Objective - Lesson 1: Motion Characteristics for Circular Motion

1 / 83
About This Presentation
Title:

Objective - Lesson 1: Motion Characteristics for Circular Motion

Description:

Objective - Lesson 1: Motion Characteristics for Circular Motion Speed and Velocity Acceleration The Centripetal Force Requirement Mathematics of Circular Motion –

Number of Views:569
Avg rating:3.0/5.0
Slides: 84
Provided by: laba154
Category:

less

Transcript and Presenter's Notes

Title: Objective - Lesson 1: Motion Characteristics for Circular Motion


1
Objective - Lesson 1 Motion Characteristics for
Circular Motion
  • Speed and Velocity
  • Acceleration
  • The Centripetal Force Requirement
  • Mathematics of Circular Motion

2
Uniform circular motion
  • Uniform circular motion is the motion of an
    object in a circle with a ___________ or uniform
    speed. The velocity is changing because the
    direction of motion is ______________.
  • Speed _____________
  • Direction of motion _____________ of the path
  • Velocity
  • magnitude ___________
  • Direction _____________

3
Speed and velocity
  • Calculation of the Average Speed
  • vavg _________
  • The distance of one complete cycle around the
    perimeter of a circle is known as the
    ____________.
  • Circumference ____ (R is the radius of the
    circle)
  • The time (T) to make one cycle around the circle
    is called one _________.
  • The average speed of an object in uniform
    circular motion is

vavg ____________
4
  • The average speed and the Radius of the circle
    are _____________________.
  • The average speed and the Period of the circle
    are _____________________.

5
The Direction of the Velocity Vector
The best word that can be used to describe the
direction of the velocity vector is the word
____________________. The direction of the
velocity vector at any instant is in the
direction of a tangent line drawn to the circle
at the object's location.
6
  • To summarize, an object moving in uniform
    circular motion is moving around the perimeter of
    the circle with a __________speed. While the
    speed of the object is constant, its velocity is
    changing. Velocity, being a vector, has a
    constant magnitude but a changing direction. The
    direction is always directed _________ to the
    circle and as the object turns the circle, the
    tangent line is always pointing in a new
    direction.

The average speed is directly proportional to the
____________ and inversely proportional to the
_____________.
7
Check Your Understanding
  • A tube is been placed upon the table and shaped
    into a three-quarters circle. A golf ball is
    pushed into the tube at one end at high speed.
    The ball rolls through the tube and exits at the
    opposite end. Describe the path of the golf ball
    as it exits the tube.

8
example
  • A vehicle travels at a constant speed of 6.0
    meters per second around a horizontal circular
    curve with a radius of 24 meters. The mass of the
    vehicle is 4.4 103 kilograms. An icy patch is
    located at P on the curve. On the icy patch of
    pavement, the frictional force of the vehicle is
    zero.  Which arrow best represents the direction
    of the vehicle's velocity when it reaches icy
    patch P?

a
b
c
d
9
Acceleration
  • An object moving in uniform circular motion is
    moving in a circle with a uniform or constant
    speed. The velocity vector is constant in
    magnitude but changing in direction.
  • Since the velocity is changing. The object is
    __________________.

where vi represents the initial velocity and vf
represents the final velocity after some time of
t
10
Direction of the Acceleration Vector
  • The velocity change is directed towards point C -
    the ________ of the circle.
  • The acceleration of the object is dependent upon
    this velocity change and is in the same direction
    as this ____________. The acceleration is
    directed towards point C as well - the
    ___________________________.

11
example
  • The initial and final speed of a ball at two
    different points in time is shown below. The
    direction of the ball is indicated by the arrow.
    For each case, indicate if there is an
    acceleration. Explain why or why not. Indicate
    the direction of the acceleration.
  • a.

b.
c.
d.
12
example
  • Explain why an object moving in a circle at
    constant speed can be said to experience an
    acceleration.

13
example
An object is moving in a clockwise direction
around a circle at constant speed.
  1. Which vector below represents the direction of
    the velocity vector when the object is located at
    point B on the circle?
  2. Which vector below represents the direction of
    the acceleration vector when the object is
    located at point C on the circle?
  3. Which vector below represents the direction of
    the velocity vector when the object is located at
    point C on the circle?
  4. Which vector below represents the direction of
    the acceleration vector when the object is
    located at point A on the circle?

