Title: Objective - Lesson 1: Motion Characteristics for Circular Motion
1Objective - Lesson 1 Motion Characteristics for
Circular Motion
- Speed and Velocity
- Acceleration
- The Centripetal Force Requirement
- Mathematics of Circular Motion
2Uniform circular motion
- Uniform circular motion is the motion of an
object in a circle with a ___________ or uniform
speed. The velocity is changing because the
direction of motion is ______________.
- Speed _____________
- Direction of motion _____________ of the path
- Velocity
- magnitude ___________
- Direction _____________
3Speed and velocity
- Calculation of the Average Speed
- vavg _________
- The distance of one complete cycle around the
perimeter of a circle is known as the
____________. - Circumference ____ (R is the radius of the
circle) - The time (T) to make one cycle around the circle
is called one _________. - The average speed of an object in uniform
circular motion is
vavg ____________
4- The average speed and the Radius of the circle
are _____________________. - The average speed and the Period of the circle
are _____________________.
5The Direction of the Velocity Vector
The best word that can be used to describe the
direction of the velocity vector is the word
____________________. The direction of the
velocity vector at any instant is in the
direction of a tangent line drawn to the circle
at the object's location.
6- To summarize, an object moving in uniform
circular motion is moving around the perimeter of
the circle with a __________speed. While the
speed of the object is constant, its velocity is
changing. Velocity, being a vector, has a
constant magnitude but a changing direction. The
direction is always directed _________ to the
circle and as the object turns the circle, the
tangent line is always pointing in a new
direction.
The average speed is directly proportional to the
____________ and inversely proportional to the
_____________.
7Check Your Understanding
- A tube is been placed upon the table and shaped
into a three-quarters circle. A golf ball is
pushed into the tube at one end at high speed.
The ball rolls through the tube and exits at the
opposite end. Describe the path of the golf ball
as it exits the tube.
8example
- A vehicle travels at a constant speed of 6.0
meters per second around a horizontal circular
curve with a radius of 24 meters. The mass of the
vehicle is 4.4 103 kilograms. An icy patch is
located at P on the curve. On the icy patch of
pavement, the frictional force of the vehicle is
zero. Which arrow best represents the direction
of the vehicle's velocity when it reaches icy
patch P?
a
b
c
d
9Acceleration
- An object moving in uniform circular motion is
moving in a circle with a uniform or constant
speed. The velocity vector is constant in
magnitude but changing in direction. - Since the velocity is changing. The object is
__________________.
where vi represents the initial velocity and vf
represents the final velocity after some time of
t
10Direction of the Acceleration Vector
- The velocity change is directed towards point C -
the ________ of the circle. - The acceleration of the object is dependent upon
this velocity change and is in the same direction
as this ____________. The acceleration is
directed towards point C as well - the
___________________________.
11example
- The initial and final speed of a ball at two
different points in time is shown below. The
direction of the ball is indicated by the arrow.
For each case, indicate if there is an
acceleration. Explain why or why not. Indicate
the direction of the acceleration. - a.
b.
c.
d.
12example
- Explain why an object moving in a circle at
constant speed can be said to experience an
acceleration.
13example
An object is moving in a clockwise direction
around a circle at constant speed.
- Which vector below represents the direction of
the velocity vector when the object is located at
point B on the circle? - Which vector below represents the direction of
the acceleration vector when the object is
located at point C on the circle? - Which vector below represents the direction of
the velocity vector when the object is located at
point C on the circle? - Which vector below represents the direction of
the acceleration vector when the object is
located at point A on the circle?
14The Centripetal Force Requirement
- According to Newton's second law of motion, an
object which experiences an acceleration requires
a __________________. - The direction of the net force is in the same
direction as the ______________. So for an object
moving in a circle, there must be an inward force
acting upon it in order to cause its inward
acceleration. This is sometimes referred to as
the ________________ force requirement. - The word centripetal means _______________. For
object's moving in circular motion, there is a
net force acting towards the center which causes
the object to seek the center.
15Centrifugal force is a fictitious force
- centrifugal (center fleeing) force
- A fictitious or inertial force that is
experienced from INSIDE a circular motion system - centripetal (center seeking) force
- A true force that pushes or pulls an object
toward the center of a circular path
16The Centripetal Force is Net Force
- Any object moving in a circle (or along a
circular path) experiences a _______________
force. This is the centripetal force requirement.
