Title: 3D Dynamic Design Of AL-Nour Building
13D Dynamic Design Of AL-Nour Building
- An-Najah National University
- Faculty of Engineering
- Civil Engineering Department
Prepared by
1. Ahmad Rashdan. 2. Jaffar Hassan
. 3. Mustafa Aqra. 4. Odai
Odeh.
Supervised by Dr. Abdul Razzaq Touqan
2Chapter 1 Introduction
3Introduction
- Al-Nour building is 8 stories reinforced concrete
building ,located in Nablus city and used as
residential building. - The first story is used as garages with plan area
of 700 m2 and the above 7 stories used as
residential apartment (two apartments per floor)
with plan area of 490 m2 due to the setback. - The soil bearing capacity 400 KN/m2
4Introduction
- The Following slides shows
- 1. columns centers plan.
- 2. 3D model of the building.
5Columns Centers Plan
6(No Transcript)
7Structural System
- The structural system used is on way ribbed slab
with load path in x-direction.
8Materials
- - Concrete
- - fc 320 kg/cm²( 32 MPa) For columns.
- - fc 240 kg/cm²( 24 MPa) for others.
- - The concrete unit weight 25 (KN/m3).
- - Reinforcing Steel The yield strength of steel
is equal to 4200 Kg/cm2 (420 MPa). - -Others
Material Unit weight (KN/m3)
Reinforced concrete 25
Plain concrete 23
Sand 18
Aggregate 17
Y-tong 5
Blocks 12
Polystyrene 0.3
Masonry stone 27
Light weight block 6
Tile 26
9Design loads
- - Dead loads in addition to slab own weight
- Superimposed dead load 4.5 KN/m2
- Partition load 1 KN/m2 .
- Masonry wall weight 21.22 KN/m.
- - Live load 2 KN/m2 .
- -Water tanks load 1.14 KN/m2
- - Seismic loads shown later.
10Design codes and load combinations
- - The following are the design codes used
- ACI code 2008 .
- IBC 2009 .
- ASCE for design loads.
- The following are the load combinations used
- Wu 1.4DL.
- Wu 1.2DL 1.6LL .
- Wu 1.2DL LL E.
- Wu 0.9DL E
11Chapter 2 Preliminary Design
12Preliminary design
- We performed a preliminary design for all
structural elements conceptually. - The story height is 3.12 m.
- The following are the preliminary dimensions
- Slab
- - depth 25 cm (based on deflection criteria) .
- - web width 12 cm.
- - slab own weight 4.55KN/m².
- - Ultimate load 14.06KN/m².
13Preliminary Design
- Beams
- Since the structural system is one way ribbed
slab (load path in x-direction) we have - Main beams in y-direction 30x60 cm.
- Secondary beams in x-direction 40x25 cm.
- Columns
- Take a sample columns ( B3)
- Area carried by column 28 m2
- Ultimate slab load 14.06KN/m²
- Pu 3769.6 KN.
- Ag 2326.9 cm2.
- ? Use columns of 40x60cm2.
-
14Preliminary design and checks
- Footing
- we performed an preliminary design for footing
of the previous column as single footing. - with dimensions of 2.9x2.7x0.7 m.
-
15Chapter 3 Static Design
16Static design
- Final dimensions
- 1. frame sections
Member Depth(cm) Width(cm)
Col. 80 40
Main interior beams 70 40
Main exterior beams 75 30
Secondary beams 25 40
Tie beams 50 30
17Static Design
- The new web width (bw) 15 cm.
- Area sections dimensions
Area section name Thickness (cm)
Actual Slab 25
Equivalent Slab thickness 19.45 (in SAP model)
Shear wall 30 (initially)
18Static design
- Verification Of SAP model
- We perform the verification for SAP models( one
and eight stories and it was OK) the following
is verification for eight stories - 1. Compatibility satisfied
19Static Design
2.Equilibrium Satisfied
Load type Hand results(KN) SAP results (KN) Error
Dead load 76262.44 76273.132 0.01
Live load 8407.24 8407.24 0
- 3.Stress -Strain relationship satisfied
- Taking beam C in second story (taking 8 m
span)
Load M-ve (left)(KN.m) Mve (KN.m) M-ve(right) (KN.m) Total moment (KN.m)
SAP Result 325.13 208.63 371.41 556.9
1D Result 0 341.40 433.61 558.21
Error 2.3
20Static Design
- Slab design
- 1. Check slab deflection
- So, ?dead 2.92 mm.
- ?Live 0.78mm.
- ? long term 7.16mm.
- The allowable deflection 4000 /240 16.67 mm.
- So the slab deflection 7.16mm lt allowable long
term def. OK. - 2. Design for shear
- The rib shear strength 23.2KN.