14
The Centripetal Force Requirement
  • According to Newton's second law of motion, an
    object which experiences an acceleration requires
    a __________________.
  • The direction of the net force is in the same
    direction as the ______________. So for an object
    moving in a circle, there must be an inward force
    acting upon it in order to cause its inward
    acceleration. This is sometimes referred to as
    the ________________ force requirement.
  • The word centripetal means _______________. For
    object's moving in circular motion, there is a
    net force acting towards the center which causes
    the object to seek the center.

15
Centrifugal force is a fictitious force
  • centrifugal (center fleeing) force
  • A fictitious or inertial force that is
    experienced from INSIDE a circular motion system
  • centripetal (center seeking) force
  • A true force that pushes or pulls an object
    toward the center of a circular path

16
The Centripetal Force is Net Force
  • Any object moving in a circle (or along a
    circular path) experiences a _______________
    force. This is the centripetal force requirement.
  • The word centripetal is merely an adjective used
    to describe the direction of the force. We are
    not introducing a new type of force but rather
    describing the direction of the ________ force
    acting upon the object that moves in the circle.

17
examples of centripetal force
As the moon orbits the Earth, the force of
____________ acting upon the moon provides the
centripetal force required for circular motion.
As a car makes a turn, the force of _____________
acting upon the turned wheels of the car provides
centripetal force required for circular motion.
As a bucket of water is tied to a string and spun
in a circle, the _____________ force acting upon
the bucket provides the centripetal force
required for circular motion.
18
  • To summarize, an object in uniform circular
    motion experiences an __________ net force. This
    inward force is sometimes referred to as a
    _______________ force, where centripetal
    describes its direction. Without this centripetal
    force, an object could never alter its direction.
    The fact that the centripetal force is directed
    ___________________ to the tangential velocity
    means that the force can alter the direction of
    the object's velocity vector without altering its
    magnitude.

19
Check your understanding
  • An object is moving in a clockwise direction
    around a circle at constant speed
  1. Which vector below represents the direction of
    the force vector when the object is located at
    point A on the circle?
  2. Which vector below represents the direction of
    the force vector when the object is located at
    point C on the circle?
  3. Which vector below represents the direction of
    the velocity vector when the object is located at
    point B on the circle?
  4.  Which vector below represents the direction of
    the velocity vector when the object is located at
    point C on the circle?
  5. Which vector below represents the direction of
    the acceleration vector when the object is
    located at point B on the circle?

20
Mathematics of Circular Motion
21
Relationship between quantities
This equation shows for a constant mass and
radius, both Fnet and a is directly proportional
to the v2.
F _____
a ______
If the speed of the object is doubled, the net
force required for that object's circular motion
and its acceleration are ____________. And if the
speed of the object is halved (decreased by a
factor of 2), the net force required and its
acceleration are decreased by a factor of
________.
22
example
  • A car going around a curve is acted upon by a
    centripetal force, F. If the speed of the car
    were twice as great, the centripetal force
    necessary to keep it moving in the same path
    would be
  • F
  • 2F           
  • F/2
  • 4F  

23
  • Centripetal force and mass of the object

This equation shows for a constant speed and
radius, the Fnet is _________________________ to
the mass.
If the mass of the object is doubled, the net
force required for that object's circular motion
is ____________. And if the mass of the object is
halved (decreased by a factor of 2), the net
force required is decreased by a factor of
______.
  • Centripetal acceleration and mass of the object

Centripetal acceleration is ________________ by
the mass of the object
24
example
  • Anna Litical is practicing a centripetal force
    demonstration at home. She fills a bucket with
    water, ties it to a strong rope, and spins it in
    a circle. Anna spins the bucket when it is
    half-full of water and when it is quarter-full of
    water. In which case is more force required to
    spin the bucket in a circle? Explain using an
    equation.