- The word centripetal is merely an adjective used
to describe the direction of the force. We are
not introducing a new type of force but rather
describing the direction of the ________ force
acting upon the object that moves in the circle.
17examples of centripetal force
As the moon orbits the Earth, the force of
____________ acting upon the moon provides the
centripetal force required for circular motion.
As a car makes a turn, the force of _____________
acting upon the turned wheels of the car provides
centripetal force required for circular motion.
As a bucket of water is tied to a string and spun
in a circle, the _____________ force acting upon
the bucket provides the centripetal force
required for circular motion.
18- To summarize, an object in uniform circular
motion experiences an __________ net force. This
inward force is sometimes referred to as a
_______________ force, where centripetal
describes its direction. Without this centripetal
force, an object could never alter its direction.
The fact that the centripetal force is directed
___________________ to the tangential velocity
means that the force can alter the direction of
the object's velocity vector without altering its
magnitude.
19Check your understanding
- An object is moving in a clockwise direction
around a circle at constant speed
- Which vector below represents the direction of
the force vector when the object is located at
point A on the circle? - Which vector below represents the direction of
the force vector when the object is located at
point C on the circle? - Which vector below represents the direction of
the velocity vector when the object is located at
point B on the circle? - Which vector below represents the direction of
the velocity vector when the object is located at
point C on the circle? - Which vector below represents the direction of
the acceleration vector when the object is
located at point B on the circle?
20Mathematics of Circular Motion
21Relationship between quantities
This equation shows for a constant mass and
radius, both Fnet and a is directly proportional
to the v2.
F _____
a ______
If the speed of the object is doubled, the net
force required for that object's circular motion
and its acceleration are ____________. And if the
speed of the object is halved (decreased by a
factor of 2), the net force required and its
acceleration are decreased by a factor of
________.
22example
- A car going around a curve is acted upon by a
centripetal force, F. If the speed of the car
were twice as great, the centripetal force
necessary to keep it moving in the same path
would be - F
- 2F
- F/2
- 4F
23- Centripetal force and mass of the object
This equation shows for a constant speed and
radius, the Fnet is _________________________ to
the mass.
If the mass of the object is doubled, the net
force required for that object's circular motion
is ____________. And if the mass of the object is
halved (decreased by a factor of 2), the net
force required is decreased by a factor of
______.
- Centripetal acceleration and mass of the object
Centripetal acceleration is ________________ by
the mass of the object
24example
- Anna Litical is practicing a centripetal force
demonstration at home. She fills a bucket with
water, ties it to a strong rope, and spins it in
a circle. Anna spins the bucket when it is
half-full of water and when it is quarter-full of
water. In which case is more force required to
spin the bucket in a circle? Explain using an
equation.
25example
- The diagram shows a 5.0-kilogram cart traveling
clockwise in a horizontal circle of radius 2.0
meters at a constant speed of 4.0 meters per
second. If the mass of the cart was doubled, the
magnitude of the centripetal acceleration of the
cart would be - doubled
- halved
- unchanged
- quadrupled
26- Centripetal Force, acceleration and the radius
This equation shows for a constant speed and
mass, the Fnet and acceleration a is
______________________ to the radius
If the radius of the object is doubled, the net
force required for that object's circular motion
and its acceleration are both ____________. And
if the radius of the object is halved (decreased
by a factor of 2), the net force required and its
acceleration are both increased by a factor of
_______________.
27example
- Two masses, A and B, move in circular paths as
shown in the diagram. The centripetal
acceleration of mass A, compared to that of mass
B, is - the same
- twice as great
- one-half as great
- four times as great
28Equations as a Recipe for Problem-Solving
- A 900-kg car moving at 10 m/s takes a turn around
a circle with a radius of 25.0 m. Determine the
acceleration and the net force acting upon the
car.
29example
- A 95-kg halfback makes a turn on the football
field. The halfback sweeps out a path which is a
portion of a circle with a radius of 12-meters.
The halfback makes a quarter of a turn around the
circle in 2.1 seconds. Determine the speed,
acceleration and net force acting upon the
halfback.
30example
- Determine the centripetal force acting upon a
40-kg child who makes 10 revolutions around the
Cliffhanger in 29.3 seconds. The radius of the
barrel is 2.90 meters.
31Lesson 2 Applications of Circular Motion
- Newton's Second law - Revisited
- Amusement Park Physics
32Applications of Circular Motion
- Newton's Second Law - Revisited
Where Fnet is the sum (the resultant) of all
forces acting on the object.
