Title: Introduction to Quantum mechanics and Molecular Spectra
1Introduction toQuantum mechanics and Molecular
Spectra
- Ka-Lok Ng
- Asia University
2Contents
- The postulates of quantum mechanics (QM)The wave
equation Schrodinger equation - Quantum mechanical operators
- Eigenvalues of QM operators
- Wave functions
- The particle in a 1D box
- Physical methods of determining the 3D structure
of proteins - References
- House J.E. Fundamentals of quantum chemistry, 2nd
ed. Elsevier 2004 - Whitford D. Proteins structure and function. J.
Wiley 2005. - http//www.spaceandmotion.com/Physics-Erwin-Schrod
inger.htm - Molecular spectra, see http//spiff.rit.edu/classe
s/phys315/lectures/lect_14/lect_14.html - http//cref.if.ufrgs.br/hiperfisica/hbase/molecul
e/molec.htmlc2
3The postulates of quantum mechanics (QM)
- Postulate I
- For any possible state of a system, there is a
function y of the coordinates of the parts of the
system and time that completely describes the
system.
Y Is called a wave function. For two particles
system,
The wave function square Y2 is proportional to
probability. Since Y may be complex, we are
interested in YY, where Y is the complex
conjugate (i ? -i) of Y. The quantity YYdt is
proportional to the probability of finding the
particles of the system in the volume element, dt
dxdydz.
that is the probability of finding the particle
in the universe is 1 ? normalization condition.
4The postulates of quantum mechanics (QM)
- Orthogonal of two wave functions
Example sinq and cosq are orthogonal functions.
Fourier series expansion sin(nq) and cos(nq)
orthogonal functions
5The Wave Equation
- In 1924 de Brogile shown that a moving particle
has a wave character. This idea was demonstrated
in 1927 by Davisson and Germer when an electron
beam was diffracted by a nickel crystal. - According to the de Brogile relationship, there
is a wavelength associate with a moving particle
which is given by
where l, h, m and v denote the wavelength,
Plancks constant, mass and velocity. Erwin
Schrodinger adapted the wave model to the problem
of the hydrogen atom and propose the Schrodinger
equation. The model needs to describe a
three-dimensional wave. Classical physics the
flooded planet problem the waveforms that would
result form a disturbance of a sphere that is
covered with water The classical 3D wave equation
is
where f is the amplitude function and v is the
phase velocity of the wave.
Schrodinger equation
6The Wave Equation
- The Schrodinger wave equation
The 1D wave equation solution http//www-solar.mcs
.st-and.ac.uk/alan/MT2003/PDE/node12.html
The 2D wave equation solution http//www.math.harv
ard.edu/archive/21b_fall_03/waves/index.html
7Operators
- Postulate II
- With every physical observable q there is
associated an operator Q, which when operating
upon the wavefunction associated with a definite
value of that observable will yield that value
times the wavefunction F, i.e. QF qF.
H
http//hyperphysics.phy-astr.gsu.edu/hbase/quantum
/qmoper.html
8Operators
- (1) The operators are linear, which means that
- O(Y1 Y2) OY1 OY2
- The linear character of the operator is related
to the superposition of states and waves
reinforcing each other in the process - (2) The second property of the operators is that
they are Hermitian (the 19th century French
mathematician Charles Hermite). - Hermitian matrix is defined as the transpose of
the complex conjugate () of a matrix is equal to
itself, i.e. (M)T M
In QM, the operator O is Hermitian if
C. Hermite
http//commons.wikimedia.org/wiki/ImageCharles_He
rmite_circa_1887.jpg
9Eigenvalues of QM operator
- Postulate III
- The permissible values that a dynamical variable
may have are those given by OF aF, where F is
the eigenfunction of the QM operator (Hermitian)
O that corresponds to the observable whose
permissible real values are a. - The is postulate can be stated in the form of an
equation as
O F a F
operator wave function eignevalue
wave function
Example Let F e2x and Od/dx ? dF/dx
d(e2x)/dx 2 e2x ? F is an eigenfunction of the
operator d/dx with an eigenvalue of 2.