25
example
  • The diagram shows a 5.0-kilogram cart traveling
    clockwise in a horizontal circle of radius 2.0
    meters at a constant speed of 4.0 meters per
    second. If the mass of the cart was doubled, the
    magnitude of the centripetal acceleration of the
    cart would be
  • doubled
  • halved
  • unchanged
  • quadrupled

26
  • Centripetal Force, acceleration and the radius

This equation shows for a constant speed and
mass, the Fnet and acceleration a is
______________________ to the radius
If the radius of the object is doubled, the net
force required for that object's circular motion
and its acceleration are both ____________. And
if the radius of the object is halved (decreased
by a factor of 2), the net force required and its
acceleration are both increased by a factor of
_______________.
27
example
  • Two masses, A and B, move in circular paths as
    shown in the diagram. The centripetal
    acceleration of mass A, compared to that of mass
    B, is
  • the same
  • twice as great
  • one-half as great
  • four times as great

28
Equations as a Recipe for Problem-Solving
  • A 900-kg car moving at 10 m/s takes a turn around
    a circle with a radius of 25.0 m. Determine the
    acceleration and the net force acting upon the
    car.

29
example
  • A 95-kg halfback makes a turn on the football
    field. The halfback sweeps out a path which is a
    portion of a circle with a radius of 12-meters.
    The halfback makes a quarter of a turn around the
    circle in 2.1 seconds. Determine the speed,
    acceleration and net force acting upon the
    halfback.

30
example
  • Determine the centripetal force acting upon a
    40-kg child who makes 10 revolutions around the
    Cliffhanger in 29.3 seconds. The radius of the
    barrel is 2.90 meters.

31
Lesson 2 Applications of Circular Motion
  • Newton's Second law - Revisited
  • Amusement Park Physics

32
Applications of Circular Motion
  • Newton's Second Law - Revisited

Where Fnet is the sum (the resultant) of all
forces acting on the object.
Newton's second law was used in combination of
circular motion equations to analyze a variety of
physical situations. Note centripetal force is
the _____ force!
33
Steps in solving problems involving forces
  • Drawing Free-Body Diagrams
  • Determining the Net Force from Knowledge of
    Individual Force Values
  • Determining Acceleration from Knowledge of
    Individual Force Values
  • Or Determining Individual Force Values from
    Knowledge of the Acceleration

34
example
  • A 945-kg car makes a 180-degree turn with a speed
    of 10.0 m/s. The radius of the circle through
    which the car is turning is 25.0 m. Determine the
    force of friction and the coefficient of friction
    acting upon the car.

35
example
  • The coefficient of friction acting upon a 945-kg
    car is 0.850. The car is making a 180-degree turn
    around a curve with a radius of 35.0 m. Determine
    the maximum speed with which the car can make the
    turn.

36
  • A 1.50-kg bucket of water is tied by a rope and
    whirled in a circle with a radius of 1.00 m. At
    the top of the circular loop, the speed of the
    bucket is 4.00 m/s. Determine the acceleration,
    the net force and the individual force values
    when the bucket is at the top of the circular
    loop.

m 1.5 kg a ________ m/s/s Fnet  _________
N  
37
  • A 1.50-kg bucket of water is tied by a rope and
    whirled in a circle with a radius of 1.00 m. At
    the bottom of the circular loop, the speed of the
    bucket is 6.00 m/s. Determine the acceleration,
    the net force and the individual force values
    when the bucket is at the bottom of the circular
    loop.

m 1.5 kg a ________ m/s/s Fnet  _________
N  
38
Roller Coasters and Amusement Park Physics
In a roller coaster, the centripetal force is
provided by the combination of ___________________
_________.
39
example
  • Anna Litical is riding on The Demon at Great
    America. Anna experiences a downwards
    acceleration of 15.6 m/s2 at the top of the loop
    and an upwards acceleration of 26.3 m/s2 at the
    bottom of the loop. Use Newton's second law to
    determine the normal force acting upon Anna's 864
    kg roller coaster car.

40
example
  • Anna Litical is riding on The American Eagle at
    Great America. Anna is moving at 18.9 m/s over
    the top of a hill which has a radius of curvature
    of 12.7 m. Use Newton's second law to determine
    the magnitude of the applied force of the track
    pulling down upon Anna's 621 kg roller coaster
    car.

