Title: Autosomal Dominant Inheritance
1Autosomal Dominant Inheritance
Human Genetics
- Autosomal dominant inheritance occurs when one
copy of an allele is sufficient for expression of
a trait and the gene is located on one of the 22
autosomes.
Genetics, Disease, and Dentistry
Each affected person has at least one affected
parent. An affected person has a 50 chance of
passing the trait to a child. Males and females
are equally likely to be affected. Two affected
people can have an unaffected child.
2Autosomal Dominant Disorders
- Progeria characterized by an appearance of
accelerated aging in children, affects 1 in 8
million newborns - Huntingtons Disease degenerative brain
disorder, slowly diminishes the affected
individuals ability to walk, think, talk and
reason ? dementia
3Autosomal Recessive Inheritance
- Autosomal recessive inheritance occurs when two
copies of an altered gene located on one of the
autosomes must be present for an individual to be
affected with the trait or condition determined
by that gene.
- An affected individual (homozygote) has two
parents who are unaffected but each parent
carries the altered gene (heterozygote). - Males and females are at equal risk for being
affected. - Two affected individuals usually produce children
all of whom are affected as well.
4Autosomal Recessive Disorders
- Tay-Sachs Disease individuals lack an enzyme in
the lysosomes of their brain cells needed to
break down lipids. The undigested lipids enlarge
and eventually destroy the brain cells that house
them. - Phenylketonuria (PKU) individuals lack an enzyme
that converts Phe to Tyr. Failure of the
conversion to take place results in a buildup of
Phe. Through a mechanism that is not well
understood, the excess Phe is toxic to the
central nervous system. This results in mental
retardation and other neurological problems if
not detected early. - Albinism
Sickle Cell Anemia
5X-Linked Inheritance
- Most individuals who are affected with the trait
or condition in questions are males. - Mothers of the affected males are carriers and
the sisters of affected males may be either
carriers or not carry the gene al all. The basis
for X-linked inheritance is that females have two
X chromosomes and males have only one X
chromosome.
- Affected males are hemizygous (their one X
chromosome has the mutant allele) - Affected females are homozygous (both X
chromosomes have the mutant allele) - Affected males transmit the gene to all
daughters, but not to any of their sons - The daughters of an affected male will usually be
a carrier (heterozygote) and thus not show the
trait (masked) - Sons of heterozygous females have a 50 chance of
receiving the gene and thus expressing the trait
or condition
6X-linked Disorders
- Colour Blindness
- In red-green colour vision deficiency, the
- visible spectrum is divided into two parts
- a red segment and a blue segment, separated
- by grey or indistinct areas. The amount of grey
- or indistinct areas varies according to the
severity of the deficiency. - Men are mainly affected
- For a woman to be colour deficient, her father
must be colour-blind and her mother must be a
carrier - A defective male always inherits his deficiency
from his mother who usually has normal colour
vision is therefore a carrier of the defect.
7- Duchenne Muscular Dystrophy
- Involves the wasting away of muscle tissue
- Muscle cells become engorged with fat and they
eventually waste away most individuals suffer
from respiratory failure in their early twenties.
8Human Pedigrees Working out Inheritance Patterns
- Pedigrees are a convention for keeping track of
human genetic traits used to infer genotype. - Pedigrees are the human equivalent of test
crosses. - In a visualization of a pedigree
- males are designated with square symbols.
- females with round symbols
- lines are drawn to indicated matings,
parent-offspring relationships, and relationships
between siblings.
Factors to Consider in Pedigrees
Is the trait located on a sex chromosome or an
autosome? Autosomal not on a sex chromosome Sex
Linkage located on one of the sex
chromosomes Y-linked - only males carry the
trait. X-linked (recessive) - sons inherit the
disease from normal parents How is the trait
expressed? Dominant - the trait is expressed in
every generation. Recessive - expression of the
trait may skip generations.
9Pedigree Diagrams I
Pedigree Diagrams II
Basic Symbols for offspring and the expression of
a trait. The offspring are depicted below the
parents. Filling the symbol with black indicates
the expression of the studied trait.
Pedigree analysis
10Note that the symbols for non-identical twins and
for identical twins differ by whether they
descend from a common vertical before bifurcating
Media Showcase
11Pedigrees
- Generations are numbered from the top of the
pedigree in uppercase Roman numerals, I, II, III
etc. Individuals in each generation are numbered
from the left in arab numberals as subscripts,
III1 , III2, III3 etc. For example, here is a
typical autosomal dominant pedigree with numbered
generations and individuals.
12Marfans Syndrome An Example
- Expressed in both sexes.
- Thus, autosomal.
- Expressed in every generation.
- Thus, dominant.
13Marfans Genotype the Normal Individuals
- Assign codes for the alleles.
- Code m for the recessive normal allele.
- Code M for the dominant allele for Marfans
syndrome. - Normal individuals must be mm.
14Marfans Genotype the Affected Individuals
- Affected individuals must have at least one M.
