Title: Matter: Properties
1Matter Properties Change
2A. Matter
- Matter anything that has mass and takes up
space - Everything around us
- Mass measurement that reflects the amount of
matter (usually in grams) - Volume the amount of space something takes up
- Chemistry the study of matter and the changes
it undergoes
3B. Four States of Matter
- Solids
- particles vibrate but cant move around
- fixed shape
- fixed volume
- incompressible
4B. Four States of Matter
- Liquids
- particles can move around but are still close
together - variable shape
- fixed volume
- Virtually incompressible
5B. Four States of Matter
- Gases
- particles can separate and move throughout
container - variable shape
- variable volume
- Easily compressed
- Vapor gaseous state of a substance that is a
liquid or solid at room temperature
6B. Four States of Matter
- Plasma
- atoms collide with enough energy to break into
charged particles (/-) - gas-like, variableshape volume
- stars, fluorescentlight bulbs, TV tubes
7- II. Properties Changes in Matter (p.73-79)
- Extensive vs. Intensive
- Physical vs. Chemical
8A. Physical Properties
- Physical Property
- can be observed measured without changing the
identity of the substance
9A. Physical Properties
- Physical properties can be described as one of 2
types - Extensive Property
- depends on the amount of matter present (example
length, mass, volume) - Intensive Property
- depends on the identity of substance, not the
amount (example scent, density, melting point)
10D. Chemical Properties
- Chemical Property
- describes the ability of a substance to be
observed reacting with or changing into another
substance
11E. Physical vs. Chemical Properties
- Examples
- melting point
- flammable
- density
- magnetic
- tarnishes in air
- physical
- chemical
- physical
- physical
- chemical
12F. Physical Changes
- Physical Change
- changes the form of a substance without changing
its identity - properties remain the same
- Examples cutting a sheet of paper, breaking a
crystal, all phase changes
13F. Phase Changes Physical
- Evaporation
- Condensation
- Melting
- Freezing
- Sublimation
- Deposition
- Liquid -gt Gas
- Gas -gt Liquid
- Solid -gt Liquid
- Liquid -gt Solid
- Solid -gt Gas
- Gas -gt Solid
14G. Chemical Changes
- Process that involves one or more substances
changing into a new substance - Commonly referred to as a chemical reaction
- New substances have different compositions and
properties from original substances - Reaction involves reactants reacting to
produce products
15G. Chemical Changes
- Signs of a Chemical Change
- change in color or odor
- formation of a gas (bubbles)
- formation of a precipitate (solid)
- change in light or heat
16H. Physical vs. Chemical Changes
- Examples
- rusting iron
- dissolving in water
- burning a log
- melting ice
- grinding spices
- chemical
- physical
- chemical
- physical
- physical
17What Type of Change?
18- Exothermic- heat energy EXITS the system
- surroundings usually feel warmer
- 1 g H2O (g) ? 1 g H2O (l) 2260 J
- ex. Combustion, evaporation of water
19- Endothermic- heat energy ENTERS the system
- - heat absorbed from surroundings
- - surroundings usually feel cooler
- - 1 g H2O (s) 333 J ? 1 g H2O (l)
- - 1 g H2O (l) 2260 J ? 1 g H2O (g)
- - ex. Cold packs, melting ice
20What Type of Change?
?
?
?
21I. Law of Conservation of Mass
- Although chemical changes occur, mass is neither
created nor destroyed in a chemical reaction - Mass of reactants equals mass of products
massreactants massproducts
A B ? C
22- III. Classification of Matter (pp. 80-87)
- Matter Flowchart
- Pure Substances
- Mixtures
23A. Matter Flowchart
MATTER
yes
no
Can it be physically separated?
