Title: MOMENTUM
1MOMENTUM COLLISIONS
2Linear Momentum
- Moving objects have momentum
- Vector quantity
- Points in the same direction as the velocity
vector - Momentum
- Equals the product of an objects mass and
velocity - Proportional to mass and velocity
- p mv
- p momentum (kg m/s)
- m mass (kg)
- v velocity (m/s)
3TAXI PROBLEM
What is the taxi cabs momentum? Mass of the
taxi 53 kg Velocity of the taxi 1.2
m/s Answer p mv p (53 kg)(1.2 m/s) p
63.6 kg m/s to the left
p 63.6 kg m/s
v 1.2 m/s
4Momentum Newtons 2nd Law
- Newtons 2nd Law
- SF ma m(?v/?t)
- SF m(?v/?t)
- Momentum
- p mv ? m p/v
- SF (p/v)(?v/?t) ? SF ?p/?t
-
5Impulse change In momentum
- If the momentum of an object changes, either
mass, velocity, or both change - If mass remains the same ? than velocity changes
? acceleration occurs - What produces an acceleration?
- FORCE
- Greater the force acting on the object ? greater
its change in velocity ? greater its change in
momentum
6Impulse change in momentum
- How long the force acts is also important
- Stalled car
- Apply a force over a brief amount of time ?
produce a change in momentum - Apply the same force over an extended period of
time ? produce a greater change in the cars
momentum - A force suspended for a long time produces more
change in momentum than does the same force
applied briefly - Both force and time are important in changing
momentum
7Impulse change in momentum
- IMPULSE (J) ?p pf pi mvf mvi
- J Favg ?t
- Favg?t m?v
- Favg m?v/?t
- Impulse (J) Change in momentum
- Impulse is also the product of the average force
and the time during which the force is applied. - Vector quantity
- Units kg m/s
8Impulse problem
- A long jumper's speed just before landing is 7.8
m/s. What is the impulse of her landing? (mass
68 kg) - J ?p
- J pf - pi
- J mvf mvi
- J 0 - (68kg)(7.8m/s)
- J -530 kg m/s
- Negative sign indicates that the direction of
the impulse is opposite to her direction of motion
9Impulsive force
- Baseball player swings a bat and hits the ball,
the duration of the collision can be as short as
1/1000th of a second and the force averages in
the thousands of newtons - The brief but large force the bat exerts on the
ball Impulsive force
10Kinetic Books
- View Kinetic books section 8.4- Physics at play
Hitting a baseball - BASEBALL PROBLEM
- The ball arrives at 40 m/s and leaves at 49 m/s
in the opposite direction. The contact time is
5.010-4 s. What is the average force on the
ball? - J ?p Favg ?t m?v
- Favg ?t m?v
- Favg?t m?v
- Favg m?v/?t
- Favg (0.14kg)(49 (-40)m/s)/5.010-4 s
- Favg 2.5104 N
-
11Impulse change in momentum
- Case 1 Increasing momentum
- To increase the momentum of an object ? apply the
greatest force possible for as long as possible - Golfer teeing off and a baseball player trying
for a home run - Swing as hard as possible (large force)
- Follow through with their swing (increase in
time)
12Impulse change in momentum
- Case 2 Decreasing momentum
- You are in a car that is out of control ? Do you
want to hit a cement wall or haystack? - In either case, your momentum is decreased by the
same impulse - But, the same impulse does not mean the same
amount of force or the same amount of time ?
rather it means the same PRODUCT of force and
time
13Impulse change momentum
- Case 2 continued Decreasing momentum
- Hit the haystack ? Extend the impact time
- Change in momentum occurs over a long time ?
Small impact force - mv Ft
- Hit the cement wall
- Change in momentum occurs over a short time ?
Large impact force - mv Ft
14Changing Momentum Scenario 1
- If you want to decrease a large momentum, you
can have the force applied for a longer time - If the change in momentum occurs over a
long time ? Force of impact is small - Examples
- Air bags in cars.
