Title: Exam 3: 2103 Chamberlin Hall, B102 Van Vleck
1Lecture 23
- Exam 3 2103 Chamberlin Hall, B102 Van Vleck
quiet room - CH Sections 604 605 606 609 610 611 (TA Moriah
T., Abdallah C., Tamara S.) - VV Sections 602 603 607 608 612 (TA Eric P., Dan
C., Zhe D.) - Format Closed book, three 8 x11 sheets, hand
written - Electronics Any calculator is okay but no
web/cell access - Quiet room Test anxiety, special accommodations,
etc. - Chapters Covered
- Chapter 9 Linear momentum and collision (not
9.9) - Chapter 10 Rotation about fixed axis and rolling
- Chapter 11 Angular Momentum (not 11.5)
- Chapter 12 Static equilibrium and elasticity
2Basic Concepts and Quantities
- Momentum, Angular Momentum
- Linear Momentum, Impulse
- Angular Momentum (magnitude and direction)
- Torque
- Collisions Elastic Inelastic
- Center of Mass
- Rotational Motion (1-axis)
- Angular displacement (?q) / Velocity(w),
Acceleration (a). - Moments of Inertia
- Rotational Kinetic Energy
- Conservation Laws Energy, Momentum, Angular
Momentum - Static Equilibrium
- Elasticity Youngs, Shear, Bulk Modulus
3Chapter 9 Momentum and Momentum Conservation
Ix
Ix
4Chapter 9
5Chapter 9
6Chapter 10
- At a point a distance R away from the axis of
rotation, the tangential motion - s (arc) ? R
- vT (tangential) ? R
- aT ? R
7Chapter 10
8Chapter 10
9Chapter 11
10Chapter 12
11Approach to Statics
- In general, we can use the two equations
- to solve any statics problems.
- When choosing axes about which to calculate
torque, choose one that makes the problem
easy.... - However if there is acceleration, then restrict
rotation axis to center of mass (as well as for
translation).
12Changes in length Youngs modulus
- Youngs modulus measures the resistance of a
solid to a change in its length.
F
elasticity in length
A
L0
?L
13Changes in volume Bulk Modulus
- Bulk modulus measures the resistance of solids
or liquids to changes in their volume.
Volume elasticity
14Changes in shape Shear Modulus
Applying a force perpendicular to a surface
15Comparison Kinematics
16Comparison Dynamics
m
I Si mi ri2
F a m
t r x F a I
L r x t I w
p mv
W F ?x
W ? D?
?K WNET
?K WNET
17Momentum and collisions
- Remember vector components
- A 5 kg cart rolling without friction to the right
at 10 m/s collides and sticks to a 5 kg
motionless block on a 30 frictionless incline. - How far along the incline do the joined blocks
slide?
18Momentum and collisions
- Remember vector components
- A 5 kg cart rolling without friction to the right
at 10 m/s collides and sticks to a 5 kg
motionless block on a q30 frictionless incline.
- Momentum parallel to incline is conserved
- Normal force (by ground on cart) is ? to the
incline - mvi cos q m 0 2m vf ? vf vi cos q /
2 4.4 m/s -
- Now use work-energy
- 2mgh 0 ½ 2m v2f ? d h / sin q v2f
/ (2g sin q)
mvi cos q
mvi
19 Example problem Going in circles A
- A 2.0 kg disk tied to a 0.50 m string undergoes
circular motion on a rough but horizontal table
top. The kinetic coefficient of friction is
0.25. If the disk starts out at 5.0 rev/sec how
many revolutions does it make before it comes to
rest? - Work-energy theorem
- W F d 0 ½ mv2
- F -mmg d - ½ mv2
- d v2 /(2mg)(5.0 x 2p x 0.50)2/ (0.50 x 10) m
5 p2 m - Rev d / 2pr 16 revolutions
- What if the disk were tilted by 60 ?
