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Title: Elliptic Curves and Elliptic Curve Cryptography


1
Elliptic Curves and Elliptic Curve Cryptography
  • Michael Karls
  • 4/22/04

2
Outline
  • Groups, Abelian Groups, and Fields
  • Elliptic Curves Over the Real Numbers
  • Elliptic Curve Groups
  • Elliptic Curves Over a Finite Field
  • An Elliptic Curve Cryptography SchemeDiffie-Hellm
    an Key Exchange

3
Group Definition
  • A group is a non-empty set G equipped with a
    binary operation that satisfies the following
    axioms for all a, b, c in G
  • Closure ab in G
  • Associativity (ab)c a(bc)
  • Identity There exists an element e in G such
    that ae a ea. We call e the identity
    element of G.
  • Inverse For each a in G, there exists an
    element d in G such that ad e da. We call
    d the inverse of a.

4
Group Definition (cont.)
  • If a group G also satisfies the following axiom
    for all a, b in G
  • Commutativity ab ba,
  • we say G is an abelian group.
  • The order of a group G, denoted G is the number
    of elements in G. If G lt 1, we say G has
    finite order.

5
Group Examples
  • Examples of groups
  • Real numbers with addition
  • Symmetric Group on n elements, Sn
  • Dihedral group of degree n, Dn
  • 2 x 2 matrices of real numbers with non-zero
    determinant
  • Which of these examples are finite?
  • Which are abelian?

6
Field Definition
  • A field F is a non-empty set with two binary
    operations, usually denoted and , which
    satisfy the following axioms for all a, b, c in
    F
  • ab is in F
  • (ab)c a(bc)
  • ab ba
  • There exists 0F in F such that a0F a 0Fa.
    We call 0F the additive identity.
  • For each a in F, there exists an element x in F
    such that
  • ax 0F xa. We call x the additive inverse
    of a and write x -a.

7
Field Definition (cont.)
  • Field axioms (cont.) For all a, b, c in F,
  • ab in F
  • (ab)c a(bc)
  • ab ba
  • There exists 1F in F, 1F ? 0F, such that for each
    a in F, a1F a 1Fa. We call 1F the
    multiplicative identity.
  • For each a ? 0F in F, there exists an element y
    in F such that ay 1F ya. We call y the
    multiplicative inverse of a and write y a-1.
  • a(bc) ab ac and (bc)a ba ca.
    (Distributive Law)

8
Field Examples
  • Note that any field is an abelian group under
    and the non-zero elements of a field form an
    abelian group under .
  • Some examples of fields
  • Real numbers
  • Zp, the set of integers modulo p, where p is a
    prime number is a finite field.
  • For example, Z70, 1, 2, 3, 4, 5, 6 and
    Z230, 1, 2, 3, , 22.

9
Elliptic Curves Over the Real Numbers
  • Let a and b be real numbers. An elliptic curve E
    over the field of real numbers R is the set of
    points (x,y) with x and y in R that satisfy the
    equation
  • together with a single element 1, called the
    point at infinity.
  • There are other types of elliptic curves, but
    well only consider elliptic curves of this form.
  • If the cubic polynomial x3axb has no repeated
    roots, we say the elliptic curve is non-singular.
  • A necessary and sufficient condition for the
    cubic polynomial x3axb to have distinct roots
    is 4a3 27 b2 ? 0.
  • In what follows, well always assume the elliptic
    curves are non-singular.

10
Examples of Elliptic Curves
  • y2 x3-7x6
  • y2 x3-2x4

11
An Elliptic Curve Lemma
  • The next result provides a way to turn the set of
    points on a non-singular elliptic curve into an
    abelian group!
  • Elliptic Curve Lemma Any line containing two
    points of a non-singular elliptic curve contains
    a unique third point, where
  • Any vertical line contains ?, the point at
    infinity.
  • Any tangent line contains the point of tangency
    twice.

12
Geometric Elliptic Curve Addition
  • Using the Elliptic Curve Lemma, we can define a
    way to geometrically add points P and Q on a
    non-singular elliptic curve E!
  • First, define the point at infinity to be the
    additive identity, i.e. for all P in E,
  • P ? P ? P.
  • Next, define the negative of the point at
    infinity to be - ? ?.

13
Geometric Elliptic Curve Addition (cont.)
  • For P (xP,yP), define the negative of P to be
    -P (xP,-yP), the reflection of P about the
    x-axis.
  • From the elliptic curve equation,
  • we see that whenever P is in E, -P is also in E.

14
Geometric Elliptic Curve Addition (cont.)
  • In what follows, assume that neither P nor Q is
    the point at infinity.
  • For P (xP,yP) and Q (xQ,yQ) in E, there are
    three cases to consider
  • P and Q are distinct points with xP ? xQ.
  • Q -P, so xP xQ and yP - yQ.
  • Q P, so xP xQ and yP yQ.

