Boolean Logic - PowerPoint PPT Presentation

About This Presentation
Title:

Boolean Logic

Description:

Boolean Logic ITI 1121 N. El Kadri What is a switching network? Logic Functions: Boolean Algebra Boolean expressions and logic circuits Basic Theorems: Operations ... – PowerPoint PPT presentation

Number of Views:96
Avg rating:3.0/5.0
Slides: 22
Provided by: NElk9
Category:
Tags: algebra | boolean | logic

less

Transcript and Presenter's Notes

Title: Boolean Logic


1
Boolean Logic
  • ITI 1121
  • N. El Kadri

2
What is a switching network?
Combinatorial Network A stateless network. The
output is completely determined by the values of
the input.
Sequential Network The network stores an
internal state. The output is determined by the
input, and by the internal state.
3
Logic Functions Boolean Algebra
4
Boolean expressions and logic circuits
Any Boolean expression can be implemented as a
logic circuit.
X A(CD)BE
5
Basic Theorems Operations with 0 and 1
6
Basic TheoremsIdempotent Laws
7
Basic Theorems Involution Law
(X)X
B
X
CX
8
Basic TheoremsLaws of Complementarity
XX 1
9
Expression Simplification using the Basic
Theorems
X can be an arbitrarily complex expression.
Simplify the following boolean expressions as
much as you can using the basic theorems.
(AB D)E 1 (AB D)(AB D) (AB CD)
(CD A) (AB CD)
(AB D)E 1 1 (AB D)(AB D) 0 (AB
CD) (CD A) (AB CD) 1
10
Associative Law
(XY)Z X(YZ)
11
Associative Law
(XY)Z X(YZ)
12
First Distributive Law
X(YZ) XYXZ
13
First Distributive Law
X(YZ) XYXZ
14
First Distributive Law
X(YZ) XYXZ
15
First Distributive Law
X(YZ) XYXZ
16
First Distributive Law
X(YZ) XYXZ
17
Second Distributive Law
XYZ (XY)(XZ)
18
Second Distributive Law
XYZ (XY)(XZ)
19
Second Distributive Law(A different proof)
(X Y)(X Z)
20
Simplification Theorems
XY XY X XY XY X(Y Y) X1 X
(X Y)(X Y) X (X Y)(X Y) XX XY
YX YY X X(Y Y)
0 X X1
X
X XY X X(1 Y) X1 X
X(X Y) X X(X Y) XX XY X1 XY
X(1 Y) X1 X
XY Y X Y (using the second distributive
law) XY Y Y XY (Y X)(Y Y)
(Y X)1 X Y
(X Y)Y XY XY YY XY 0 XY
21
Examples
Simplify the following expressions
W M NP (R ST)M NP R ST
X M NP Y R ST W (X Y)(X
Y)
W XX XY YX YY
W X1 XY XY 0
W X X(Y Y) X X1 X
W M NP
Write a Comment
User Comments (0)
About PowerShow.com