Top view
20 Example problem Going in circles B
- A 2.0 kg disk tied to a long string undergoes
circular motion on a frictionless horizontal
table top. The string passes through a hole and
then hangs vertically. The disk starts out at 5.0
rev/sec 0.50 m away from hole. If you pull
slowly down on the string so that the final
radius is 0.25 m, what is the final angular
velocity? - No external torque so angular momentum is
conserved. - Ib wb Ia wa
- I mR2
- (0.50)2 wb (0.25)2 wa
- 4 wb wa 20 rev/sec
21Spinning ball on incline
- A solid disk of mass m and radius R is spinning
with angular velocity w. It is positioned so that
it can either move directly up or down an incline
of angle q (but it is not rolling motion). The
coefficient of kinetic friction is m. At what
angle will the disks position on the incline not
change?
w
q
22Spinning ball on incline
- A solid disk of mass m and radius R is spinning
with angular velocity w. It is positioned so that
it can either move directly up or down an incline
of angle q (but it is not rolling motion). The
coefficient of kinetic friction is m. - At what angle will the disks position on the
incline not change?
23Spinning ball on incline
- A solid disk of mass m and radius r is spinning
with angular velocity w. It is positioned so that
it can either move directly up or down an incline
of angle q (but it is not rolling motion). The
coefficient of kinetic friction is m. While
spinning the disks position will not change. - How long will it be before it starts to roll?
- This will occur only when w0.
24Example Problem
- A 3.0 kg mass is attached to a light, rigid rod
1.5 m long. The rod is vertical and is anchored
to the ground through a frictionless pivot. It
sits perfectly balanced at an unstable
equilibrium. A 500 gm bullet is shot
horizontally at 100 m/s through the mass. The
force versus time plot is shown. - How fast is the bullet going when
- it leaves?
- What is the tension in the rod just
- after the bullet exits?
Method Impulse
I area under curve
25Example Problem
- A 3.0 kg mass is attached to a light, rigid rod
1.5 m long. The rod is vertical and is anchored
to the ground through a frictionless pivot. It
sits perfectly balanced at an unstable
equilibrium. A 500 gm bullet is shot
horizontally at 100 m/s through the mass. The
force versus time plot is shown. - How fast is the bullet going when
- it leaves?
26Example Problem
- A 3.0 kg mass is attached to a light, rigid rod
1.5 m long. The rod is vertical and is anchored
to the ground through a frictionless pivot. It
sits perfectly balanced at an unstable
equilibrium. A 500 gm bullet is shot
horizontally at 100 m/s through the mass. The
force versus time plot is shown. - What is the tension in the rod just
- after the bullet exits?
27Statics Example
- A sign of mass M is hung 1 m from the end of a
4 m long beam (mass m) as shown in the diagram.
The beam is hinged at the wall. What is the
tension in the wire in terms of m, M, g and any
other given quantity?
wire
q 30o
1 m
SIGN
28Statics Example
T
Fy
30
X
Fx
mg
2 m
Mg
3 m
Process Make a FBD and note known / unknown
forces. Chose axis of rotation at support because
Fx Fy are not known
- F 0 ? 0 Fx T cos 30
- 0 Fy T sin 30 - mg - Mg
- z-dir Stz 0 -mg 2r Mg 3r T sin 30 4r
(r 1m) - The torque equation get us where we need to go, T
- T (2m 3M) g / 2
29Center of Mass Example Astronauts Rope
- Two astronauts are initially at rest in outer
space and 20 meters apart. The one on the right
has 1.5 times the mass of the other (as shown).
The 1.5 m astronaut wants to get back to the ship
but his jet pack is broken. There happens to be
a rope connected between the two. The heavier
astronaut starts pulling in the rope. - (1) Does he/she get back to the ship ?
- (2) Does he/she meet the other astronaut ?
M 1.5m
m
30Example Astronauts Rope
- There is no external force so if the larger
astronaut pulls on the rope he will create an
impulse that accelerates him/her to the left and
the small astronaut to the right. The larger
ones velocity will be less than the smaller
ones so he/she doesnt let go of the rope they
will either collide (elastically or
inelastically) and thus never make it.