15
Geometric Case 1 xP ? xQ
  • By the Elliptic Curve Lemma, the line L through P
    and Q will intersect the curve at one other
    point.
  • Call this third point -R.
  • Reflect the point -R about the x-axis to point R.
  • PQ R
  • y2 x3-7x6

16
Geometric Case 2 xP xQ and yP - yQ
  • In this case, the line L through P and Q -P is
    vertical.
  • By the Elliptic Curve Lemma, L will also
    intersect the curve at ?.
  • PQ P(-P) ?
  • It follows that the additive inverse of P is -P.
  • y2 x3-2x4

17
Geometric Case 3 xPxQ and yP yQ
  • Since P Q, the line L through P and Q is
    tangent to the curve at P.
  • If yP 0, then P -P, so we are in Case 2, and
    PP ?.
  • For yP ? 0, the Elliptic Curve Lemma says that L
    will intersect the curve at another point, -R.
  • As in Case 1, reflect -R about the x-axis to
    point R.
  • PP R
  • Notation 2P PP
  • y2 x3-7x6

18
Geometric Elliptic Curve Model
  • For an interactive illustration of how geometric
    elliptic addition works, a great resource is
    Certicoms Geometric Elliptic Curve Model.
  • For the elliptic curves y2 x3-7x6 and y2
    x3-2x4, try adding points P and Q or doubling P
    (i.e. 2 P PP), graphically.

19
Algebraic Elliptic Curve Addition
  • Geometric elliptic curve addition is useful for
    illustrating the idea of how to add points on an
    elliptic curve.
  • Using algebra, we can make this definition more
    rigorous!
  • As in the geometric definition, the point at
    infinity is the identity, - ? ?, and for any
    point P in E, -P is the reflection of P about the
    x-axis.

20
Algebraic Elliptic Curve Addition (cont.)
  • In what follows, assume that neither P nor Q is
    the point at infinity.
  • As in the geometric case, for P (xP,yP) and Q
    (xQ,yQ) in E, there are three cases to consider
  • P and Q are distinct points with xP ? xQ.
  • Q -P, so xP xQ and yP - yQ.
  • Q P, so xP xQ and yP yQ.

21
Algebraic Case 1 xP ? xQ
  • First we consider the case where P (xP,yP) and
    Q (xQ,yQ) with xP ? xQ.
  • The equation of the line L though P and Q is y
    ? x?, where
  • In order to find the points of intersection of L
    and E, substitute ? x ? for y in the equation
    for E to obtain the following
  • The roots of (2) are the x-coordinates of the
    three points of intersection.
  • Expanding (2), we find

22
Algebraic Case 1 xP ? xQ (cont.)
  • Since a cubic equation over the real numbers has
    either one or three real roots, and we know that
    xP and xQ are real roots, it follows that (3)
    must have a third real root, xR.
  • Writing the cubic on the left-hand side of (3) in
    factored form
  • we can expand and equate coefficients of like
    terms to find

23
Algebraic Case 1 xP ? xQ (cont.)
  • We still need to find the y-coordinate of the
    third point, -R (xR,-yR) on the
    curve E and line L.
  • To do this, we can use the fact that the slope of
    line L is determined by the points P and -R, both
    of which are on L
  • Thus, the sum of P and Q will be the point R
    (xR, yR) with
  • where

24
Algebraic Case 2 xP xQ and yP - yQ
  • In this case, the line L through P and Q -P is
    vertical, so L contains the point at infinity.
  • As in the geometric case, we define PQ P(-P)
    ?, which makes P and -P additive inverses.

25
Algebraic Case 3 xPxQ and yP yQ
  • Finally, we need to look at the case when Q P.
  • If yP 0, then P -P, so we are in Case 2, and
    PP ?.
  • Therefore, we can assume that yP ? 0.
  • Since P Q, the line L through P and Q is the
    line tangent to the curve at (xP,yP).

26
Algebraic Case 3 xPxQ and yP yQ
  • The slope of L can be found by implicitly
    differentiating the equation y2 x3 ax b and
    substituting in the coordinates of P
  • Arguing as in Case 1, we find that
  • PP 2P R, with R (xR,yR), where

27
Elliptic Curve Groups
  • From these definitions of addition on an elliptic
    curve, it follows that
  • Addition is closed on the set E.
  • Addition is commutative.
  • ? is the identity with respect to addition.
  • Every point P in E has an inverse with respect to
    addition, namely -P.
  • The associative axiom also holds, but is hard
    to prove.