Homogeneous Mixture (solution)
Heterogeneous Mixture
Compound
Element
24A. Matter Flowchart
- Examples
- graphite
- pepper
- sugar (sucrose)
- paint
- soda
- element
- hetero. mixture
- compound
- hetero. mixture
- solution
25B. Pure Substances
- Element
- composed of one type of identical atoms
- Atom Composed of protons, electrons, and
neutrons. Smallest particle of matter that can
be identified as one element - EX copper wire, aluminum foil
26B. Pure Substances
- Compound
- composed of 2 or more elements in a fixed ratio
(bonded together) - properties differ from those of individual
elements - EX table salt (NaCl)
27C. Mixtures
- Variable combination of 2 or more pure
substances, each retains its chemical identity
properties.
Heterogeneous
Homogeneous
28C. Mixtures
- Homogeneous are uniform throughout
- Solutions
- very small particles
- particles dont settle
- EX rubbing alcohol, gasoline, soda
29C. Mixtures
- Heterogeneous
- medium-sized to large-sized particles
- particles may or may not settle
- EX milk, fresh-squeezed lemonade
30C. Mixtures
- Examples
- tea
- muddy water
- fog
- saltwater
- Italian salad dressing
- Answers
- Solution
- Heterogeneous
- Heterogeneous
- Solution
- Heterogeneous
31Separation Methods
- Ways to separate mixtures Chapter 3 Matter
Its Properties
32Separating Mixtures
- Substances in a mixture are physically combined,
so processes bases on differences in physical
properties are used to separate component - Numerous techniques have been developed to
separate mixtures to study components - Visually
- Magnetism
- Filtration
- Distillation
- Crystallization
- Chromatography
33Filtration
- Used to separate heterogeneous mixtures composed
of solids and liquids - Uses a porous barrier to separate the solid from
the liquid - Liquid passes through leaving the solid in the
filter paper
34Distillation
- Used to separate homogeneous mixtures
- Based on differences in boiling points of
substances involved
35Crystallization
- Separation technique that results in the
formation of pure solid particles from a solution
containing the dissolved substance - As one substance evaporates, the dissolved
substance comes out of solution and collects as
crystals - Produces highly pure solids
- Rocky candy is an example of this
36Chromatography
- Separates components of a mixture based on
ability of each component to be drawn across the
surface of another material - Mixture is usually liquid and is usually drawn
across chromatography paper - Separation occurs because various components
travel at different rates - Components with strongest attraction for paper
travel the slowest
37Thermochemistry
- Chapter 171
- Pages 505 510
38A. Vocabulary
ThermochemistryThe study of energy changes
that occur during chemical reactions and changes
in state
EnergyThe capacity to do work or produce heat
39A. Vocabulary
- TEMPERATURE is a measure of the amount of kinetic
energy an object/substance has - HEAT is energy that transfers from one
object/substance to another (thermal energy) - Represented by the symbol q
- Transfers because of difference in temperature
- Always flows from a warmer to a cooler object
40A. Vocabulary
- Which has more thermal energy?
41B. Heat Transfer
- Why does A feel hot and B feel cold?