- The max shear 36.75 KN/m.
- shear per rib 0.5536.75 20.2 KN.
- So 23.2 20.2 OK
- So the slab is Ok for shear.
21Static Design
- 3. Design for bending moment
- The moments are read from SAP using section cut
Point location/term Moment(KN.m) As(mm2) Bars
A1 6.3 113 2 F 12
A1- B1 8.6 113 2 F 10
B1 10.48 125 2 F 12
B1- C1 7.25 113 2 F 10
C1 10.29 122 2 F 12
C1 D1 8.1 113 2 F 10
D1 9 113 2 F 12
D1 E1 8.1 113 2 F 10
E1 13.55 163.3 2 F 12
22Static Design
- Design of beams in y-direction
- Taking a sample beam (beam B in the first floor)
- - The beam section dimensions are
- - Total depth (h) 700 mm.
- - The effective depth (d) 650 mm.
- -Beam width (bw) 400 mm.
- - min reinforcement ratio 0.0033.
- - As min ?bd 0.0033400650 858 mm2
- - fVc 159.1 KN.
- - (Av/s)min 0.333.
-
23Static Design
point As(mm) As min (Av/s) (Av/s) min PI(m) Length(m) bars stirrups
B1 700 858 0.333 0.333 0.6 2 5F16 1F8 _at_30 cm
B1-2 854 858 0.333 0.333 -- 5.9 5F16 1F8 _at_30 cm
B2(L) 1676 858 0.333 0.333 1.3 4.8 6f20 1F8 _at_30 cm
B2(R) 1676 858 0.55 0.333 1.5 4.8 6f20 1F8 _at_15 cm
B2-3 1044 858 0.333 0.333 _ 7.9 5F16 1F8 _at_30 cm
B3(L) 1581 858 0.48 0.333 1.5 4.8 6f20 1F8 _at_20 cm
B3(R) 1581 858 0.333 0.333 1.3 4.8 6f20 1F8 _at_30 cm
B3-4 772 858 0.333 0.333 _ 5.9 5F16 1F8 _at_30 cm
B4 854 858 0.333 0.333 1 2.3 5F16 1F8 _at_30 cm
24Static Design
- Design of secondary beams
- Total depth(H) 25cm.(hidden beam)
- d 21cm (cover 4cm)
- Width 40cm.
- The following are the values of min
reinforcement - (As) min 0.0033bd0.0033400210 277.2 mm
(3F12). - Vc 0.750.167400210/1000 68.58KN.
25Static Design
Point As(mm) As min (mm) (Av/s) (Av/s)min PI(m) bars stirrups
A4 469 277.2 0.333 0.333 0.88 5F12 1_at_10cm
A4-B4 277 277.2 0.333 0.333 0.88 3F12 1_at_10cm
B4 429 277.2 0.333 0.333 0.88 4F12 1_at_10cm
B4-C4 259 277.2 0.333 0.333 0.88 3F12 1_at_10cm
C4 424 277.2 0.333 0.333 0.88 4F12 1_at_10cm
C4-D4 260 277.2 0.333 0.333 0.88 3F12 1_at_10cm
D4 425 277.2 0.333 0.333 0.88 4F12 1_at_10cm
D4-E4 265 277.2 0.333 0.333 0.88 3F12 1_at_10cm
E4 432 277.2 0.333 0.333 0.88 4F12 1_at_10cm
E4-F4 147 277.2 0.333 0.333 0.88 3F12 1_at_10cm
F4 432 277.2 0.333 0.333 0.88 4F12 1_at_10cm
26Design of columns
- Column grouping, Area of steel stirrups
Floor no. Columns As(mm2) column group Distribution of steel Stirrups spacing (mm)
All floors except No.8 All Columns 3200 C1 16f16 3f10 _at_250 mm
Floor No.8 D2 G2 3766 C2 20f16 3f10 _at_300 mm
Floor No.8 A2, B2, C2, H2, I2 J2 4774 C3 16f20 3f10 _at_300 mm
27Manual design
Pu3034.75KN MY 11.02 KN.m(maximum value) MX
153.1 KN.m( maximum value) Mc ?nsM2
1.67(153.1) 255 KN.m
- From the interaction diagram
- ?1 use minimum steel ratio use ?1.
- As 0.01xAg 0.01x40x80 3200mm2
- Same as SAP value.
28Tie beam design
Minimum area of steel 0.0033bd 436 mm2. Use
4?12mm bottom steel. Use 4?12mm top steel.
Shear design Vu at distance (d 44cm)
16.35KN, ?Vc 80.83KN. Use 1?8 mm_at_200mm.