28
Elliptic Curves Over Finite Fields
  • Instead of choosing the field of real numbers, we
    can create elliptic curves over other fields!
  • Let a and b be elements of Zp for p prime, pgt3.
    An elliptic curve E over Zp is the set of points
    (x,y) with x and y in Zp that satisfy the
    equation
  • together with a single element ?, called the
    point at infinity.
  • As in the real case, to get a non-singular
    elliptic curve, well require 4a3 27 b2 (mod p)
    ? 0 (mod p).
  • Elliptic curves over Zp will consist of a finite
    set of points!

29
Addition on Elliptic Curves over Zp
  • Just as in the real case, we can define addition
    of points on an elliptic curve E over Zp, for
    prime pgt3.
  • This is done in the essentially the same way as
    the real case, with appropriate modifications.

30
Addition on Elliptic Curves over Zp (cont.)
  • Suppose P and Q are points in E.
  • Define P ? ? P P for all P in E.
  • If Q -P (mod p), then PQ ?.
  • Otherwise, PQ R (xR,yR), where

31
Elliptic Curves Over Z23 Model
  • Again, Certicom provides a model for an elliptic
    curve over a finite field Finite Geometric
    Elliptic Curve Model.
  • For the elliptic curves y2 x316x6 and y2
    x321x4 over the field Z23, try adding points P
    and Q or doubling P (i.e. 2 P PP).

32
Cryptography on an Elliptic Curve
  • Using an elliptic curve over a finite field, we
    can exchange information securely!
  • For example, we can implement a scheme invented
    by Whitfield Diffie and Martin Hellman in 1976
    for exchanging a secret key.

33
Diffie-Hellman Key Exchange via Colors of Paint
  • Alice and Bob each have a three-gallon bucket
    that holds paint.
  • Alice and Bob choose a public color of paint,
    such as yellow.
  • Alice chooses a secret color, red.
  • Alice mixes one gallon of her secret color, red,
    with one gallon of yellow and sends the mixture
    to Bob.
  • Bob chooses a secret color, purple.
  • Bob mixes one gallon of his secret color, purple,
    with one gallon of yellow and sends the mixture
    to Alice.

34
Diffie-Hellman Key Exchange via Colors of Paint
(cont.)
  • Alice adds one gallon of her secret color, red to
    the mixture from Bob. Alice ends up with a
    bucket of one gallon each of yellow, purple, and
    red paint.
  • Bob adds one gallon of his secret color, purple,
    to the mixture from Alice. Bob ends up with a
    bucket one gallon each of yellow, red, and purple
    paint.
  • Both Alice and Bob will have a bucket of paint
    with the same colorthis common color is the key!
  • Note that even if eavesdropper Eve knows that the
    common color is yellow, or intercepts the paint
    mixtures from Alice or Bob, she will not be able
    to figure out Alices or Bobs secret color!

35
Diffie-Hellman Key Exchange via an Elliptic Curve
  • Alice and Bob publicly agree on an elliptic curve
    E over a finite field Zp.
  • Next Alice and Bob choose a public base point B
    on the elliptic curve E.
  • Alice chooses a random integer 1lt?ltE, computes
    P ? B, and sends P to Bob. Alice keeps her
    choice of ? secret.
  • Bob chooses a random integer 1lt?ltE, computes Q
    ? B, and sends Q to Alice. Bob keeps his
    choice of ? secret.
  • Alice and Bob choose E to be the curve y2
    x3x6 over Z7.
  • Alice and Bob choose the public base point to be
    B(2,4).
  • Alice chooses ? 4, computes P ?B 4(2,4)
    (6,2), and sends P to Bob. Alice keeps ? secret.
  • Bob chooses ? 5, computes Q ?B 5(2,4)
    (1,6), and sends Q to Alice. Bob keeps ? secret.

36
Diffie-Hellman Key Exchange via an Elliptic Curve
(cont.)
  • Alice computes KA ?Q ?(?B).
  • Bob computes KB ?P ?(?B).
  • The shared secret key is K KA KB.
  • Even if Eve knows the base point B, or P or Q,
    she will not be able to figure out ? or ?, so K
    remains secret!
  • Alice computes KA?Q 4(1,6) (4,2).
  • Bob computes KB ?P 5(6,2)
    (4,2).
  • The shared secret key is K (4,2).

37
References
  • Hungerford, Thomas W. Abstract Algebra An
    Introduction Second Edition. New York Saunders
    College Publishing, 1997.
  • Koblitz, Neal. Algebraic Aspects of Cryptography.
    Berlin Springer-Verlag, 1999.
  • Online ECC Tutorial. Certicom. www.certicom.com
  • Stinson, Douglas R. Cryptography Theory and
    Practice Second Edition. New York Chapman
    Hall/CRC, 2002.
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