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Molarity, Dilution, and pH

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* Molarity Equation To calculate a solution s molarity, you must know the volume of the solution in liters and the amount of dissolved solute in moles. – PowerPoint PPT presentation

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Title: Molarity, Dilution, and pH


1
Molarity, Dilution, and pH
  • Main Idea Solution concentrations are measured
    in molarity. Dilution is a useful technique for
    creating a new solution from a stock solution. pH
    is a measure of the concentration of hydronium
    ions in a solution.

2
Molarity Review
  • One of the most common units of solution
    concentration is molarity.
  • Molarity (M) is the number of moles of solute per
    liter of solution.
  • Molarity is also known as molar concentration,
    and the unit M is read as molar.
  • A liter of solution containing 1 mol of solute is
    a 1M solution, which is read as a one-molar
    solution.
  • A liter of solution containing 0.1 mol of solute
    is a 0.1 M solution.

3
Molarity Equation
  • To calculate a solutions molarity, you must know
    the volume of the solution in liters and the
    amount of dissolved solute in moles.
  • Molarity (M) moles of solute
  • liters of solution

4
Molarity Example
  • A 100.5-mL intravenous (IV) solution contains
    5.10 g of glucose (C6H12O6). What is the molarity
    of the solution? The molar mass of glucose is
    180.16 g/mol.
  • SOLUTION
  • Calculate the number of moles of C6H12O6 by
    dividing mass over molar mass 0.0283 mol
    C6H12O6
  • Convert the volume of H2O to liters by dividing
    volume by 1000 0.1005 L
  • Solve for molarity by dividing moles by liters
    0.282 M

5
Preparing Molar Solutions
  • Now that you know how to calculate the molarity
    of a solution, how would you prepare one in the
    laboratory?
  • STEP 1 Calculate the mass of the solute needed
    using the molarity definition and accounting for
    the desired concentration and volume.
  • STEP 2 The mass of the solute is measured on a
    balance.
  • STEP 3 The solute is placed in a volumetric
    flask of the correct volume.
  • STEP 4 Distilled water is added to the flask to
    bring the solution level up to the calibration
    mark.

6
http//www.ltcconline.net/stevenson/2008CHM101Fall
/CHM101LectureNotes20081022.htm
7
Diluting Molar Solutions
  • In the laboratory, you might use concentrated
    solutions of standard molarities, called stock
    solutions.
  • For example, concentrated hydrochloric acid (HCl)
    is 12 M.
  • You can prepare a less-concentrated solution by
    diluting the stock solution with additional
    solvent.
  • Dilution is used when a specific concentration is
    needed and the starting material is already in
    the form of a solution (i.e., acids).

8
PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
  • Add water to the 3.0 M solution to lower its
    concentration to 0.50 M
  • Dilute the solution!

9
PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
But how much water do we add?
10
PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
  • How much water is added?
  • The important point is that ---gt

11
PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
  • Amount of NaOH in original solution
  • M V
  • (3.0 mol/L)(0.050 L) 0.15 mol NaOH
  • Amount of NaOH in final solution must also 0.15
    mol NaOH
  • Volume of final solution
  • (0.15 mol NaOH) / (0.50 M) 0.30 L
  • or 300 mL

12
PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
  • Conclusion
  • add 250 mL of water to 50.0 mL of 3.0 M NaOH to
    make 300 mL of 0.50 M NaOH.

13
Preparing Solutions by Dilution
  • A shortcut
  • M1 V1 M2 V2
  • Where M represents molarity and V represents
    volume. The 1s are for the stock solution and the
    2s are for the solution you are trying to create.

14
The pH scale is a way of expressing the strength
of acids and bases. Instead of using very small
numbers, we just use the NEGATIVE power of 10 on
the Molarity of the H (or OH-) ion.Under 7
acid 7 neutralOver 7 base
15
pH of Common Substances
16
Calculating the pH
  • pH - log H
  • (The means Molarity)
  • Example If H 1 X 10-10pH - log 1 X
    10-10
  • pH - (- 10)
  • pH 10
  • Example If H 1.8 X 10-5pH - log 1.8 X
    10-5
  • pH - (- 4.74)
  • pH 4.74

17
pH calculations Solving for H
  • If the pH of Coke is 3.12, H ???
  • Because pH - log H then
  • - pH log H
  • Take antilog (10x) of both sides and get
  • 10-pH H
  • H 10-3.12 7.6 x 10-4 M
  • to find antilog on your calculator, look
    for Shift or 2nd function and then the log
    button

18
pH calculations Solving for H
  • A solution has a pH of 8.5. What is the Molarity
    of hydrogen ions in the solution?

pH - log H 8.5 - log H -8.5 log
H Antilog -8.5 antilog (log H) 10-8.5
H 3.16 X 10-9 H
19
More About Water
  • H2O can function as both an ACID and a BASE.
  • In pure water there can be AUTOIONIZATION

Equilibrium constant for water Kw Kw H3O
OH- 1.00 x 10-14 at 25 oC
20
More About Water
Autoionization
  • Kw H3O OH- 1.00 x 10-14 at 25 oC
  • In a neutral solution H3O OH-
  • so Kw H3O2 OH-2
  • and so H3O OH- 1.00 x 10-7 M

21
pOH
  • Since acids and bases are opposites, pH and pOH
    are opposites!
  • pOH does not really exist, but it is useful for
    changing bases to pH.
  • pOH looks at the perspective of a base
  • pOH - log OH-
  • Since pH and pOH are on opposite ends,
  • pH pOH 14

22
pH
H
OH-
pOH
23
H3O, OH- and pH
  • What is the pH of the 0.0010 M NaOH
    solution?
  • OH- 0.0010 (or 1.0 X 10-3 M)
  • pOH - log 0.0010
  • pOH 3
  • pH 14 3 11
  • OR Kw H3O OH-
  • H3O 1.0 x 10-11 M
  • pH - log (1.0 x 10-11) 11.00

24
OH-
1.0 x 10-14 OH-
10-pOH
1.0 x 10-14 H
-LogOH-
H
pOH
10-pH
14 - pOH
-LogH
14 - pH
pH
25
HOMEWORK
  1. How much calcium hydroxide Ca(OH)2, in grams,
    is needed to produce 1.5 L of a 0.25 M solution?
  2. What volume of a 3.00M KI stock solution would
    you use to make 0.300 L of a 1.25 M KI solution?
  3. How many mL of a 5.0 M H2SO4 stock solution would
    you need to prepare 100.0 mL of 0.25 M H2SO4?
  4. If 0.50 L of 5.00 M stock solution is diluted to
    make 2.0 L of solution, how much HCl, in grams,
    is in the solution?

26
HOMEWORK
  • 5) Calculate the pH of solutions having the
    following ion concentrations at 298 K.
  • a) H 1.0 x 10-2 M b) H 3.0 x 10-6 M
  • 6) Calculate the pH of a solution having OH-
    8.2 x 10-6 M.
  • 7) Calculate pH and pOH for an aqueous solution
    containing 1.0 x 10-3 mol of HCl dissolved in 5.0
    L of solution.
  • 8) Calculate the H and OH- in a sample of
    seawater with a pOH 5.60.
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