Newton's second law was used in combination of
circular motion equations to analyze a variety of
physical situations. Note centripetal force is
the _____ force!
33Steps in solving problems involving forces
- Drawing Free-Body Diagrams
- Determining the Net Force from Knowledge of
Individual Force Values - Determining Acceleration from Knowledge of
Individual Force Values - Or Determining Individual Force Values from
Knowledge of the Acceleration
34example
- A 945-kg car makes a 180-degree turn with a speed
of 10.0 m/s. The radius of the circle through
which the car is turning is 25.0 m. Determine the
force of friction and the coefficient of friction
acting upon the car.
35example
- The coefficient of friction acting upon a 945-kg
car is 0.850. The car is making a 180-degree turn
around a curve with a radius of 35.0 m. Determine
the maximum speed with which the car can make the
turn.
36- A 1.50-kg bucket of water is tied by a rope and
whirled in a circle with a radius of 1.00 m. At
the top of the circular loop, the speed of the
bucket is 4.00 m/s. Determine the acceleration,
the net force and the individual force values
when the bucket is at the top of the circular
loop.
m 1.5 kg a ________ m/s/s Fnet _________
N
37- A 1.50-kg bucket of water is tied by a rope and
whirled in a circle with a radius of 1.00 m. At
the bottom of the circular loop, the speed of the
bucket is 6.00 m/s. Determine the acceleration,
the net force and the individual force values
when the bucket is at the bottom of the circular
loop.
m 1.5 kg a ________ m/s/s Fnet _________
N
38Roller Coasters and Amusement Park Physics
In a roller coaster, the centripetal force is
provided by the combination of ___________________
_________.
39example
- Anna Litical is riding on The Demon at Great
America. Anna experiences a downwards
acceleration of 15.6 m/s2 at the top of the loop
and an upwards acceleration of 26.3 m/s2 at the
bottom of the loop. Use Newton's second law to
determine the normal force acting upon Anna's 864
kg roller coaster car.
40example
- Anna Litical is riding on The American Eagle at
Great America. Anna is moving at 18.9 m/s over
the top of a hill which has a radius of curvature
of 12.7 m. Use Newton's second law to determine
the magnitude of the applied force of the track
pulling down upon Anna's 621 kg roller coaster
car.
41Lesson 3 Universal Gravitation
- Gravity is More than a Name
- The Apple, the Moon, and the Inverse Square Law
- Newton's Law of Universal Gravitation
- Cavendish and the Value of G
- The Value of g
42Gravity is More Than a Name
- We know that gravity is a force and we represent
it by the symbol Fgrav. It causes an acceleration
of all objects around it. The acceleration is
referred as the acceleration of gravity. On and
near Earth's surface, the value for the
acceleration of gravity is approximately 9.81
m/s/s. It is the same acceleration value for all
objects, regardless of their mass (and assuming
that the only significant force is gravity). - but
- How and by whom was gravity discovered?
- What is the cause of this force of gravity?
- What variables affect the actual value of the
force of gravity? - Is the force of gravity that attracts my body to
the Earth related to the force of gravity between
the planets and the Sun?
43The Apple, the Moon, and the Inverse Square Law
- In the early 1600's, German mathematician and
astronomer Johannes ________________ developed
three laws to describe the motion of planets
about the sun. However, there was no accepted
explanation for why such paths existed.
- Newton was troubled by the lack of explanation
for the planet's orbits. Newton knew that for the
motion of the moon in a circular path required
that there be an inward component of __________.
However, the nature of such a force - its cause
and its origin - bothered Newton for some time.
44And according to legend, a breakthrough came at
age 24 in an apple orchard in England.
Clearly, it was Newton's ability to relate the
cause for heavenly motion (the orbit of the moon
about the earth) to the cause for Earthly motion
(the falling of an apple to the Earth) that led
him to his notion of __________________________
45Newton's reasoning
Suppose a cannonball is fired horizontally from a
very high mountain in a region devoid of air
resistance. In the presence of gravity, the
cannonball would ___________________
Now suppose that the cannonball is fired
horizontally again with a greater speed. In this
case, the cannonball would _______________________
___________.
Now suppose that there is a speed at which the
cannonball could be fired such that the
trajectory of the falling cannonball matched the
curvature of the earth, then the cannonball would
_________________________________________________
______
46And then at even greater launch speeds, a
cannonball would once more orbit the earth, but
in an ____________ path, like the planets
The motion of the cannonball orbiting to the
earth under the influence of gravity is similar
to the motion of the moon orbiting the Earth. And
if the orbiting moon can be compared to the
falling cannonball, it can even be compared to a
falling apple. The same force that causes objects
on Earth to fall to the earth also causes objects
in the heavens to move along their circular and
elliptical paths.
