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3.2 Solve Linear Systems Algebraically Fri Oct 28

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3.2 Solve Linear Systems Algebraically Fri Oct 28 Do Now Solve the system by graphing 1) X + y = 2 2x + y = 3 HW Review: p.156 #3-21 odds 3) (1,-1) 19) no solution ... – PowerPoint PPT presentation

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Title: 3.2 Solve Linear Systems Algebraically Fri Oct 28


1
3.2 Solve Linear Systems AlgebraicallyFri Oct 28
  • Do Now
  • Solve the system by graphing
  • 1) X y 2
  • 2x y 3

2
HW Review p.156 3-21 odds
  • 3) (1,-1) 19) no solution inconsistent
  • 5) (4,-1) 21) infinitely many consistent
  • 7) (5,0) and dependent
  • 9) (-2,4)
  • 11) infinitely many solutions
  • 13) (3,3)
  • 15) C (1,-6)
  • 17) (2,-1) consistent and independent

3
HW Review 23-29 odds
  • 23) (2,0) consistent and independent
  • 25) (3, -1) consistent and independent
  • 27) infinitely many consistent and dependent
  • 29) A

4
Solving Linear Systems
  • There are 2 ways to solve a linear system
    algebraically
  • The Substitution Method
  • The Elimination Method
  • It is important to note to ALWAYS check your
    answers by plugging into one of the equations

5
Substitution Method
  • Step 1 Solve one of the equations for one of its
    variables
  • Step 2 Substitute the expression from Step 1
    into the other equation and solve for the other
    variable
  • Step 3 Substitute the value from Step 2 back
    into Step 1 equation to solve the last variable

6
Ex Substitution
  • Solve the system using substitution
  • 2x 5y -5
  • X 3y 3
  • Step 1 Solve equation 2 for x
  • X -3y 3
  • Step 2 Substitute the X equation into the other
    equation and solve for Y
  • 2x 5y -5
  • 2(-3y 3) 5y -5
  • -6y 6 5y -5
  • Y 11
  • Step 3 Substitute the value of y back into Step
    1
  • X -3y 3
  • X -3(11) 3
  • X -30

7
Elimination Method
  • Step 1 Multiply one or both of the equations by
    a constant to obtain coefficients that are
    opposite (Least common multiple)
  • Step 2 Add the two equations together and solve
    for the variable that doesnt cancel
  • Step 3 Substitute the value obtained into either
    equation and solve for the other variable

8
Ex Elimination
  • Solve the system using the elimination method
  • 3x - 7y 10
  • 6x - 8y 8
  • Step 1 Multiply Equation1 by -2 so the x
    coefficients are opposite
  • -6x 14y -20
  • 6x - 8y 8
  • Step 2 Add the 2 equations together and solve
    for y
  • 6y -12
  • Y -2
  • Step 3 Substitute back into y and solve for x
  • 3x - 7(-2) 10
  • 3x 14 10
  • 3x -4 x -4/3

9
Infinite or no solutions
  • When solving a system, we could get infinitely
    many or no solutions
  • Infinitely many solutions a true statement
  • Ex 2 2
  • No solutions a false statement
  • Ex 12 8

10
You try
  • Solve the linear system using either substitution
    or elimination
  • 1)
  • 2)
  • 3)
  • 4)

11
Closure
  • Journal Entry Which method of solving systems
    algebraically do you like better? Why? Explain
    how to solve using that method
  • HW p.164 3-39 odds

12
3.1-3.2 PracticeMon Oct 31
  • Do Now
  • Solve the linear systems
  • 1) 3x 2y 1
  • -2x y 4
  • 2) 8x 2y 4
  • -2x 3y 13

13
HW Review p.164 3-39 odds
  • 3) (6,-1) 23) no solution
  • 5) no solution 25) (7, 3)
  • 7) (4/3, 2) 27) did not multiply whole
    equation by -2
  • 9) (0,3) 29) (-5, -6)
  • 11) (-3, 8 ) 31) infinitely many
  • 13) (44, -17) 33) (-8, 0)
  • 15) (7, 1/2) 35) (7, -6)
  • 17) (-6, -2) 37) (-3/2, 4)
  • 19) (-1/2, 1/6) 39) (-3/4, 1/2)
  • 21) (-8, 6)

14
Worksheet 3.1 and 3.2
  • 3.1 4-12
  • 3.2 1-21

15
Closure
  • Hand in Solve the linear system by either the
    substitution or elimination method
  • 3x 7y -1
  • 2x 3y 6
  • HW Finish worksheets
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