Title: Molarity, Dilution, and pH
1Molarity, Dilution, and pH
- Main Idea Solution concentrations are measured
in molarity. Dilution is a useful technique for
creating a new solution from a stock solution. pH
is a measure of the concentration of hydronium
ions in a solution.
2Molarity Review
- One of the most common units of solution
concentration is molarity. - Molarity (M) is the number of moles of solute per
liter of solution. - Molarity is also known as molar concentration,
and the unit M is read as molar. - A liter of solution containing 1 mol of solute is
a 1M solution, which is read as a one-molar
solution. - A liter of solution containing 0.1 mol of solute
is a 0.1 M solution.
3Molarity Equation
- To calculate a solutions molarity, you must know
the volume of the solution in liters and the
amount of dissolved solute in moles. - Molarity (M) moles of solute
- liters of solution
4Molarity Example
- A 100.5-mL intravenous (IV) solution contains
5.10 g of glucose (C6H12O6). What is the molarity
of the solution? The molar mass of glucose is
180.16 g/mol. - SOLUTION
- Calculate the number of moles of C6H12O6 by
dividing mass over molar mass 0.0283 mol
C6H12O6 - Convert the volume of H2O to liters by dividing
volume by 1000 0.1005 L - Solve for molarity by dividing moles by liters
0.282 M
5Preparing Molar Solutions
- Now that you know how to calculate the molarity
of a solution, how would you prepare one in the
laboratory? - STEP 1 Calculate the mass of the solute needed
using the molarity definition and accounting for
the desired concentration and volume. - STEP 2 The mass of the solute is measured on a
balance. - STEP 3 The solute is placed in a volumetric
flask of the correct volume. - STEP 4 Distilled water is added to the flask to
bring the solution level up to the calibration
mark.
6http//www.ltcconline.net/stevenson/2008CHM101Fall
/CHM101LectureNotes20081022.htm
7Diluting Molar Solutions
- In the laboratory, you might use concentrated
solutions of standard molarities, called stock
solutions. - For example, concentrated hydrochloric acid (HCl)
is 12 M. - You can prepare a less-concentrated solution by
diluting the stock solution with additional
solvent. - Dilution is used when a specific concentration is
needed and the starting material is already in
the form of a solution (i.e., acids).
8PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
- Add water to the 3.0 M solution to lower its
concentration to 0.50 M - Dilute the solution!
9PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
But how much water do we add?
10PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
- How much water is added?
- The important point is that ---gt
11PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
- Amount of NaOH in original solution
- M V
- (3.0 mol/L)(0.050 L) 0.15 mol NaOH
- Amount of NaOH in final solution must also 0.15
mol NaOH - Volume of final solution
- (0.15 mol NaOH) / (0.50 M) 0.30 L
- or 300 mL
12PROBLEM You have 50.0 mL of 3.0 M NaOH and you
want 0.50 M NaOH. What do you do?
- Conclusion
- add 250 mL of water to 50.0 mL of 3.0 M NaOH to
make 300 mL of 0.50 M NaOH.
13Preparing Solutions by Dilution
- A shortcut
- M1 V1 M2 V2
- Where M represents molarity and V represents
volume. The 1s are for the stock solution and the
2s are for the solution you are trying to create.
14The pH scale is a way of expressing the strength
of acids and bases. Instead of using very small
numbers, we just use the NEGATIVE power of 10 on
the Molarity of the H (or OH-) ion.Under 7
acid 7 neutralOver 7 base
15pH of Common Substances
16Calculating the pH
- pH - log H
- (The means Molarity)
- Example If H 1 X 10-10pH - log 1 X
10-10 - pH - (- 10)
- pH 10
- Example If H 1.8 X 10-5pH - log 1.8 X
10-5 - pH - (- 4.74)
- pH 4.74
17pH calculations Solving for H
- If the pH of Coke is 3.12, H ???
- Because pH - log H then
- - pH log H
- Take antilog (10x) of both sides and get
- 10-pH H
- H 10-3.12 7.6 x 10-4 M
- to find antilog on your calculator, look
for Shift or 2nd function and then the log
button
18pH calculations Solving for H
- A solution has a pH of 8.5. What is the Molarity
of hydrogen ions in the solution?
pH - log H 8.5 - log H -8.5 log
H Antilog -8.5 antilog (log H) 10-8.5
H 3.16 X 10-9 H
19More About Water
- H2O can function as both an ACID and a BASE.
- In pure water there can be AUTOIONIZATION
Equilibrium constant for water Kw Kw H3O
OH- 1.00 x 10-14 at 25 oC
20More About Water
Autoionization
- Kw H3O OH- 1.00 x 10-14 at 25 oC
- In a neutral solution H3O OH-
- so Kw H3O2 OH-2
- and so H3O OH- 1.00 x 10-7 M
21pOH
- Since acids and bases are opposites, pH and pOH
are opposites! - pOH does not really exist, but it is useful for
changing bases to pH. - pOH looks at the perspective of a base
- pOH - log OH-
- Since pH and pOH are on opposite ends,
- pH pOH 14
22pH
H
OH-
pOH
23H3O, OH- and pH
- What is the pH of the 0.0010 M NaOH
solution? - OH- 0.0010 (or 1.0 X 10-3 M)
- pOH - log 0.0010
- pOH 3
- pH 14 3 11
- OR Kw H3O OH-
- H3O 1.0 x 10-11 M
- pH - log (1.0 x 10-11) 11.00
24OH-
1.0 x 10-14 OH-
10-pOH
1.0 x 10-14 H
-LogOH-
H
pOH
10-pH
14 - pOH
-LogH
14 - pH
pH
25HOMEWORK
- How much calcium hydroxide Ca(OH)2, in grams,
is needed to produce 1.5 L of a 0.25 M solution? - What volume of a 3.00M KI stock solution would
you use to make 0.300 L of a 1.25 M KI solution? - How many mL of a 5.0 M H2SO4 stock solution would
you need to prepare 100.0 mL of 0.25 M H2SO4? - If 0.50 L of 5.00 M stock solution is diluted to
make 2.0 L of solution, how much HCl, in grams,
is in the solution?
26HOMEWORK
- 5) Calculate the pH of solutions having the
following ion concentrations at 298 K. - a) H 1.0 x 10-2 M b) H 3.0 x 10-6 M
- 6) Calculate the pH of a solution having OH-
8.2 x 10-6 M. - 7) Calculate pH and pOH for an aqueous solution
containing 1.0 x 10-3 mol of HCl dissolved in 5.0
L of solution. - 8) Calculate the H and OH- in a sample of
seawater with a pOH 5.60.