31Example Astronauts Rope
- (2) However if the larger astronaut lets go of
the rope he will get to the ship. (Too bad for
the smaller astronaut!) - In all cases the center of mass will remain fixed
because they are initially at rest and there is
no external force. - To find the position where they meet all we need
do is find the Center of Mass
32Forces and rigid body rotation
- To change the angular velocity of a rotating
object, a force must be applied - How effective an applied force is at changing the
rotation depends on several factors - The magnitude of the force
- Where, relative to the axis of rotation the force
is applied - The direction of the force
A
B
C
Which applied force will cause the wheel to spin
the fastest?
33Leverage
- The same concept applies to leverage
- the lever undergoes rigid body rotation about a
pivot point
B
C
A
Which applied force provides the greatest lift ?
34More on torques
- You need to change the tire on you car. You use a
tire wrench which allows you to apply a pair of
forces. - (A) What is the torque produced by a tire wrench
of length L, given an applied couple of magnitude
F, acting on a lug nut (point F) as shown in the
figure? - (B) Assume the lug nut is stuck What is the
torque acting on the wheel, if the lug nut is a
distance r from the center?
Image courtesy John Wiley Sons, Inc.
35Wheel wrench
- 1. tF (L/2) F (L/2) F LF
- 2. tF r F sinf r F sin ( p-q )
- LF
- 3. tF L F 0 F
- Notice the torque is the same everywhere.
f
f
36For Thursday
- Chapter 13 (Newtons Law of Gravitation)
37Momentum Impulse
- A rubber ball collides head on (i.e., velocities
are opposite) with a clay ball of the same mass.
The balls have the same speed, v, before the
collision, and stick together after the
collision. What is their speed immediately after
the collision?
- 0
- ½ v
- 2 v
- 4 v
38Momentum Impulse
- A rubber ball collides head on with a clay ball
of the same mass. The balls have the same speed,
v, before the collision, and stick together after
the collision. What is their speed after the
collision? - (a) 0
- (b) ½ v
- (c) 2 v
- (d) 4 v
39Momentum, Work and Energy
- A 0.40 kg block is pushed up against a spring
(with spring constant 270 N/m ) on a frictionless
surface so that the spring is compressed 0.20 m.
When the block is released, it slides across the
surface and collides with the 0.60 kg bob of a
pendulum. The bob is made of clay and the block
sticks to it. The length of the pendulum is 0.80
m. (See the diagram.) - To what maximum height above the surface will the
ball/block assembly rise after the collision?
(g9.8 m/s2) - A. 2.2 cm
- B. 4.4 cm
- C. 11. cm
- D. 22 cm
- E. 44 cm
- F. 55 cm
40Momentum, Work and Energy
- A 0.40 kg block is pushed up against a spring
(with spring constant 270 N/m ) on a frictionless
surface so that the spring is compressed 0.20 m.
When the block is released, it slides across the
surface and collides with the 0.60 kg bob of a
pendulum. The bob is made of clay and the block
sticks to it. The length of the pendulum is .80
m. (See the diagram.) - To what maximum height above the surface will the
ball/block assembly rise after the collision? - A. 2.2 cm
- B. 4.4 cm
- C. 11. cm
- D. 22 cm
- E. 44 cm
- F. 55 cm
41Momentum, Work and Energy ( Now with friction)
- A 0.40 kg block is pushed up against a spring
(with spring constant 270 N/m ) on a surface. - If mstatic 0.54, how far can the spring be
compressed and the block remain stationary (i.e.,
maximum static friction)? - S F 0 k u - f k u - m N
- u m mg/k 0.54 (0.40x10 N) / 270 N/m
0.0080 m
42Momentum, Work and Energy ( Now with friction)
- A 0.40 kg block is pushed up against a spring
(with spring constant 270 N/m ) on a surface.
The spring is compressed 0.20 m - If mkinetic 0.50 and the block is 9.8 m away
from the unstretched spring, how high with the
clay/block pair rise? - Emech (at collision) Uspring Wfriction ½ k
u2 - m mg d - 1/2 m v2 135(0.04)-0.50(0.40x10.)10.(540-20)
J520 J - v2 1040/0.40 m2/s2
- Now the collision (cons. of momentum) and the
swing.