41
Lesson 3 Universal Gravitation
  1. Gravity is More than a Name
  2. The Apple, the Moon, and the Inverse Square Law
  3. Newton's Law of Universal Gravitation
  4. Cavendish and the Value of G
  5. The Value of g

42
Gravity is More Than a Name
  • We know that gravity is a force and we represent
    it by the symbol Fgrav. It causes an acceleration
    of all objects around it. The acceleration is
    referred as the acceleration of gravity. On and
    near Earth's surface, the value for the
    acceleration of gravity is approximately 9.81
    m/s/s. It is the same acceleration value for all
    objects, regardless of their mass (and assuming
    that the only significant force is gravity).
  • but
  • How and by whom was gravity discovered?
  • What is the cause of this force of gravity?
  • What variables affect the actual value of the
    force of gravity?
  • Is the force of gravity that attracts my body to
    the Earth related to the force of gravity between
    the planets and the Sun?

43
The Apple, the Moon, and the Inverse Square Law
  • In the early 1600's, German mathematician and
    astronomer Johannes ________________ developed
    three laws to describe the motion of planets
    about the sun. However, there was no accepted
    explanation for why such paths existed.
  • Newton was troubled by the lack of explanation
    for the planet's orbits. Newton knew that for the
    motion of the moon in a circular path required
    that there be an inward component of __________.
    However, the nature of such a force - its cause
    and its origin - bothered Newton for some time.

44
And according to legend, a breakthrough came at
age 24 in an apple orchard in England.
Clearly, it was Newton's ability to relate the
cause for heavenly motion (the orbit of the moon
about the earth) to the cause for Earthly motion
(the falling of an apple to the Earth) that led
him to his notion of __________________________
45
Newton's reasoning
Suppose a cannonball is fired horizontally from a
very high mountain in a region devoid of air
resistance. In the presence of gravity, the
cannonball would ___________________
Now suppose that the cannonball is fired
horizontally again with a greater speed. In this
case, the cannonball would _______________________
___________.
Now suppose that there is a speed at which the
cannonball could be fired such that the
trajectory of the falling cannonball matched the
curvature of the earth, then the cannonball would
_________________________________________________
______
46
And then at even greater launch speeds, a
cannonball would once more orbit the earth, but
in an ____________ path, like the planets
The motion of the cannonball orbiting to the
earth under the influence of gravity is similar
to the motion of the moon orbiting the Earth. And
if the orbiting moon can be compared to the
falling cannonball, it can even be compared to a
falling apple. The same force that causes objects
on Earth to fall to the earth also causes objects
in the heavens to move along their circular and
elliptical paths.
47
  • It was known at the time, that the force of
    gravity causes earthbound objects (such as
    falling apples) to accelerate towards the earth
    at a rate of 9.81 m/s2. And it was also known
    that the moon accelerated towards the earth at a
    rate of 0.00272 m/s2.
  • If the same force that causes the acceleration of
    the apple to the earth also causes the
    acceleration of the moon towards the earth, then
    there must be a plausible explanation for why the
    acceleration of the moon is so much smaller than
    the acceleration of the apple. What is it about
    the force of gravity that causes the more distant
    moon to accelerate at a rate of acceleration that
    is approximately 1/3600-th the acceleration of
    the apple?

48
  • Newton knew that the force of gravity must
    somehow be ____________" by distance.
  • The riddle is solved by a comparison of the
    _____________ from the apple to the center of the
    earth with the __________ from the moon to the
    center of the earth. The moon in its orbit about
    the earth is approximately _____________ further
    from the earth's center than the apple is. The
    mathematical relationship becomes clear. The
    force of gravity between the earth and any object
    is inversely proportional to the square of the
    distance that separates that object from the
    earth's center. The moon, being 60 times further
    away than the apple, experiences a force of
    gravity that is 1/(60)2 times that of the apple.
    The force of gravity follows an
    _____________________.

49
Inverse square law.
  • The relationship between the force of gravity
    (Fgrav) between the earth and any other object
    and the distance that separates their centers (d)
    can be expressed by the following relationship

The force of gravity is inversely related to the
square of the distance. This mathematical
relationship is sometimes referred to as an
inverse square law.
50
Relationships in the equation
  • The inverse square law suggests that the force of
    gravity acting between any two objects is
    ___________________________ to the ___________ of
    the separation __________________ between the
    object's centers.
  • If the separation distance is increased by a
    factor of 2, then the force of gravity is
    decreased by a factor of four (______). And if
    the separation distance is increased by a factor
    of 3, then the force of gravity is decreased by a
    factor of nine (_______).