47- It was known at the time, that the force of
gravity causes earthbound objects (such as
falling apples) to accelerate towards the earth
at a rate of 9.81 m/s2. And it was also known
that the moon accelerated towards the earth at a
rate of 0.00272 m/s2. - If the same force that causes the acceleration of
the apple to the earth also causes the
acceleration of the moon towards the earth, then
there must be a plausible explanation for why the
acceleration of the moon is so much smaller than
the acceleration of the apple. What is it about
the force of gravity that causes the more distant
moon to accelerate at a rate of acceleration that
is approximately 1/3600-th the acceleration of
the apple?
48- Newton knew that the force of gravity must
somehow be ____________" by distance. - The riddle is solved by a comparison of the
_____________ from the apple to the center of the
earth with the __________ from the moon to the
center of the earth. The moon in its orbit about
the earth is approximately _____________ further
from the earth's center than the apple is. The
mathematical relationship becomes clear. The
force of gravity between the earth and any object
is inversely proportional to the square of the
distance that separates that object from the
earth's center. The moon, being 60 times further
away than the apple, experiences a force of
gravity that is 1/(60)2 times that of the apple.
The force of gravity follows an
_____________________.
49Inverse square law.
- The relationship between the force of gravity
(Fgrav) between the earth and any other object
and the distance that separates their centers (d)
can be expressed by the following relationship -
The force of gravity is inversely related to the
square of the distance. This mathematical
relationship is sometimes referred to as an
inverse square law.
50Relationships in the equation
- The inverse square law suggests that the force of
gravity acting between any two objects is
___________________________ to the ___________ of
the separation __________________ between the
object's centers. - If the separation distance is increased by a
factor of 2, then the force of gravity is
decreased by a factor of four (______). And if
the separation distance is increased by a factor
of 3, then the force of gravity is decreased by a
factor of nine (_______).
Fg
r
51Check Your Understanding
- 1 . Suppose that two objects attract each other
with a gravitational force of 16 units. If the
distance between the two objects is doubled, what
is the new force of attraction between the two
objects? -
-
- 2. Suppose that two objects attract each other
with a gravitational force of 16 units. If the
distance between the two objects is tripled, then
what is the new force of attraction between the
two objects? -
-
- 3. Suppose that two objects attract each other
with a gravitational force of 16 units. If the
distance between the two objects is reduced in
half, then what is the new force of attraction
between the two objects? -
-
- 4. Suppose that two objects attract each other
with a gravitational force of 16 units. If the
distance between the two objects is reduced by a
factor of 5, then what is the new force of
attraction between the two objects?
52example
- An astronaut weighs 8.00 102 newtons on the
surface of Earth. What is the weight of the
astronaut 6.37 106 meters above the surface of
Earth? - 0.00 N
- 2.00 102 N
- 1.60 103 N
- 3.20 103 N
53Newton's Law of Universal Gravitation
- Consider Newton's famous equation Fnet m a
- Newton knew that the force that caused the
apple's acceleration (gravity) must be dependent
upon the mass of the __________. And since the
force acting to cause the apple's downward
acceleration also causes the earth's upward
acceleration (Newton's third law), that force
must also depend upon the mass of the ________. - So for Newton, the force of gravity acting
between the earth and any other object is
directly proportional to the mass of the _______,
directly proportional to the mass of the
________, and inversely proportional to the
_______________________ that separates the
centers of the earth and the object. - Newton's law of universal gravitation is about
the _______________ of gravity. _________ objects
attract each other with a force of gravitational
attraction.
54Examples
- What happens to Fg in the following cases?
- Double one mass
- Double both masses
- Triple one mass
- Triple both masses
- Halve one mass
- Halve one mass and double the other
55Examples
- What happens to Fg in the following cases?
- Double the distance
- Triple the distance
- Halve the distance
- Quarter the distance
56Examples
- What happens to Fg in the following cases?
- Double one mass and double the distance
- Double both masses and double the distance
- Halve one mass and halve the distance
- Triple one mass and quarter the distance
-
57Newton's Law of Universal Gravitation
- Another means of representing the
proportionalities is to express the relationships
in the form of an equation using a constant of
proportionality.