- Crash test video
FDt
15Changing Momentum Scenario 2
- If the change in momentum occurs over a short
time, the force of impact is large. - Karate link
- Boxing video
FDt
16Impulse change in momentum
- QUESTION
- When a glass falls, will the impulse be less if
it lands on a carpet than if it lands on a hard
floor? - NO? Impulse is the same for either surface
because the change in momentum is the same - Carpet More time is available for the change in
momentum ? smaller force for the impulse - Hard floor Less time is available for the change
in momentum (due to less give) ? larger force
for the impulse
17Conservation of momentum
- Conservation of momentum
- Occurs when there are no net external force(s)
acting on the system - Result ? Total momentum of an isolated system is
constant - Momentum before Momentum after
- Playing pool example
- Kinetic books 8.6
18Conservation of momentum
- Momentum
- p mv
- Conservation of momentum
- Momentum before Momentum after
- pi1 pi2 pin pf1 pf2 pfn
- pi1, pi2, , pin initial momenta
- pf1, pf2, , pfn final momenta
- m1vi1 m2vi2 m1vf1 m2vf2
- m1, m2 masses of objects
- vi1, vi2 initial velocities
- vf1, vf2 final velocities
19Conservation of momentum
- A 55.0 kg astronaut is stationary in the
spaceships reference frame. She wants to move at
0.500 m/s to the left. She is holding a 4.00 kg
bag of dehydrated astronaut chow. At what
velocity must she throw the bag to achieve her
desired velocity? (Assume the positive direction
is to the right.)
20solution
- VARIABLES
- Mass of astronaut ma 55 kg
- Mass of bag mb 4 kg
- Initial velocity of astronaut via 0 m/s
- Initial velocity of bag vib 0 m/s
- Final velocity of astronaut vfa -0.5 m/s
- Final velocity of bag vfb ?
- EQUATION
- m1vi1 m2vi2 m1vf1 m2vf2
- mavia mbvib mavfa mbvfb
- 0 mavfa mbvfb
- Vfb - (mavfa / mb)
- Vfb - ((55kg)(-0.5m/s))/(4kg) 6.875 m/s
21collisions
- Collision of objects ? Demonstrates the
conservation of momentum - Whenever objects collide in the absence of
external forces - net momentumbefore collision net momentumafter
collision
22collisions
- Momentum is conserved in ALL TYPES of collisions
- Elastic Collisions
- Objects collide without being permanently
deformed and without generating heat - Inelastic Collisions
- Colliding objects become distorted (tangled or
coupled together) and generate heat
23collisions
- Problem
- Consider a 6-kg fish that swims toward and
swallows a 2-kg fish that is at rest. If the
larger fish swims at 1 m/s, what is its velocity
immediately after lunch? - net momentumbefore collision net momentumafter
collision - (net mv)before (net mv)after
- (6kg)(1m/s) (2kg)(0) (6kg 2kg)(vafter)
- vafter ¾ m/s
24collisions
- Problem
- Consider a 6-kg fish that swims toward and
swallows a 2-kg fish that is moving towards the
larger fish at 2 m/s. If the larger fish swims at
1 m/s, what is its velocity immediately after
lunch? - net momentumbefore collision net momentumafter
collision - (net mv)before (net mv)after
- (6kg)(1m/s) (2kg)(-2m/s) (6kg 2kg)(vafter)
- vafter 1/4 m/s
25collisions
- Perfectly Elastic collisions
- Not common in the everyday world
- Some heat is generated during collisions
- Drop a ball and after it bounces from the floor,
both the ball and the floor are a bit warmer - At the microscopic level ? perfectly elastic
collisions are common - Electrically charged particles bounce off one
another without generating heat
26Examples of Perfectly ELASTIC Collisions
- Electron scattering
- Hard spheres (Pool balls)
27collisions
- Elastic collision
- Kinetic energy is conserved
- KE before KE after
- KE 1/2mv2
- Momentum is conserved in any collision ? Elastic
or inelastic
28ELASTIC collisions in 1-dimension
- Conservation of Kinetic Energy
- Conservation of Momentum
- Rearrange both equations and divide
29Elastic collisions
- Final velocities in Head-On Two-Body Elastic
Collisions (v2i 0 m/s)
30Examples of Perfectly INELASTIC Collisions
- Catching a baseball Video
- Football tackle
- Cars colliding and sticking
- Bat eating an insect
31collisions
- Inelastic collision
- Kinetic energy is NOT conserved
- KE before ? KE after
- Momentum is conserved in any collision ? Elastic
or inelastic
32Perfectly INELASTIC collisionsin 1-dimension
- Final velocities are the same
33Problem
A 5879-lb (2665 kg) Cadillac Escalade going 35
mph smashes into a 2342-lb (1061 kg) Honda Civic
also moving at 35 mph (15.64 m/s) in the opposite
direction. The cars collide and stick.
a) What is the final velocity of the two
vehicles?