29Footing design
- Single footing
- Is one of the most economical types of footing
and is used when columns are spaced at relatively
long distances . - Bearing capacity of the soil400 KN/m2.
30 Footing grouping
Group Name Columns Service load(KN) Ultimate load (KN)
F1 A1, B1,C1,D1,E1,F1,G1,H1,I1,J1 305.6 375.7
F2 A2, J2,A4 B4,C4,D4,G4,H4,I4,J4, 2329.95 2878.51
F3 B2,C2, D2,G2,H2,I2,A3,B3,C3,D3,G3,H3, I3,J3 3667.66 4599.75
Combined E4 F4 2218.20 2741.80
Footing grouping according to columns
ultimate load.
31footing details
Group Area of footing (m2) Dimensions (m) Depth (m) Steel distribution/m (Both directions) Area of shrinkage steel (mm2) Distribution in each direction
F1 0.96 1.2x0.8 0.3 4 Ø 14mm no No
F2 6.21 2.7x2.3 0.55 5 Ø 18mm 1 Ø 14_at_300mm
F3 9.57 3.3x2.9 0.75 6 Ø 18mm 1 Ø 14_at_200mm
Combined 13.11 5.7x2.3 0.55 1Ø25 /200mm 778.2 1 Ø 14_at_200mm
32Design of Stairs
33Verification of SAP model
Compatibility
Compatibility Satisfied
34Cont.
Load type Hand results(KN) SAP results(KN) Error
Dead load 293.04 292.82 0.08
Live load 181.24 181.12 0.07
Equilibrium
Equilibrium Satisfied
Stress-Strain Relationships
Load M-ve(left) (KN.m) Mve (KN.m) M-ve(right) (KN.m)
3D SAP Result 22.1 11.9 19.46 32.68
1D Result 21.72 10.86 21.72 32.58
Error 0.3
Stressstrain relationship satisfied
35Chapter 4 Dynamic Design
36Dynamic Design
- Methods for dynamic analysis
- Equivalent static method.
- Time history method.
- Response spectrum analysis.
- Input parameters in dynamic analysis
- - Importance factor (I) 1 .
- - Peak ground acceleration (PGA) 0.2g .
- - Area mass 0.458 ton/m2
- - Soil class Class B.
- - Spectral accelerations Ss 0.5 .
- S1
0.2 . - - response modification factor R 3 in
x-direction. -
R 4.5 in y-direction.
37Dynamic Design
- Modal information
- - For eight stories before enlarging beams in
x-direction
Mode No. Direction Period (sec.) MMPR
1 X 2.55 77
2 RZ(Torsion) 1.707 67
4 y 0.972 65
- - Enlarge the beams 2 4 to 30x70 (widthdepth)
38Dynamic Design
- - For eight stories after enlarging beams in
x-direction
Mode No. Direction Period (sec.) MMPR
1 X 1.58 80
2 RZ(Torsion) 1.5 64
3 Y 0.795 65.4
4 X 0.497 11
- - Comparison with manual results
Mode direction SAP result(sec) Manual result(sec) Error
x- direction 1.58 1.45 8
y- direction 0.795 0.73 8
39Dynamic Design
- Response spectrum analysis
- We will perform the dynamic design using response
spectrum method - Define two response spectrum load cases one in
x-direction and the another in y-direction - - For response-x Scale factor 3.27.
- Scale factor
0.654. - - For response-y Scale factor 2.18.
- Scale factor
0.981. - Perform design using envelope combination and
check whether static or dynamic combination
controls .
40Dynamic Design
- Slab design
- The comparison is performed.
- Static design controls
41(No Transcript)
42Dynamic Design
- Design of beams in y-direction
- - Reinforcement from envelope combination
- - Reinforcement from static combination
Static design Controls
43Dynamic Design
- Design of beams in X-direction
- - Reinforcement from envelope combination is
considered since the dimensions are increased
Dynamic design Controls
44Dynamic Design
- Design of columns
- Three representative columns are selected
- Interior column B3.
- Edge column B2.
- Corner column A4 .
- The comparison is performed and static design
controls for all columns. - The following table shows the comparison for
column B3
45Dynamic Design
The following table shows the comparison for
column B3 (M3, V2 )
floor/term Envelope combination Envelope combination Envelope combination Envelope combination Static combination Static combination Static combination Static combination
floor/term moment shear axial As(mm2) moment shear axial As(mm2)
1 68.04 31.34 4553.25 3200 5.54 1.678 4553.3 3200
2 45.78 22.15 3982.31 3200 6.97 3.7 3982.2 3200
3 49.81 22.82 3409.11 3200 4.78 2.73 3409.1 3200
4 47.33 20.07 2841.94 3200 4.62 2.55 2841.9 3200
5 44.51 18.49 2277.7 3200 3.78 2.12 1716.5 3200
6 42.58 16.78 1716.51 3200 3.71 2 1699.8 3200
7 39.19 13.98 1156.2 3200 2.88 1.36 1156.2 3200
8 26.75 8 600.378 3200 6.82 3.18 603.8 3200
Static design OK for columns.