10Eigenvalues of QM operator
- Eigenvalues of QM operator must be real !
- Example
The two values for l are real
11Wave functions
- Postulate IV
- The state function Y is given as a solution of
- where is the total energy operator, that is
the Hamiltonian operator. - The hamiltonian function is the total energy,
TV, where T is the kinetic energy and V is the
potential energy. In operator form
Schrodinger equation
where is the operator for kinetic energy and
is the operator for potential energy. In
differential operator form, the time dependent
Schrodinger equation is
where qi is the generalized coordinates, m is the
mass of the particle.
12The particle in a one-dimensional box
- We treat the behavior of a particle that is
confined to motion in a box - The coordinate system for this problem is show at
the right - The Hamiltonian operator, H, is H T V p2/2m
V - where p is the momentum, mass is the mass of the
particle, and V is the potential energy - Outside the box V 8, so the Schrodinger equation
For the equation to be valid, y must be 0 ?
Boundary condition the probability of finding
the particle outside the box is zero Inside the
box, V 0, so the Schrodinger equation becomes
http//www.everyscience.com/Chemistry/Physical/Qua
ntum_Mechanics/a.1128.php
13The particle in a one-dimensional box
- Where k2 8p2mE/h2. This is a linear
differential equation with constant coefficients,
which have a solution fo the form Y A cos(kx)
B sin(kx). - The constant A and B must be evaluated using the
boundary conditions. Boundary conditions are
those requirments that must be met becase of the
the physical limits fo the system. - For the probability of finding the particle to
vanish at the walls of the box, that is Y 0
both at x?0 and x?L. - At x?0
- Y 0 A B(0) ? A 0
- At x?L
- Y 0 B sin kL
- Since B ? 0, otherwise the complete wavefunction
0 ! - ? sin kL 0 that is kL np ? quantization
condition !
14The particle in a one-dimensional box
- quantization condition ? kL np
- Recall k2 8p2mE/h2
- k2 L2 8p2mE/h2 L2 n2p2, where n 1, 2 . is
the quantum number
- Zero-point energy
- One quantum number arise from a 1D system
E n2 E 1/L2 E m To determine the
wavefunction Y, one uses the normalization
condition
n 1, 2, 3
http//www.everyscience.com/Chemistry/Physical/Qua
ntum_Mechanics/a.1128.php
15The particle in a one-dimensional box
- Consider a carbon chain like
- CC-CC-C
- as an arrangement where the p electrons can move
along the chain. If we take an average bond
length of 1.40 Angstrom, the entire chain would
be 5.60 Angstrom length, Therefore, the energy
difference between the n1 and n2 state would be
The energy corresponds to a wavelength of 344 nm,
and the maximum in the absorption spectrum of
1,3-pentadiene is found at 224 nm. Although this
not close agreement, the simple model does
predict absorption in the UV region of the
spectrum.
16Molecular Spectra
- Three types of energy levels in molecules
- electronic large energy separations (200-400
kJ/mol) ? optical or UV - vibrational medium energy separations (10-40
kJ/mol) ? Infrared - rotational small energy separations (10-40
J/mol) ? microwave - All the energy levels are quantized
17Molecular Spectra
- For a spectral line of 6000 Angstrom, which is in
the visible light region, the corresponding
energy is E hc/l 3.3x10-12 erg - ? a molar quantity multiply by Avogadros number
? E 200 kJ/mol - Diatmoic molecule can be viewed as if they are
held together by bonds that have some stretching
and bending (vibrational) capability, and the
whole molecule can rotate as a unit.