43Momentum and Impulse
- Henri Lamothe holds the world record for the
highest shallow dive. He belly-flopped from a
platform 12.0 m high into a tank of water just
30.0 cm deep! Assuming that he had a mass of 50.0
kg and that he stopped just as he reached the
bottom of the tank, what is the magnitude of the
impulse imparted to him while in the tank of
water (in units of kg m/s)? - (a) 121
- (b) 286
- (c) 490
- (d) 623
- (e) 767
44Momentum and Impulse
- Henri Lamothe holds the world record for the
highest shallow dive. He belly-flopped from a
platform 12.0 m high into a tank of water just
30.0 cm deep! Assuming that he had a mass of 50.0
kg and that he stopped just as he reached the
bottom of the tank, what is the magnitude of the
impulse imparted to him while in the tank of
water (in units of kg m/s)? - (a) 121
- (b) 286
- (c) 490
- (d) 623
- (e) 767
Dp sqrt(2x9.8x12.3)x50
45Momentum Impulse
- Suppose that in the previous problem, the
positively charged particle is a proton and the
negatively charged particle, an electron. (The
mass of a proton is approximately 1,840 times the
mass of an electron.) Suppose that they are
released from rest simultaneously. If, after a
certain time, the change in momentum of the
proton is Dp, what is the magnitude of the change
in momentum of the electron? - (a) Dp / 1840
- (b) Dp
- (c) 1840 Dp
46Momentum Impulse
- Suppose that in the previous problem, the
positively charged particle is a proton and the
negatively charged particle, an electron. (The
mass of a proton is approximately 1,840 times the
mass of an electron.) Suppose that they are
released from rest simultaneously. If, after a
certain time, the change in momentum of the
proton is Dp, what is the magnitude of the change
in momentum of the electron? - (a) Dp / 1840
- (b) Dp
- (c) 1840 Dp
47Conservation of Momentum
- A woman is skating to the right with a speed of
12.0 m/s when she is hit in the stomach by a
giant snowball moving to the left. The mass of
the snowball is 2.00 kg, its speed is 25.0 m/s
and it sticks to the woman's stomach. If the mass
of the woman is 60.0 kg, what is her speed after
the collision? - (a) 10.8 m/s
- (b) 11.2 m/s
- (c) 12.4 m/s
- (d) 12.8 m/s
48Conservation of Momentum
- A woman is skating to the right with a speed of
12.0 m/s when she is hit in the stomach by a
giant snowball moving to the left. The mass of
the snowball is 2.00 kg, its speed is 25.0 m/s
and it sticks to the woman's stomach. If the mass
of the woman is 60.0 kg, what is her speed after
the collision? - (a) 10.8 m/s
- (b) 11.2 m/s
- (c) 12.4 m/s
- (d) 12.8 m/s
49Conservation of Momentum
- Sean is carrying 24 bottles of beer when he slips
in a large frictionless puddle. He slides
forwards with a speed of 2.50 m/s towards a very
steep cliff. The only way for Sean to stop before
he reaches the edge of the cliff is to throw the
bottles forward at 20.0 m/s (relative to the
ground). If the mass of each bottle is 500 g, and
Sean's mass is 72 kg, what is the minimum number
of bottles that he needs to throw? - (a) 18
- (b) 20
- (c) 21
- (d) 24
- (e) more than 24
50Momentum and Impulse
- A stunt man jumps from the roof of a tall
building, but no injury occurs because the person
lands on a large, air-filled bag. Which one of
the following statements best describes why no
injury occurs? - (a) The bag provides the necessary force to stop
the person. - (b) The bag reduces the impulse to the person.
- (c) The bag reduces the change in momentum.
- (d) The bag decreases the amount of time during
which the momentum is changing and reduces the
average force on the person. - (e) The bag increases the amount of time during
which the momentum is changing and reduces the
average force on the person.
51Momentum and Impulse
- A stunt man jumps from the roof of a tall
building, but no injury occurs because the person
lands on a large, air-filled bag. Which one of
the following statements best describes why no
injury occurs? - (a) The bag provides the necessary force to stop
the person. - (b) The bag reduces the impulse to the person.