46Chapter 5 Structural Modeling Of One Way Ribbed
Slab
47Structural Modeling Of One Way Ribbed Slabs
- The ribbed slabs can be represented by one of
the following ways - Equivalent stiffness method find the equivalent
thickness of a solid slab that can achieve the
same rib stiffness. - Represent it as separate ribs (T-section).
- Represent the ribs by rectangular ribs and
flange. - The main objective is to prove that three models
give the nearly the same results.
48Structural Modeling Of One Way Ribbed Slabs
- Model 1 Equivalent stiffness method
- Equivalent slab thickness (t) 19.45 cm.
- I T-sec I rec ?( 0.55h3eq /12) 3.37110-4
- h3eq 19.45 cm.
- ?eq 23.87 KN/m3 . . . . .. .to achieve
the same weight. - - Stiffness modifiers
- M11 0.35 .
- M22 0.0244
- M1-2 0.0244.
49Structural Modeling Of One Way Ribbed Slabs
- Model 2 Representation as separate ribs
- - Stiffness modifiers
- I 3-3 0.35 .
- I 2-2 0.35 .
- Torsional constant(J) 0.35 .
- The loads are inserted as line
- Loads on ribs.
- Substitute the weight of blocks.
-
50Structural Modeling Of One Way Ribbed Slabs
- Model 3 the slab is represented as rectangular
ribs and flange. - 1. The rectangle section should satisfy
- The actual T-section.
- 2. Stiffness modifiers
- I 3-3 0.6 .
- I2-2 0.6 .
- J 0.52 .
- 3. Weight modifier 0.68 .
- Flange Modifiers
- - M11 0.0001 .(almost zero).
- - M 22 0.25 .
- - M 1-2 0.0001(almost zero).
- ? we have to substitute the weight of blocks.
55 cm
8 cm
25 cm
15 cm
51Structural Modeling Of One Way Ribbed Slabs
- All the previous models are verified according
to manual solution. - Static analysis is performed for the three models
and we read the moment and shear at point C3 in
span C3-4 for beam C in the second floor
load Moment (KN.m) Shear (KN) (mm2) ( (mm2/mm)
SAP Model 1 Results 371.41 268.63 1615 0.545
SAP Model 2 Results 377.87 286.43 1645.1 0.634
SAP Model 3 Results 373.56 274.13 1625 0.573
52Structural Modeling Of One Way Ribbed Slabs
- also dynamic analysis and design performed for
the three models and the following are the modal
information
Model 1
Mode Direction Period MMPR
Mode 1 x-direction 1.581 80
Mode 2 Torsion(Rz) 1.503 64
Mode 3 y- direction 0.796 65.4
Model 2
Mode Direction Period MMPR
Mode 1 x-direction 1.622 77.0
Mode 2 Torsion(Rz) 1.555 79.5
Mode 3 y- direction 0.924 70.9
Model 3
Mode Direction Period MMPR
Mode 1 x-direction 1.542 80.3
Mode 2 Torsion(Rz) 1.456 65.5
Mode 3 y- direction 0.769 65.7
53Structural Modeling Of One Way Ribbed Slabs
- Also the same span taken in the beam C and the
following are the values of moment and shear from
envelope combination
Model 1
Point Envelope combination Envelope combination Envelope combination Envelope combination
Point moment shear As(mm2) Av/s (mm2/mm)
C2 316.0 243.7 1359.4 0.422
C2-C3 208.6 16.3 1053 0
C3 371.1 268.5 1613 0.545
Model 2
Point Envelope combination Envelope combination Envelope combination Envelope combination
Point moment shear As(mm2) Av/s (mm2/mm)
C2 329.7 259.6 1422 0.5
C2-C3 211.0 17.7 899.1 0
C3 377.9 286.4 1645 0.634
Model3
Point Envelope combination Envelope combination Envelope combination Envelope combination
Point moment shear As(mm2) Av/s (mm2/mm)
C2 317.6 243.0 1367 0.418
C2-C3 209.1 16.2 891.3 0
C3 373.6 274.1 1625 0.573
54Structural Modeling Of One Way Ribbed Slabs
- Final conclusion
- from the previous data shown in tables we note
that all the three models give near results. - So, we can represent the slab model by any of the
previous models but perform the changes in loads
assignment and stiffness modifiers.
55Thanks for your attention