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Entropy and Second Law of Thermodynamics

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Title: Entropy and Second Law of Thermodynamics


1
CHAPTER-20
  • Entropy and Second Law of Thermodynamics

2
CHAPTER-20 Entropy and Second Law of
Thermodynamics
  1. Topics to be covered
  2. Reversible processes
  3. Entropy
  4. The Carnot engine
  5. Refrigerators
  6. Real engines

3
Ch 20-2 Irreversible Process and Entropy
  • Irreversible Process One way process
  • If the irreversible process proceed in a closed
    system in a reverse way, we will wonder about it.
    A melted piece of ice freezes by itself. Although
    from energy conservation, the process can proceed
    in the reverse path i.e.heat released in in the
    environment in melting ice can be recovered back
    into ice piece to solidify it . Energy
    conservation does not prohibit the process to
    proceed one way or the reverse way.
  • Which parameter the one ay direction of the
    process?.
  • Entropy set the direction of irreversible process
    and irreversible process proceed through that
    path in which entropy of the system always
    increases
  • Entropy Postulate If an irreversible process
    occurs in a closed system, the entropy S of the
    system always increases

4
Ch 20-2 Irreversible Process and Entropy
  • Change in entropy (The arrow of time)-time
    reversal impossible due to entropy violation
  • Entropy definition Two methods
  • Using systems temperature and heat loss/gain by
    the system
  • By counting the ways in which the atoms or
    molecules of the system can be arranged
  • Entropy S state property like P,V,T, S
  • Change in entropy ?S?Q/T
  • ?SSf-Si?fi ?Q/T

5
Ch 20-3 Change in Entropy
  • Free Expansion of an ideal gas- Irreversible
    Process
  • An ideal gas expands from i to f state in an
    adiabatic process such that no work is done on or
    by the gas and no change in the internal energy
    of the system i.e. TiTf piVipfVf W?Eint0
  • ?SSf-Si?fi ?Q/T
  • Integral from i to f cannot be solved for an
    irreversible process but can be solved for a
    reversible process.
  • Since S is state variable (?Sif)rev (?Sif)irrev
  • ?Sirrev ?Srev Sf-Si ?fi ?Q/T (irreversible)
  • To find the entropy change for an irreversible
    process in a closed system, replace that process
    with any reversible process that connects that
    connects same initial and final states and
    calculate its change in entropy

6
Ch 20-3 Change in Entropy
  • Calculation of Entropy in Reversible Process
  • In free expansion TiTf, i.e. isothermal process
    then reversible isothermal expansion process can
    be used to calculate change in entropy in free
    expansion. Then
  • ?Srev Sf-Si ?fi ?Q/T 1/T?fi?Q (isothermal)
  • An ideal gas confined in a insulated cylinder
    fitted with a piston . The cylinder rest on a
    thermal reservoir maintained at temp T.
  • Gas is expanded isothermally from I to f state
    and heat is absorbed by the gas from the
    reservoir.?S is positive because ?Q is positive
  • ?S Sf-Si ??Q/T

7
Ch 20-3,4 Change in Entropy, Second Law of
Thermodynamics
  • Entropy as a State function
  • ?S Sf-Si ??Q/T but
  • ?Eint?Q-W or ?Q ?EintW WpdV ?Eint nCV?T
  • Then ?S ? ?Q/T ?if (nCVdT/T) ?if (pdV/T)
  • nCV ?if (dT/T) ?if (nRdV/V)
  • ?S nCV ln(Tf/Ti) nR ln(Vf/Vi)
  • Second Law of Thermodynamics
  • In a closed system entropy remains constant for
    reversible process but it increases for
    irreversible process.
  • Entropy never decreases
  • Change in Entropy of a reversible compression of
    an ideal gas in a closed system reservoir gas
  • ?Ssys ?Sgas ?Sres -Q/TQ/T0

8
Ch 20-5 Entropy in Real World Engines
  • A Carnot engine is a device that extracts heat QH
    from a reservoir at temperature TH, does useful
    work W and rejects heat QL to a reservoir at
    temperature TL.
  • On a p-V diagram Carnot cycle ( executed by a
    cylinder fitted with a piston and in thermal
    contact with one of two reservoirs at
    temperatures TH and TL.) is bound by two
    isotherms and two adiabatic.

9
Ch 20-5 Entropy in Real World Engines
  • Heat QH is absorbed at Temperature TH and heat QL
    is rejected at TL.
  • Work According to first law of thermodynamics,
    ?Eint?Q-W, ?Eint0
  • and W?Q?QH?-?QL?
  • Entropy Change ?S
  • In Carnot cycle ?S0
  • ?S0 QH/TH-QL/TL
  • QH/THQL/TL

10
Ch 20-5 Entropy in Real World Engines
  • Thermal Efficiency of an Engine ?
  • ? work we get /energy we pay for
  • ? ?W?/ ?QH?
  • For a Carnot engine W?QH?-?QL?
  • Then Carnot engine efficiency ?C is
  • ?C ?QH?-?QL?/?QH?
  • ?C1-?QL?/?QH?1- ?TL?/?TH?
  • There is no perfect engine i.e. QL0

11
Ch 20-6 Entropy in Real World Refrigerators
12
Ch 20-6 Entropy in Real World Refrigerators
  • A Refrigerator A device that uses work to
    transfer energy QL from a low temperature
    reservoir at temperature TL to a high-temperature
    reservoir at temperature TH
  • Coefficient of performance of a refrigerator K
  • K what we want /what we pay for
  • K?QL?/?W? but W?QH?-?QL?
  • K ?QL?/?W??QL?/?QH-?QL?
  • K ?QL?/?QH? ?TL?/?TH?-1
  • KTL/(TH-TL)
  • There is no perfect refrigerator i.e. W0
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