- (c) The bag reduces the change in momentum.
- (d) The bag decreases the amount of time during
which the momentum is changing and reduces the
average force on the person. - (e) The bag increases the amount of time during
which the momentum is changing and reduces the
average force on the person.
52Momentum and Impulse
- Two blocks of mass m1 M and m2 2M are both
sliding towards you on a frictionless surface.
The linear momentum of block 1 is half the linear
momentum of block 2. You apply the same constant
force to both objects in order to bring them to
rest. What is the ratio of the two stopping
distances d2/d1? - (a) 1/ 2
- (b) 1/ 2½
- (c) 1
- (d) 2½
- (e) 2
- (f) Cannot be determined without knowing the
masses of the objects and their velocities.
53Momentum and Impulse
- Two blocks of mass m1 M and m2 2M are both
sliding towards you on a frictionless surface.
The linear momentum of block 1 is half the linear
momentum of block 2. You apply the same constant
force to both objects in order to bring them to
rest. What is the ratio of the two stopping
distances d2/d1? - (a) 1/ 2
- (b) 1/ 2½
- (c) 1
- (d) 2½
- (e) 2
- (f) Cannot be determined without knowing the
masses of the objects and their velocities.
54Momentum and Impulse
- In a table-top shuffleboard game, a heavy moving
puck collides with a lighter stationary puck as
shown. The incident puck is deflected through an
angle of 20 and both pucks are eventually
brought to rest by friction with the table. The
impulse approximation is valid (i.e.,the time of
the collision is short relative to the time of
motion so that momentum is conserved). - Which of the following
- statements is correct?
- A. The collision must be inelastic because the
pucks have different masses. - B. The collision must be inelastic because there
is friction between the pucks and the surface. - C. The collision must be elastic because the
pucks bounce off each other. - D. The collision must be elastic because, in the
impulse approximation, - momentum is conserved.
- E. There is not enough information given to
decide whether the collision is - elastic or inelastic.
55Momentum and Impulse
- In a table-top shuffleboard game, a heavy moving
puck collides with a lighter stationary puck as
shown. The incident puck is deflected through an
angle of 20 and both pucks are eventually
brought to rest by friction with the table. The
impulse approximation is valid (i.e.,the time of
the collision is short relative to the time of
motion so that momentum is conserved). - Which of the following
- statements is correct?
- A. The collision must be inelastic because the
pucks have different masses. - B. The collision must be inelastic because there
is friction between the pucks and the surface. - C. The collision must be elastic because the
pucks bounce off each other. - D. The collision must be elastic because, in the
impulse approximation, - momentum is conserved.
- E. There is not enough information given to
decide whether the collision is - elastic or inelastic.
56Exercise Ladder against smooth wall
- Bill (mass M) is climbing a ladder (length L,
mass m) that leans against a smooth wall (no
friction between wall and ladder). A frictional
force F between the ladder and the floor keeps it
from slipping. The angle between the ladder and
the wall is ?. - What is the magnitude of F as a function of
Bills distance up the ladder?
?
L
m
Bill
F
57Ladder against smooth wall...
- Consider all of the forces acting. In addition to
gravity and friction, there will be normal forces
Nf and Nw by the floor and wall respectively on
the ladder. - First sketch the FBD
Nw
L/2
?
- Again use the fact that FNET 0
in both x and y directions - x Nw F
- y Nf Mg mg
mg
d
Mg
F
Nf
58Ladder against smooth wall...
- Since we are not interested in Nw, calculate
torques about an axis through the top end of the
ladder, in the z direction.
torque axis
Nw
?
L/2
m
- Substituting Nf Mg mg andsolve for F
mg
a
d
Mg
F
Nf
a
59Example Ladder against smooth wall
We have just calculated that
- For a given coefficient of static friction
?s,the maximum force of friction F that can
beprovided is ?sNf ?s g(M m). - The ladder will slip if F exceedsthis value.
?
m
Cautionary note (1) Brace the bottom of
ladders! (2) Dont make ? too big!
d
F