G represent Gravitational Constant G
____________________
58Example
- Determine the force of gravitational attraction
between the earth (m 5.98 x 1024 kg) and a
70-kg physics student if the student is standing
at sea level, a distance of 6.38 x 106 m from
earth's center.
59The Universality of Gravity
Mass of Object 1 (kg) Mass of Object 2 (kg) Separation Distance (m) Force of Gravity (N)
Student 70 kg Earth 5.98 x1024 kg 6.60 x 106 m (low-height orbit)
Student 70 kg Physics Student 70 kg 1 m
Student 70 kg Physics Book 1 kg 1 m
Student 70 kg Jupiter 1.901 x 1027 kg 6.98 x 107 m (on surface)
60Cavendish and the Value of G
- The value of G was not experimentally determined
until nearly a century later (1798) by Lord Henry
Cavendish using a torsion balance.
Lord Henry Cavendish - English chemist and
physicist
61The Value of g
Fgrav mg
- We can use the two equations above to derive an
equation for the value of g.
The acceleration of gravity is dependent upon the
mass of the earth (approx. 5.98x1024 kg) and the
distance (d) that an object is from the center of
the earth.
The acceleration of gravity is location dependent.
62Note that g is inversely proportional to the
distance squared inverse square law.
63The table below shows the value of g at various
locations from Earth's center.
The table below shows the value of g at various
locations from Earth's center.
Location Distance from Earth's center (m) Value of g m/s2
Earth's surface 6.38 x 106 m 9.8
1000 km above surface 7.38 x 106 m
5000 km above surface 1.14 x 107 m
10000 km above surface 1.64 x 107 m
50000 km above surface 5.64 x 107 m
64Using this equation, the following acceleration
of gravity values can be calculated for the
various planets.
Planet Radius (m) Mass (kg) g (m/s2)
Mars 3.38 x 106 6.42 x 1023
Jupiter 6.98 x 107 1.901 x 1027
Neptune 2.27 x 107 1.03 x 1026
Pluto 1.15 x 106 1.2 x 1022
65Example - Calculating the mass of the Earth
- Knowing G, and the radius of the Earth, RE
6.37 x 106 m, we can now actually calculate the
mass of the Earth. -
66Gravity is a field force
- Gravitational field a ________________ where an
object would experience a gravitational force.
Every mass is surrounded by a gravitational
field. - As the distance from the Earth increases, the
strength of gravitational ___________________. - As the distance from the Earth increases, the
arrows are further apart and the length of arrows
are _________, indicating the strength of the
gravitational force _______________.
67The gravitational field around Earth
Gravitational field strength is a vector
quantity. Its direction is directed
_____________________ of Earth, or normal to
Earths surface. Its magnitude at a point equals
the force per unit mass at that point.
- The concentration of the field lines increases as
the distance from Earth decreases.
68example
- The weight of an object was determined at five
different distances from the center of Earth. The
results are shown in the table below. Position A
represents results for the object at the surface
of Earth. What is the approximate mass of the
object?
69Lesson 4 Satellite Motion
- Circular Motion Principles for Satellites
- Mathematics of Satellite Motion
- Weightlessness in Orbit
70Circular Motion Principles for Satellites
- A satellite is any object that is orbiting the
earth, sun or other massive body. Satellites can
be categorized as ____________ satellites or
_____________ satellites. - The ___________, the _______________ and comets
are examples of natural satellites. - ________________ launched from earth for purposes
of communication, scientific research, weather
forecasting, intelligence, etc. are man-made
satellites. - Every satellite's motion is governed by the same
physics principles and described by the same
mathematical equations.
71Velocity, Acceleration and Force Vectors
- The motion of an orbiting satellite can be
described by the same motion characteristics as
any object in circular motion. - The ______________ of the satellite would be
directed tangent to the circle at every point
along its path. - The _______________ of the satellite would be
directed towards the center of the circle -
towards the central body that it is orbiting. - And this acceleration is caused by a ____________
that is directed inwards in the same direction as
the acceleration. This centripetal force is
supplied by _________________ - the force that
universally acts at a distance between any two
objects that have mass.
72(No Transcript)
73Mathematics of Satellite Motion
- If the satellite moves in circular motion, then
the net centripetal force acting upon this
orbiting satellite is given by the relationship - Fnet ____________________
- This net centripetal force is the result of the
gravitational force that attracts the satellite
towards the central body and can be represented
as - Fgrav ____________________
74- Since Fgrav Fnet,
-
- _________________________________
- v2 _______________
- v _______________
where G is 6.673 x 10-11 Nm2/kg2, Mcentral
is the mass of the central body about which
the satellite orbits, and R is the radius of
orbit for the satellite.