- Heat flows from A to your hand hot
- Heat flows from your hand to B cold
42C. Types of Energy
- Potential due to position or composition can
be converted to work - Kinetic due to motion of the object
- KE ½ mv2
- (m mass, v velocity)
- Law of Conservation of Energy energy can be
neither created nor destroyed
43C. Types of Energy
- Energy that is stored in the chemical bonds of a
substance is called CHEMICAL POTENTIAL ENERGY - Types of atoms and their arrangement determine
amount of energy stored in substance
44D. Exothermic and Endothermic
- System the reaction (our focus)
- Surroundings everything around the reaction
(rxn container, room, etc) - Surroundings
- Universe System Surroundings
System
45D. Exothermic and Endothermic
- Exothermic process heat is released into the
surroundings - Exo Exit
- Exothermic processes are represented by a
negative q
46B. Exothermic and Endothermic
47D. Exothermic and Endothermic
- Endothermic Process heat is absorbed from the
surroundings - Endo Into
- Endothermic processes are represented by a
positive q
48D. Exothermic and Endothermic
- Formation of Nitric Oxide
49D. Exothermic and Endothermic
- Sign of (q) is a signal to indicate the
direction of the heat transfer
- Exothermic
- - q heat transferred from a substance
- Endothermic
- q heat transferred into a substance
50E. Measuring Heat Flow
- Two Common Units
- Joule
- calorie
- 4.184 J 1 cal
- 1J 0.2390 cal
- 1Calorie 1 kilocal 1000 cal
51F. Heat Capacity
- the amount of heat needed to increase the
temperature of an object by 1oC - Heat Capacity depends on
- The mass of the object
- The chemical composition of the object
52G. Specific Heat Capacity
- Specific heat capacity amount of heat needed to
raise the temperature of 1g of a substance by 1oC - Specific Heat of H2O (l) 4.184 J/goC
- Specific Heat of H2O (s) 2.02 J/goC
- Molar heat capacity amount of heat needed to
raise the temperature of 1 mole of a
substance by 1oC
53G. Specific Heat Capacity
q m ? C ? ?T
q heat (J) m mass (g) C specific heat (J/gK)
or (J/goC) ?T change in temperature (K or C)
54G. Specific Heat Capacity
- q m x C X ?T
- q heat (joules or calories)
- m mass (grams)
- C Specific Heat
- ?T change in temperature
- The change in temperature can be measure in
Kelvin or degrees Celsius
55G. Heat Transfer Problem
- A 32.0-g silver spoon cools from 60.0C to
20.0C. How much heat is lost by the spoon?
GIVEN m 32.0 g Ti 60.0C Tf 20.0C q ? C
.235 J/gC
WORK q mC?T ?T 20C - 60C 40C q
(32.0g)(-40C)(.235J/gC) q 301 J
Exo
56G. Heat Transfer Problem
- The temperature of a 95.4g piece of copper
increases from 25.0 oC to 48.0 oC when it absorbs
849 J of heat. What is the specific heat of
copper?
WORK q mC?T C q/m ?T ?T 48C 25C
23C C 849J/(95.4g)(23C) C 0.387 J/gC
GIVEN m 95.4 g Ti 25.0C Tf 48.0C q 849
J C ?
Endo
57G. Heat Transfer Problem
- What is the molar heat capacity of copper?
WORK C 0.387 J
GIVEN C 0.387 J/gC MM 63.55 g/mol
63.55 g Cu 1 mol Cu
g oC
24.6 J/mol oC
58Thermochemistry
- Chapter 172
- Pages 511 517
59A. Calorimetry
- Measures the heat flow into or out of a system
- Heat released by the system is equal to heat
absorbed by the surroundings
- Calorimeter Insulated device used to measure
absorption or release of heat
60A. Calorimetry
- Enthalpy (H) the heat absorbed or released of a
system at constant pressure - ? H is the heat of a reaction
- Heat or enthalpy change are used interchangeably
here - q ? H
61B. Thermochemical Equations
- In a thermochemical equation, the enthalpy of
change for the reaction can be written as either
a reactant or a product - Endothermic (positive ?H)
- 2NaHCO3 129kJ Na2CO3 H2O CO2
- ?H 129 kJ
- Exothermic (negative ?H)
- CaO H2O Ca(OH)2 65.2kJ
- ?H - 65.2 kJ
62A. Calorimetry
- ?H Hfinal - Hinitial OR
- ?Hreaction (rxn) Hproducts Hreactants
-
- For endothermic reactions HfinalgtHinitial ?H
is positive (?H) - For exothermic reaction HfinalltHinitial and ?H is
negative (-?H)
63A. Calorimetry
- When solving for the heat transfer of a system
(between 2 objects), assume that - q initial soln - qfinal rxn
- heat goes in heat goes out
-
- ?H -?H or
- CH20 x m H20 x ?T H20 -1(Cmetal x mmetal x
?Tmetal)
64A. Calorimetry
- Example
- 2 H2 O2 ? 2 H2O 483.6 kJ
- ?H - 483.6 kJ
- Exothermic
65A. Calorimetry
- How to measure ? H for a reaction in aqueous
solution - Dissolve chemicals in water
- Place in calorimeter
- Measure temperature change
66A. Calorimetry
- qsurr m x C x ?T
- qsys ?H - qsurr -m x C x ?T
- Negative enthalpy exothermic
- Positive enthalpy endothermic
67- When 25.0mL of water containing HCl at 25.0 oC is
added to 25.0mL of water containing NaOH at 25.0
oC in a calorimeter a rxn occurs. Calculate the
enthalpy change (in kJ) during the rxn if the
highest temperature observed was 32.0 oC. Assume
all densities 1.00g/mL - KNOWN
- Cwater 4.184 J/g oC
- V 25.0mL 25.0mL
- ?T 32.0 25.0 7.0 oC
- Density 1.00g/mL
- M (50mL) x (1.00g/mL) 50g
- ?H ?