15Marfans Parent-Offspring Relationships
- Possibilities for 1 and 2 Heterozygote (Mm) or
homozygous for M? - If MM, all offspring from a normal mate should
be affected. - Therefore, both must be heterozygotes.
16Marfans Parental Genotypes Known
- M must have come from the mother.
- The father can contribute only m.
- Thus, the remaining genotypes are Mm.
17Albinism An Example
- Expressed in both sexes at approximately equal
frequency. - Thus, autosomal.
- Not expressed in every generation.
- Thus, recessive.
18Albinism Genotype the Affected Individuals
- Assign codes for the alleles.
- Code A for the dominant normal allele.
- Code a for the recessive allele for albinism.
- Affected individuals must be homozygous for a.
- First generation parents must be Aa because
they have normal phenotypes, but affected
offspring.
19Albinism Genotype the Normal Individuals
- Normal individuals must have at least one A.
20Albinism Parent-Offspring Relationships
- 1 must transmit a to each offspring.
- The A in the offspring must come from the
father. - Normal father could be either heterozygous or
homozygous for an A.
21Albinism Parental Genotypes are Known
- Both parents are heterozygous.
- Normal offspring could have received an A from
either parent, or from both.
22Albinism One Parental Genotype is Known
- Only the genotype of the offspring expressing
albinism are known. - Normal offspring must have received an a from
their affected father.
23Hairy Ears An Example
- Only males are affected.
- All sons of an affected father have hairy ears.
- Thus, hairy ears is Y-linked.
24Hairy Ears Female Sex Determination
25Hairy Ears Male Sex Determination
26Hairy Ears Gene on the Y Chromosome
- Code H indicates the allele on the Y chromosome
for hairy ears
27Hairy Ears Wild-Type Allele for Normal Ears
- Code indicates the allele on the Y chromosome
for normal ears.
28Hemophilia An Example
- In this pedigree, only males are affected, and
sons do not share the phenotypes of their
fathers. - Thus, hemophilia is linked to a sex
chromosomethe X. - Expression of hemophilia skips generations.
- Thus, it is recessive.
Children resemble their parents. Animation
Extensive bruising of the left forearm and hand
in a patient with hemophilia.
29Hemophilia Expression of the Female Sex
Chromosomes
30Hemophilia Expression of Male Sex Chromosomes
31Hemophilia Genotype the Affected Individuals
- Assign codes for the alleles.
- Code H for the recessive hemophilia allele.
- Code for the wild-type normal allele.
- Affected individuals must have an H on an X
chromosome.
32Hemophilia Father-Daughter Relationship
- All daughters of an affected father receive an X
chromosome with the H allele.
33Hemophilia Genotyping the Normal Individuals
- Normal individuals must have at least one X
chromosome with the wild-type allele, .
34Hemophilia Homozygous or Heterozygous?
- Only males affected
- Not Y-linked
- Skips a generation recessive
- X-linked
35Try It!
- Let us begin by drawing the pedigree described
below (which is not necessarily an autosomal
dominant condition and which contains extraneous
information).
36The Scenario
- Alice and Bob have a two year old son, Charles,
who is showing mental retardation, short stature,
micropenis, and cryptorchidism. Alice has two
living, unaffected, brothers but her eldest
brother died at age 9 and a second brother died
aged 10 months. Both had similar problems to
Charles. Alice's father, David, who was
symptomless, has a sister, Ethel, who has an
unaffected boy and girl, and a brother, Fred, who
also has two unaffected children. Alice's mother,
Gertrude, has two living sisters and had a
brother who had died in childhood and who, she
remembers, had been mentally retarded. Bob has
two brothers, Henry and Ignatius, who are still
unmarried. His parents, John and Kate, had tragic
lives, both were adopted and never knew their
biological parents and both died as the result of
a road accident.
37Step 1
- Begin with Alice, Bob and Charles.
- Here are three possible drawings of this nuclear
family.
38Correct Solution
- Alice and Bob are connected by a horizontal line
to show that this is a mating. Charles is
connected to that horizontal line to show that he
is a product of that mating.
39Choose One
- Now add Alice's siblings and parents to the
pedigree.
Step 2
40Correct Solution was Possiblilty 3
Alice and her four brothers are connected
vertically to a horizontal line which is, in
turn, connected to the line drawn between her
parents David and Gertrude. Her two dead brothers
(whom we presume died of the same genetic disease
- though this can sometimes be a foolish
assumption without medical evidence) are shaded
in (to show that they suffered from the disease)
and are crossed through (to show that they are
dead).
41Step 3
- Now add Gertrude's siblings to the pedigree.
- And David's siblings and his nephews and nieces
- Finally add Bob's side of the family
- Try Drawing it!!!
42Correct Drawing!
http//bio1151.nicerweb.net/med/Vid/Discover2e/ch1
3a04_Pedigree.swf
Children resemble their parents. Problem