Fg
r
51
Check Your Understanding
  • 1 . Suppose that two objects attract each other
    with a gravitational force of 16 units. If the
    distance between the two objects is doubled, what
    is the new force of attraction between the two
    objects?
  •  
  •   
  • 2. Suppose that two objects attract each other
    with a gravitational force of 16 units. If the
    distance between the two objects is tripled, then
    what is the new force of attraction between the
    two objects?
  •  
  •   
  • 3. Suppose that two objects attract each other
    with a gravitational force of 16 units. If the
    distance between the two objects is reduced in
    half, then what is the new force of attraction
    between the two objects?
  •  
  •   
  • 4. Suppose that two objects attract each other
    with a gravitational force of 16 units. If the
    distance between the two objects is reduced by a
    factor of 5, then what is the new force of
    attraction between the two objects?

52
example
  • An astronaut weighs 8.00 102 newtons on the
    surface of Earth. What is the weight of the
    astronaut 6.37 106 meters above the surface of
    Earth?
  • 0.00 N
  • 2.00 102 N
  • 1.60 103 N
  • 3.20 103 N

53
Newton's Law of Universal Gravitation
  • Consider Newton's famous equation Fnet m a
  • Newton knew that the force that caused the
    apple's acceleration (gravity) must be dependent
    upon the mass of the __________. And since the
    force acting to cause the apple's downward
    acceleration also causes the earth's upward
    acceleration (Newton's third law), that force
    must also depend upon the mass of the ________.
  • So for Newton, the force of gravity acting
    between the earth and any other object is
    directly proportional to the mass of the _______,
    directly proportional to the mass of the
    ________, and inversely proportional to the
    _______________________ that separates the
    centers of the earth and the object.
  • Newton's law of universal gravitation is about
    the _______________ of gravity. _________ objects
    attract each other with a force of gravitational
    attraction.

54
Examples
  • What happens to Fg in the following cases?
  • Double one mass
  • Double both masses
  • Triple one mass
  • Triple both masses
  • Halve one mass
  • Halve one mass and double the other

55
Examples
  • What happens to Fg in the following cases?
  • Double the distance
  • Triple the distance
  • Halve the distance
  • Quarter the distance

56
Examples
  • What happens to Fg in the following cases?
  • Double one mass and double the distance
  • Double both masses and double the distance
  • Halve one mass and halve the distance
  • Triple one mass and quarter the distance

57
Newton's Law of Universal Gravitation
  • Another means of representing the
    proportionalities is to express the relationships
    in the form of an equation using a constant of
    proportionality.

G represent Gravitational Constant G
____________________
58
Example
  • Determine the force of gravitational attraction
    between the earth (m 5.98 x 1024 kg) and a
    70-kg physics student if the student is standing
    at sea level, a distance of 6.38 x 106 m from
    earth's center.

59
The Universality of Gravity
Mass of Object 1 (kg) Mass of Object 2 (kg) Separation Distance (m) Force of Gravity (N)
Student 70 kg Earth 5.98 x1024 kg 6.60 x 106 m (low-height orbit)
Student 70 kg Physics Student 70 kg 1 m
Student 70 kg Physics Book 1 kg 1 m
Student 70 kg Jupiter 1.901 x 1027 kg 6.98 x 107 m (on surface)
 
60
Cavendish and the Value of G
  • The value of G was not experimentally determined
    until nearly a century later (1798) by Lord Henry
    Cavendish using a torsion balance.

Lord Henry Cavendish - English chemist and
physicist
61
The Value of g
Fgrav mg
  • We can use the two equations above to derive an
    equation for the value of g.