http//cref.if.ufrgs.br/hiperfisica/hbase/molecule
/molec.htmlc2
18Molecular Spectra
- Normal mode of vibration for the CO2 molecule
- behaves much like a simple harmonic oscillator
- The vibrational energies can therefore be
described by the relation (?1/2)h?, where ?,
the vibrational quantum number 0,1,2,3. and
?the classical frequency - the symmetric stretch mode
- the asymmetric stretch mode
- the bending mode
http//www.phy.davidson.edu/StuHome/shmeidt/Junior
Lab/CO2Laser/Theory.htm
19Vibrational and Rotational energy levels
transition spectra
- The CO2 molecule is free to rotate. The energies
of the rotational modes (E h2/(8p2I), where I
is the moment of inertia)) are smaller than for
vibrational modes. Hence, the energy levels for
two vibrational states with the rotational
divisions looks like
Vibrational and Rotational energy levels
transition spectra for HCl
http//universe-review.ca/F12-molecule.htm
20Applications of the Vibrational Energy Levels
- determination of bond lengths
- determination of bond force constants
- determination of bond dissociation energy
- qualitative and quantitative chemical analysis
21Selection rules for energy level transitions
- Selection rules are divided into high probability
or allowed transitions - and Forbidden transitions of much lower
probability - Forbidden transition symmetry-forbidden and
spin-forbidden transitions - Spin-forbidden transitions involve a change in
spin multiplicity defined as 2S1 where S is the
electron spin number. Spin multiplicity reflects
electron pairing (see Table). For a favourable
transition there is no change in multiplicity
(DS0)
Number of unpair electrons Electron spin S 2S1 Multiplicity
0 0 1 Singlet
1 ½ 2 Doublet
2 1 3 Triplet
3 3/2 4 quartet
22Selection rules for energy level transitions
- Symmetry-forbidden transitions reflect
redistributin of charge during transitions in a
quantity called the transition dipole moment. - Differences in dipole moment arise from the
different electron distributions of ground and
excited states - For an allowing transition it requires a change
in dipole moment - EM radiation can induce Rotational transitions
only in molecule with a permanent dipole moment. - Not all molecules have dipole moments!
- (1) only polar molecules can absorb and emit
electromagnetic photons - (2) non-polar molecules H2 ,CO2 ,CH4
- (3) energy transfer can take place during
collisions - The intensity of the signals in a rotational
spectrum increase with the molecular dipole
moment.
23Fluorescence Spectroscopy
- Fluorescence excited molecules decay to the
ground state via the emission of a photon with DS
0 ( no change in spin multiplicity, S1 ? S0) - Emission is occurs at longer wavelengths than the
corresponding absorbance band - Quantum yield of Fluorescence emission
- photons emitted/number of photons absorbed
- maximum value of quantum yield is 1
- Photophysical properties of a fluorophore can be
used to obtain information on its immediate
molecular environment. Relaxation of a
fluorophore from its excited state can be
accelerated by fluorescence resonance energy
transfer (FRET). - FRETcan be used to characterize protein-protein
interactions as observed in signaling complexes
of ion channel proteins.
http//www.physiologie.uni-freiburg.de/fluorscence
.html
24Raman Spectroscopy
- Chandrasekhara Venkata Raman (1888-1970) who
discovered in 1928 that light interacts with
molecules vai absorbance, transmission or
scattering - the first Indian Nobel Laureate in physics
- Raman made many major scientific discoveries in
acoustics, ultrasonic, optics, magnetism and
crystal physics - Scattering can occur at the same wavelength when
it is known as Rayleigh scattering (elastic, n0)
or it can occur at altered frequency (change in
the colour of the scattered light) when it is the
Raman effect
Figure. See http//www.search.com/reference/Raman_
spectroscopy
Figure. See http//www.inphotonics.com/raman.htm
http//www.vigyanprasar.gov.in/dream/feb2002/artic
le1.htm
25Raman Spectroscopy
- some weaker bands of shifted frequency are
detected. Moreover, while most of the shifted
bands are of lower frequency n0 - ni, there are
some at higher frequency, n0 ni. By analogy to
fluorescence spectrometry, the former are called
Stokes bands and the latter anti-Stokes bands.
