Title: HEAT AND CALORIMETRY
1HEAT AND CALORIMETRY
2What is Heat?
- Modern definition energy transferred because of
a difference in temperature(energy on the move) - 1 calorie raises the temperature of 1 gram of
water by 1 Celsius degree. - 1 kilocalorie (kcal or Calorie) raises
temperature of 1 kg of water by 1 degree Celsius - 1 British Thermal Unit (BTU) raises temperature
of 1 pound of water by one degree Farenheit
3Mechanical Equivalent of Heat
- Discovered by James Joule
- Falling weight makes
- paddle turn
- 4.186 x 103 J 1 kcal
- Interpretation
- HEAT IS ENERGY
- TRANSFER
Courtesy W. Bauer http//lecture.lite.msu.edu/mmp
/kap11/cd295.htm
4Joules Apparatus
Link to Joules original article
5Imagine This
- What other situations could be used to
demonstrate the mechanical equivalent of heat?
6Example
- When digested a slice of bread yields 100 kcal.
How high a hill would a 60 kg student need to
climb to work off this slice of bread? (100
kcal is energy released by burning the bread
100 kcal x 4.186 x 103 J/kcal 4.2 x 105 J
W mgh
h W/mg 4.2 x 105 / (60 kg)(9.80 m/s2) 714m
7.1 x 102 m
If the body is only 20 percent efficient in
transforming the bread, how high need they climb?
7Bullet in Block
- When a 10 g bullet traveling 500 m/s is stopped
inside a 1kg wood block nearly all its KE is
transformed to heat. How many kcal are released?
KE ½ mv2 0.5 x 0.010 kg x (500)2 1250 J
1250 J x 1 kcal/4186 J 0.30 kcal
8Internal Energy, Temperature and Heat
- The thermal energy or internal energy of an
object is the sum total of all the energy in its
molecules - (symbol U)
- Temperature is measure of average KE per molecule
(T) - Heat refers to transfer of energy
- (symbol Q)
9Internal Energy Does Not Include KE
- KE of whole object represents all molecules
moving in the same direction - U is random motion only
10Internal Energy of an Ideal Gas
- U N (1/2 mv2)
- But 1/2 mv2 3/2kT
- U 3/2NkT
- U 3/2 nRT
N is total number of molecules in sample
k R/NA
U 3/2 nRT
Internal Energy of an ideal gas depends only on
temperature and number of moles
11Specific Heat
- How much does temperature rise when heat is put
into something? - Depends on the material, the mass and the
quantity of heat - Q m c DT c is specific heat in J/kg Co
- or
- Q n c DT c is specific heat in J/mol
Co - Specific Heat of water 4.186 x 103J/kg Co
DT Q/mc
Table of Specific Heats
12Understanding Specific Heat
- For a given amount of heat added, temperature
increases more for a smaller specific heat - Water has a very large specific heat and is
therefore relatively difficult to heat or cool.
13Examples
- How much heat is required to heat 1 liter of
water from 20 oC to 100 oC? - Q mcDT 1Kg x 4186 J/kg oC x 80 oC
- 3.35 x 105 J 80 kcal
- How much heat is required to heat 1.0 kg iron
from 20 oC to 100 oC - Q mcDT 1Kg x 450 J/kg oC x 80 oC
- 3.6 x 104 J
-
14On the Stove
- In heating 3.0 liters of water to make spaghetti
Mikes stove heats water at a rate of 4500 watts.
The initial temperature of the water is 150 C.
After five minutes he sticks his hand in the
water. Will he get scalded? What is the
temperature?
DT Q/mc (4.5 x 103 x 300s)/(3.0kg x 4186 J/kg
oC)
107 degrees! What actually happened to the
water?
Started boiling when it reached 100 0C
15Oops
- A 145 g baseball crashes into a 500g pane of
glass while moving at 30 m/s. The specific heat
of the glass is 840 J/kg oC. Find the
temperature increase of the glass assuming that
half the balls KE is transformed into heating
the glass.
KE ½ mbv2 0.5 x 0.145kg x (30)2 65.25 J
DT Q/mgc ½ KE/mgc (.5)(65.25)/(0.500kg x
840 J/kgoC)
0.078 degrees
16Armageddon
- An asteroid crashes into Earth while traveling 60
km/sec. All its KE is transformed into heating a
mass of rock (specific heat 860 J/kg 0C) equal to
its own mass. What is the temperature increase
of the rock? What happens to it?
½ mv2 mcDT
DT v2/2c
DT (6 x 104 m/s)2 / 2 x 860 J/kg 0C 2.1 x 106
0C
VAPORIZED BECOMES PLASMA
17Calorimetry
- When objects at different temperature are placed
in thermal contact heat flows from the hotter to
the cooler - Energy is conserved
- Heat lost by one part of system heat gained by
other part or parts - Calorimetry should be done in a container well
insulated so that little heat is lost or gained
from the outside. Sometimes it is necessary to
include heat gained by Calorimeter cup.
18Temperature of an Iron Block
- 500g of iron is heated on a hot plate. It is
placed in 200ml of water at 20 0C. After
allowing time for thermal equilibrium to be
reached the temperature of the water is found to
be 500C. What was the initial temperature of the
iron?
Heat lost by iron heat gained by water
Let TW be initial temp. of water TI that of
iron TF final temp of both
mIcI(TI-TF) mW cW (TF TW)
19Temperature of an Iron Block, Continued
- mIcITI mW cW (TF TW) mIcITF
- TI mW cW (TF TW) mIcITF/ mIcI
- TI 0.2 x 4186(50-20) 0.5 x 450 x 50/(0.5 x
450) - TI 161 oC
20Method of Mixtures
- How can the specific heat of an unknown liquid
such as antifreeze be determined? Design an
experiment to do this.
21Change of phase and Latent Heat
Courtesy Hyperphysics web site. Georgia State
University
22Key Facts
- Temperature does not change during change of
phase - For water 00 C for freezing and melting
- For water 1000 C for boiling and condensation
- Slope during heating is related to specific heat!
- Question compare the specific heat of ice with
that of water.
That of ice is less
23Q mL
- Q is heat added or released
- M is mass
- L is latent heat
- Heat of fusion solid to liquid or vica versa
- Heat of vaporization liquid to vapor or vv
- Table of Latent Heats
- For water LF 333 kJ/kg 3.33 x 105 J/kg
- LV 22.6 x 105 J/kg
24Example
- How much heat is required to turn 1 kg of ice at
- - 200C to steam?
- Heat the ice 1 x 2100 x 20 4.2 x 104 J
- Melt the ice 1 x 3.33 x 105 3.33 x 105 J
- Heat the water to boiling 1 x 4186 x 100 4.19
x 105 - Vaporize the water 1 x 22.6 x 105 22.6 x 105
J - Total 3.05 x 106 J
- How long would this take on a 4500 w burner?
- Time Q/rate 3.05 x 106 / 4.5 x 103 678 sec
11.3 min