The acceleration of gravity is dependent upon the
mass of the earth (approx. 5.98x1024 kg) and the
distance (d) that an object is from the center of
the earth.
The acceleration of gravity is location dependent.
62
Note that g is inversely proportional to the
distance squared inverse square law.
63
The table below shows the value of g at various
locations from Earth's center.
The table below shows the value of g at various
locations from Earth's center.
Location Distance from Earth's center (m) Value of g m/s2
Earth's surface 6.38 x 106 m 9.8
1000 km above surface 7.38 x 106 m
5000 km above surface 1.14 x 107 m
10000 km above surface 1.64 x 107 m
50000 km above surface 5.64 x 107 m

64
Using this equation, the following acceleration
of gravity values can be calculated for the
various planets.
Planet Radius (m) Mass (kg) g (m/s2)
Mars 3.38 x 106 6.42 x 1023
Jupiter 6.98 x 107 1.901 x 1027
Neptune 2.27 x 107 1.03 x 1026
Pluto 1.15 x 106 1.2 x 1022

65
Example - Calculating the mass of the Earth
  • Knowing G, and the radius of the Earth, RE
    6.37 x 106 m, we can now actually calculate the
    mass of the Earth.

66
Gravity is a field force
  • Gravitational field a ________________ where an
    object would experience a gravitational force.
    Every mass is surrounded by a gravitational
    field.
  • As the distance from the Earth increases, the
    strength of gravitational ___________________.
  • As the distance from the Earth increases, the
    arrows are further apart and the length of arrows
    are _________, indicating the strength of the
    gravitational force _______________.


67
The gravitational field around Earth
Gravitational field strength is a vector
quantity. Its direction is directed
_____________________ of Earth, or normal to
Earths surface. Its magnitude at a point equals
the force per unit mass at that point.
  • The concentration of the field lines increases as
    the distance from Earth decreases.

68
example
  • The weight of an object was determined at five
    different distances from the center of Earth. The
    results are shown in the table below. Position A
    represents results for the object at the surface
    of Earth. What is the approximate mass of the
    object?

69
Lesson 4 Satellite Motion
  • Circular Motion Principles for Satellites
  • Mathematics of Satellite Motion
  • Weightlessness in Orbit

70
Circular Motion Principles for Satellites
  • A satellite is any object that is orbiting the
    earth, sun or other massive body. Satellites can
    be categorized as ____________ satellites or
    _____________ satellites.
  • The ___________, the _______________ and comets
    are examples of natural satellites.
  • ________________ launched from earth for purposes
    of communication, scientific research, weather
    forecasting, intelligence, etc. are man-made
    satellites.
  • Every satellite's motion is governed by the same
    physics principles and described by the same
    mathematical equations.

71
Velocity, Acceleration and Force Vectors
  • The motion of an orbiting satellite can be
    described by the same motion characteristics as
    any object in circular motion.
  • The ______________ of the satellite would be
    directed tangent to the circle at every point
    along its path.
  • The _______________ of the satellite would be
    directed towards the center of the circle -
    towards the central body that it is orbiting.
  • And this acceleration is caused by a ____________
    that is directed inwards in the same direction as
    the acceleration. This centripetal force is
    supplied by _________________ - the force that
    universally acts at a distance between any two
    objects that have mass.

72
(No Transcript)
73
Mathematics of Satellite Motion
  • If the satellite moves in circular motion, then
    the net centripetal force acting upon this
    orbiting satellite is given by the relationship
  • Fnet ____________________
  • This net centripetal force is the result of the
    gravitational force that attracts the satellite
    towards the central body and can be represented
    as
  • Fgrav ____________________

74
  • Since Fgrav Fnet,
  • _________________________________
  • v2 _______________
  • v _______________

where G is 6.673 x 10-11 Nm2/kg2, Mcentral
is the mass of the central body about which
the satellite orbits, and R is the radius of
orbit for the satellite.
The speed of satellite is determined by its
location ___ and mass of the central body
__________.
75
Check your understanding
  • A satellite is orbiting the earth. Which of the
    following variables will affect the speed of the
    satellite?
  • a. mass of the satellite
  • b. height above the earth's surface
  • c. mass of the earth

76
Weightlessness in Orbit
  • Astronauts who are orbiting the Earth often
    experience sensations of weightlessness. These
    sensations experienced by orbiting astronauts are
    the __________ sensations experienced by anyone
    who has been temporarily suspended above the seat
    on an amusement park ride.
  • Not only are the sensations the same (for
    astronauts and roller coaster riders), but the
    __________ of those sensations of weightlessness
    are also the ________. Unfortunately however,
    many people have difficulty understanding the
    causes of weightlessness.