- m1v1i m2v2i (m1 m2)vf
- (2665kg)(15.64m/s) (1061kg)(-15.64m/s) (2665
1061kg)vf - vf 6.73 m/s 15.1 mph
34Collisions
- Momentum is always conserved in a collision
- Collision video
- Classification of collisions
- ELASTIC
- Both energy momentum are conserved
- INELASTIC
- Momentum conserved, not energy
- Perfectly inelastic -gt objects stick
- Lost energy goes to heat
35Center of mass
- Average location of mass
- An object can be treated as though all its mass
were located at this point - For a symmetric object made from a uniformly
distributed material, the center of mass is the
same as its geometric center
36Center of mass
- Equation
- xcm m1x1 m2x2 mnxn / m1 m2 mn
- xCM x position of center of mass
- mi mass of object i
- xi x position of object i
37Center of mass
- View section 8.20 in Kinetic books
- Specifically example 1- Center of mass problem
-
38Center of Mass
- Video
- Balancing Activity video demo
39Dont use following slides???
40Conservation of momentum
- Key Facts
- Newtons 2nd Law (F ma)
- To accelerate an object ? Net force must be
applied - To change the momentum of an object ? exert an
impulse on it - The momentum of a system cannot change unless it
is acted on by external forces
41Conservation of momentum
- Law of Conservation of Momentum
- In the absence of an external force, the momentum
of a system remains unchanged - Examples in which the net momentum is the same
before and after the event - Radioactive decay
- Cars colliding
- Stars exploding
42Conservation of Momentum
mv(initial) mv(final) An astronaut of mass
80 kg pushes away from a space station by
throwing a 0.75-kg wrench which moves with a
velocity of 24 m/s relative to the original frame
of the astronaut. What is the astronauts recoil
speed?
(0.75kg)(24m/s) 80kg(v) v 0.225 m/s
43Conservation of momentum
- Question
- Newtons 2nd law states that if no net force is
exerted on a system, no acceleration occurs. Does
it follow that no change in momentum occurs? - Yes, because no acceleration (a ?v/t) ? means
no change in velocity ? and no change in momentum
(p m?v) - Also, no net force means ? no net impulse (J
Ft) ? J ?p ? no change in momentum
44Conservation of momentum
- Question
- Newtons 3rd law states that the force a rifle
exerts on a bullet is equal and opposite to the
force the bullet exerts on the rifle. Does is
follow that the impulse the rifle exerts on the
bullet is equal and opposite to the impulse the
bullet exerts on the rifle? - Yes, because the rifle acts on the bullet and
bullet reacts on the rifle during the same time
interval - Since time is equal and force is equal and
opposite for both ? Impulse, Ft, is also equal
and opposite for both (Impulse vector quantity
and can be canceled)
45Conservation of momentum
- The law of conservation of momentum can be
derived from Newtons 2nd and 3rd laws - Newtons 2nd law ? F ma
- Newtons 3rd law ? Forces are equal but opposite
- Refer to Kinetic Books- 8.7 For step-by-step
derivation
46collisions
- Collisions
- Momentum- Useful concept when applied to
collisions - In a collision, two or more objects exert forces
on each other for a brief instant of time, and
these forces are significantly greater than any
other forces they may experience during the
collision
47Problem
A proton (mp1.67x10-27 kg) elastically collides
with a target proton which then moves straight
forward. If the initial velocity of the
projectile proton is 3.0x106 m/s, and the target
proton bounces forward, what are a) The final
velocity of the projectile proton? b) The final
velocity of the target proton?
0.0 m/s 3.0 x 106 m/s
48Elastic collision in 1-dimension
- Final equations for head-on elastic collision
- Relative velocity changes sign
- Equivalent to Conservation of Energy
49Problem
An proton (mp1.67x10-27 kg) elastically collides
with a target deuteron (mD2mp) which then moves
straight forward. If the initial velocity of the
projectile proton is 3.0x106 m/s, and the target
deuteron bounces forward, what are a) The final
velocity of the projectile proton? b) The final
velocity of the target deuteron?
vp -1.0 x 106 m/s vd 2.0 x 106 m/s Head-on
collisions with heavier objects always lead to
reflections