- ?H -mC?T
- -(50.0g)(4.184J/goC) (7.0oC)
- ?H -1463 J -1460J
Exo
68C. Heat of Combustion
- The heat of reaction for the complete burning of
one mole of a substance - Written the same way as change in enthalpy
69- Write the thermochemical equation for the
oxidation of Iron (III) if its ?H -1652 kJ - Fe(s) O2(g)? Fe2O3(s) 1652 kJ
- How much heat is evolved when 10.00g of Iron is
reacted with excess oxygen?
Exo
4
3
2
1 mol
10.00g Fe
1652 kJ
73.97 kJ of heat
4 mol Fe
55.85g Fe
70Thermochemistry
- Chapter 173
- Pages 520 526
71A. Heat of Fusion
- Heat of Fusion (?Hfus)
- Heat absorbed by one mole of a solid substance
when it melts to a liquid at a constant
temperature - ?Hfus of ice 6.009 kJ/mol
- Heat of Solidification (?Hsolid)
- Heat lost by one mole of a liquid substance when
it solidifies at a constant temperature - ?Hfus - ?Hsolid
- ?Hsolid of water -6.009 kJ/mol
72B. Heating Curves
73B. Heating Curves
- Temperature Change
- change in KE (molecular motion)
- depends on heat capacity
- Phase Change
- change in PE (molecular arrangement)
- temp remains constant
74C. Heat of Vaporization
- Heat of Vaporization (?Hvap)
- energy required to boil 1 gram of a substance at
its b.p. - ?Hvap for water 40.79 kJ/mol
- usually larger than ?Hfuswhy?
75D. Practice Problems
- How much heat energy is required to melt 25 grams
of ice at 0oC to liquid water at a temperature of
0oC?
ice
6.009 kJ 1 mol H2O
25 g H2O
1 mol H2O 18.02 g H2O
8.3 kJ
76D. Practice Problems
- How much heat energy is required to change 500.0
grams of liquid water at 100oC to steam at 100oC?
steam
40.79 kJ 1 mol H2O
500.0 g H2O
1 mol H2O 18.02 g H2O
1132 kJ
77D. Practice Problems
- How many kJ are absorbed when 0.46g of C2H5Cl
vaporizes at its normal boiling point? The molar
?Hvap is 26.4 kJ/mol.
26.4 kJ 1 mol C2H5Cl
0.46 g C2H5Cl
1 mol C2H5Cl 64.52 g C2H5Cl
0.19 kJ
78E. Heat of Solution
- During the formation of a solution, heat is
either released or absorbed - Enthalpy change caused by dissolution of 1 mol of
a substance is the molar heat of solution ?Hsoln - Examples hot packs, cold packs
79E. Heat of Solution
- NaOH(s) ? Na(aq) OH-(aq)
- ?Hsoln -445.1 kJ/mol
- NH4NO3 ? NH4(aq) NO3-(aq)
- ?Hsoln 25.7 kJ/mol