77
Test your preconceived notions about
weightlessness
  • Astronauts on the orbiting space station are
    weightless because...
  • there is no gravity in space and they do not
    weigh anything.
  • space is a vacuum and there is no gravity in a
    vacuum.
  • c. space is a vacuum and there is no air
    resistance in a vacuum.
  • d. the astronauts are far from Earth's surface
    at a location where gravitation has a minimal
    affect.

78
Contact versus Non-Contact Forces
79
Contact versus Non-Contact Forces
  • As you sit in a chair, you experience two forces
    ________
  • The normal force and results from the
    _______________ between the chair and you. You
    can feel this force because of the contact you
    have with the chair.
  • The force of gravity acting upon your body is a
    field force, which is the result of your center
    of mass and the Earth's center of mass exerting a
    mutual pull on each other this force would even
    exist if you were not in contact with the Earth.
  • The force of gravity ___________________. Forces
    that result from contact ____________. And in the
    case of sitting in your chair, you can feel the
    chair force and it is this force that provides
    you with a sensation of weight. Without the
    contact force (the normal force), there is no
    means of feeling the non-contact force (the force
    of gravity).

80
Scale Readings and Weight
Now consider Otis L. Evaderz who is conducting
one of his famous elevator experiments. He stands
on a bathroom scale and rides an elevator up and
down. As he is accelerating upward and downward,
the scale reading is __________________ than when
he is at rest and traveling at constant speed.
81
Fnet ma Fnet 0 N Fnet ma Fnet 400 N, up Fnet ma Fnet 400 N, down Fnet ma Fnet 784 N, down
Fnorm equals Fgrav Fnorm ____N Fnorm gt Fgrav by 400 N Fnorm ____ N Fnorm lt Fgrav by 400 N Fnorm _____ N Fnorm lt Fgrav by 784 N Fnorm __ N
82
Weightlessness in Orbit
  • Earth-orbiting astronauts are weightless for the
    same reasons that riders of a free-falling
    amusement park ride or a free-falling elevator
    are weightless. They are weightless because there
    is ______________________ force pushing or
    pulling upon their body.
  • In each case, gravity is the _____________ acting
    upon their body. Being an action-at-a-distance
    force, it cannot be felt and therefore would not
    provide any sensation of their weight. But for
    certain, the orbiting astronauts weigh something
    that is, there is a force of gravity acting upon
    their body.
  • In fact, if it were not for the force of gravity,
    the astronauts would not be orbiting in circular
    motion. It is the force of gravity that supplies
    the ____________________ requirement to allow the
    __________________ acceleration that is
    characteristic of circular motion.
  • The astronauts and their surroundings are falling
    towards the Earth under the sole influence of
    _______________.

83
  • 1. Otis stands on a bathroom scale and reads the
    scale while ascending and descending the John
    Hancock building. Otis' mass is 80 kg.. Use a
    free-body diagram and Newton's second law of
    motion to solve the following problems.
  • a. What is the scale reading when Otis
    accelerates upward at 0.40 m/s2?
  •  
  • b. What is the scale reading when Otis is
    traveling upward at a constant velocity of at 2.0
    m/s?
  •  
  • c. As Otis approaches the top of the building,
    the elevator slows down at a rate of 0.40 m/s2.
    Be cautious of the direction of the acceleration.
    What does the scale read?
  •  
  • d. Otis stops at the top floor and then
    accelerates downward at a rate of 0.40 m/s2. What
    does the scale read?
  •  
  • e. As Otis approaches the ground floor, the
    elevator slows down (an upward acceleration) at a
    rate of 0.40 m/s2. Be cautious of the direction
    of the acceleration. What does the scale read?
  •  
  • Use the results of your calculations above to
    explain why Otis fells less weighty when
    accelerating downward on the elevator and why he
    feels heavy when accelerating upward on the
    elevator.
  •  
Write a Comment
User Comments (0)
About PowerShow.com