Gas Laws - PowerPoint PPT Presentation

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Gas Laws

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Gas Laws Gas Pressure Pressure is defined as force per unit area. Gas particles exert pressure when they collide with the walls of their container. – PowerPoint PPT presentation

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Title: Gas Laws


1
Gas Laws
2
Gas Pressure
  • Pressure is defined as force per unit area.
  • Gas particles exert pressure when they collide
    with the walls of their container.
  • The SI unit of pressure is the pascal (Pa).
  • However, there are several units of pressure
  • Pascal (Pa)
  • Kilopascal (KPa)
  • Atmosphere (atm)
  • mmHg
  • Torr

3
Boyles Law Pressure and Volume
  • Boyle was an Irish chemist who studied the
    relationship between volume and pressure
  • Boyles law states that the pressure and volume
    of a gas at constant temperature are inversely
    proportional.

4
Boyles Law Pressure and Volume
  • At a constant temperature, the pressure exerted
    by a gas depends on the frequency of collisions
    between gas particles and the container.
  • If the same number of particles is squeezed into
    a smaller space, the frequency of collisions
    increases, thereby increasing the pressure.

5
Boyles Law Pressure and Volume
  • In mathematical terms, this law is expressed as
    follows.
  • P1 initial pressure
  • V1 initial volume
  • P2 final pressure
  • V2 final volume
  • P1 P2 can be in anything as long as they are
    the same
  • V1 V2 can be in anything as long as they are
    the same

6
Example
  • A sample of Helium gas is compressed from 4.0 L
    to 2.5 L at a constant temperature. If the
    pressure of the gas in the 4.0 L volume is 210
    KPa, what will the pressure be at 2.5 L?

7
Example
  • P1 210 KPa
  • P2 ?
  • V1 4.0 L
  • V2 2.5 L
  • P1V1 P2V2
  • (210 KPa)(4.0L) (P2)(2.5 L)
  • P2 340 KPa

8
Charles Law Volume Temperature
  • Charles was a French physicist who looked at the
    relationship between temperature and volume
  • He noted that as temperature went up, so did
    volume when pressure was held constant

9
Charles Law Volume Temperature
  • This observation is Charless law, which can be
    stated mathematically as follows.

10
Charles Law Volume Temperature
  • V1 V2
  • T1 T2
  • V1 initial volume
  • V2 final volume
  • T1 initial temperature
  • T2 final temperature
  • V1 V2 can be in any unit as long as they are
    the same
  • T1 T2 MUST be in Kelvin

11
Temperature conversions
  • K 273 C
  • C 0.56 (F 32)
  • F 1.8 C 32

12
Example
  • A sample of gas at 40.0 C occupies a volume of
    2.32 L. If the temperature is raised to 75.0 C
    what will the new volume be?

13
Example
  • V1 2.32 L
  • V2 ?
  • T1 40.0 C 313 K
  • T2 75.0 C 348 K
  • V1 V2
  • T1 T2
  • 2.32 L V2
  • 313K 348 K
  • V2 2.58 L

14
Gay Lussacs Law Pressure Temperature
  • Gay Lussac studied the relationship between
    pressure and temperature
  • He noticed that at a constant volume a direct
    relationship existed between the Kelvin
    temperature and volume
  • Giving the equation
  • P1 P2
  • T1 T2

15
Gay Lussacs Law Pressure Temperature
  • P1 P2
  • T1 T2
  • P1 initial pressure
  • P2 final pressure
  • T1 initial temperature
  • T2 final temperature
  • P1 P2 can be in any unit as long as they are
    the same
  • T1 T2 MUST be in Kelvin

16
Example
  • The pressure of a gas in a tank is 3.20 atm at
    22.0 C. If the temperature rises to 60.0 C,
    what will the new pressure in the tank be?

17
Example
  • P1 3.20 atm
  • P2 ?
  • T1 22.0 C 295 K
  • T2 60.0 C 333 K
  • P1 P2
  • T1 T2
  • 3.20 atm P2
  • 295K 333K
  • P2 3.61 atm

18
Combined Gas Law
  • P1V1 P2V2
  • T1 T2
  • Instead of memorizing all three equations, you
    can simply memorize this one
  • Just delete what you don t need

19
Example
  • A gas at 110.0 kPa and 30.0C fills a flexible
    container to a volume of 2.00 L. If the
    temperature was raised to 80.0C and the pressure
    was increased to 440.0 kPa, what is the new
    volume?

20
Example
  • P1V1 P2V2
  • T1 T2
  • P1 110.0 kPa
  • V1 2.00 L
  • T1 30.0 C 303 K
  • P2 440.0 kPa
  • V2 ?
  • T2 80.0 C 353 K

21
Example
  • P1V1 P2V2
  • T1 T2
  • (110.0)(2.00L) (440.0kPa)(V2)
  • 303K 353K
  • V2 0.583 L
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