
constructors and destructor List()
// copy constructor List(const List
aList) List() // list
operations bool isEmpty() const int
getLength() const void insert(int index,
ListItemType newItem) void remove(int
index) void retrieve(int index,
ListItemType dataItem) const
64
Array vs. Pointer
  • an Array-Based List
  • Static arrays fixed size, some space is wasted.
  • Dynamic arrays the initial size is approximated,
    some space can be wasted, reallocation is costly.
  • To delete or insert an item all other items has
    to be shifted (costly)
  • a Pointer-Based List
  • memory allocation on demand, no direct access to
    a specified item (in order to find it the list
    has to be searched from its head).

65
Recursive Traversal
  • Write the contents of a list of characters.

struct Node char item Node next Node
stringPtr void writeString(Node stringPtr)
if (stringPtr ! NULL) // write the first
character cout ltlt stringPtr-gtitem
// write the string minus its first character
writeString(stringPtr-gtnext) // end if
// end writeString
66
Recursive Insertion
void linkedListInsert(Node headPtr, ItemType
newItem) if ((headPtr NULL) (newItem lt
headPtr-gtitem)) // base case insert
newItem at beginning // of the linked list
to which headPtr points Node newPtr new
Node if (newPtr NULL) throw
ListException( "ListException insert
cannot allocate memory") else
newPtr-gtitem newItem newPtr-gtnext
headPtr headPtr newPtr //
end if else linkedListInsert(headPtr
-gtnext, newItem) // end linkedListInsert
67
A Pointer Implementation
  • It is very common to implement a linked list
    using pointers and either structures or objects
    for the nodes.
  • Examine the file l-simple.zip for a simple
    implementation using pointers.

68
Linked List Example -- l-list.zip
  • This is an example of a singly linked linear
    list. It is in three files, list_node.h,
    main.cpp, and list_node.cpp.
  • This illustrates the general idea of linked lists
    done in the classical, procedural style,
    characterized by struct for a node.
  • Any node can be treated as the beginning of
    linked list.

69
Linked List Example -- l-class.zip
  • Implementation of a simple linked list using
    classes.

70
End of Lecture
  • All Programming Assignments due by the Final Exam
    day. (12/9)
  • Final Exam preparation Thurs., 12/2
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