The speed of satellite is determined by its
location ___ and mass of the central body
__________.
75Check your understanding
- A satellite is orbiting the earth. Which of the
following variables will affect the speed of the
satellite? - a. mass of the satellite
- b. height above the earth's surface
- c. mass of the earth
76Weightlessness in Orbit
- Astronauts who are orbiting the Earth often
experience sensations of weightlessness. These
sensations experienced by orbiting astronauts are
the __________ sensations experienced by anyone
who has been temporarily suspended above the seat
on an amusement park ride. - Not only are the sensations the same (for
astronauts and roller coaster riders), but the
__________ of those sensations of weightlessness
are also the ________. Unfortunately however,
many people have difficulty understanding the
causes of weightlessness.
77Test your preconceived notions about
weightlessness
- Astronauts on the orbiting space station are
weightless because... - there is no gravity in space and they do not
weigh anything. - space is a vacuum and there is no gravity in a
vacuum. - c. space is a vacuum and there is no air
resistance in a vacuum. - d. the astronauts are far from Earth's surface
at a location where gravitation has a minimal
affect.
78Contact versus Non-Contact Forces
79Contact versus Non-Contact Forces
- As you sit in a chair, you experience two forces
________ - The normal force and results from the
_______________ between the chair and you. You
can feel this force because of the contact you
have with the chair. - The force of gravity acting upon your body is a
field force, which is the result of your center
of mass and the Earth's center of mass exerting a
mutual pull on each other this force would even
exist if you were not in contact with the Earth. - The force of gravity ___________________. Forces
that result from contact ____________. And in the
case of sitting in your chair, you can feel the
chair force and it is this force that provides
you with a sensation of weight. Without the
contact force (the normal force), there is no
means of feeling the non-contact force (the force
of gravity).
80Scale Readings and Weight
Now consider Otis L. Evaderz who is conducting
one of his famous elevator experiments. He stands
on a bathroom scale and rides an elevator up and
down. As he is accelerating upward and downward,
the scale reading is __________________ than when
he is at rest and traveling at constant speed.
81Fnet ma Fnet 0 N Fnet ma Fnet 400 N, up Fnet ma Fnet 400 N, down Fnet ma Fnet 784 N, down
Fnorm equals Fgrav Fnorm ____N Fnorm gt Fgrav by 400 N Fnorm ____ N Fnorm lt Fgrav by 400 N Fnorm _____ N Fnorm lt Fgrav by 784 N Fnorm __ N
82Weightlessness in Orbit
- Earth-orbiting astronauts are weightless for the
same reasons that riders of a free-falling
amusement park ride or a free-falling elevator
are weightless. They are weightless because there
is ______________________ force pushing or
pulling upon their body. - In each case, gravity is the _____________ acting
upon their body. Being an action-at-a-distance
force, it cannot be felt and therefore would not
provide any sensation of their weight. But for
certain, the orbiting astronauts weigh something
that is, there is a force of gravity acting upon
their body. - In fact, if it were not for the force of gravity,
the astronauts would not be orbiting in circular
motion. It is the force of gravity that supplies
the ____________________ requirement to allow the
__________________ acceleration that is
characteristic of circular motion. - The astronauts and their surroundings are falling
towards the Earth under the sole influence of
_______________.
83- 1. Otis stands on a bathroom scale and reads the
scale while ascending and descending the John
Hancock building. Otis' mass is 80 kg.. Use a
free-body diagram and Newton's second law of
motion to solve the following problems. - a. What is the scale reading when Otis
accelerates upward at 0.40 m/s2? -
- b. What is the scale reading when Otis is
traveling upward at a constant velocity of at 2.0
m/s? -
- c. As Otis approaches the top of the building,
the elevator slows down at a rate of 0.40 m/s2.
Be cautious of the direction of the acceleration.
What does the scale read? -
- d. Otis stops at the top floor and then
accelerates downward at a rate of 0.40 m/s2. What
does the scale read? -
- e. As Otis approaches the ground floor, the
elevator slows down (an upward acceleration) at a
rate of 0.40 m/s2. Be cautious of the direction
of the acceleration. What does the scale read? -
- Use the results of your calculations above to
explain why Otis fells less weighty when
accelerating downward on the elevator and why he
feels heavy when accelerating upward on the
elevator. -