The Stokes and anti-Stokes bands are equally
displaced about the Rayleigh band however, the
intensity of the anti-Stokes bands is much weaker
than the Stokes bands and they are seldom
observed.
http//www.gfz-potsdam.de/pb4/pg2/equipment/raman/
raman.html
26Raman Spectroscopy Application
- commonly used in chemistry
- provides a fingerprint by which the molecule can
be identified. The fingerprint region of organic
molecules is in the range 500-2000 cm-1. - to study changes in chemical bonding, e.g. when a
substrate is added to an enzyme. - Raman gas analyzers have many practical
applications, for instance they are used in
medicine for real-time monitoring of anaesthetic
(???) and respiratory gas mixtures during
surgery. - In solid state physics, spontaneous Raman
spectroscopy is used to, among other things,
characterize materials, measure temperature, and
find the crystallographic orientation of a
sample.
http//www.search.com/reference/Raman_spectroscopy
27Nuclear Magnetic Resonance Spectroscopy
- In 1945, the NMR phenomenon was given by F. Bloch
and E. M. Purcell (both share the 1952 Nobel
Prize) - NMR spectra are observed upon the pulse
absorption of a photon (radio frequency) of
energy and the transition of nuclear spins from
ground to excited states
Bloch F (1905-1983)
Purcell E.M. (1912-1997)
http//nobelprize.org/nobel_prizes/physics/laureat
es/1952/ http//cancer.stanford.edu/research/miles
tones/ http//www.pulseblaster.com/gallery/1.html
28Nuclear Magnetic Resonance Spectroscopy
- For 1H there are two orientations. In one
orientation the protons are aligned with the
external magnetic field (north pole of the
nucleus aligned with the south pole of the magnet
and south pole of the nucleus with the north pole
of the magnet) and in the other where the nuclei
are aligned against the field (north with north,
south with south)
A spinning nucleus is equivalent to a magnet
http//www.brynmawr.edu/Acads/Chem/mnerzsto/The_Ba
sics_Nuclear_Magnetic_Resonance20_Spectroscopy_2.
htm http//vam.anest.ufl.edu/simulations/nuclearma
gneticresonance.php
29Nuclear Magnetic Resonance Spectroscopy
- Nuclei possessing angular moment (also called
spin) have an associated magnetic moment (current
generate magnetic field). Certain atomic nuclei,
such as 1H, 13C, 15N and 31P have spin S½ and
2H, 14N have spin S1, 18O has S5/2). - For nuclei such as 12C is the most common isotope
is NMR silent, that is not magnetic. If a nucleus
is not magnetic, it can't be studied by nuclear
magnetic resonance spectroscopy. For the
purposes, biomolecular NMR spectroscopy requires
proteins enriched with 1H, 13C or 15N or ideally
all nuclei. - Nuclear transitions differed in frequency from
one nucleus to another but also showed subtle
differences according to the nature of the
chemical group (chemical shift effect). - Methyl protons resonating at a frequency ?
amide proton ? a-carbon proton ? b-carbon proton
? The chemical environment of such nuclei are
different - Probe by NMR and this technique can be exploited
to give information on the distances between
atoms in a molecules. These distances can then
be used to derive a 3D model of the molecule.
The frequency range needed to excite protons is
relatively high. It ranges from 300 MHz to 900
MHz.
30Nuclear Magnetic Resonance Spectroscopy
- Why do we see peaks ?
- When the excited nuclei in the beta orientation
start to relax back down to the alpha
orientation, a fluctuating magnetic field is
created. This fluctuating field generates a
current in a receiver coil that is around the
sample. The current is electronically converted
into a peak. - Why do we see peaks at different positions?
- because nuclei that are not in identical
structural situations do not experience the
external magnetic field to the same extent. The
nuclei are shielded or deshielded due to small
local fields generated by circulating s, p and
lone pair electrons.
NMR spectra
Solid-state 900 MHz (21.1 tesla) NMR spectrometer
at the Canadian National Ultrahigh-field NMR
Facility for Solids.
http//www.answers.com/topic/solid-state-nuclear-m
agnetic-resonance http//www.scielo.br/scielo.php?
pidS0100-41582002000500017scriptsci_arttext
31Nuclear Magnetic Resonance Spectroscopy
- Limitations for NMR methods
- 1. For small proteins with size lt 100 kD
- 2. Require highly concentrated protein solutions
on the order of 1-2 mM. - 3. pH of solution lt 6.